An electronic point source emits sound isotropically at a frequency of 4 × 10 3 Hz and a power of 33 watts. A small microphone has an area of 0.78 cm 2 and is located 248 meters from the point source. 1) What is the sound intensity at the microphone ? I = W/m 2 2) What is the power intercepted by the microphone? P in = W 3) How many minutes will it take for the microphone to recieve 0.1 Joules from this sound? ?T = min 4) What is the sound intensity level at the microphone from this point source? ? = dB 5) What would be the sound intensity level at the microphone if the point source doubled its power output? ? = Solution (1) Intensity = P / 4pir^2 l = 33 / 4*3.14*248^2 l = 4.27*10^(-5) W/m^2 (2) Pin = l * A Pin = 4.27*10^(-5) * 0.78 *10^(-4) Pin = 3.33*10^(-9) W (3) E = P*t t = 0.1 / 3.33*10^(-9) t = 3*10^7 s (4) l = 4.27*10^(-5) W/m^2 .