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US Klein- Organic Chemistry- 3e & Practice Assignment ent Gradebook OR.docx

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US Klein- Organic Chemistry- 3e & Practice Assignment ent Gradebook OR.docx

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US Klein, Organic Chemistry, 3e & Practice Assignment ent Gradebook ORION Downloadable eTextbook Assignment RCES Practice Problem 17.30 Write the number of t electrons for the following compound er 17.24 17.25 17.30 1734 17.37 17.39 n 17.42 lem blem Number of x electrons: by Stud exact number, no tolerance SHOW HINT LINK TO TEXT
Solution
No. Of pi electrons :- we can calculate it by counting the number of pi bond x 2.
And if there is any lone pair on atom than we also add it in our count. So, here we can see that no lone pair of electrons.
No. of pi bonds = 5
Hence no. Of pi electrons = 5 x 2 = 10.
If you satisfied with the solution please like it thankxx....
.

US Klein, Organic Chemistry, 3e & Practice Assignment ent Gradebook ORION Downloadable eTextbook Assignment RCES Practice Problem 17.30 Write the number of t electrons for the following compound er 17.24 17.25 17.30 1734 17.37 17.39 n 17.42 lem blem Number of x electrons: by Stud exact number, no tolerance SHOW HINT LINK TO TEXT
Solution
No. Of pi electrons :- we can calculate it by counting the number of pi bond x 2.
And if there is any lone pair on atom than we also add it in our count. So, here we can see that no lone pair of electrons.
No. of pi bonds = 5
Hence no. Of pi electrons = 5 x 2 = 10.
If you satisfied with the solution please like it thankxx....
.

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US Klein- Organic Chemistry- 3e & Practice Assignment ent Gradebook OR.docx

  1. 1. US Klein, Organic Chemistry, 3e & Practice Assignment ent Gradebook ORION Downloadable eTextbook Assignment RCES Practice Problem 17.30 Write the number of t electrons for the following compound er 17.24 17.25 17.30 1734 17.37 17.39 n 17.42 lem blem Number of x electrons: by Stud exact number, no tolerance SHOW HINT LINK TO TEXT Solution No. Of pi electrons :- we can calculate it by counting the number of pi bond x 2. And if there is any lone pair on atom than we also add it in our count. So, here we can see that no lone pair of electrons. No. of pi bonds = 5 Hence no. Of pi electrons = 5 x 2 = 10. If you satisfied with the solution please like it thankxx....

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