Find the dimension of a rectangle A rectangle is 10ft longer than it\'s width. The width of the surrounding deck is 3inches on each side. If the area is 1824sq.ft, find the dimension of the outside edge of the deck. Solution To solve this problem we must first find out the dimension of the rectangle. To do this let us assume that width of the rectangle is X ft. Then the length will be = X + 10 Then area of the rectangle = X * (X + 10) = 1824 Therefore X^2 + 10X = 1824 adding 25 on both sides of equation we get X^2 + 10x + 25 = 1849 Therefore (X + 5)^2 = 1849 (X + 5) = 43 X = 43 - 5 = 38 Therefore the rectangle is 38 ft wide and 48 ft long. As the deck is 3 inch (0.25 ft) wide the dimensions of the outer edge of deck are: 38.5 ft wide by 48.5 ft long..