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A compound lens system consists of two converging lenses one at z -20.0 cm with focal length fi-+10.0 cm. and the other at z +20.0 cm with focal length f2 +8.00 cm. (Figure 1)An object 1.00 centimeter tall is placed at x 50.0cm What is the location of the final image produced by the compound lens system? Give the x coordinate of the image. Express your answer in centimeters, to three significant figures or as a fraction. View Available Hint(s -31.8 cm Previous Answers Correct Figure 1 of 1 Part How tall is the image? Express your answer in centimeters, to three significant figures or as a fraction View Available Hint(s) fi f2 cm Submit Solution here, for the first lens the focal length , f1 = 10 cm object distance , do1 = 30 cm let the image distance be di1 using the lens formula 1/f1 = 1/di1 + 1/do1 1/10 = 1/di1 + 1/30 di1 = 15 cm for the seccond lens the focal length , f2 = 8 cm object distance , do2 = 25 cm let the image distance be di2 using the lens formula 1/f2 = 1/di2 + 1/do2 1/8 = 1/di2 + 1/25 di2 = 11.8 cm B) the image height , hi = h0 * ( di1/do1) *(di2/do2) hi = 1 * ( 15/30) *(11.8/25) hi = 0.24 .

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- A compound lens system consists of two converging lenses one at z -20.0 cm with focal length fi-+10.0 cm. and the other at z +20.0 cm with focal length f2 +8.00 cm. (Figure 1)An object 1.00 centimeter tall is placed at x 50.0cm What is the location of the final image produced by the compound lens system? Give the x coordinate of the image. Express your answer in centimeters, to three significant figures or as a fraction. View Available Hint(s -31.8 cm Previous Answers Correct Figure 1 of 1 Part How tall is the image? Express your answer in centimeters, to three significant figures or as a fraction View Available Hint(s) fi f2 cm Submit Solution here, for the first lens the focal length , f1 = 10 cm object distance , do1 = 30 cm let the image distance be di1 using the lens formula 1/f1 = 1/di1 + 1/do1 1/10 = 1/di1 + 1/30 di1 = 15 cm for the seccond lens the focal length , f2 = 8 cm object distance , do2 = 25 cm let the image distance be di2
- using the lens formula 1/f2 = 1/di2 + 1/do2 1/8 = 1/di2 + 1/25 di2 = 11.8 cm B) the image height , hi = h0 * ( di1/do1) *(di2/do2) hi = 1 * ( 15/30) *(11.8/25) hi = 0.24

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