1. Carilah:
1. Jumlah Subnet
2. Jumlah Host
3. Blok Subnet
Dari IP berikut:
a. 172.140.56.9 /29
b. 210.124.111.11 /27
c. 30.68.100.72 /26
d. 128.96.200.10/23
e. 10.0.213.7 /21
172.140.56.9 /29
11111111.11111111.11111111.11111000
10101100.10001100.00111000.00001001
10101100.10001100.00111000.00001000
AND
Network ID dari 172.140.56.9 adalah = 172.140.56.8
1. jumlah subnet
2x, x = 5
maka 25 = 32
2. jumlah host
2y-2, y =3 maka 23-2 = 8 - 2 = 6
3. blok subnet
256-248 = 8
1) 0
2) 0+8=8
3) 8+8=16
4) ..
32) 240+8=248
Subnet/net
172.140.56.0
172.140.56.8
Host pertama 172.140.56.1
172.140.56.9
Host terakhir
172.140.56.6
172.140.56.14
Broadcast
172.140.56.7
172.140.56.15
172.140.56.16
172.140.56.17
172.140.56.22
172.140.56.23
…
…
…
…
210.124.111.11 /27
11111111.11111111.11111111.11100000
11010010.11111000.11011110.00001011
11010010.11111000.11011110.00000000
Network ID dari 210.124.111.11 adalah = 210.124.111.0
1. jumlah subnet
2x, x = 3
maka 23 = 8
AND
172.140.56.248
172.140.56.249
172.140.56.254
172.140.56.255

2. 2. jumlah host
2y-2, y =5 maka 25-2 = 32 - 2 = 30
3. blok subnet
256-224 = 32
1) 0
2) 0+32=32
3) 32+32=64
4) …
8) 192+32=224
Subnet/net
210.124.111.0
210.124.111.32
Host pertama 210.124.111.1
210.124.111.33
Host terakhir 210.124.111.30 210.124.111.62
Broadcast
210.124.111.31 210.124.111.63
210.124.111.64
210.124.111.65
210.124.111.94
210.124.111.95
…
…
…
…
210.124.111.224
210.124.111.225
210.124.111.254
210.124.111.255
30.68.100.72 /26
11111111.11111111.11111111.11000000
00011110.01000100.01100100.01001000
00011110.01000100.01100100.01000000
AND
Network ID dari 30.68.100.72 adalah = 30.68.100.64
1. jumlah subnet
2x, x = 2
maka 22 = 4
2. jumlah host
2y-2, y =6
maka 26-2 = 64 - 2 = 62
3. blok subnet
256-192=64
1) 0
2) 0+64=64
3) 64+64=128
4) 128+64=192
Subnet/net
30.68.100.0
30.68.100.64
Host pertama 30.68.100.1
30.68.100.65
Host terakhir
30.68.100.62
30.68.100.126
Broadcast
30.68.100.63
30.68.100.127
30.68.100.128
30.68.100.129
30.68.100.190
30.68.100.191
30.68.100.192
30.68.100.193
30.68.100.254
30.68.100.255
128.96.200.10/23
11111111.11111111.11111110.00000000
10000000.01100000.11001000.00001010
10000000.01100000.11001000.00000000
Network ID dari 128.96.200.10 adalah = 128.96.200.0
AND

3. 1. jumlah subnet
2x, x = 7
maka 27 = 128
2. jumlah host
2y-2, y =9
maka 29-2 = 512 - 2 = 510
3. blok subnet
256-254=2
1) 0
2) 0+2=2
3) 2+2=4
4) …
128)252+2=254
Subnet/net
128.96.0.0
128.96.2.0
Host pertama
128.96.0.1
128.96.2.1
Host terakhir
128.96.1.254
128.96.3.254
Broadcast
128.96.1.255
128.96.3.255
128.96.4.0
128.96.4.1
128.96.5.254
128.96.5.255
…
…
…
…
128.96.254.0
128.96.254.1
128.96.255.254
128.96.255.255
10.0.213.7 /21
11111111.11111111.11111000.00000000
00001010.01100000.11001000.00001010
10000000.01100000.11001000.00000000
AND
Network ID dari 128.96.200.10 adalah = 128.96.200.0
1. jumlah subnet
2x, x = 5
maka 25 = 32
2. jumlah host
2y-2, y =11
maka 211-2 = 2048 - 2 = 2046
3. blok subnet
256-248=8
1) 0
2) 0+8=8
3) 8+8=16
4) …
32) 240+8=248
Subnet/net
10.0.0.0
10.0.8.0
10.0.16.0
Host pertama
10.0.0.1
10.0.8.1
10.0.16.1
Host terakhir
10.0.7.254
10.0.15.254
10.0.23.254
Broadcast
10.0.7.255
10.0.15.255
10.0.23.255
…
…
…
…
10.0.248.0
10.0.248.1
10.0.255.254
10.0.255255