Explain one identity 3(/x-1 -2/x+1 ):x+2/x^2-1=2 Solution You need to establish the identity [(3/(x-1) -2/(x+1)):(x+2)/(x^2-1)=2. ] Notice that you need to multiply brackets by reverse of fraction [(x+2)/(x^2-1)] such that: [(3/(x-1) -2/(x+1))*(x^2 -1)/(x+2) = 2] You need to bring the fractions in brackets to a common denominator such that: [((3(x+1)-2(x-1))/(x-1)(x+1))*(x^2 -1)/(x+2) = 2] Notice that you may write the common denominator as difference of squares such that: [((3(x+1)-2(x-1))/(x^2 - 1))*(x^2 -1)/(x+2) = 2] Reducing by ( [x^2 - 1] ) yields: [(3(x+1)-2(x-1))/(x+2) = 2] You need to open the brackets to numerator such that: [(3x + 3 - 2x + 2)/(x + 2) = 2] [(x+5)/(x+2)=2 =gt x + 5 = 2x + 4] The last line proves that the identity is not established..