The document describes a problem where the area of a triangle must be at least 42, the base is twice the height, and asks to find the inequality to solve for the shortest possible base. It provides the solution that using the area formula 0.5*b*h=42, substituting 2b for h, and solving for b yields b=7, so the correct inequality is 1/4b^2=42.

1. please help me with the problem below.
The area of a triangle must be at least 42. The base is twice the height.
Which of the following is an inequality that can be used to solve for the shortest possible base?
Select one.
A. 1
2
b·2h = 42
B. 1
4
b2 = 42
C. 1
2
bh = 42
D. 1
4
b2 = 42
Solution
0.5*b*h = 42. 2b = h 0.5*b*2b = 42 3b = 42/0.5 3b = 21, B = 7.