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Cuatro amigos presentation
1.
Cuatro amigos! By Janice,
Pei Yu and Kinsey Friday, 24 May, 13
2.
Problem Friday, 24 May,
13
3.
SOLVE J=5,10,15 A=2M==>M<10(J=5) C=A/3 ==>A=12,18 M>J==>J=5:M>5 J<C ==>5<C Mcannotbeover10.Aisanevennumberabove10.Factssofar: J=5 A=12,18 C=4,6 ------------------------- C>5 C=6 6x2=12 A=18 18÷2=9 M=9 Friday,
24 May, 13
4.
Answers Juan’snumberis5 Carlos’numberis6 Maria’snumberis9 Anna’snumberis18 Friday, 24 May,
13
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