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Module 5 (properties of pure substance)2021 2022
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### A compressor brings R-134a from 140kPa- -10 C to 1200 kPa- 50 C- It is.docx

1. A compressor brings R-134a from 140kPa, -10 C to 1200 kPa, 50 C. It is water cooled with heat loss estimated to 40kW and the shaft work input is measure to be 150 kW. What is the mass flow rate through the compressor? Professor gave us the answer of 3.45 kg/s. Not sure what tables to look up the information for the coolant on. Any help is appreciated. Step by step please. Solution C.V compressor steady flow Neglect kinetic & potential energy Energy mHi + Q = mHe + W m = (Q - W)/(He - Hi) Q = -40, W = -150 To get, He & Hi use table given to you,
2. m = 110/(He - Hi) (You didn't provide table, this will be some enthalpy table for water which will give you value of enthalpy for given pressure & temperature) value for hi ( 140kPa, -10 C) will be in between 390 to 410 & for he( 1200 kPa, 50 C) it will be around (hi + 31). put value of He & Hi you will get m.
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