Find the current Io in the circuit shown at right. Find the current Io in the circuit shown at right. Solution consider the resistance network to the right of the current source in the figure lets first simplify this part by finding the equivalent resistance for the all these resistors 20K and 40 K are in series ==> net of them is 60k now this net 60k is parallel to 20k so the net of them is 20k*60k / 20k+60k = 15k this is in series to 15k \\so overall net resistance to the right of current source is 30k 9mA is to be divided between the left resistance i.e 60k and right net resistance i. e 30k ratio of the resistances . i.e 60k :30k = 2:1 the current divides in the inverse ratio of the resistances . i.e 1:2 so Io = 1/3 * 9mA = 3mA .