Publicidad

Próximo SlideShare

Chemical dynamics, intro,collision theory by dr. y. s. thakare

Cargando en ... 3

3 de Feb de 2023•0 recomendaciones## 0 recomendaciones

•2 vistas## vistas

Sé el primero en que te guste

ver más

Total de vistas

0

En Slideshare

0

De embebidos

0

Número de embebidos

0

Descargar para leer sin conexión

Denunciar

Educación

An expression for the equilibrium constant, Keq, based in statistical thermodynamics is shown below. Answer the following questions. Ke, - i) How is the sign of vj different for reactants and products? ii) What is the effect on Keq if the reactants are higher in energy than the products? Explain Would this case be exothermic or endothermic? iii) How is the Keq effected if the reactants have a greater number of thermally accessible states than the products? How is this related to the expression for Keq? case. Predict the sign of ArS in this Solution vi is actually called the stoichiometric number which is the difference of the stoichiometric factor for the reactents minus the products.. If the reactents are higher in energy then the delE is large.. The exponential term dominates but the minus sign before guarantees that the K is very very less than 1. This in turn illustrates that the concentration of the product is very low. In the equilibrium. As the energy states ( electronic) are higher for the products than the reactents the reaction is endothermic. K is directly propotional to the ratio of the partition function of the product and the reactent then the higher number of the thermally accesible states of reactent means that the ratio will decrease, as the denominator is high.. Thus the K will decrease and reactent side will be predominating in the equilibrium. The entropy on the reactant side will be greater than that of the product side because of the higher number of accessible states (as S =k lnw) and the delS will be negative for the overall reaction. .

shawnk7Seguir

Publicidad

Publicidad

Publicidad

Chemical dynamics, intro,collision theory by dr. y. s. thakarepramod padole

Chemical dynamics, intro,collision theoryShri Shivaji Science College Amravati

How to Read Potential Energy DiagramsChristy Cole

Tang 03 rate theoriesmrtangextrahelp

Bioenergetics VarshaChaudhari9

Tang 08 rate theoriesmrtangextrahelp

- An expression for the equilibrium constant, Keq, based in statistical thermodynamics is shown below. Answer the following questions. Ke, - i) How is the sign of vj different for reactants and products? ii) What is the effect on Keq if the reactants are higher in energy than the products? Explain Would this case be exothermic or endothermic? iii) How is the Keq effected if the reactants have a greater number of thermally accessible states than the products? How is this related to the expression for Keq? case. Predict the sign of ArS in this Solution vi is actually called the stoichiometric number which is the difference of the stoichiometric factor for the reactents minus the products.. If the reactents are higher in energy then the delE is large.. The exponential term dominates but the minus sign before guarantees that the K is very very less than 1. This in turn illustrates that the concentration of the product is very low. In the equilibrium. As the energy states ( electronic) are higher for the products than the reactents the reaction is endothermic. K is directly propotional to the ratio of the partition function of the product and the reactent then the higher number of the thermally accesible states of reactent means that the ratio will decrease, as the denominator is high.. Thus the K will decrease and reactent side will be predominating in the equilibrium. The entropy on the reactant side will be greater than that of the product side because of the higher number of accessible states (as S =k lnw) and the delS will be negative for the overall reaction.

Publicidad