2. a) Sketch the graph. y=2x
(0,16)
B1
(5√5, 6)
F2 A A1 F1 (5√5, 6)
a = 5 2
C (5,6)
(5,6) (0,6)
b = 10
c = 5√5
B2
(0,4)
3. a is the semitransverse axis. It is the
distance from the centre to one of the
vertices.
b is the semiconjugate axis. It is
a = 5
the distance from the centre to
b = 10
one of the points B1 or B2.
c = 5√5
c is the distance between the centre
and one of the foci. It is also equal to
the distance between the vertex to one
of the points B1 or B2.
5. b) Find the equation.
We know from the graph we made
centre (h,k)
that the we had a horizontal hyperbola.
C (0,6) Therefore the standard equation would
be:
a = 5
2 2
(xh) _ (yk) = 1
b = 10
a2 b2
c = 5√5