calculate the quantity of work of a system in joules associated with a compression of a gas from 5.37 L to 3.62 L by a constant pressure of 1.33 atm Solution Sol:- For the compression of gas W = P ext. delta V ............ (1) here W = work done = ? P ext. = external pressure = 1.33 atm delta V = change in volume = final volume (V f ) - initial volume (V i ) V i = 5.37 and L V f = 3.62 L Now on substituting the values in equation (1) , we have W = 1.33 atm ( 3.62 L - 5.37 L ) W = 1.33 atm x (- 1.75 L ) W = - 2.3275 L atm because 1 L atm = 101.33 J therefore W = - 2.3275 x 101.33 J W = - 235.84 J Hence quantity of work of a system = - 235.84 J .

1. calculate the quantity of work of a system in joules associated with a compression of a gas from
5.37 L to 3.62 L by a constant pressure of 1.33 atm
Solution
Sol:-
For the compression of gas
W = P ext. delta V ............ (1)
here W = work done = ?
P ext. = external pressure = 1.33 atm
delta V = change in volume = final volume (V f ) - initial volume (V i )
V i = 5.37 and L
V f = 3.62 L
Now on substituting the values in equation (1) , we have
W = 1.33 atm ( 3.62 L - 5.37 L )
W = 1.33 atm x (- 1.75 L )
W = - 2.3275 L atm
because
1 L atm = 101.33 J
therefore
W = - 2.3275 x 101.33 J

2. W = - 235.84 J
Hence quantity of work of a system = - 235.84 J