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Pressure Measurements
Pascal’s Law
β€’ β€œ The intensity of pressure at any point in a liquid at rest, is the same in all
directions”
Proof: Let us consider a very small wedge shaped element LMN of a liquid.
Let, 𝑝π‘₯ = 𝑖𝑛𝑑𝑒𝑛𝑠𝑖𝑑𝑦 π‘œπ‘“ β„Žπ‘œπ‘Ÿπ‘–π‘§π‘œπ‘›π‘‘π‘Žπ‘™ π‘π‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ π‘œπ‘› π‘‘β„Žπ‘’ π‘’π‘™π‘’π‘šπ‘’π‘›π‘‘ π‘œπ‘“ π‘™π‘–π‘žπ‘’π‘–π‘‘
𝑝𝑦 = 𝑖𝑛𝑑𝑒𝑛𝑠𝑖𝑑𝑦 π‘œπ‘“ π‘£π‘’π‘Ÿπ‘‘π‘–π‘π‘Žπ‘™ π‘π‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ π‘œπ‘› π‘‘β„Žπ‘’ π‘’π‘™π‘’π‘šπ‘’π‘›π‘‘ π‘œπ‘“ π‘™π‘–π‘žπ‘’π‘–π‘‘
𝑝𝑧
= 𝑖𝑛𝑑𝑒𝑛𝑠𝑖𝑑𝑦 π‘œπ‘“ π‘π‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ π‘œπ‘› π‘‘β„Žπ‘’ π‘‘π‘–π‘Žπ‘”π‘œπ‘›π‘Žπ‘™ π‘œπ‘“ π‘‘β„Žπ‘’ π‘Ÿπ‘–π‘”β„Žπ‘‘ π‘Žπ‘›π‘”π‘™π‘’π‘‘ π‘‘π‘Ÿπ‘–π‘Žπ‘›π‘”π‘’π‘™π‘Žπ‘Ÿ π‘’π‘™π‘’π‘š
Ξ± = Angle of the element of the liquid
𝑃π‘₯ = π‘‡π‘œπ‘‘π‘Žπ‘™ π‘π‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ π‘œπ‘› π‘‘β„Žπ‘’ π‘£π‘’π‘Ÿπ‘‘π‘–π‘π‘Žπ‘™ 𝑠𝑖𝑑𝑒 𝐿𝑁 π‘œπ‘“ π‘‘β„Žπ‘’ π‘™π‘–π‘žπ‘’π‘–π‘‘
𝑃𝑦 = π‘‡π‘œπ‘‘π‘Žπ‘™ π‘π‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ π‘œπ‘› π‘‘β„Žπ‘’ β„Žπ‘œπ‘Ÿπ‘–π‘§π‘œπ‘›π‘‘π‘Žπ‘™ 𝑠𝑖𝑑𝑒 𝑀𝑁 π‘œπ‘“ π‘‘β„Žπ‘’ π‘™π‘–π‘žπ‘’π‘–π‘‘
𝑃𝑧 = π‘‡π‘œπ‘‘π‘Žπ‘™ π‘π‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ π‘œπ‘› π‘‘β„Žπ‘’ π‘‘π‘–π‘Žπ‘”π‘œπ‘›π‘Žπ‘™ 𝑠𝑖𝑑𝑒 𝐿𝑀 π‘œπ‘“ π‘‘β„Žπ‘’ π‘™π‘–π‘žπ‘’π‘–π‘‘
Now, 𝑃π‘₯ = 𝑝π‘₯ x LN ……(i)
𝑃𝑦 = 𝑝𝑦 x MN………….(ii)
𝑃𝑧 = 𝑝𝑧 x LM……………(iii)
β€’ As the element of the liquid is at rest, therefore
the sum of horizontal and vertical components
of the liquid pressures must be equal to zero
β€’ Resolving the forces horizontally:
β€’ 𝑃π‘₯ = 𝑃𝑧 sin Ξ±
β€’ 𝑝π‘₯ x LN = 𝑝𝑧 x LM sin Ξ±
β€’ 𝑝π‘₯ x LN = 𝑝𝑧 x LM x
𝐿𝑁
𝐿𝑀
β€’ 𝑝π‘₯ = 𝑝𝑧 ….. (iV)
β€’ Resolving the forces vertically:
𝑃𝑦 βˆ’ π‘Š = 𝑃𝑧 cos Ξ± (W= weight of the liquid element)
Since the element is very small, neglecting its weight we have
β€’ 𝑃𝑦 = 𝑃𝑧 cos Ξ±
β€’ 𝑝𝑦. MN = 𝑝𝑧 LM cos Ξ±
β€’ 𝑝𝑦. MN = 𝑝𝑧 LM
MN
LM
β€’ 𝑝𝑦 = 𝑝𝑧 ……..(v)
β€’ From (iv) & (v) we get
β€’ 𝑝π‘₯ = 𝑝𝑦 = 𝑝𝑧
Pressure Head of a Liquid
β€’ A liquid is subjected to pressure due to its own
weight, this pressure increases as the depth of
the liquid increases.
β€’ Consider a vessel containing liquid, the liquid
will exert pressure on all sides and bottom of
the vessel.
Now let cylinder be
made to stand in the liquid
β€’ Let h = height of liquid in the cylinder,
β€’ A = area of the cylinder base,
β€’ W = specific weight of the liquid,
β€’ P = intensity of pressure
Now Total pressure on the base of the cylinder =
weight if liquid in the cylinder
i.e., p A = w x A x h
𝑝 =
π‘€π΄β„Ž
𝐴
= π‘€β„Ž
𝑝 = π‘€β„Ž (β„Ž =
𝑝
𝑀
)
The intensity of pressure in a liquid due to its depth
will vary directly with depth
Measurement of Pressure
β€’ 1. Manometers
These are defined as the devices used for
measuring the pressure at a point in a fluid by
balancing the column of fluid by the same or
another column of liquid. These are classified as
a) Simple manometers
i. Piezometer
ii. U-tube manometer
iii. Single column manometer
b) Differential manometers
β€’ Mechanical gauges:
β€’ These are the devices in which the pressure is
measured by balancing the fluid column by
spring or dead weight.
β€’ These gauges are used for measuring high
pressure and high precision is not required.
β€’ Bourdon tube pressure gauge
β€’ Bellow pressure gauge
β€’ Diaphragm pressure gauge
β€’ Dead-weight pressure gauge
Simple manometers
β€’ 1. Piezometer: A piezometer is the simplest form of
manometer which can be used for measuring moderate
pressures of liquids.
β€’ It consists of a glass tube inserted in the wall of a vessel or
of a pipe, containing liquid whose pressure is to be
measured. The tube extends vertically upward to such a
height that liquid can freely rise in it without overflowing.
β€’ U- tube manometer:
β€’ A U-tube manometer consists of a glass tube
bent in U-shape, one end of which is
connected to a point at which pressure is to
be measured and other end remains open to
the atmosphere.

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Pressure Measurements.pptx

  • 2. Pascal’s Law β€’ β€œ The intensity of pressure at any point in a liquid at rest, is the same in all directions” Proof: Let us consider a very small wedge shaped element LMN of a liquid. Let, 𝑝π‘₯ = 𝑖𝑛𝑑𝑒𝑛𝑠𝑖𝑑𝑦 π‘œπ‘“ β„Žπ‘œπ‘Ÿπ‘–π‘§π‘œπ‘›π‘‘π‘Žπ‘™ π‘π‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ π‘œπ‘› π‘‘β„Žπ‘’ π‘’π‘™π‘’π‘šπ‘’π‘›π‘‘ π‘œπ‘“ π‘™π‘–π‘žπ‘’π‘–π‘‘ 𝑝𝑦 = 𝑖𝑛𝑑𝑒𝑛𝑠𝑖𝑑𝑦 π‘œπ‘“ π‘£π‘’π‘Ÿπ‘‘π‘–π‘π‘Žπ‘™ π‘π‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ π‘œπ‘› π‘‘β„Žπ‘’ π‘’π‘™π‘’π‘šπ‘’π‘›π‘‘ π‘œπ‘“ π‘™π‘–π‘žπ‘’π‘–π‘‘ 𝑝𝑧 = 𝑖𝑛𝑑𝑒𝑛𝑠𝑖𝑑𝑦 π‘œπ‘“ π‘π‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ π‘œπ‘› π‘‘β„Žπ‘’ π‘‘π‘–π‘Žπ‘”π‘œπ‘›π‘Žπ‘™ π‘œπ‘“ π‘‘β„Žπ‘’ π‘Ÿπ‘–π‘”β„Žπ‘‘ π‘Žπ‘›π‘”π‘™π‘’π‘‘ π‘‘π‘Ÿπ‘–π‘Žπ‘›π‘”π‘’π‘™π‘Žπ‘Ÿ π‘’π‘™π‘’π‘š Ξ± = Angle of the element of the liquid 𝑃π‘₯ = π‘‡π‘œπ‘‘π‘Žπ‘™ π‘π‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ π‘œπ‘› π‘‘β„Žπ‘’ π‘£π‘’π‘Ÿπ‘‘π‘–π‘π‘Žπ‘™ 𝑠𝑖𝑑𝑒 𝐿𝑁 π‘œπ‘“ π‘‘β„Žπ‘’ π‘™π‘–π‘žπ‘’π‘–π‘‘ 𝑃𝑦 = π‘‡π‘œπ‘‘π‘Žπ‘™ π‘π‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ π‘œπ‘› π‘‘β„Žπ‘’ β„Žπ‘œπ‘Ÿπ‘–π‘§π‘œπ‘›π‘‘π‘Žπ‘™ 𝑠𝑖𝑑𝑒 𝑀𝑁 π‘œπ‘“ π‘‘β„Žπ‘’ π‘™π‘–π‘žπ‘’π‘–π‘‘ 𝑃𝑧 = π‘‡π‘œπ‘‘π‘Žπ‘™ π‘π‘Ÿπ‘’π‘ π‘ π‘’π‘Ÿπ‘’ π‘œπ‘› π‘‘β„Žπ‘’ π‘‘π‘–π‘Žπ‘”π‘œπ‘›π‘Žπ‘™ 𝑠𝑖𝑑𝑒 𝐿𝑀 π‘œπ‘“ π‘‘β„Žπ‘’ π‘™π‘–π‘žπ‘’π‘–π‘‘ Now, 𝑃π‘₯ = 𝑝π‘₯ x LN ……(i) 𝑃𝑦 = 𝑝𝑦 x MN………….(ii) 𝑃𝑧 = 𝑝𝑧 x LM……………(iii)
  • 3. β€’ As the element of the liquid is at rest, therefore the sum of horizontal and vertical components of the liquid pressures must be equal to zero β€’ Resolving the forces horizontally: β€’ 𝑃π‘₯ = 𝑃𝑧 sin Ξ± β€’ 𝑝π‘₯ x LN = 𝑝𝑧 x LM sin Ξ± β€’ 𝑝π‘₯ x LN = 𝑝𝑧 x LM x 𝐿𝑁 𝐿𝑀 β€’ 𝑝π‘₯ = 𝑝𝑧 ….. (iV)
  • 4. β€’ Resolving the forces vertically: 𝑃𝑦 βˆ’ π‘Š = 𝑃𝑧 cos Ξ± (W= weight of the liquid element) Since the element is very small, neglecting its weight we have β€’ 𝑃𝑦 = 𝑃𝑧 cos Ξ± β€’ 𝑝𝑦. MN = 𝑝𝑧 LM cos Ξ± β€’ 𝑝𝑦. MN = 𝑝𝑧 LM MN LM β€’ 𝑝𝑦 = 𝑝𝑧 ……..(v) β€’ From (iv) & (v) we get β€’ 𝑝π‘₯ = 𝑝𝑦 = 𝑝𝑧
  • 5. Pressure Head of a Liquid β€’ A liquid is subjected to pressure due to its own weight, this pressure increases as the depth of the liquid increases. β€’ Consider a vessel containing liquid, the liquid will exert pressure on all sides and bottom of the vessel. Now let cylinder be made to stand in the liquid
  • 6. β€’ Let h = height of liquid in the cylinder, β€’ A = area of the cylinder base, β€’ W = specific weight of the liquid, β€’ P = intensity of pressure Now Total pressure on the base of the cylinder = weight if liquid in the cylinder i.e., p A = w x A x h 𝑝 = π‘€π΄β„Ž 𝐴 = π‘€β„Ž 𝑝 = π‘€β„Ž (β„Ž = 𝑝 𝑀 ) The intensity of pressure in a liquid due to its depth will vary directly with depth
  • 7. Measurement of Pressure β€’ 1. Manometers These are defined as the devices used for measuring the pressure at a point in a fluid by balancing the column of fluid by the same or another column of liquid. These are classified as a) Simple manometers i. Piezometer ii. U-tube manometer iii. Single column manometer b) Differential manometers
  • 8. β€’ Mechanical gauges: β€’ These are the devices in which the pressure is measured by balancing the fluid column by spring or dead weight. β€’ These gauges are used for measuring high pressure and high precision is not required. β€’ Bourdon tube pressure gauge β€’ Bellow pressure gauge β€’ Diaphragm pressure gauge β€’ Dead-weight pressure gauge
  • 9. Simple manometers β€’ 1. Piezometer: A piezometer is the simplest form of manometer which can be used for measuring moderate pressures of liquids. β€’ It consists of a glass tube inserted in the wall of a vessel or of a pipe, containing liquid whose pressure is to be measured. The tube extends vertically upward to such a height that liquid can freely rise in it without overflowing.
  • 10. β€’ U- tube manometer: β€’ A U-tube manometer consists of a glass tube bent in U-shape, one end of which is connected to a point at which pressure is to be measured and other end remains open to the atmosphere.