Here are the steps to solve the problems:6) Rectangular prism with dimensions 10 ft x 5 ft x 3 ft - Front/Back: A = l x w = 10 x 5 = 50 ft^2 - Left/Right sides: A = l x h = 10 x 3 = 30 ft^2 - Top/Bottom: A = w x h = 5 x 3 = 15 ft^2 - Total SA = 2(Front + Sides + Top) = 2(50 + 2*30 + 15) = 2(50 + 60 + 15) = 2(125) = 250 ft^27) Triangular prism with dimensions shown - Triangle base: A
Here are the steps to solve these problems:
6) Rectangular prism with dimensions 10 ft x 5 ft x 3 ft
- Front/Back: A = l x w = 10 x 3 = 30 ft^2
- Left/Right sides: A = l x h = 5 x 3 = 15 ft^2
- Top/Bottom: A = w x h = 10 x 5 = 50 ft^2
- Total SA = 2(Front/Back) + 2(Left/Right) + Top/Bottom
= 2(30) + 2(15) + 50 = 120 + 30 + 50 = 200 ft^2
7) Triangular prism with dimensions 6 in x 4 in x
Similar a Here are the steps to solve the problems:6) Rectangular prism with dimensions 10 ft x 5 ft x 3 ft - Front/Back: A = l x w = 10 x 5 = 50 ft^2 - Left/Right sides: A = l x h = 10 x 3 = 30 ft^2 - Top/Bottom: A = w x h = 5 x 3 = 15 ft^2 - Total SA = 2(Front + Sides + Top) = 2(50 + 2*30 + 15) = 2(50 + 60 + 15) = 2(125) = 250 ft^27) Triangular prism with dimensions shown - Triangle base: A
Similar a Here are the steps to solve the problems:6) Rectangular prism with dimensions 10 ft x 5 ft x 3 ft - Front/Back: A = l x w = 10 x 5 = 50 ft^2 - Left/Right sides: A = l x h = 10 x 3 = 30 ft^2 - Top/Bottom: A = w x h = 5 x 3 = 15 ft^2 - Total SA = 2(Front + Sides + Top) = 2(50 + 2*30 + 15) = 2(50 + 60 + 15) = 2(125) = 250 ft^27) Triangular prism with dimensions shown - Triangle base: A (20)
Gripping Adult Web Series You Can't Afford to Miss
Here are the steps to solve the problems:6) Rectangular prism with dimensions 10 ft x 5 ft x 3 ft - Front/Back: A = l x w = 10 x 5 = 50 ft^2 - Left/Right sides: A = l x h = 10 x 3 = 30 ft^2 - Top/Bottom: A = w x h = 5 x 3 = 15 ft^2 - Total SA = 2(Front + Sides + Top) = 2(50 + 2*30 + 15) = 2(50 + 60 + 15) = 2(125) = 250 ft^27) Triangular prism with dimensions shown - Triangle base: A
1. In 1861 the Union’s population was 23,000,000
people and the Confederacy’s was 9,000,000.
In the U.S. Civil War, the cost to the Union was
about $3.2 billion, and the cost to the
Confederacy was about $2 billion
How much money did the Union spend for each
person in the Union?
How much money did the Confederacy spend for
each person in the Confederacy ?
2. In 1861 the Union’s population was 23,000,000
people and the Confederacy’s was 9,000,000.
In the U.S. Civil War, the cost to the Union was
about $3.2 billion, and the cost to the
Confederacy was about $2 billion
How much money did the Union spend for each
person in the Union?
$139.13
How much money did the Confederacy spend for
each person in the Confederacy ?
$222.22
3. Lesson 10.4, For use with pages 542-547
Identify the solid.
1.
2. Count the number of faces, edges, and vertices
for the figure.
4. Lesson 10.4, For use with pages 542-547
Identify the solid.
1.
ANSWER triangular prism
2. Count the number of faces, edges, and vertices
for the figure.
ANSWER 5; 9; 6
6. Vocabulary
Surface Area: (SA) of a polyhedron is the sum of
the areas of all the faces.
Prism: a polyhedron that has two congruent faces
that are parallel polygons. Each parallel,
congruent face is called a base.
Prisms are named for the shape of their bases.
7. If you were to find the surface area of
rectangular prism, what measurements
would you need to know?
8. You would need the length, width, and the
height of the prism.
Think front and back
5 in
Top and bottom
L/R Sides 2 in
9 in
9. Find the SA of the rectangular prism
Front: A = b x h
30 x 12 = 360 12 ft
Side: A = b x h
30 x 10 = 300
Top: A = b x h 30 ft
12 x 10 = 120
360+360+300+ 10 ft
300+120+120= 1560 ft sq.
10. Find the SA of this triangular
prism
Triangle A= b x h ÷ 2
(5 x 7) ÷ 2= 17.5
Rectangle A = b x h
15 x 5 = 75
5 5
17.5 + 17.5 + 75 15 ft
7
+75 + 75= 7
260 ft sq.
5
11. Base: A = b x h ÷ 2
6 ft 15 ft
(9x12) ÷ 2= 54
Bottom: A = b x h
9 ft 12 x 6 = 72
Top: A=bxh
12 ft
Find SA
15 x 6 = 90
Think : Left back: A = b x h
2 Bases (f/b)
Bottom 6 x 9 = 54
Slanted Top
54 + 54 + 90 + 54 +72 = 324 ft s q.
Left Back