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Presentation on 

Moment Distribution Moment

Submitted by

:-Abhishek M Chavan, Roll no-04

B.Tech Second Year, 

Civil Dept

Under the Guidance of

:-Prof Tushar Somvanshi

Page of1 16
Index
1. Introduction
2. Theorem
3. Basic Definitions Of Terms In The
Moment Distribution Method
4. Basic Stages in Moment Distribution
Moment
5. Summary
Page of2 16
INTRODUCTION
The end moments of a redundant framed structure are
determined by using the classical methods, viz. Clapeyron’s
theorem of three moments, strain energy method and slope
deflection method. These methods of analysis require a
solution of set of simultaneous equations. Solving equations
is a laborious task if the unknown quantities are more than
three in number. In such situations, the moment distribution
method developed by Professor Hardy Cross is useful. This
method is essentially balancing the moments at a joint or
junction. It can be described as a method which gives
solution by successive approximations of slope deflection
equations.
In the moment distribution method, initially the structure is
rigidly fixed at every joint or support. The fixed end
moments are calculated for any loading under
consideration. Subsequently, one joint at a time is then
released. When the moment is released at the joint, the joint
moment becomes unbalanced. The equilibrium at this joint
is maintained by distributing the unbalanced moment. This
joint is temporarily fixed again until all other joints have
been released and restrained in the new position. This
procedure of fixing the moment and releasing them is
repeated several times until the desired accuracy is
obtained. The experience of designers points that about five
cycles of moment distribution lead to satisfactory
converging results.
Page of3 16
Basically, in the slope deflection method, the end moments
are computed using the slopes and deflection at the ends.
Contrarily in the moment distribution method, as a first step
— the slopes at the ends are made zero. This is done by
fixing the joints. Then with successive release and
balancing the joint moments, the state of equilibrium is
obtained. The release-balance cycles can be carried out
using the following theorems.
Page of4 16
Theorem 2
Indeterminate Structural Analysis
In conclusion, when a positive moment M is applied to
the hinged end of a beam a positive moment of Ê1ˆ M
will be transferred to the fixed end. Á̃
Consider a two span continuous beam ACB as shown in
Fig. 2.2(a). A and B are fixed supports with a prop at C. A
moment is applied at C and it is required to know how
much moment is distributed between spans AC and CB.
Let this moment M be decomposed and distributed as
M1 to CA and M2 to CB as shown in Fig. 2.2(b).
i.e.
M1 +M2 =M
Page of5 16
As the ends A and B are fixed; the slope between A
and B is zero. That is, the area of the bending moment
diagram between A and B is zero.
Page of6 16
Page of7 16
Page of8 16
BASIC DEFINITIONS OF TERMS IN THE
MOMENT DISTRIBUTION METHOD
Stiffness
Rotational stiffness can be defined as the moment required to rotate
through a unit angle (radian) without translation of either end.
(b) Stiffness Factor
• (i)  It is the moment that must be applied at one end of a constant
section member (which is unyielding supports at both ends) to
produce a unit rotation of that end when the other end is fixed, i.e. k
= 4EI/l.
• (ii)  It is the moment required to rotate the near end of a prismatic
member through a unit angle without translation, the far end being
hinged is k = 3EI/l.
(c) Carry Over Factor
It is the ratio of induced moment to the applied moment (Theorem 1). The
carry over factor is always (1/2) for members of constant moment of
inertia (prismatic section). If the end is hinged/pin connected, the carry
over factor is zero. It should be mentioned here that carry over factors
values differ for non-prismatic members. For non-prismatic beams (beams
with variable moment of inertia); the carry over factor is not half and is
different for both ends.
(d) Distribution Factors
Consider a frame with members OA, OB, OC and OD rigidly connected at
O as shown in Fig. 2.6. Let M be the applied moment at joint O in the
clockwise direction. Let the joint rotate through an angle . The members
OA,OB,OC and OD also rotate by the same angle θ.
Page of9 16
Page of10 16
BASIC STAGES IN THE MOMENT
DISTRIBUTION METHOD
The moment distribution method can be illustrated with the following
example.
Page of11 16
Page of12 16
Page of13 16
Page of14 16
It is desired to draw the bending moment diagram by computing the
bending moments at salient points of the given beam as shown below.
Page of15 16
Summary
The moment distribution method is a structural
analysis method for statically indeterminate beams
and frames developed by Hardy Cross. It was
published in 1930 in an ASCE journal.[1] The method
only accounts for flexural effects and ignores axial and
shear effects. From the 1930s until computers began
to be widely used in the design and analysis of
structures, the moment distribution method was the
most widely practiced method.
Page of16 16

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Presentation Moment Distribution Method

  • 1. Presentation on Moment Distribution Moment Submitted by :-Abhishek M Chavan, Roll no-04 B.Tech Second Year, Civil Dept Under the Guidance of :-Prof Tushar Somvanshi
 Page of1 16
  • 2. Index 1. Introduction 2. Theorem 3. Basic Definitions Of Terms In The Moment Distribution Method 4. Basic Stages in Moment Distribution Moment 5. Summary Page of2 16
  • 3. INTRODUCTION The end moments of a redundant framed structure are determined by using the classical methods, viz. Clapeyron’s theorem of three moments, strain energy method and slope deflection method. These methods of analysis require a solution of set of simultaneous equations. Solving equations is a laborious task if the unknown quantities are more than three in number. In such situations, the moment distribution method developed by Professor Hardy Cross is useful. This method is essentially balancing the moments at a joint or junction. It can be described as a method which gives solution by successive approximations of slope deflection equations. In the moment distribution method, initially the structure is rigidly fixed at every joint or support. The fixed end moments are calculated for any loading under consideration. Subsequently, one joint at a time is then released. When the moment is released at the joint, the joint moment becomes unbalanced. The equilibrium at this joint is maintained by distributing the unbalanced moment. This joint is temporarily fixed again until all other joints have been released and restrained in the new position. This procedure of fixing the moment and releasing them is repeated several times until the desired accuracy is obtained. The experience of designers points that about five cycles of moment distribution lead to satisfactory converging results. Page of3 16
  • 4. Basically, in the slope deflection method, the end moments are computed using the slopes and deflection at the ends. Contrarily in the moment distribution method, as a first step — the slopes at the ends are made zero. This is done by fixing the joints. Then with successive release and balancing the joint moments, the state of equilibrium is obtained. The release-balance cycles can be carried out using the following theorems. Page of4 16
  • 5. Theorem 2 Indeterminate Structural Analysis In conclusion, when a positive moment M is applied to the hinged end of a beam a positive moment of Ê1ˆ M will be transferred to the fixed end. Á̃ Consider a two span continuous beam ACB as shown in Fig. 2.2(a). A and B are fixed supports with a prop at C. A moment is applied at C and it is required to know how much moment is distributed between spans AC and CB. Let this moment M be decomposed and distributed as M1 to CA and M2 to CB as shown in Fig. 2.2(b). i.e. M1 +M2 =M Page of5 16
  • 6. As the ends A and B are fixed; the slope between A and B is zero. That is, the area of the bending moment diagram between A and B is zero. Page of6 16
  • 9. BASIC DEFINITIONS OF TERMS IN THE MOMENT DISTRIBUTION METHOD Stiffness Rotational stiffness can be defined as the moment required to rotate through a unit angle (radian) without translation of either end. (b) Stiffness Factor • (i)  It is the moment that must be applied at one end of a constant section member (which is unyielding supports at both ends) to produce a unit rotation of that end when the other end is fixed, i.e. k = 4EI/l. • (ii)  It is the moment required to rotate the near end of a prismatic member through a unit angle without translation, the far end being hinged is k = 3EI/l. (c) Carry Over Factor It is the ratio of induced moment to the applied moment (Theorem 1). The carry over factor is always (1/2) for members of constant moment of inertia (prismatic section). If the end is hinged/pin connected, the carry over factor is zero. It should be mentioned here that carry over factors values differ for non-prismatic members. For non-prismatic beams (beams with variable moment of inertia); the carry over factor is not half and is different for both ends. (d) Distribution Factors Consider a frame with members OA, OB, OC and OD rigidly connected at O as shown in Fig. 2.6. Let M be the applied moment at joint O in the clockwise direction. Let the joint rotate through an angle . The members OA,OB,OC and OD also rotate by the same angle θ. Page of9 16
  • 11. BASIC STAGES IN THE MOMENT DISTRIBUTION METHOD The moment distribution method can be illustrated with the following example. Page of11 16
  • 15. It is desired to draw the bending moment diagram by computing the bending moments at salient points of the given beam as shown below. Page of15 16
  • 16. Summary The moment distribution method is a structural analysis method for statically indeterminate beams and frames developed by Hardy Cross. It was published in 1930 in an ASCE journal.[1] The method only accounts for flexural effects and ignores axial and shear effects. From the 1930s until computers began to be widely used in the design and analysis of structures, the moment distribution method was the most widely practiced method. Page of16 16