Lecture16

Physics 101: Lecture 16 Angular Momentum ,[object Object],Exam II

Overview ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

Linear and Angular ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Today

Define Angular Momentum Momentum Angular Momentum p = mV L = I  conserved if  F ext = 0 conserved if  ext =0 Vector Vector! units: kg-m/s units: kg-m 2 /s

Right Hand Rule ,[object Object],[object Object],[object Object]

Act: Two Disks ,[object Object],[object Object], i Wheel rim drop z  f z

Act: Two Disks ,[object Object],[object Object], 0 z 2 1  f z

Lecture 16, Pre-flights ,[object Object],[object Object]

Bonus Question! ,[object Object],[object Object],Key is no external torques about vertical axis! FBD has gravity and normal force.

Lecture 16, Preflight 1 ,[object Object],[object Object],“ Because there are no external torques present, angular momentum is conserved ” L 1 L 2 CORRECT

Lecture 16, Preflight 2 ,[object Object],[object Object],“ you decreased the I so w increases ” “ I tried this out Friday night ” “ thanks for the new drinking game”  1  2 I 2 I 1 L L CORRECT

Lecture 16, Preflight 3 ,[object Object],[object Object],“ KE is inversly related to intertia, therefore, increases.” CORRECT  1  2 I 2 I 1 L L (using L = I  )

What about Energy Conservation? ,[object Object],[object Object],[object Object],[object Object],[object Object]

Turning the bike wheel ,[object Object],[object Object],Start w/ angular momentum L pointing up from wheel. When wheel is flipped, no more angular momentum from it pointing up, so need to spin person/stool to conserve L! CORRECT

Turning the bike wheel (more) ,[object Object],[object Object]

Turning the bike wheel... ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],L W,F L S L W,I L W,I = L W,F + L S

Act 2 Rotations  ,[object Object],(a) 2 (b) 4 (c) 8 Puck on ice

Act 2 Solution ,[object Object],L 1 = I 1  1 = mR 2  1    m R    m R/2 L 2 = I 2  2 = m  2 = mR 2  1 = m R 2  2  1 =  2  2 = 4  1

Gyroscopic Motion: ,[object Object],[object Object], pivot support g

Gyroscopic Motion... ,[object Object],[object Object],[object Object], pivot g

Gyroscopic Motion... ,[object Object], pivot Bicycle wheel

Summary ,[object Object],[object Object],[object Object],[object Object]

Lecture16

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Lecture16

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