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A compressor, in delivering compressed air to power tools, compresses air from an initial pressure and temperature of P 1 = 120 kPa, and T 1 = 20 o C, up to a final pressure and temperature of P 2 = 1.0 MPa, and T 2 = 300 o C. The volumetric flow rate of air into the compressor is 0.01 m 3 /sec. Find: The mass flow rate of air through the compressor. The power drawn by the compressor. Solution P*V=mRT R for air=286.9 J/kgK T=20=273+20=293K so m=120*10^3*0.01/(286.9*293) =0.014 kg/s for adiabatic gas relation is T1/P1^(n-1)/n=T2/P2^(n-1)/n so T1/T2=(P1/P2)^(n-1)/n so n=1.46 P=mR(T2-T1)/(n-1)=0.014*286.9*(573-293)/(1.46-1) =2444.88 W .

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- A compressor, in delivering compressed air to power tools, compresses air from an initial pressure and temperature of P 1 = 120 kPa, and T 1 = 20 o C, up to a final pressure and temperature of P 2 = 1.0 MPa, and T 2 = 300 o C. The volumetric flow rate of air into the compressor is 0.01 m 3 /sec. Find: o The mass flow rate of air through the compressor. o The power drawn by the compressor. Solution P*V=mRT R for air=286.9 J/kgK T=20=273+20=293K so m=120*10^3*0.01/(286.9*293) =0.014 kg/s for adiabatic gas relation is T1/P1^(n-1)/n=T2/P2^(n-1)/n
- so T1/T2=(P1/P2)^(n-1)/n so n=1.46 P=mR(T2-T1)/(n-1)=0.014*286.9*(573-293)/(1.46-1) =2444.88 W

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