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International Journal of Smart Computing and Information Technology
2020, Vol. 1, No. 1, pp. 4–6
Copyright © 2020 BOHR Publishers
www.bohrpub.com
For Investment Geometric Problems
Dragan Obradovic1
and Lakshmi Narayan Mishra2,∗
1
Elementary school “Jovan Cvijic”, Kostolac-Pozarevac, Serbia
2
Department of Mathematics, School of Advanced Sciences, Vellore Institute of Technology (VIT) University,
Vellore, Tamil Nadu, India
*Corresponding author: lakshminarayanmishra04@gmail.com
Abstract. Solving geometric problems of special importance is the transformation of a plane called inversion. When solving
geometric problems, the transformation of the plane called inversion is of special importance. An inversion is a mapping of a
plane that a set of directions and a circle maps to the same set, and in doing so it can map a line either to a line or to a circle, and
it can also map a circle to either a line or a circle.
Keywords: Inversion, Euler’s circle, Feuerbach’s theorem, Apollonius problem.
Introduction
Often, when solving geometric tasks, we use one of the transfor-
mations of the plane. In this article, we will get acquainted with
inversion, symmetry with respect to the circle, a mapping which
in many respects is analogous to symmetry with respect to the
direction. Examples of inversion are not often found in nature, but
as a relatively young method, it presents great relief in many geo-
metric problems and even in the problems of mechanical nature.
In this article, the conclusions on geometric inversion are pre-
sented, to which all the mentioned mathematicians agreed upon,
and at the end, discussions about its application through interest-
ing tasks and its use in the real world are provided.
Properties of Inversion
In this section, we will study the significant properties of inver-
sions. We will also consider cases, such as when the inversion
maps the direction in the direction, when the direction is in the
circle, when the circle is mapped in the direction, and when the
circle is mapped to the circle. We have listed some specific inver-
sion maps as follows.
Theorem 1.
Let p ⊂ M be the direction through the center O of inversion IO,
then IO (p{O}) = p{O}.
Proof.
The proof is a direct consequence of the fact that O, T, and T0
must be collinear points and that the IO is a bijection.
Theorem 2.
Let A, A0
and B, B0
pairs belong to the inverse points of IO with
the circle of the invertebrate k(O, R), then it is worth it.
∠OAB = ∠OB0
A0
e., ∠OBA = ∠OA0
B0
Proof.
Let A and A0
be associated points of inverse IO, then |OA|·|OA0
| =
R2
(Figure 1). Analogously, |OB| · |OB0
| = R2
; however,
|OA| : |OB| = |OB0
| : |OA0
| ⇒ |OA| : |OB0
| = |OB| : |OA0
|.
Figure 1. Pairs of associated inversion points.
For Investment Geometric Problems 5
Since ∠AOB = ∠B0
OA0
is followed by ∆OAB ∼ ∆OB0
A0
, from
which we get ∠OAB = ∠OB0
A0
and ∠OBA = ∠OA0
B0
.
The immediate consequence of the theorem is the following
assertion.
Corrollary.
The inversion is determined by the inversion center and the pair
of associates.
Theorem 3.
The direction p which does not pass by the center O of inversion
IO is mapped into a circle which passes through the center O of
invasion.
Proof.
Let p ⊂ (M{O}) be some direction (Figure 2). Make sure that
you’re okay with the spu wall from O to p, and N0
= IO(N). Let
T ⊂ p be any of the directions p, and T0
= IO(T).
Figure 2. The image of the direction that does not pass by the
center of inversion is a circle.
Theorem 2, ∠ONT = ∠OT0
N0
= 90◦
. From this, according
to the turn of Tales’ teaching, it follows that T0
is located on the
circle p0
with ON0
the diameter. So, each of these directions, p,
is mapped in that circle, p0
. As soon as IO is a bounce, the claim
is followed immediately.
Remark.
If the direction fires the inversion in the points M and N, then
the circle p0
is determined by the nonlinear points O, M, and N
(Figure 3); and if the direction p enters the circle of inversion in
point D, then p0
is a circle with a diameter OD (Figure 4).
In order to demonstrate the following inversion properties, it
is necessary to introduce the notion of potency in this respect in
view of a crochet. First, we prove the following theorem.
Figure 3. A picture of the direction that does not pass through
the center of inversion and shows a vertex of inversion.
Figure 4. A picture of the direction that does not pass through
the center of inversion and touches the circle of inversion.
Theorem 4.
Let k(S, r) be a circle, T be any plane, and q be any direction that
passes through T, and A and B be some points on the circle, then
the product p = |TA| · |T B| does not depend on the choice of the
direction q through T, and we call it the potential p point T with
respect to the circle k.
Proof 1.
Let T be a point on the circle k(S, r) (Figure 5), then T = A or
T = B. If T = A, then |TA| = 0; and if T = B, then |T B| = 0.
From this, it follows that |TA| · |T B| = 0.
Proof 2.
Let T be a point within the circle k(S, r). Let q1 and q2 be the
directions passing through the point T, that is, q1 ∩ k = {A, B}
and q2 ∩ k = {C, D} (Figure 6). Since the circumferential corners
over the same arc are the same, they follow:
∠CAB = ∠CDB;
∠DCA = ∠DBA.
6 Dragan Obradovic and Lakshmi Narayan Mishra
Figure 5. Directions passing through point T.
Figure 6. The point T lies outside the circle k (S, r).
It follows that the triangles TAC and TDB are similar, and
hence, it is valid
|TA|
|TD|
=
|TC|
|T B|
,
therefore, |TA| · |T B| = |TC| · |TD|.
Conclusion
After all, it remains to us only to identify a couple of obvious
things. First of all, geometric inversion in relation to the circle,
with its many and very affected properties, has a very large
application in non-standard geometric problems. When using
invariants during the mapping itself, many difficult detectable
dependencies between circles become apparent as addictions
between the real ones. In addition, we also presented the appli-
cation of inversion in real life, which was found in an attempt to
turn the circular motion into a straight line motion.
Bibliography
[1] M. Mitrovic, S. Ognjanovic, M. Veljkovic, Lj. Petkovic, N. Lazarevic, Geom-
etry for the First Grade of the Mathematical Gymnasium, Krug, Belgrade,
1988.
[2] D. Lopandic, Geometry for the Third Grade of Targeted Education, Scientific
book, Belgrade, 1980.
[3] Lj. Petkovic, M. Petkovic, Matematrix from the Life of Major Mathemati-
cians, New Yugoslavia, Vranje, 2000.
[4] H. S. M. Coxeter, Introduction to Geometry, Wiley, New York, 1969.
[5] D. Ðukić, Inversion, Olympiad Training Materials (IMO Compendium
Group), 2007.
CITATION OF THE PAPER
In this paper, after considering the properties of inversion, Feuerbach’s theorem and analytical proof of the theorem are given.
Feuerbach’s theorem, one of the most beautiful theorems on the geometry of a triangle, states that the Euler circle of a triangle touches
a triangle inscribed circle inside and all three triangles assigned a circle outside. The paper discusses the solution of the problem in an
algebraic way and shows how this problem can be solved using inversion.
Therefore, inversion is used for various constructions related to circles so that by applying the inversion some of the circles are
mapped in directions and thus the task is reduced to an analog simpler problem in which some circles are replaced by directions.

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For Investment Geometric Problems

  • 1. International Journal of Smart Computing and Information Technology 2020, Vol. 1, No. 1, pp. 4–6 Copyright © 2020 BOHR Publishers www.bohrpub.com For Investment Geometric Problems Dragan Obradovic1 and Lakshmi Narayan Mishra2,∗ 1 Elementary school “Jovan Cvijic”, Kostolac-Pozarevac, Serbia 2 Department of Mathematics, School of Advanced Sciences, Vellore Institute of Technology (VIT) University, Vellore, Tamil Nadu, India *Corresponding author: lakshminarayanmishra04@gmail.com Abstract. Solving geometric problems of special importance is the transformation of a plane called inversion. When solving geometric problems, the transformation of the plane called inversion is of special importance. An inversion is a mapping of a plane that a set of directions and a circle maps to the same set, and in doing so it can map a line either to a line or to a circle, and it can also map a circle to either a line or a circle. Keywords: Inversion, Euler’s circle, Feuerbach’s theorem, Apollonius problem. Introduction Often, when solving geometric tasks, we use one of the transfor- mations of the plane. In this article, we will get acquainted with inversion, symmetry with respect to the circle, a mapping which in many respects is analogous to symmetry with respect to the direction. Examples of inversion are not often found in nature, but as a relatively young method, it presents great relief in many geo- metric problems and even in the problems of mechanical nature. In this article, the conclusions on geometric inversion are pre- sented, to which all the mentioned mathematicians agreed upon, and at the end, discussions about its application through interest- ing tasks and its use in the real world are provided. Properties of Inversion In this section, we will study the significant properties of inver- sions. We will also consider cases, such as when the inversion maps the direction in the direction, when the direction is in the circle, when the circle is mapped in the direction, and when the circle is mapped to the circle. We have listed some specific inver- sion maps as follows. Theorem 1. Let p ⊂ M be the direction through the center O of inversion IO, then IO (p{O}) = p{O}. Proof. The proof is a direct consequence of the fact that O, T, and T0 must be collinear points and that the IO is a bijection. Theorem 2. Let A, A0 and B, B0 pairs belong to the inverse points of IO with the circle of the invertebrate k(O, R), then it is worth it. ∠OAB = ∠OB0 A0 e., ∠OBA = ∠OA0 B0 Proof. Let A and A0 be associated points of inverse IO, then |OA|·|OA0 | = R2 (Figure 1). Analogously, |OB| · |OB0 | = R2 ; however, |OA| : |OB| = |OB0 | : |OA0 | ⇒ |OA| : |OB0 | = |OB| : |OA0 |. Figure 1. Pairs of associated inversion points.
  • 2. For Investment Geometric Problems 5 Since ∠AOB = ∠B0 OA0 is followed by ∆OAB ∼ ∆OB0 A0 , from which we get ∠OAB = ∠OB0 A0 and ∠OBA = ∠OA0 B0 . The immediate consequence of the theorem is the following assertion. Corrollary. The inversion is determined by the inversion center and the pair of associates. Theorem 3. The direction p which does not pass by the center O of inversion IO is mapped into a circle which passes through the center O of invasion. Proof. Let p ⊂ (M{O}) be some direction (Figure 2). Make sure that you’re okay with the spu wall from O to p, and N0 = IO(N). Let T ⊂ p be any of the directions p, and T0 = IO(T). Figure 2. The image of the direction that does not pass by the center of inversion is a circle. Theorem 2, ∠ONT = ∠OT0 N0 = 90◦ . From this, according to the turn of Tales’ teaching, it follows that T0 is located on the circle p0 with ON0 the diameter. So, each of these directions, p, is mapped in that circle, p0 . As soon as IO is a bounce, the claim is followed immediately. Remark. If the direction fires the inversion in the points M and N, then the circle p0 is determined by the nonlinear points O, M, and N (Figure 3); and if the direction p enters the circle of inversion in point D, then p0 is a circle with a diameter OD (Figure 4). In order to demonstrate the following inversion properties, it is necessary to introduce the notion of potency in this respect in view of a crochet. First, we prove the following theorem. Figure 3. A picture of the direction that does not pass through the center of inversion and shows a vertex of inversion. Figure 4. A picture of the direction that does not pass through the center of inversion and touches the circle of inversion. Theorem 4. Let k(S, r) be a circle, T be any plane, and q be any direction that passes through T, and A and B be some points on the circle, then the product p = |TA| · |T B| does not depend on the choice of the direction q through T, and we call it the potential p point T with respect to the circle k. Proof 1. Let T be a point on the circle k(S, r) (Figure 5), then T = A or T = B. If T = A, then |TA| = 0; and if T = B, then |T B| = 0. From this, it follows that |TA| · |T B| = 0. Proof 2. Let T be a point within the circle k(S, r). Let q1 and q2 be the directions passing through the point T, that is, q1 ∩ k = {A, B} and q2 ∩ k = {C, D} (Figure 6). Since the circumferential corners over the same arc are the same, they follow: ∠CAB = ∠CDB; ∠DCA = ∠DBA.
  • 3. 6 Dragan Obradovic and Lakshmi Narayan Mishra Figure 5. Directions passing through point T. Figure 6. The point T lies outside the circle k (S, r). It follows that the triangles TAC and TDB are similar, and hence, it is valid |TA| |TD| = |TC| |T B| , therefore, |TA| · |T B| = |TC| · |TD|. Conclusion After all, it remains to us only to identify a couple of obvious things. First of all, geometric inversion in relation to the circle, with its many and very affected properties, has a very large application in non-standard geometric problems. When using invariants during the mapping itself, many difficult detectable dependencies between circles become apparent as addictions between the real ones. In addition, we also presented the appli- cation of inversion in real life, which was found in an attempt to turn the circular motion into a straight line motion. Bibliography [1] M. Mitrovic, S. Ognjanovic, M. Veljkovic, Lj. Petkovic, N. Lazarevic, Geom- etry for the First Grade of the Mathematical Gymnasium, Krug, Belgrade, 1988. [2] D. Lopandic, Geometry for the Third Grade of Targeted Education, Scientific book, Belgrade, 1980. [3] Lj. Petkovic, M. Petkovic, Matematrix from the Life of Major Mathemati- cians, New Yugoslavia, Vranje, 2000. [4] H. S. M. Coxeter, Introduction to Geometry, Wiley, New York, 1969. [5] D. Ðukić, Inversion, Olympiad Training Materials (IMO Compendium Group), 2007. CITATION OF THE PAPER In this paper, after considering the properties of inversion, Feuerbach’s theorem and analytical proof of the theorem are given. Feuerbach’s theorem, one of the most beautiful theorems on the geometry of a triangle, states that the Euler circle of a triangle touches a triangle inscribed circle inside and all three triangles assigned a circle outside. The paper discusses the solution of the problem in an algebraic way and shows how this problem can be solved using inversion. Therefore, inversion is used for various constructions related to circles so that by applying the inversion some of the circles are mapped in directions and thus the task is reduced to an analog simpler problem in which some circles are replaced by directions.