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Urdhva-Tirayk Sutra
                                  Multiplication
   Urdhva-Tirayak Sutra

   Principle : (ax2+bx+c)*(dx2+ex+f)=
                x4*ad+x3(ac+bd)+x2(af+bc+cd)+x(bf+ce)+cf
   Explanation: - Any number can be written as the sum of digits multiplied by a power of 10
                  e.g. 8 = 100*8
                       18= 101*1+100*8
                       218 = 102*2+101*1+100*8 etc.

                  - Replace x by 10 in the above equation, and a, b,c etc by digits.
                  - The left hand side of the equation represents the multiplication of two
                    numbers (First one is the multiplicand and the second one, multiplier)
                  - The right side of the equation is the result (Product)
                  - The coefficient of x4 is the first digit of the product, the coefficient x3 is the
                    second digit of the product and so on.

                                                                                                  (Contd.)
                                                                                                       1
Urdhva-Tirayk Sutra



Thumb Rule: A close observation of the equation of the previous slide would
 reveal the following thumb rules for multiplication of two numbers with three
 digits each;

- The first digit of the product is got by the vertical multiplication of the first digits from
the left side.
- The second digit is got by the cross-wise multiplication of the first two
  digits and by the addition of the two products
- The third digit is obtained by summing the results of multiplication of the first digit of
the multiplicand by the last digit of the multiplier, of the middle one by the middle one
and the last one by the first one.
- The fourth digit is obtained by summing the results of multiplication of the second
digit of the multiplicand by the third digit of the multiplier and the third digit of the
multiplicand by the second digit of the mutiplier
-The last digit of the product is obtained by multiplying the last digit of the
  multiplicand by the first digit of the multiplier.

            This rule can be extended to numbers containing any number of
digits.


                                                                                                  2
Urdhva-Tirayk Sutra

Pictorial Explanation of the
rule:
 142 * 327

    First digit:          Second digit           Third digit
    1     4      2        1   4     2            1    4      2


    3     2      7        3        2   7         3     2        7
    3                         14                       21

Fourth digit                   Fifth digit
1    4      2                  1      4      2
                                                     = 3 | 14 | 21 | 32 | 14

3        2     7               3       2     7
        32                             14

               = 3+1 | 4+2 | 1+3 | 2+1 | 4
               = 46434
                                                                               3
Urdhva-Tirayk Sutra


Examples:
                                 Note:In Example 3, the sum of the
1. 12*13 = 1*1|1*3+2*1|2*3       products gives 30 and the digit in
         = 1 | 5 | 6 = 156       ten’s place i.e. 3, is Carried forward
                                 to the left of the ‘ | ’ and added to 9.
                                 Similarly, 7*3 gives 21 and the 2,
2. 23*21 = 2*2 | 2*1+3*2 | 3*1   being a carry, is added to the 0 on
         = 4 | 8 | 3 = 483       the left of the ‘ | “.In these
3 37*33 = 3*3 | 3*3+7*3 | 7*3    exercises,
                                 the ‘Carry’s’ are shown as
         = 9 |30 | 21            subscripts and ‘negative digits’ with
         = 9+3 | 0 +2| 1         a bar on the top of the digit, for
         = 1221                  better understanding.
4. 111*111 = 1*1 | 1*1+1*1 |     In Example 4, the digits of the
             1*1+1*1+1*1 |       multiplicand and multiplier are
              1*1+1*1 | 1*1      having the same color code, but the
                                 Digits in the multiplier are in Bold’.
         =1 | 2 | 3 | 2 | 1      This would enable a better
         =12321                  understanding of the pattern of
                                 cross multiplications of digits from
                                 multiplicand and multiplier in a
                                 systematic manner.


                                                                     4
Urdhva-Tirayk Sutra



   5. 108*108
       108
       108
    1*1 | 1*0+0*1 | 1*8+0*0+8*1 | 0*8+8*0 | 8*8
   = 1 | 0 | 16 | 0 | 64
   = 1 | 0+1 | 6 | 0+6 | 4
   = 1| 1 | 6 | 6 | 4
   = 11664

   Note the subscripts, which are carried and
   Added to the previous digits.

   6. 321*52
     = 321*052
       321
       052
    3*0 | 3*5+2*0 | 3*2+2*5+1*0 | 2*2+1*5 | 1*2
   = 0 | 15 | 16 | 9 | 2
   = 0+1 | 5+1 | 6 | 9 | 2
   = 16692
                                                  5
Urdhva-Tirayk Sutra


Owing to their relevance to this context, a few algebraic examples of the
Urdhva-Tiryak type are given below:

1. (a+b)*(a+9b)
   a+b
   a+9b
 a2+10ab+b2

2. (a+3b)*(5a+7b)
   a+3b
   5a+7b
 5a2+22ab+21b2

3. (3x2+5x+7)*(4x2+7x+6)
   3x2+5x+7
   4x2+7x+6
 12x4+41x3+81x2+79x+42



                                                                            6
Urdhva-Tirayk Sutra

The Use of the Vinculum
The multiplications by digits higher than 5 may some times be facilitated by the
use of the vinculum.
Note: A negative digit in a number (not negative number) is represented by a bar on the top of the
digit. This is called vinivulum
Ex: 1. In the number 576, the digits 7 and 6 can be written with viniculum as follows;
             500+76
            =500+(100-24)
            =600-20-4
            =624
Ex 2. The number 73 can be written as follows;
           73 = 70+3
              = (100-30)+3
              = 1+(-3)+3
              =1 3 3

But the vinculum process is one which one must very carefully practice,
before one resorts to it and relies on it.
                                                                                                     7
Urdhva-Tirayk Sutra


Miscellaneous Examples:

1. 73*37
   By urdhva-tirayak method:        By vinculum method
    73                              133
    37                              043
  2181                              04519
   52                                12
  2701                              2701
Obviously, this method is
better.


2. 94*81
urdhva-tirayak :           Vinculum:               Nikhilam:
    94                     114                      94 -6
    81                     121                      81 – 19
   72414                  13794                  (175-100) |
114
   = 7614                  = 7614                  = 7614
                                                               8
Urdhva-Tirayk Sutra


Practical Applications in Compound Multiplication:

A. Area of a rectangle
   Examples:
   1. 5’11” * 7’8”
       Suppose 12” = x, then the above multiplication can be written as
      ( 5x+11) * (7x+8)             5x+11
     = 35x2+117x+88                 7x+8
                 = 35x2+(108x+9x)+88
                 = 35x2+(9x*x+9x)+(7x+4)
                 = 35x2+9x2+16x+4
                 = 44x2+ (12+4)x+4
                 = 44x2 + (x+4)x + 4
                 = 45x2 + 4*12 + 4
                 = 45x2 + 52
                 = 45sq.ft+ 52 sq.in

     2. Similarly, work out 3’7” * 5’10”
        The answer should be 44 sq.ft + 124 sq.in

                                                                          9
Urdhva-Tirayk Sutra

Volume of Parallelpipeds
Examples:
1. 3’7” * 5’10” * 7’2”
   Suppose 12” = x, then the above multiplication can be written as
   (3x+7) * (5x+10) * (7x+2)
   = (15x2+65x+70) * (7x+2)
   =((15x2+(5x+5)*x+ (5x+10)) * (7x+2)
   = (20x2+10x+10) * (7x+2)
   =140x3+110x2+90x+20
   = 140x3+(9x+2)x2+(7x+6)x+(x+8)
   = 149x3+9x2+7x+8
   = 149 cuft +9*144 cuin+7*12 cuin+8 cuin
   = 149cuft and 1388 cuin
Questions relating to paving, carpeting, ornamenting etc can be
Readily answered by this method.
Example: At the rate of 7 annas, 9 pices per foot, how much 8 yards,
          1 foot, 3 inches costs?
( Note: 1 Re=16 Annas and 1 Anna = 12pices
8 yards and 1 foot = 25 ft)
Answer;    25 ft – 3 in
            7 annas – 9 pies
          = 175 annas| 246 pies | 9*3/12 pies
          = 175 annas + ( 20 annas + 6 pies) + (2 1¼ pies)
or 195 annas, 8 1/4 pies or Rs 12/3/8¼



                                                End of chapter 1B – Urdhva-tiravk sutra   10

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Lesson 1.2 multiplication

  • 1. Urdhva-Tirayk Sutra Multiplication Urdhva-Tirayak Sutra Principle : (ax2+bx+c)*(dx2+ex+f)= x4*ad+x3(ac+bd)+x2(af+bc+cd)+x(bf+ce)+cf Explanation: - Any number can be written as the sum of digits multiplied by a power of 10 e.g. 8 = 100*8 18= 101*1+100*8 218 = 102*2+101*1+100*8 etc. - Replace x by 10 in the above equation, and a, b,c etc by digits. - The left hand side of the equation represents the multiplication of two numbers (First one is the multiplicand and the second one, multiplier) - The right side of the equation is the result (Product) - The coefficient of x4 is the first digit of the product, the coefficient x3 is the second digit of the product and so on. (Contd.) 1
  • 2. Urdhva-Tirayk Sutra Thumb Rule: A close observation of the equation of the previous slide would reveal the following thumb rules for multiplication of two numbers with three digits each; - The first digit of the product is got by the vertical multiplication of the first digits from the left side. - The second digit is got by the cross-wise multiplication of the first two digits and by the addition of the two products - The third digit is obtained by summing the results of multiplication of the first digit of the multiplicand by the last digit of the multiplier, of the middle one by the middle one and the last one by the first one. - The fourth digit is obtained by summing the results of multiplication of the second digit of the multiplicand by the third digit of the multiplier and the third digit of the multiplicand by the second digit of the mutiplier -The last digit of the product is obtained by multiplying the last digit of the multiplicand by the first digit of the multiplier. This rule can be extended to numbers containing any number of digits. 2
  • 3. Urdhva-Tirayk Sutra Pictorial Explanation of the rule: 142 * 327 First digit: Second digit Third digit 1 4 2 1 4 2 1 4 2 3 2 7 3 2 7 3 2 7 3 14 21 Fourth digit Fifth digit 1 4 2 1 4 2 = 3 | 14 | 21 | 32 | 14 3 2 7 3 2 7 32 14 = 3+1 | 4+2 | 1+3 | 2+1 | 4 = 46434 3
  • 4. Urdhva-Tirayk Sutra Examples: Note:In Example 3, the sum of the 1. 12*13 = 1*1|1*3+2*1|2*3 products gives 30 and the digit in = 1 | 5 | 6 = 156 ten’s place i.e. 3, is Carried forward to the left of the ‘ | ’ and added to 9. Similarly, 7*3 gives 21 and the 2, 2. 23*21 = 2*2 | 2*1+3*2 | 3*1 being a carry, is added to the 0 on = 4 | 8 | 3 = 483 the left of the ‘ | “.In these 3 37*33 = 3*3 | 3*3+7*3 | 7*3 exercises, the ‘Carry’s’ are shown as = 9 |30 | 21 subscripts and ‘negative digits’ with = 9+3 | 0 +2| 1 a bar on the top of the digit, for = 1221 better understanding. 4. 111*111 = 1*1 | 1*1+1*1 | In Example 4, the digits of the 1*1+1*1+1*1 | multiplicand and multiplier are 1*1+1*1 | 1*1 having the same color code, but the Digits in the multiplier are in Bold’. =1 | 2 | 3 | 2 | 1 This would enable a better =12321 understanding of the pattern of cross multiplications of digits from multiplicand and multiplier in a systematic manner. 4
  • 5. Urdhva-Tirayk Sutra 5. 108*108 108 108 1*1 | 1*0+0*1 | 1*8+0*0+8*1 | 0*8+8*0 | 8*8 = 1 | 0 | 16 | 0 | 64 = 1 | 0+1 | 6 | 0+6 | 4 = 1| 1 | 6 | 6 | 4 = 11664 Note the subscripts, which are carried and Added to the previous digits. 6. 321*52 = 321*052 321 052 3*0 | 3*5+2*0 | 3*2+2*5+1*0 | 2*2+1*5 | 1*2 = 0 | 15 | 16 | 9 | 2 = 0+1 | 5+1 | 6 | 9 | 2 = 16692 5
  • 6. Urdhva-Tirayk Sutra Owing to their relevance to this context, a few algebraic examples of the Urdhva-Tiryak type are given below: 1. (a+b)*(a+9b) a+b a+9b a2+10ab+b2 2. (a+3b)*(5a+7b) a+3b 5a+7b 5a2+22ab+21b2 3. (3x2+5x+7)*(4x2+7x+6) 3x2+5x+7 4x2+7x+6 12x4+41x3+81x2+79x+42 6
  • 7. Urdhva-Tirayk Sutra The Use of the Vinculum The multiplications by digits higher than 5 may some times be facilitated by the use of the vinculum. Note: A negative digit in a number (not negative number) is represented by a bar on the top of the digit. This is called vinivulum Ex: 1. In the number 576, the digits 7 and 6 can be written with viniculum as follows; 500+76 =500+(100-24) =600-20-4 =624 Ex 2. The number 73 can be written as follows; 73 = 70+3 = (100-30)+3 = 1+(-3)+3 =1 3 3 But the vinculum process is one which one must very carefully practice, before one resorts to it and relies on it. 7
  • 8. Urdhva-Tirayk Sutra Miscellaneous Examples: 1. 73*37 By urdhva-tirayak method: By vinculum method 73 133 37 043 2181 04519 52 12 2701 2701 Obviously, this method is better. 2. 94*81 urdhva-tirayak : Vinculum: Nikhilam: 94 114 94 -6 81 121 81 – 19 72414 13794 (175-100) | 114 = 7614 = 7614 = 7614 8
  • 9. Urdhva-Tirayk Sutra Practical Applications in Compound Multiplication: A. Area of a rectangle Examples: 1. 5’11” * 7’8” Suppose 12” = x, then the above multiplication can be written as ( 5x+11) * (7x+8) 5x+11 = 35x2+117x+88 7x+8 = 35x2+(108x+9x)+88 = 35x2+(9x*x+9x)+(7x+4) = 35x2+9x2+16x+4 = 44x2+ (12+4)x+4 = 44x2 + (x+4)x + 4 = 45x2 + 4*12 + 4 = 45x2 + 52 = 45sq.ft+ 52 sq.in 2. Similarly, work out 3’7” * 5’10” The answer should be 44 sq.ft + 124 sq.in 9
  • 10. Urdhva-Tirayk Sutra Volume of Parallelpipeds Examples: 1. 3’7” * 5’10” * 7’2” Suppose 12” = x, then the above multiplication can be written as (3x+7) * (5x+10) * (7x+2) = (15x2+65x+70) * (7x+2) =((15x2+(5x+5)*x+ (5x+10)) * (7x+2) = (20x2+10x+10) * (7x+2) =140x3+110x2+90x+20 = 140x3+(9x+2)x2+(7x+6)x+(x+8) = 149x3+9x2+7x+8 = 149 cuft +9*144 cuin+7*12 cuin+8 cuin = 149cuft and 1388 cuin Questions relating to paving, carpeting, ornamenting etc can be Readily answered by this method. Example: At the rate of 7 annas, 9 pices per foot, how much 8 yards, 1 foot, 3 inches costs? ( Note: 1 Re=16 Annas and 1 Anna = 12pices 8 yards and 1 foot = 25 ft) Answer; 25 ft – 3 in 7 annas – 9 pies = 175 annas| 246 pies | 9*3/12 pies = 175 annas + ( 20 annas + 6 pies) + (2 1¼ pies) or 195 annas, 8 1/4 pies or Rs 12/3/8¼ End of chapter 1B – Urdhva-tiravk sutra 10