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Cuatro amigos!
By Janice, Pei Yu and Kinsey
Friday, 24 May, 13
Problem
Friday, 24 May, 13
SOLVE
J=5,10,15
A=2M==>M<10(J=5)
C=A/3 ==>A=12,18
M>J==>J=5:M>5
J<C ==>5<C
Mcannotbeover10.Aisanevennumberabove10.Factssofar:
J=5
A=12,18
C=4,6
-------------------------
C>5
C=6
6x2=12
A=18
18÷2=9
M=9
Friday, 24 May, 13
Answers
Juan’snumberis5
Carlos’numberis6
Maria’snumberis9
Anna’snumberis18
Friday, 24 May, 13

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