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8
0 1 ‫ﺍﻟﺻﻔﺣﺔ‬
‫ﺍﻟﺸﻌﺒﻴﺔ‬ ‫ﺍﻟﺪﻳﻤﻘﺮﺍﻁﻴﺔ‬ ‫ﺍﻟﺠﺰﺍﺋﺮﻳﺔ‬ ‫ﺍﻟﺠﻤﻬﻮﺭﻳﺔ‬
‫ﺍﻟﺘﺮﺑﻴﺔ‬ ‫ﻣﺪﻳﺮﻳﺔ‬
:
: ‫ﻳﻮﻡ‬
: ‫ﺛﺎﻧﻮﻳﺔ‬
‫ﺩ‬
‫ﻭﺭﺓ‬
:
‫ﻣـــﺎﻱ‬
2018
‫ﺷﻌﺒﺔ‬
:
‫ﺭﻳﺎﺿﻲ‬ ‫ﺗﻘﻨﻲ‬
‫ﺑﻜﺎﻟﻮﺭﻳﺎ‬
‫ﺗﺠﺮﻳﺒﻲ‬
‫ﺍﺧﺘﺒﺎﺭ‬
: ‫ﻣﺎﺩﺓ‬
‫ﺍﻟﻔﻴﺰﻳﺎﺋﻴﺔ‬ ‫ﺍﻟﻌﻠﻮﻡ‬
: ‫ﺍﻟﻤﺪﺓ‬
4
‫ﺳــﺎﻋﺔ‬
‫ﻭ‬
30
‫ﺩﻗﻴﻘﺔ‬
‫ﺍﻻﻭﻝ‬ ‫ﺍﻟﻤﻮﺿﻮﻉ‬
‫اﳉﺰ‬
‫ء‬
‫اﻻول‬
‫ﻋﻠﻰ‬ :
13
‫ﻳ‬‫ﺰ‬‫اﻟﻔﻴ‬ ) ‫ﻧﻘﻄﺔ‬
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
(‫ﺎء‬
): ‫اﻻول‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
04
‫ﻧﻘ‬
‫ﺎ‬
‫ط‬
(
‫ﻋﻠﻰ‬ ‫ﺗﺤﺘﻮﻱ‬ ‫ﺩﺍﺭﺍﺕ‬ ‫ﻣﻦ‬ ‫ﺗﺘﻜﻮﻥ‬ ‫ﺍﻟﻜﻬﺮﺑﺎﺋﻴﺔ‬ ‫ﺍﻻﺟﻬﺰﺓ‬ ‫ﺍﻥ‬ ‫ﺣﻴﺚ‬ ‫ﺍﻟﻀﺮﻭﺭﻳﺎﺕ‬ ‫ﺍﻫﻢ‬ ‫ﻣﻦ‬ ‫ﺣﺎﻟﻲ‬ ‫ﻭﻗﺘﻨﺎ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻜﻬﺮﺑﺎء‬ ‫ﺗﻌﺘﺒﺮ‬
‫ﺛﻨﺎﺋﻲ‬
‫ﻗﻄﺐ‬
-
RC
-
RL
-
LC
-
‫ﺍﻟﻘﻄﺐ‬ ‫ﺛﻨﺎﺋﻲ‬ ‫ﺳﻨﺪﺭﺱ‬
RC
‫ﻭ‬
LC
‫ﺍﻧﻈﺮ‬
‫ﺍﻟﺸﻜﻞ‬
-
1
-
: ‫ﺍﻟﺘﺮﻛﻴﺐ‬ ‫ﻓﻲ‬ ‫ﻣﺴﺘﻌﻤﻠﺔ‬ ‫ﻛﻬﺮﺑﺎﺋﻴﺔ‬ ‫ﻋﻨﺎﺻﺮ‬
ƒ
‫ﺗﻮﺗﺮﻩ‬ ‫ﺣﻘﻴﻘﻲ‬ ‫ﻣﻮﻟﺪ‬
E
‫ﺩﺍﺧﻠﻴﺔ‬ ‫ﻣﻘﺎﻭﻣﺘﻪ‬
r=20Ω
.
ƒ
‫ﺳﻌﺘﻬﻤﺎ‬ ‫ﻣﻜﺜﻔﺔ‬
C
.
ƒ
‫ﻣﻘﺎﻭﻣﺘﻪ‬ ‫ﺍﻭﻣﻲ‬ ‫ﻧﺎﻗﻞ‬
R=40Ω
.
ƒ
‫ﺫﺍﺗﻴﺘﻬﺎ‬ ‫ﻭﺷﻴﻌﺔ‬
L
‫ﺩﺍﺧﻠﻴﺔ‬ ‫ﻣﻘﺎﻭﻣﺘﻬﺎ‬
0
r
.
I
.
‫ﻗﻄﺐ‬ ‫ﺛﻨﺎﺋﻲ‬ ‫ﺩﺭﺍﺳﺔ‬
RC
):
02
( ‫ﻧﻘﺎﻁ‬
‫ﻧ‬
‫ﻭﺿﻊ‬ ‫ﻓﻲ‬ ‫ﻗﺎﻁﻌﺔ‬ ‫ﻀﻊ‬
1
:
1
(
‫ﻣﻜﺜﻔﺔ‬ ‫ﺗﻮﺗﺮ‬ ‫ﻟﺘﻄﻮﺭﺍﺕ‬ ‫ﺍﻟﺘﻔﺎﺿﻠﻴﺔ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺍﻥ‬ ‫ﺑﻴﻦ‬
(t)
c
U
: ‫ﻫﻮ‬
ௗ୙ୡሺ୲ሻ
ୢ୲
൅
ଵ
ୖ஼
Ǥ …ሺ–ሻ ൌ
୉
ୖେ
2
(
‫ﺷﻜﻞ‬ ‫ﻣﻦ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺣﻞ‬ ‫ﻳﻌﻄﻰ‬
:
…ሺ–ሻ ൌ ሺͳ െ ‡஑୲ሻ
‫ﺛﻮﺍﺑﺖ‬ ‫ﻋﺒﺎﺭﺓ‬ ‫ﺍﻋﻂ‬
A
‫ﻭ‬
α
‫؟‬ ‫ﻛﻬﺮﺑﺎﺋﻴﺔ‬ ‫ﺩﺍﺭﺓ‬ ‫ﺛﻮﺍﺑﺖ‬ ‫ﺑﺪﻻﻟﺔ‬
3
(
‫ﺗﻄﻮﺭﺍﺕ‬ ‫ﻣﻨﺤﻨﻰ‬ ‫ﻣﻬﺒﻄﻲ‬ ‫ﺍﻫﺘﺰﺍﺯ‬ ‫ﺭﺍﺳﻢ‬ ‫ﻳﻌﻄﻰ‬
‫ﺑﻴﻦ‬ ‫ﺗﻮﺗﺮ‬
‫ﻣﻜﺜﻔﺔ‬ ‫ﻁﺮﻓﻲ‬
‫ﺷﻜﻞ‬
-
2
-
: ‫ﺍﻭﺟﺪ‬ ‫ﺍﻟﺒﻴﺎﻥ‬ ‫ﺑﺎﺳﺘﻐﻼﻝ‬
ƒ
‫ﻗﻴﻤﺔ‬
E
‫؟‬
ƒ
‫ﺩﺍﺭﺓ‬ ‫ﺯﻣﻦ‬ ‫ﺛﺎﺑﺖ‬ ‫ﻗﻴﻤﺔ‬
τ
‫؟‬
ƒ
‫ﻗﻴﻤﺔ‬
C=…..
‫؟‬
4
(
‫ﺗﻴﺎﺭ‬ ‫ﻋﺒﺎﺭﺓ‬ ‫ﺍﻋﻂ‬
i(t)
. ‫ﺍﻻﺑﺘﺪﺍﺋﻴﺔ‬ ‫ﻗﻴﻤﺘﻪ‬ ‫ﻣﺎﻫﻲ‬ ‫؟‬
‫ﺷﻛﻝ‬
–
1
-
‫ﺷﻛﻝ‬
–
2
-
‫ﺷﻛﻝ‬
–
3
-
e
n
c
y
-
e
d
u
c
a
t
i
o
n
.
c
o
m
/
e
x
a
m
s
‫اﳉﺰ‬
‫اﳉﺰ‬
‫ء‬
‫ء‬‫ﺰ‬
‫ﺰ‬
‫ﺰ‬
‫اﻻول‬
‫اﻻول‬
:
m
s
): ‫اﻻول‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
: ‫اﻻول‬ ‫ﻳﻦ‬‫ﺮ‬‫ﺘﻤ‬
4
a
m
‫ﺣ‬ ‫ﻭﻗﺘﻨﺎ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻜﻬﺮﺑﺎء‬ ‫ﻌﺘﺒﺮ‬
‫ﻭ‬ ‫ﻓﻲ‬ ‫ﻜﻬﺮﺑﺎء‬
RL
-
-
LC
LC
-
‫ﺛﻨ‬ ‫ﺳﻨﺪﺭﺱ‬
‫ﺳﻨﺪﺭﺱ‬
‫ﺍﻟﺘﺮﻛﻴ‬ ‫ﻓﻲ‬ ‫ﻣﺴﺘﻌﻤﻠﺔ‬ ‫ﺑﺎﺋﻴﺔ‬
‫ﺍﻟﺘﺮﻛﻴ‬ ‫ﻓﻲ‬ ‫ﺴﺘﻌﻤﻠﺔ‬
‫ﺗﻮﺗﺮﻩ‬ ‫ﻲ‬
‫ﺗﺮﻩ‬
E
E
‫ﺩﺍ‬ ‫ﻣﻘﺎﻭﻣﺘﻪ‬
‫ﻣﻘﺎﻭ‬
C
R=40
R
.
.
‫ﺩﺍﺧﻠﻴﺔ‬
0
0
r
r
.
.
(
‫ﻜﺜﻔﺔ‬
(t)
(
c
c
U
U
‫ﺘﺒﺎ‬
a
3as.ency-education.com
0
‫ﻣﻥ‬
8
0 2 ‫ﺍﻟﺻﻔﺣﺔ‬
II
.
‫ﺍﻟﻘﻄﺐ‬ ‫ﺛﻨﺎﺋﻲ‬ ‫ﺩﺭﺍﺳﺔ‬
LC
):
02
( ‫ﻧﻘﺎﻁ‬
‫ﻭﺿﻊ‬ ‫ﺍﻟﻰ‬ ‫ﺍﻟﻘﺎﻁﻌﺔ‬ ‫ﻭﺿﻊ‬ ‫ﻧﻐﻴﺮ‬ ‫ﺍﻟﺪﺍﺋﻢ‬ ‫ﻟﻨﻈﺎﻡ‬ ‫ﻧﺼﻞ‬ ‫ﻋﻨﺪﻣﺎ‬
2
‫ﺍﺯﻣﻨﺔ‬ ‫ﻣﺒﺪﺍ‬ ‫ﻭﻧﻌﺘﺒﺮﻩ‬
t=0 s
.
1
(
‫ﺍﻟﺸﺤﻨﺔ‬ ‫ﻟﺘﻐﻴﺮﺍﺕ‬ ‫ﺗﻔﺎﺿﻠﻴﺔ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺍﻛﺘﺐ‬
q(t)
‫؟‬ ‫ﺩﺍﺭﺓ‬ ‫ﻓﻲ‬
2
(
‫؟‬ ‫ﺳﺒﺒﻪ‬ ‫ﻣﻦ‬ ‫؟‬ ‫ﺍﻻﻫﺘﺰﺍﺯ‬ ‫ﻧﻤﻂ‬ ‫ﻣﺎﻫﻮ‬ ‫ﺍﻟﺸﻜﻞ‬ ‫ﺣﺴﺐ‬
3
(
: ‫ﺍﻭﺟﺪ‬ ‫ﺍﻟﺸﻜﻞ‬ ‫ﺣﺴﺐ‬
ƒ
‫ﺍﻟﺤﺮﻛﺔ‬ ‫ﺩﻭﺭ‬ ‫ﺷﺒﻪ‬ ‫ﻗﻴﻤﺔ‬
T
.
ƒ
‫ﺍﻟﻨﺒﺾ‬ ‫ﻗﻴﻤﺔ‬
ɘ
.
ƒ
‫ﺑ‬
‫ﺈ‬
‫ﻭﺷﻴﻌﺔ‬ ‫ﺫﺍﺗﻴﺔ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ ‫ﻣﺎﺩﺭﺳﺖ‬ ‫ﻋﻠﻰ‬ ‫ﻋﺘﻤﺎﺩ‬
L
‫اﻟ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
‫ﺜﺎﱐ‬
):
05
‫ﻧﻘ‬
‫ﺎ‬
(‫ط‬
I
.
‫ﻣﺎﺋﻠﺔ‬ ‫ﻁﺮﻳﻖ‬ ‫ﻋﻠﻰ‬ ‫ﻳﻨﺰﻟﻖ‬ ‫ﺟﺴﻢ‬ ‫ﺣﺮﻛﺔ‬ ‫ﺩﺭﺍﺳﺔ‬
):
03
( ‫ﻧﻘﺎﻁ‬
‫ﺻﻠﺐ‬ ‫ﺟﺴﻢ‬ ‫ﻳﻨﺰﻟﻖ‬
(S)
‫ﻛﺘﻠﺘﻪ‬
m = 100g
‫ﻋﻠﻰ‬
‫ﺑﺰﺍﻭﻳﺔ‬ ‫ﺍﻷﻓﻖ‬ ‫ﻋﻦ‬ ‫ﻣﺎﺋﻞ‬ ‫ﻣﺴﺘﻮ‬ ‫ﻁﻮﻝ‬
α = 20°
‫ﻭﻓﻖ‬
‫ﺍﻟﻤﺤﻮﺭ‬
‫ܤܣ‬
ሬሬሬሬሬԦ
)
‫ﺍﻧﻈﺮ‬
‫ﺍﻟﻤﺘﻌﺎﻗﺐ‬ ‫ﺑﺎﻟﺘﺼﻮﻳﺮ‬ ‫ﻗﻤﻨﺎ‬ .( ‫ﺍﻟﺸﻜﻞ‬
‫ﺑﺒﺮﻣﺠﻴﺔ‬ ‫ﺍﻟﻔﻴﺪﻳﻮ‬ ‫ﺷﺮﻳﻂ‬ ‫ﻭﻋﻮﻟﺞ‬ ‫ﺭﻗﻤﻴﺔ‬ ‫ﺑﻜﺎﻣﻴﺮﺍ‬
(Aviméca)
‫ﻋﻠﻰ‬ ‫ﻭﺗﺤﺼﻠﻨﺎ‬ ‫ﺍﻵﻟﻲ‬ ‫ﺍﻹﻋﻼﻡ‬ ‫ﺑﺠﻬﺎﺯ‬
‫ﺍﻟﺒﻴﺎﻥ‬ ‫ﺭﺳﻢ‬
v=f(t)
.
1
–
:‫ﺍﻟﺒﻴﺎﻥ‬ ‫ﻋﻠﻰ‬ ‫ﺑﺎﻻﻋﺘﻤﺎﺩ‬
‫ﺃ‬
–
‫ﺣﺮﻛﺔ‬ ‫ﻁﺒﻴﻌﺔ‬ ‫ﺑﻴﻦ‬
(S)
.
‫ﺏ‬
–
‫ﻟﻠﺘﺴﺎﺭﻉ‬ ‫ﺍﻟﺘﺠﺮﻳﺒﻴﺔ‬ ‫ﺍﻟﻘﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬
a
.
‫ﺝ‬
–
‫ﺍﻟﺴﺮﻋﺔ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬
0
v
‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻓﻲ‬
t=0
.
‫ﺩ‬
–
:‫ﺍﻟﻠﺤﻈﺘﻴﻦ‬ ‫ﺑﻴﻦ‬ ‫ﺍﻟﻤﻘﻄﻮﻋﺔ‬ ‫ﺍﻟﻤﺴﺎﻓﺔ‬ ‫ﺍﺣﺴﺐ‬
)
= 0,04s
1
t
‫ﻭ‬
= 0,08s
2
t
.(
2
–
:‫ﻣﻬﻤﻠﺔ‬ ‫ﺍﻻﺣﺘﻜﺎﻛﺎﺕ‬ ‫ﺃﻥ‬ ‫ﺑﻔﺮﺽ‬
‫ﺃ‬
–
‫ﺍﻟﻌﺒﺎﺭﺓ‬ ‫ﺃﻭﺟﺪ‬ ‫ﻟﻨﻴﻮﺗﻦ‬ ‫ﺍﻟﺜﺎﻧﻲ‬ ‫ﺍﻟﻘﺎﻧﻮﻥ‬ ‫ﺑﺘﻄﺒﻴﻖ‬
‫ﻟﻠﺘﺴﺎﺭﻉ‬ ‫ﺍﻟﺤﺮﻓﻴﺔ‬
0
a
.‫ﻗﻴﻤﺘﻪ‬ ‫ﺍﺣﺴﺐ‬ ‫ﺛﻢ‬
‫ﺏ‬
–
‫ﺑﻴﻦ‬ ‫ﻗﺎﺭﻥ‬
0
a
‫ﻭ‬
a
‫؟‬
3
-
‫ﺳﺆﺍﻝ‬ ‫ﻣﻦ‬
1
‫ﺳﺆﺍﻝ‬ ‫ﻭ‬
2
‫ﺍﻟﻘﻮﺓ‬ ‫ﺷﺪﺓ‬ ‫ﺃﻭﺟﺪ‬
݂
Ԧ
.‫ﺍﻟﻤﺎﺋﻞ‬ ‫ﺍﻟﻤﺴﺘﻮﻱ‬ ‫ﻋﻠﻰ‬ ‫ﻟﻼﺣﺘﻜﺎﻛﺎﺕ‬ ‫ﺍﻟﻤﻨﻤﺬﺟﺔ‬
e
n
c
y
-
e
d
u
c
a
t
i
o
n
.
c
o
m
/
e
x
a
m
s
3
3
(
‫ﺣ‬
ƒ
ƒ
‫ﻗﻴﻤ‬
ƒ
ƒ
‫ﺍﻟﻨﺒﺾ‬ ‫ﻗﻴﻤﺔ‬
‫ﻗﻴﻤ‬
ƒ
ƒ
‫ﺑ‬
‫ﺑ‬
‫ﺈ‬
‫ﺈ‬‫ﺑ‬
‫ﺑ‬
‫ﺑ‬
‫ﻣ‬ ‫ﻋﻠﻰ‬ ‫ﻋﺘﻤﺎﺩ‬
‫ﻋﻠ‬ ‫ﻋﺘﻤﺎﺩ‬
‫ﺜﺎﱐ‬
):
)
05
05
‫ﻧﻘ‬
‫ﻧﻘ‬
‫ﺎ‬
‫ﺎ‬‫ﻘ‬
‫ﻘ‬
‫ﻘ‬
(‫ط‬
(‫ط‬
e
x
‫ﻁﺮﻳﻖ‬ ‫ﻋﻠﻰ‬ ‫ﻳﻨﺰﻟﻖ‬ ‫ﺟﺴﻢ‬ ‫ﺣﺮﻛﺔ‬
‫ﻋﻠﻰ‬ ‫ﻳﻨﺰﻟﻖ‬ ‫ﺴﻢ‬
/
e
‫ﺐ‬
(S
( )
S
‫ﻛﺘﻠﺘﻪ‬
‫ﻛﺘﻠﺘﻪ‬
= 100g
100g
‫ﺑﺰﺍﻭﻳﺔ‬ ‫ﻷﻓﻖ‬
‫ﺑﺰﺍﻭﻳﺔ‬
α = 20°
20°
‫ﺍﻟﻤﺘﻌﺎﻗﺐ‬ ‫ﺑﺎﻟﺘﺼﻮﻳﺮ‬ ‫ﻗﻤﻨﺎ‬
‫ﺍﻟﻤﺘﻌ‬ ‫ﻟﺘﺼﻮﻳﺮ‬
‫ﺑﺒﺮﻣﺠﻴﺔ‬ ‫ﻮ‬
‫ﺠﻴﺔ‬
‫ﻋﻠﻰ‬ ‫ﺼﻠﻨﺎ‬
‫ﻠﻰ‬
3as.ency-education.com
0
‫ﻣﻥ‬
8
0 3 ‫ﺍﻟﺻﻔﺣﺔ‬
II
.
‫ﺍﻓﻘﻲ‬ ‫ﻁﺮﻳﻖ‬ ‫ﻋﻠﻰ‬ ‫ﺟﺴﻢ‬ ‫ﺣﺮﻛﺔ‬ ‫ﺩﺭﺍﺳﺔ‬
): ‫ﺧﺸﻦ‬
02
( ‫ﻧﻘﺎﻁ‬
‫ﻋﻠﻰ‬ ‫ﺣﺮﻛﺘﻪ‬ ‫ﺍﻟﺴﺎﺑﻖ‬ ‫ﺍﻟﺠﺴﻢ‬ ‫ﻳﻮﺍﺻﻞ‬
‫ﺍﻟ‬
‫ﻄﺮﻳﻖ‬
‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻋﻨﺪ‬ ‫ﺍﻻﻓﻘﻲ‬
t= 0.12 s
‫ﻧﻘﻄﺔ‬ ‫ﻣﻦ‬
B
‫ﺍﻟﻨﻘﻄﺔ‬ ‫ﺍﻟﻰ‬
C
1
-
‫ﺍﻟﻨﻘﻄﺔ‬ ‫ﻋﻨﺪ‬ ‫ﺍﻟﺤﺮﻛﻴﺔ‬ ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﻫﻲ‬ ‫ﻛﻢ‬
B
‫؟‬
2
-
‫؟‬ ‫ﺍﻟﻄﺮﻳﻖ‬ ‫ﻫﺬﺍ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﺠﺴﻢ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﻤﻄﺒﻘﺔ‬ ‫ﺍﻟﻘﻮﺓ‬ ‫ﻣﺜﻞ‬
3
-
‫ﺍﻟﺘﺴﺎﺭﻉ‬ ‫ﻋﺒﺎﺭﺓ‬ ‫ﺍﻋﻂ‬
a
‫؟‬
4
-
‫ﺍﻟﻨﻘﻄﺔ‬ ‫ﻋﻨﺪ‬ ‫ﻳﺘﻮﻗﻒ‬ ‫ﺍﻟﺠﺴﻢ‬ ‫ﺍﻥ‬ ‫ﻋﻠﻤﺖ‬ ‫ﺍﺫﺍ‬
C
‫؟‬ ‫ﻟﺬﻟﻚ‬ ‫ﺍﻻﺯﻣﺔ‬ ‫ﺍﻻﺣﺘﻜﺎﻙ‬ ‫ﻗﻮﺓ‬ ‫ﻗﻴﻤﺔ‬ ‫ﻣﺎﻫﻲ‬
:‫ﻳﻌﻄﻰ‬
2
-
g = 10 m.s
‫؛‬
sin 20° = 0,34
.
‫اﻟ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
‫ﺜﺎﻟﺚ‬
):
04
‫ﻧﻘ‬
‫ﺎ‬
(‫ط‬
‫ﺍﻟﻔﻮﺳﻔﻮﺭ‬
32
15 P
‫ﺇﺷﻌﺎﻋﻪ‬ ‫ﻧﻤﻂ‬ ، ‫ﺍﻟﺰﺍﺋﺪﺓ‬ ‫ﺍﻟﺤﻤﺮﺍء‬ ‫ﺍﻟﻜﺮﻳﺎﺕ‬ ‫ﺧﻼﻳﺎ‬ ‫ﻟﺘﺨﺮﻳﺐ‬ ‫ﺍﻟﻄﺐ‬ ‫ﻓﻲ‬ ‫ﻳﺴﺘﻌﻤﻞ‬ ‫ﻣﺸﻊ‬ ‫ﻧﻈﻴﺮ‬
β 
‫ﻋﻤﺮﻩ‬ ‫ﻧﺼﻒ‬ ‫ﺯﻣﻦ‬ ‫ﻭ‬
1/2 14,3
t j
.
1
-
‫ﺍﻟﺠﺴﻴﻢ‬ ‫ﻁﺒﻴﻌﺔ‬ ‫ﻫﻲ‬ ‫ﻣﺎ‬
β 
‫ﺍﻟﻤﻨﺒﻌﺚ؟‬
2
-
‫ﺍ‬
‫ﺍﻹﺟﺎﺑﺔ‬ ‫ﺗﺒﺮﻳﺮ‬ ‫ﻣﻊ‬ ‫ﺍﻟﺤﺎﺩﺙ‬ ‫ﺍﻹﺷﻌﺎﻋﻲ‬ ‫ﺍﻟﺘﻔﻜﻚ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﻛﺘﺐ‬
:‫ﻳﻌﻄﻰ‬ .‫ﺍﻟﻤﺴﺘﻌﻤﻠﺔ‬ ‫ﺍﻟﻘﻮﺍﻧﻴﻦ‬ ‫ﺑﺬﻛﺮ‬
14Si
،
15P
،
16S
،
17Cl
.
3
-
‫ﻧ‬
‫ﻛﺘﻠﺔ‬ ‫ﻋﻠﻰ‬ ‫ﺗﺤﺘﻮﻱ‬ ‫ﺍﻟﺼﻮﺩﻳﻮﻡ‬ ‫ﻓﻮﺳﻔﺎﺕ‬ ‫ﻣﻦ‬ ‫ﺟﺮﻋﺔ‬ ‫ﺍﻟﻮﺭﻳﺪ‬ ‫ﻓﻲ‬ ‫ﻟﻠﻤﺮﻳﺾ‬ ‫ﺤﻘﻦ‬
8
0 10
m g

‫ﺍﻟﻔﻮﺳﻔﻮﺭ‬ ‫ﻣﻦ‬
32
.
‫ﺃ‬
-
‫ﺍﻹﺑﺘﺪﺍﺋﻴﺔ‬ ‫ﺍﻷﻧﻮﻳﺔ‬ ‫ﻋﺪﺩ‬ ‫ﺃﺣﺴﺐ‬
0
N
‫ﻟﻠﻔﻮﺳﻔﻮﺭ‬
32
.
‫ﺏ‬
-
‫ﻋﺒﺎﺭﺓ‬ ‫ﺃﻛﺘﺐ‬
λ
‫ﺑﺪﻻﻟﺔ‬
1/2
t
‫ﺑـ‬ ‫ﻗﻴﻤﺘﻪ‬ ‫ﺍﺣﺴﺐ‬ ‫ﺛﻢ‬
1
s
.
‫ﺟـ‬
-
‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻋﺮﻑ‬
( )
A t
‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻋﻨﺪ‬ ‫ﺍﻟﻤﺸﻌﺔ‬ ‫ﻟﻠﻌﻴﻨﺔ‬
t
‫ﺑﻴﻦ‬ ‫ﺍﻟﻌﻼﻗﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ ‫ﻭ‬ ،
( )
A t
‫ﺍﻷﻧﻮﻳﺔ‬ ‫ﻋﺪﺩ‬ ‫ﻭ‬
( )
N t
‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻓﻲ‬
t
.
‫ﺩ‬
-
‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬
0
A
.‫ﺍﻟﻤﺮﻳﺾ‬ ‫ﺗﻠﻘﺎﻫﺎ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺍﻟﻔﻮﺳﻔﻮﺭ‬ ‫ﻟﻌﻴﻨﺔ‬
‫ﻫـ‬
-
‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﺍﺣﺴﺐ‬
1
t
‫ﻋﺸﺮ‬ ‫ﻳﺴﺎﻭﻱ‬ ‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻓﻴﻬﺎ‬ ‫ﻳﺼﺒﺢ‬ ‫ﺍﻟﺘﻲ‬
)
10
1
(
‫ﺍﻟﻘﻴﻤﺔ‬
0
A
.
3
-
‫ﺃ‬
-
‫ﺃ‬
:‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻓﻲ‬ ‫ﺃﻧﻪ‬ ‫ﺛﺒﺖ‬
1/2
t nt
‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻋﺒﺎﺭﺓ‬ ‫ﺗﻜﻮﻥ‬
( )
A t
:‫ﻳﻠﻲ‬ ‫ﻛﻤﺎ‬
0
( )
2n
A
A t
‫ﺣﻴﺚ‬ ،
0
A
. ‫ﺍﻹﺑﺘﺪﺍﺋﻲ‬ ‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻫﻮ‬
‫ﺏ‬
-
‫ﺍﻟﻤﻨﺤﻨﻰ‬ ‫ﺃﺭﺳﻢ‬
( )
A t
‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻗﻴﻢ‬ ‫ﺗﻤﺜﻴﻞ‬ ‫ﻣﻊ‬ ، ‫ﺍﻟﺤﺎﺳﺒﺔ‬ ‫ﺍﻵﻟﺔ‬ ‫ﺍﺳﺘﻌﻤﺎﻝ‬ ‫ﺩﻭﻥ‬
( )
A t
:‫ﻟﻠﺤﻈﺎﺕ‬ ‫ﺍﻟﻤﻮﺍﻓﻘﺔ‬
1/2
t
،
1/2
2t
،
1/2
3t
،
1/2
4t
.
:‫ﺃﻓﻮﻏﺎﺩﺭﻭ‬ ‫ﻋﺪﺩ‬ :‫ﻳﻌﻄﻰ‬
23 1
6,02 10 .
A
N mol 
u
3
-
4
4
-
‫ﻋﻠﻤ‬ ‫ﺍﺫﺍ‬
‫ﺍﺫ‬
:‫ﻳﻌﻄﻰ‬
‫ﻳﻌﻄﻰ‬
2
-
m.s
‫اﻟ‬ ‫ﻳﻦ‬‫ﺮ‬
‫ﻟ‬
‫ﺜﺎﻟﺚ‬
‫ﻟﺜﺎﻟﺚ‬‫ﻟ‬
):
):
04
04
‫ﻧﻘ‬
‫ﻧﻘ‬
‫ﻘﺎ‬
(‫ط‬
x
a
3
‫ﻓﻲ‬ ‫ﻳﺴﺘﻌﻤﻞ‬ ‫ﻣﺸﻊ‬ ‫ﻧﻈﻴﺮ‬
‫ﻓﻲ‬ ‫ﻳﺴﺘﻌﻤﻞ‬ ‫ﻣﺸﻊ‬ ‫ﻈﻴﺮ‬
β 
‫ﺍﻟﻤﻨﺒﻌﺚ؟‬
‫ﺍﻟﻤﻨﺒﻌﺚ؟‬
‫ﺍﻹﺟ‬ ‫ﺗﺒﺮﻳﺮ‬ ‫ﻣﻊ‬ ‫ﺍﻟﺤﺎﺩﺙ‬ ‫ﻋﻲ‬
‫ﺗﺒﺮﻳ‬ ‫ﻣﻊ‬ ‫ﺎﺩﺙ‬
‫ﺗﺤ‬ ‫ﺍﻟﺼﻮﺩﻳﻮﻡ‬ ‫ﻓﻮﺳﻔﺎﺕ‬ ‫ﻣﻦ‬
‫ﺍﻟﺼﻮ‬ ‫ﻮﺳﻔﺎﺕ‬
32
.
‫ﺑﻴﻦ‬ ‫ﺍﻟﻌﻼﻗﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬
‫ﺑﻴﻦ‬ ‫ﺍﻟﻌﻼﻗﺔ‬ ‫ﺞ‬
( )
)
A(
‫ﻤﺔ‬
0
A
A
.
( )
A
A(
‫ﺣﻴﺚ‬ ،
‫ﺣﻴﺚ‬ ،
0
0
A
A
‫ﺍﻟﻨ‬ ‫ﻫﻮ‬
‫ﻫ‬
:‫ﻟﻠﺤﻈﺎﺕ‬ ‫ﻘﺔ‬
:‫ﺤﻈﺎﺕ‬
1/2
1/2
t
t
،
،
1/2
1/2
2t
2
،
2
3as.ency-education.com
0
‫ﻣﻥ‬
8
0 4 ‫ﺍﻟﺻﻔﺣﺔ‬
‫اﳉﺰ‬
‫ء‬
‫اﻟﺜﺎﱐ‬
‫ﻋﻠﻰ‬ :
)
7
‫ﻧﻘﺎط‬
(
‫ـ‬‫ـ‬‫ـ‬‫ﻴ‬‫اﻟﻜﻤ‬ )
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
‫ـ‬‫ـ‬‫ـ‬‫ـ‬
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
(‫ﺎء‬
‫اﻟﺜﺎﻟﺚ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
:
‫ﺍﻟﺪﺭﺟﺔ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﺤﺎﻟﻴﻞ‬ ‫ﻛﻞ‬ ‫ﺗﺆﺧﺬ‬
25°C
.
‫ﺍﻹﺟﻤﺎﻟﻴﺔ‬ ‫ﺍﻟﺠﺰﻳﺌﻴﺔ‬ ‫ﺻﻴﻐﺘﻪ‬ ‫ﻛﺮﺑﻮﻛﺴﻴﻠﻲ‬ ‫ﺣﻤﺾ‬ ‫ﺍﻹﻳﺒﻮﺑﺮﻭﻓﻴﻦ‬
‫ܥ‬ଵଷ‫ܪ‬ଵ଼ܱଶ
‫ﺷﺒﻴﻪ‬ ،‫ﻟﻼﻟﺘﻬﺎﺑﺎﺕ‬ ‫ﺍﻟﻤﻀﺎﺩﺍﺕ‬ ‫ﻣﻦ‬ ‫ﻳﻌﺘﺒﺮ‬ ‫ﺩﻭﺍء‬ ،
‫ﺃﻛﻴﺎﺱ‬ ‫ﻓﻲ‬ ‫ﻣﺴﺤﻮﻕ‬ ‫ﺷﻜﻞ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﺼﻴﺪﺍﻟﻴﺎﺕ‬ ‫ﻓﻲ‬ ‫ﺍﻹﻳﺒﻮﺑﺮﻭﻓﻴﻦ‬ ‫ﻣﺴﺘﺤﻀﺮﺍﺕ‬ ‫ﺗﺒﺎﻉ‬ .‫ﻟﻠﺤﺮﺍﺭﺓ‬ ‫ﻭﻣﺨﻔﺾ‬ ‫ﻟﻶﻻﻡ‬ ‫ﻣﺴﻜﻦ‬ ،‫ﺑﺎﻷﺳﺒﺮﻳﻦ‬
‫ﺍﻟﻤﻘﺪﺍﺭ‬ ‫ﺗﺤﻤﻞ‬
200 mg
‫ﺑـ‬ ‫ﺍﻹﻳﺒﻮﺑﺮﻭﻓﻴﻦ‬ ‫ﻟﺤﻤﺾ‬ ‫ﻧﺮﻣﺰ‬ ‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻫﺬﺍ‬ ‫ﻛﻞ‬ ‫ﻓﻲ‬ .‫ﺍﻟﻤﺎء‬ ‫ﻓﻲ‬ ‫ﻳﺬﻭﺏ‬
ܴ‫ܪܱܱܥ‬
‫ﺍﻟﻤﺮﺍﻓﻖ‬ ‫ﻭﻷﺳﺎﺳﻪ‬
‫ﺑﺎﻟﺮﻣﺰ‬
ܴ‫ܱܱܥ‬ି
:‫ﻳﻌﻄﻰ‬ .
‫ܯ‬ሺܴ‫ܪܱܱܥ‬ሻ ൌ ʹͲ͸݃Ȁ݉‫݈݋‬
.
): ‫ﻛﺮﺑﻮﻛﺴﻴﻠﻲ‬ ‫ﻟﺤﻤﺾ‬ ‫ﺗﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺩﺭﺍﺳﺔ‬
03.5
( ‫ﻧﻘﺎﻁ‬
‫ﺍﻹﻳﺒﻮﺑﺮﻭﻓﻴﻦ‬ ‫ﻛﻴﺲ‬ ‫ﻣﺤﺘﻮﻯ‬ ‫ﻧﺬﻳﺐ‬
mg
200
‫ﻣﺎﺋﻲ‬ ‫ﻣﺤﻠﻮﻝ‬ ‫ﻋﻠﻰ‬ ‫ﻓﻨﺤﺼﻞ‬ ‫ﻣﺎء‬ ‫ﺑﻪ‬ ‫ﺑﻴﺸﺮ‬ ‫ﻓﻲ‬ ‫ﺍﻟﺤﻤﺾ‬ ‫ﻣﻦ‬
0
S
‫ﺍﻟﻤﻮ‬ ‫ﺗﺮﻛﻴﺰﻩ‬
‫ﻟﻲ‬
0
C
‫ﻭﺣﺠﻤﻪ‬
=500 ml
0
V
.
1
–
: ‫ﺃﻥ‬ ‫ﻣﻦ‬ ‫ﺗﺄﻛﺪ‬
= 0.002 mol/l
0
C
.
2
–
‫ﻗﻴﺎﺱ‬ ‫ﺃﻋﻄﻰ‬
pH
‫ﺍﻟﻤﺤﻠﻮﻝ‬
0
S
‫ﺍﻟﻘﻴﻤﺔ‬
pH =3,5
.
‫ﺃ‬
–
‫ﺗ‬
.‫ﻣﺤﺪﻭﺩ‬ ‫ﺍﻟﻤﺎء‬ ‫ﻣﻊ‬ ‫ﺍﻹﻳﺒﻮﺑﺮﻭﻓﻴﻦ‬ ‫ﺣﻤﺾ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﺃﻥ‬ ‫ﺍﻟﺘﻘﺪﻡ‬ ‫ﻝ‬ ّ‫ﺑﺠﺪﻭ‬ ‫ﺑﺎﺳﺘﻌﺎﻧﺘﻚ‬ ‫ﺤﻘﻖ‬
‫ﺏ‬
–
‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻛﺴﺮ‬ ‫ﺍﻛﺘﺐ‬
r
Q
.‫ﻝ‬ ّ‫ﺍﻟﺘﺤﻮ‬ ‫ﻟﻬﺬﺍ‬
‫ﺝ‬
–
‫ﻋﺒﺎﺭﺓ‬ ‫ﺃﻥ‬ ‫ّﻦ‬‫ﻴ‬‫ﺑ‬
r
Q
:‫ﺍﻟﺸﻜﻞ‬ ‫ﻋﻠﻰ‬ ‫ﺗﻜﺘﺐ‬ ‫ﺍﻟﺘﻮﺍﺯﻥ‬ ‫ﻋﻨﺪ‬
ܳ௥Ǥé௤ ൌ
௑೘ೌೣǤఛ೑
మ
௏బǤሺଵିఛ೑ሻ
.
‫ﺣﻴﺚ‬
f
τ
‫ﻭ‬ ‫ﻟﻠﺘﻔﺎﻋﻞ‬ ‫ﺍﻟﻨﻬﺎﺋﻲ‬ ‫ﺍﻟﺘﻘﺪﻡ‬ ‫ﻧﺴﺒﺔ‬ :
max
X
‫ﺑـ‬ ‫ﻋﻨﻪ‬ ‫ﻭﻳﻌﺒﺮ‬ ‫ﺍﻷﻋﻈﻤﻲ‬ ‫ﺍﻟﺘﻘﺪﻡ‬ :
mol
.
‫ﺩ‬
–
‫ﺍﻟﺘﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬
K
.
II
.
‫ﺍﻟﺘﺠﺎﺭﻱ‬ ‫ﺍﻟﺨﻞ‬ ‫ﺣﻤﻀﻴﺔ‬ ‫ﺩﺭﺟﺔ‬
):
03.5
( ‫ﻧﻘﺎﻁ‬
‫ﺣﺠﻤﺎ‬ ‫ﻧﺄﺧﺬ‬ ، ‫ﺍﻟﻜﻴﺲ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﻤﺴﺠﻞ‬ ‫ﺍﻟﻤﻘﺪﺍﺭ‬ ‫ﺻﺤﺔ‬ ‫ﻣﻦ‬ ‫ﻟﻠﺘﺤﻘﻖ‬
=100 ml
b
V
‫ﻣﺎﺋﻲ‬ ‫ﻣﺤﻠﻮﻝ‬ ‫ﻣﻦ‬
b
S
‫ﺍﻟﺼﻮﺩﻳﻮﻡ‬ ‫ﻟﻬﻴﺪﺭﻭﻛﺴﻴﺪ‬
ሺܰܽାሺƒ“ሻ ൅ ିሺƒ“ሻሻ
‫ﺍﻟﻤﻮﻟﻲ‬ ‫ﺗﺮﻛﻴﺰﻩ‬.
=0.02 mol/l
b
C
‫ﻣﺎﺋﻲ‬ ‫ﻣﺤﻠﻮﻝ‬ ‫ﻋﻠﻰ‬ ‫ﻓﻨﺤﺼﻞ‬ ‫ﺍﻟﻜﻴﺲ‬ ‫ﻣﺤﺘﻮﻯ‬ ‫ﻛﻠﻴﺎ‬ ‫ﻓﻴﻪ‬ ‫ﻭﻧﺬﻳﺐ‬
S
‫ﻧﻌﺘﺒﺮ‬ )
‫ﺍﻟﻤﺤﻠﻮﻝ‬ ‫ﺣﺠﻢ‬ ‫ﺃﻥ‬
S
‫ﻫﻮ‬
b
V
‫ﻧﺄﺧﺬ‬ .(
ml
20
‫ﺍﻟﻤﺤﻠﻮﻝ‬ ‫ﻣﻦ‬
S
‫ﻭﻧﻀﻌﻪ‬
‫ﺍﻟﻬﻴﺪﺭﻭﺟﻴﻦ‬ ‫ﻛﻠﻮﺭ‬ ‫ﺣﻤﺾ‬ ‫ﺑﻤﺤﻠﻮﻝ‬ ‫ﻭﻧﻌﺎﻳﺮﻩ‬ ‫ﺑﻴﺸﺮ‬ ‫ﻓﻲ‬
‫ﺍﻟﻤﻮﻟﻲ‬ ‫ﺗﺮﻛﻴﺰﻩ‬
= 0.02 mol/l
a
C
‫ﺍﻟﻤﻨﺤﻨﻰ‬ ‫ﻋﻠﻰ‬ ‫ﻓﻨﺤﺼﻞ‬
‫ﺍﻟﺒﻴﺎﻧﻲ‬
‫ﺍﻟﺸﻜﻞ‬
–
9
:‫ﻫﻲ‬ ‫ﺍﻟﻤﻌﺎﻳﺮﺓ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ،
‫ܪ‬ଷܱାሺܽ‫ݍ‬ሻ ൅‫ܱܪ‬ିሺܽ‫ݍ‬ሻ ൌʹ‫ܪ‬ଶܱሺℓሻ
.
1
–
.‫ﺍﻟﻤﻌﺎﻳﺮﺓ‬ ‫ﻋﻤﻠﻴﺔ‬ ‫ﺗﺨﻄﻴﻄﻲ‬ ‫ﺑﺸﻜﻞ‬ ‫ﺍﺭﺳﻢ‬
2
–
‫ﺍﻟﻨﻘﻄﺔ‬ ‫ﻫﺬﻩ‬ ‫ﺇﺣﺪﺍﺛﻴﺘﻲ‬ ‫ﺣﺪﺩ‬ ّ‫ﻢ‬‫ﺛ‬ ،‫ﺍﻟﺘﻜﺎﻓﺆ‬ ‫ﻧﻘﻄﺔ‬ ‫ﻑ‬ّ‫ﻋﺮ‬
E
.
3
–
‫ﻟﺸﻮﺍﺭﺩ‬ ‫ﺍﻟﻤﺎﺩﺓ‬ ‫ﻛﻤﻴﺔ‬ ‫ﺟﺪ‬
‫ܱܪ‬ି
ሺܽ‫ݍ‬ሻ
.‫ﻣﻌﺎﻳﺮﺗﻬﺎ‬ ‫ﺗﻤﺖ‬ ‫ﺍﻟﺘﻲ‬
4
–
‫ﺟﺪ‬
‫ﻟﺸﻮﺍﺭﺩ‬ ‫ﺍﻷﺻﻠﻴﺔ‬ ‫ﺍﻟﻤﺎﺩﺓ‬ ‫ﻛﻤﻴﺔ‬
‫ܱܪ‬ି
ሺܽ‫ݍ‬ሻ
‫ﺍﻟﺤﻤﺾ‬ ‫ﻣﻊ‬ ‫ﺗﻔﺎﻋﻠﺖ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺗﻠﻚ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ ‫ﺛﻢ‬ ،
RCOOH
.‫ﺍﻟﻜﻴﺲ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﺘﻮﺍﺟﺪ‬
5
–
‫ﺍﺣﺴﺐ‬
m
.‫ﺍﻟﻜﻴﺲ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﺘﻮﺍﺟﺪﺓ‬ ‫ﺍﻟﺤﻤﺾ‬ ‫ﻛﺘﻠﺔ‬
‫ﺗﺴﺘﻨﺘﺞ؟‬ ‫ﻣﺎﺫﺍ‬
e
n
c
y
-
e
d
u
c
a
t
i
o
n
.
c
o
m
/
e
x
a
m
s
‫ﺑﺎﻷﺳ‬
‫ﺍ‬ ‫ﺗﺤﻤﻞ‬
‫ﺗ‬
‫ﺑﺎﻟﺮﻣﺰ‬
‫ﺑﺎﻟﺮﻣ‬
ܱି
‫ﻟﺤﻤ‬ ‫ﺗﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺩﺭﺍﺳﺔ‬
‫ﺗﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺭﺍﺳﺔ‬
m
‫ﻛﻴﺲ‬ ‫ﻣﺤﺘﻮﻯ‬ ‫ﻧﺬﻳﺐ‬
‫ﻣﺤﺘﻮﻯ‬ ‫ﻧﺬﻳﺐ‬
0
0
C
C
‫ﻭﺣﺠﻤﻪ‬
‫ﻭﺣﺠﻤﻪ‬
0 ml
–
: ‫ﺃﻥ‬ ‫ﻣﻦ‬ ‫ﺗﺄﻛﺪ‬
: ‫ﺃﻥ‬ ‫ﻣﻦ‬ ‫ﻛﺪ‬
mol/l
‫ﻗﻴﺎﺱ‬ ‫ﻄﻰ‬
‫ﻗﻴﺎﺱ‬
pH
pH
‫ﺍﻟﻤﺤﻠﻮﻝ‬
‫ﺍﻟﻤﺤﻠﻮﻝ‬
‫ﺍﻟﺘﻘﺪﻡ‬ ‫ﻝ‬
‫ﺍﻟ‬ ‫ﺑﺠﺪﻭﻝ‬ ‫ﺑﺎﺳﺘﻌﺎﻧﺘﻚ‬
‫ﺑﺠﺪﻭ‬ ‫ﻌﺎﻧﺘﻚ‬
ّّ
‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﺮ‬
‫ﻋﻞ‬
r
r
Q
Q
‫ﺍﻟﺘﺤﻮ‬ ‫ﻟﻬﺬﺍ‬
‫ﺍﻟ‬ ‫ﻟﻬﺬﺍ‬
‫ﻋﻠﻰ‬ ‫ﺗﻜﺘﺐ‬ ‫ﺍﻟﺘﻮﺍﺯﻥ‬ ‫ﻋﻨﺪ‬
‫ﺗﻜﺘﺐ‬ ‫ﺘﻮﺍﺯﻥ‬
‫ﻭ‬ ‫ﻟﻠﺘﻔﺎﻋﻞ‬ ‫ﻲ‬
‫ﻋﻞ‬
max
max
Xm
‫ﺍﻟﺘﻘ‬ :
‫ﺣﺠﻤﺎ‬
=100 ml
=100 m
b
b
V
V
‫ﻣ‬ ‫ﻣﻦ‬
‫ﻣﻦ‬
=
b
C
‫ﺮ‬
.‫ﺍﻟﻜﻴﺲ‬
‫ﺲ‬
3as.ency-education.com
0
‫ﻣﻥ‬
8
0 5 ‫ﺍﻟﺻﻔﺣﺔ‬
‫ﺍﻟﺜﺎﻧﻲ‬ ‫ﻣﻮﺿﻮﻉ‬
‫اﳉﺰ‬
‫ء‬
‫اﻻول‬
:
‫ﻋﻠﻰ‬
13
‫ﻧﻘﻄﺔ‬
‫ﻳ‬‫ﺰ‬‫اﻟﻔﻴ‬ )
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
(‫ﺎء‬
‫اﻟ‬
‫اﻻول‬ ‫ﻳﻦ‬‫ﺮ‬‫ﺘﻤ‬
:
)
04
(‫ﻧﻘﻄﺔ‬
I
.
): ‫ﻣﻜﺜﻔﺔ‬ ‫ﻭﺗﻔﺮﻳﻎ‬ ‫ﺷﺤﻦ‬ ‫ﺩﺭﺍﺳﺔ‬
03
( ‫ﻧﻘﺎﻁ‬
‫ﺳﻌﺘﻬﺎ‬ ‫ﻣﻜﺜﻔﺔ‬
C
) ‫ﺛﺎﺑﺖ‬ ‫ﺗﻮﺗﺮ‬ ‫ﺗﺤﺖ‬ ‫ﺷﺤﻨﻬﺎ‬ ‫ﺗﻢ‬
E = 12V
‫ﺛﻢ‬ . (
‫ﻣﻘﺎﻭﻣﺘﻪ‬ ‫ﺃﻭﻣﻲ‬ ‫ﻧﺎﻗﻞ‬ ‫ﻓﻲ‬ ‫ﺗﻔﺮﻳﻐﻬﺎ‬ ‫ﺃﻋﻴﺪ‬
:
5
R = 10
.
1
-
/
‫ﺍﻟﻘﺎﻁﻌﺔ‬ ‫ﻧﻌﺘﺒﺮ‬
) ‫ﻭﺿﻊ‬ ‫ﻓﻲ‬
1
(
‫ﺣﻘﻴﻘﻲ‬ ‫ﺑﻞ‬ ‫ﻣﺜﺎﻟﻲ‬ ‫ﻟﻴﺲ‬ ‫ﻭﺍﻟﻤﻮﻟﺪ‬
)
Ω
r=10
(
.
1
-
1
‫ﻟﺘﻮﺗﺮ‬ ‫ﺍﻟﺘﻔﺎﺿﻠﻴﺔ‬ ‫ﺍﻟﻤﻌﺎﺩﻟﺔ‬ ‫ﺍﻋﻂ‬ ‫ﺗﻮﺗﺮﺍﺕ‬ ‫ﻗﺎﻧﻮﻥ‬ ‫ﺑﺎﺳﺘﻌﻤﺎﻝ‬
Uc
‫؟‬ ‫ﺍﻟﻤﻜﺜﻔﺔ‬ ‫ﻁﺮﻓﻲ‬ ‫ﺑﻴﻦ‬
1
-
2
‫ﻋﻨﺪ‬
t=0
‫ﺍﻟﺘﻴﺎﺭ‬ ‫ﺷﺪﺓ‬ ‫ﺗﻜﻮﻥ‬ ‫ﻛﻢ‬
0
I
‫؟‬ ‫ﺩﺍﺭﺓ‬ ‫ﻓﻲ‬
2
-
/
) ‫ﻭﺿﻊ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻘﺎﻁﻌﺔ‬ ‫ﻧﻌﺘﺒﺮ‬
2
‫ﺍﻟﺴﺎﺑﻖ‬ ‫ﺍﻟﺸﻜﻞ‬ ‫ﻓﻲ‬ (
.
2
-
1
‫ﺑﺪﻻﻟﺔ‬ ‫ﻟﻠﺪﺍﺭﺓ‬ ‫ﺍﻟﺘﻔﺎﺿﻠﻴﺔ‬ ‫ﺍﻟﻤﻌﺎﺩﻟﺔ‬ ‫ﺃﻛﺘﺐ‬
q ( t )
‫؟‬ ‫ﺍﻟﺘﻔﺮﻳﻎ‬ ‫ﺧﻼﻝ‬
2
-
2
‫ﻫﻮ‬ ‫ﺣﻠﻬﺎ‬ ‫ﺃﻥ‬ ‫ﺑﻴﻦ‬
W
t/
-
e
0
= Q
q( t )
‫؟‬
2
-
3
‫؟‬ ‫ﺍﻟﺰﻣﻦ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺑﻴﺎﻧﻴﺎ‬ ‫ﻋﻴﻦ‬
2
-
4
‫ﺍﻟﻤﻜﺜﻔﺔ‬ ‫ﺳﻌﺔ‬ ‫ﺃﺣﺴﺐ‬
C
‫؟‬
6
‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻋﻨﺪ‬ ‫ﺍﻟﻤﻜﺜﻔﺔ‬ ‫ﺷﺤﻨﺔ‬ ‫ﺃﺣﺴﺐ‬ ‫ـ‬ (
t = 0
‫؟‬
7
‫ﺃ‬ ‫ـ‬ (
‫ﺍﻟﻠﺤﻈ‬ ‫ﻧﻔﺲ‬ ‫ﻋﻨﺪ‬ ‫ﺍﻟﺘﻴﺎﺭ‬ ‫ﺷﺪﺓ‬ ‫ﺣﺴﺐ‬
‫ﺔ‬
‫؟‬
‫ﺩﺭﺍﺳﺔ‬
‫ﺍﻟﻬﻴﺪﺭﻭﺟﻴﻦ‬ ‫ﻧﻈﺎﺋﺮ‬ ‫ﻧﻮﺍﺗﻲ‬ ‫ﺍﻧﺪﻣﺎﺝ‬
):
02
( ‫ﻧﻘﺎﻁ‬
‫ﺗﻘﺎﺭﺏ‬ ‫ﺍﻟﻨﺠﻮﻡ‬ ‫ﻫﺬﻩ‬ ‫ﺣﺮﺍﺭﺓ‬ ‫ﺩﺭﺟﺔ‬ ‫ﺗﻜﻮﻥ‬ ‫ﻋﻨﺪﻣﺎ‬ . ‫ﺍﻟﻬﻴﺪﺭﻭﺟﻴﻦ‬ ‫ﻣﻦ‬ ‫ﺃﺳﺎﺳﺎ‬ ‫ﺗﺘﻜﻮﻥ‬ ‫ﺍﻟﺸﻤﺲ‬ ‫ﻣﺜﻞ‬ ‫ﺍﻟﺼﻔﺮﺍء‬ ‫ﺍﻟﻨﺠﻮﻡ‬
K
7
10
5
.
1 u
‫ﺗﺤﺪﺙ‬
‫ﺍﻧﺪﻣﺎﺝ‬ ‫ﺗﻔﺎﻋﻼﺕ‬
‫ﻧﻮﺍﺓ‬ ‫ﻓﺘﻌﻄﻲ‬ ‫ﺍﻟﺒﺮﻭﺗﻮﻧﺎﺕ‬ ‫ﺑﻴﻦ‬
Y
A
Z
/
/
: ‫ﺍﻟﺘﺎﻟﻴﺔ‬ ‫ﺍﻟﺴﻠﺴﻠﺔ‬ ‫ﺣﺴﺐ‬
)
3
........(
2
)
2
.....(
..........
)
1
.......(
.......... 1
1
/
/
3
2
3
2
3
2
1
1
0
1
1
1
1
1 H
Y
H
H
H
X
H
e
X
H
H A
Z
e
e
e
A
Z
A
Z 
o


o


o
 J
1
/
-
‫ﺍﻧ‬
‫ﺍﻟﻨﻮﺍﺗﻴﻦ‬ ‫ﻋﻠﻰ‬ ‫ﺗﻌﺮﻑ‬ ‫ﺍﻟﻤﻌﺎﺩﻻﺕ‬ ‫ﻫﺬﻩ‬ ‫ﻣﻦ‬ ‫ﻄﻼﻗﺎ‬
Y
‫ﻭ‬
X A
Z
A
Z
/
/
2
/
-
‫ﺍﻛ‬
‫ﺍﻟﻨﻮﺍﺓ‬ ‫ﻟﺘﺸﻜﻞ‬ ‫ﺍﻹﺟﻤﺎﻟﻲ‬ ‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺘﺐ‬
Y
A
Z
/
/
‫ﺍﻻﻧﺪﻣﺎﺝ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻋﺮﻑ‬ . ‫ﺍﻟﻬﻴﺪﺭﻭﺟﻴﻦ‬ ‫ﺍﻧﻮﻳﺔ‬ ‫ﻣﻦ‬ ‫ﺍﻧﻄﻼﻗﺎ‬
.
3
/
-
‫ﺗﻔﺎ‬ ‫ﺍﻻﻥ‬ ‫ﻧﻌﺘﺒﺮ‬
: ‫ﺍﻟﺘﺎﻟﻲ‬ ‫ﺍﻻﻧﺪﻣﺎﺝ‬ ‫ﻋﻞ‬
J
2
2
4 0
1
4
2
1
1 

o e
H
H e
‫ﺃ‬
-
‫ﺍﻟﻜﺘﻠﺔ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻨﻘﺺ‬ ‫ﺍﺣﺴﺐ‬
‫ﻟ‬
‫ﻠﺘﻔﺎﻋﻞ‬
‫ﺍ‬ ‫ﻧﻜﻠﻴﻮﻥ‬ ‫ﻟﻜﻞ‬ ‫ﺍﻟﻤﺤﺮﺭﺓ‬ ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ ‫ﻭ‬ ‫ﺍﻟﻤﺤﺮﺭﺓ‬ ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﺛﻢ‬
‫ﺍﻻﻧﺪﻣﺎ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﺛﻨﺎء‬
‫ﻫﺬﺍ‬ ‫ﺝ‬
‫ﺑـ‬
Mev
.
‫ﺏ‬
-
‫ﺍﻟﻤﺤﺮ‬ ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﺍﺣﺴﺐ‬
‫ﻋﻠﻰ‬ ‫ﻟﻠﺤﺼﻮﻝ‬ ‫ﺭﺓ‬
1g
‫ﺍﻟﻬﻠﻴﻮﻡ‬ ‫ﻣﻦ‬
4
‫ﺑـ‬
Mev
‫ﺑـ‬ ‫ﺛﻢ‬ ‫ﺍﻟﺠﻮﻝ‬ ‫ﺑـ‬ ،
(T.e.p)
‫ﺍﻟﺒﺘﺮﻭﻝ‬ ‫ﻣﻦ‬ ‫ﺍﻟﻤﻜﺎﻓﺊ‬ ‫)ﺍﻟﻄﻦ‬
(T.e.p)
‫ﺍﻟﺼﻨﺎﻋﺔ‬ ‫ﻣﺠﺎﻝ‬ ‫ﻓﻲ‬ ‫ﺗﺴﺘﻌﻤﻞ‬ ، ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﻟﻘﻴﺎﺱ‬ ‫ﻭﺣﺪﺓ‬ ‫ﻫﻲ‬
(
e
n
c
y
-
e
d
u
c
a
t
i
o
n
.
c
o
m
/
e
x
a
m
s
I
‫ﺳﻌ‬ ‫ﻣﻜﺜﻔﺔ‬
‫ﻣﻜﺜﻔﺔ‬
‫ﻓﻲ‬ ‫ﺗﻔﺮﻳﻐﻬﺎ‬ ‫ﺃﻋﻴﺪ‬
‫ﺗﻔﺮﻳﻐ‬ ‫ﺃﻋﻴﺪ‬
1
-
/
/
‫ﺍﻟﻘﺎﻁﻌﺔ‬ ‫ﻧﻌﺘﺒﺮ‬
‫ﺍﻟﻘﺎﻁ‬ ‫ﻌﺘﺒﺮ‬
‫ﻓﻲ‬
Ω
r=10
r=
(
(
.
.
‫ﺍ‬ ‫ﺗﻮﺗﺮﺍﺕ‬ ‫ﻗﺎﻧﻮﻥ‬ ‫ﺳﺘﻌﻤﺎﻝ‬
‫ﺗﻮﺗﺮ‬ ‫ﻗﺎﻧﻮﻥ‬ ‫ﺎﻝ‬
‫؟‬ ‫ﻤﻜﺜﻔﺔ‬
‫ﺍﻟﺘﻴﺎﺭ‬ ‫ﺷﺪﺓ‬ ‫ﺗﻜﻮﻥ‬
‫ﺍﻟﺘﻴﺎﺭ‬ ‫ﺷﺪﺓ‬ ‫ﻥ‬
0
0
I
I
‫ﺩ‬ ‫ﻓﻲ‬
) ‫ﺿﻊ‬
)
2
2
‫ﺍﻟﺴﺎﺑﻖ‬ ‫ﺍﻟﺸﻜﻞ‬ ‫ﻓﻲ‬ (
‫ﺍ‬ ‫ﺍﻟﺸﻜﻞ‬ ‫ﻓﻲ‬ (
‫ﺑﺪﻻﻟﺔ‬ ‫ﻟﻠﺪﺍﺭﺓ‬
‫ﺑﺪﻻﻟﺔ‬ ‫ﺭﺓ‬
q ( t )
q ( t )
‫ﺧﻼ‬
q(
‫؟‬
‫؟‬
‫ﺍﻟﻨﺠ‬ ‫ﻫﺬﻩ‬ ‫ﺣﺮﺍﺭﺓ‬ ‫ﺩﺭﺟﺔ‬ ‫ﻮﻥ‬
‫ﺣﺮﺍﺭﺓ‬ ‫ﺭﺟﺔ‬
.......
..........
........
0
0
1e
e
X
X
A
X
Z
Z 

o
‫ﺍﻻﻧﺪﻣﺎﺝ‬
‫ﺝ‬
.
.
‫ﻫﺬﺍ‬ ‫ﺝ‬
‫ﺑـ‬
‫ﺑـ‬
M
Mev
ev
.
3as.ency-education.com
0
‫ﻣﻥ‬
8
0 6 ‫ﺍﻟﺻﻔﺣﺔ‬
‫ﺝ‬
-
‫ﺍ‬
‫؟‬ ‫ﺗﺴﺘﻨﺘﺞ‬ ‫ﻣﺎﺫﺍ‬ . ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﻧﻔﺲ‬ ‫ﺗﺤﺮﺭ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺍﻟﺒﺘﺮﻭﻝ‬ ‫ﻛﺘﻠﺔ‬ ‫ﺣﺴﺐ‬
e
H
4
2
e
H
3
2
H
2
1
H
1
1
e
0
1
‫ﺍﻟﻨﻮﺍﺓ‬
4.0015
3.0149
2.0134
1.0073
0.0006
)
(u
m
X
A
Z
2
Kg = 931.5Mev/c
27
-
u = 1.661.10
1
1
-
mol
23
=6.02 . 10
A
N
,
J
13
-
10
.
Mev = 1.6
1
,
J
9
T.e.p = 42 10
1
): ‫اﻟﺜﺎﱐ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
05
(‫ﻧﻘﻄﺔ‬
I
.
‫ﺩﺭﺍﺳﺔ‬
‫ﺣﺮﻛﺔ‬
‫ﻁﻔﻞ‬
‫ﻣﺎﺋﻠﺔ‬ ‫ﻁﺮﻳﻖ‬ ‫ﻋﻠﻰ‬ ‫ﻳﻨﺰﻟﻖ‬
:
)
02
( ‫ﻧﻘﺎﻁ‬
‫ﻋﻄﺎﻟﺘﻪ‬ ‫ﻣﺮﻛﺰ‬ ‫ﻁﻔﻞ‬ ‫ﻳﻨﺰﻟﻖ‬
G
‫ﻭﻛﺘﻠﺘﻪ‬
m
‫ﺟﺰء‬ ‫ﻣﻦ‬ ‫ﻣﻜﻮﻧﺔ‬ ‫ﻣﺴﺒﺢ‬ ‫ﻣﺰﻟﻘﺔ‬ ‫ﻓﻮﻕ‬
AB
‫ﺑﺰﺍﻭﻳﺔ‬ ‫ﺍﻷﻓﻖ‬ ‫ﻋﻦ‬ ‫ﻣﺎﺋﻞ‬ ‫ﻣﺴﺘﻮ‬
α
‫ﻭﺟﺰء‬
BC
‫ﻣﺴﺘﻮ‬
‫ﺍﻻﺭﺗﻔﺎﻉ‬ ‫ﻋﻠﻰ‬ ‫ﻳﻮﺟﺪ‬ ‫ﺃﻓﻘﻲ‬
h
‫ﺍﻟﺸﻜﻞ‬ ) ‫ﺍﻟﻤﺴﺒﺢ‬ ‫ﻣﺎء‬ ‫ﺳﻄﺢ‬ ‫ﻣﻦ‬
-
1
.(
:‫ﺍﻟﻤﻌﻄﻴﺎﺕ‬
، ‫ﻣﻬﻤﻠﺔ‬ ‫ﺍﻻﺣﺘﻜﺎﻛﺎﺕ‬
g=10(si)
،
AB=10m
،
CE=h=1,8m
.
‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻋﻨﺪ‬ ‫ﺍﻟﻄﻔﻞ‬ ‫ﻳﻨﻄﻠﻖ‬
t=0
‫ﺍﻟﻤﻮﺿﻊ‬ ‫ﻣﻦ‬ ‫ﺍﺑﺘﺪﺍﺋﻴﺔ‬ ‫ﺳﺮﻋﺔ‬ ‫ﺑﺪﻭﻥ‬
A
‫ﻋﻠﻰ‬ ‫ﻓﻴﻨﺰﻟﻖ‬ ،
AB
‫ﺣﺮﻛﺔ‬ ‫ﻟﺪﺭﺍﺳﺔ‬ ،
G
‫ﻣﻌ‬ ‫ﻧﺨﺘﺎﺭ‬ ،
‫ﻠﻤﺎ‬
ሺ‫ܣ‬ǡ ଓ
Ԧሻ
‫ﺣﻴﺚ‬ ‫ﺑﺎﻷﺭﺽ‬ ‫ﻣﺮﺗﺒﻄﺎ‬
=0
A
=X
G
X
‫ﻋﻨﺪ‬
)
t=0
(
.
1
(
‫ﺍﻟﻤﻌﺎﺩﻟﺔ‬ ‫ﺃﻥ‬ ‫ﺃﺛﺒﺖ‬ ،‫ﻟﻨﻴﻮﺗﻦ‬ ‫ﺍﻟﺜﺎﻧﻲ‬ ‫ﺍﻟﻘﺎﻧﻮﻥ‬ ‫ﺑﺘﻄﺒﻴﻖ‬
‫ﺍﻟﻔﺎﺻﻠﺔ‬ ‫ﺗﺤﻘﻘﻬﺎ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺍﻟﺘﻔﺎﺿﻠﻴﺔ‬
G
X
‫ﻋﻄﺎﻟﺔ‬ ‫ﻟﻤﺮﻛﺰ‬
:‫ﻳﻠﻲ‬ ‫ﻛﻤﺎ‬ ‫ﺗﻜﺘﺐ‬ ‫ﺍﻟﻄﻔﻞ‬
ௗమ௑ಸ
ௗ௧మ
ൌ ‰Ǥ •‹α
‫ﺣﺮﻛﺔ‬ ‫ﻁﺒﻴﻌﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ .
G
.
2
(
‫ﺭﻗﻤﻴﺔ‬ ‫ﻛﺎﻣﻴﺮﺍ‬ ‫ﺑﻮﺍﺳﻄﺔ‬ ‫ﺍﻟﻄﻔﻞ‬ ‫ﺣﺮﻛﺔ‬ ‫ﺗﺼﻮﻳﺮ‬ ‫ﺑﻌﺪ‬
‫ﺗﻢ‬ ‫ﻣﻨﺎﺳﺐ‬ ‫ﺑﺮﻧﺎﻣﺞ‬ ‫ﺑﻮﺍﺳﻄﺔ‬ ‫ﺍﻟﻤﻌﻄﻴﺎﺕ‬ ‫ﻭﻣﻌﺎﻟﺠﺔ‬
‫ﺍﻟﻌﻄﺎﻟﺔ‬ ‫ﻟﻤﺮﻛﺰ‬ ‫ﺍﻟﺴﺮﻋﺔ‬ ‫ﻣﺨﻄﻂ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﺤﺼﻮﻝ‬
G
‫)ﺍﻟﺸﻜﻞ‬
-
2
.(
‫ﺃ‬
.
‫ﺍﻟﺘﺴﺎﺭﻉ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺑﻴﺎﻧﻴﺎ‬ ‫ﺃﻭﺟﺪ‬
G
a
.
‫ﺏ‬
.
‫ﺍﻟﺠﺰء‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﻤﺴﺘﻐﺮﻗﺔ‬ ‫ﺍﻟﺰﻣﻨﻴﺔ‬ ‫ﺍﻟﻤﺪﺓ‬ ‫ﺣﺪﺩ‬
AB
.
e
n
c
y
-
e
d
u
c
a
t
i
o
n
AB=
،
،
CE=h=1,8m
E=h=1,8m
‫ﻤﻮﺿﻊ‬
‫ﺿﻊ‬
A
A
/
e
x
a
m
s
Mev/c
): ‫اﻟﺜﺎﱐ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
‫اﻟﺜﺎ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
m
s
I
.
‫ﺩﺭﺍﺳﺔ‬
‫ﺭﺍﺳﺔ‬
‫ﺣﺮﻛﺔ‬
a
m
‫ﻋﻄﺎﻟﺘﻪ‬ ‫ﻣﺮﻛﺰ‬ ‫ﻁﻔﻞ‬ ‫ﻖ‬
‫ﻋﻄﺎﻟ‬ ‫ﻣﺮﻛﺰ‬ ‫ﻔﻞ‬
G
‫ﺍﻻﺭﺗﻔﺎﻉ‬ ‫ﻋﻠﻰ‬ ‫ﺪ‬
‫ﺍﻻﺭﺗﻔﺎﻉ‬ ‫ﻰ‬
h
h
‫ﺳﻄ‬ ‫ﻣﻦ‬
‫ﻋﻠﻰ‬ ‫ﻓﻴﻨﺰﻟﻖ‬ ،
‫ﻋ‬ ‫ﻓﻴﻨﺰﻟﻖ‬ ،
3as.ency-education.com
0
‫ﻣﻥ‬
8
0 7 ‫ﺍﻟﺻﻔﺣﺔ‬
II
.
‫ﻗﺬﻳﻔﺔ‬ ‫ﺷﻜﻞ‬ ‫ﻋﻠﻰ‬ ‫ﻁﻔﻞ‬ ‫ﺣﺮﻛﺔ‬ ‫ﺩﺭﺍﺳﺔ‬
):
03
( ‫ﻧﻘﺎﻁ‬
‫ﺍﻟﻤﻮﺿﻊ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﺰﻟﻘﺔ‬ ‫ﺍﻟﻄﻔﻞ‬ ‫ﻋﻄﺎﻟﺔ‬ ‫ﻣﺮﻛﺰ‬ ‫ﻳﻐﺎﺩﺭ‬
C
‫ﺑﺎﻟﺴﺮﻋﺔ‬
1
-
=11 m.s
c
V
‫ﻣﺎء‬ ‫ﻓﻲ‬ ‫ﻟﻴﺴﻘﻂ‬ ‫ﺍﻷﺯﻣﻨﺔ‬ ‫ﻣﺒﺪﺃ‬ ‫ﻫﺎ‬ ‫ﻧﻌﺘﺒﺮ‬ ‫ﻟﺤﻈﺔ‬ ‫ﻋﻨﺪ‬
‫ﺣﺮﻛﺔ‬ ‫ﻧﺪﺭﺱ‬ .‫ﺍﻟﻤﺴﺒﺢ‬
G
‫ﺍﻟﻤﻌﻠﻢ‬ ‫ﻓﻲ‬
ሺ‫ܥ‬ǡ ଓ
Ԧǡ ଔ
Ԧሻ
.
1
(
‫ﺍﻟﺰﻣﻨﻴﺘﻴﻦ‬ ‫ﺍﻟﻤﻌﺎﺩﻟﺘﻴﻦ‬ ‫ﻋﺒﺎﺭﺓ‬ ‫ﺃﻭﺟﺪ‬ ،‫ﺍﻟﺜﺎﻧﻲ‬ ‫ﻧﻴﻮﺗﻦ‬ ‫ﻗﺎﻧﻮﻥ‬ ‫ﺑﺘﻄﺒﻴﻖ‬
x(t)
‫ﻭ‬
y(t)
‫ﻟﺤﺮﻛﺔ‬
G
‫ﺍﺳﺘﻨﺘﺞ‬ .
‫ﻣﻌﺎﺩﻟﺔ‬
.‫ﺍﻟﻤﺴﺎﺭ‬
2
(
‫ﻳﺼﻞ‬
G
‫ﺍﻟﻤﻮﺿﻊ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﺎء‬ ‫ﺳﻄﺢ‬ ‫ﺇﻟﻰ‬
I
‫ﺑﺎﻟﺴﺮﻋﺔ‬
‫ݒ‬ூ
ሬሬሬԦ
.
‫ﻭﺻﻮﻝ‬ ‫ﻟﺤﻈﺔ‬ ‫ﺃﻥ‬ ‫ﺗﺤﻘﻖ‬ .‫ﺃ‬
G
‫ﺇﻟﻰ‬
I
‫ﻫﻲ‬
=0,6s
I
t
.
‫ﺍ‬ .‫ﺏ‬
‫ﺣ‬
‫ﻗﻴﻤﺔ‬ ‫ﺴﺐ‬
‫ݒ‬ூ
‫ﺍﻟﻤﺴﺎﻓﺔ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺣﺪﺩ‬ .
EI
.
3
(
‫ﻳﻨﺰﻟﻖ‬
‫ﻛﺘﻠﺘﻪ‬ ‫ﺁﺧﺮ‬ ‫ﻁﻔﻞ‬
m’
‫ﻣﻦ‬ ‫ﺃﻛﺒﺮ‬
m
‫ﺍﻟﻤﺴﺎﺭ‬ ‫ﻧﻔﺲ‬ ‫ﻋﻠﻰ‬
‫ﺍﻟﻤﺴﺎﻓﺔ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺗﺘﻐﻴﺮ‬ ‫ﻫﻞ‬
EI
.‫ﻋﻠﻞ‬ ‫؟‬
‫اﻟ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
‫ﺜﺎﻟﺚ‬
):
04
‫ﻧﻘ‬
‫ﺎ‬
(‫ط‬
2
-
N.m.Kg
11
-
G=6,67x10
.‫ﺍﻟﻜﻮﻧﻲ‬ ‫ﺍﻟﺘﺠﺎﺫﺏ‬ ‫ﺛﺎﺑﺖ‬
Km
3
R=9,38x10
‫ﺗﻮﺍﺑﻌﻪ‬ ‫ﺃﺣﺪ‬ ‫ﻭﻣﺮﻛﺰ‬ ‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﻛﻮﻛﺐ‬ ‫ﻣﺮﻛﺰ‬ ‫ﺑﻴﻦ‬ ‫ﺍﻟﺒﻌﺪ‬
)
P
(
Kg
23
=6,42x10
M
m
‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﻛﻮﻛﺐ‬ ‫ﻛﺘﻠﺔ‬
،
p
m
‫ﺍﻟﻤﺪﺭﻭﺱ‬ ‫ﺗﺎﺑﻌﻪ‬ ‫ﻛﺘﻠﺔ‬
.
=24h37min
M
T
‫ﻧﻔﺴﻪ‬ ‫ﺣﻮﻝ‬ ‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﻛﻮﻛﺐ‬ ‫ﺩﻭﺭ‬
‫ﻁﺒﻴﻌﻴﺎ‬ ‫ﻗﻤﺮﺍ‬ ‫ﻧﻌﺘﺒﺮ‬
)
P
(
‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﻟﻜﻮﻛﺐ‬ ‫ﺗﺎﺑﻌﺎ‬
‫ﺑﺴﺮﻋﺔ‬ ‫ﻣﻨﺘﻈﻤﺔ‬ ‫ﺩﺍﺋﺮﻳﺔ‬ ‫ﺑﺤﺮﻛﺔ‬ ‫ﺣﻮﻟﻪ‬ ‫ﻳﺪﻭﺭ‬
X
I
:‫ﻣﺪﺍﺭﻩ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﻄﺒﻴﻌﻲ‬ ‫ﺍﻟﻘﻤﺮ‬ ‫ﺗﻮﺍﺯﻥ‬ ‫ﺩﺭﺍﺳﺔ‬
1
-
‫ﺍﻟﺪﺍﺋ‬ ‫ﺍﻟﺤﺮﻛﺔ‬ ‫ﺗﻌﺮﻳﻒ‬ ‫ﺃﻋﻂ‬
.‫ﺍﻟﻤﻨﺘﻈﻤﺔ‬ ‫ﺮﻳﺔ‬
2
-
‫ﺑ‬
‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﻟﻜﻮﻛﺐ‬ ‫ﺍﻟﺘﺎﺑﻊ‬ ‫ﺍﻟﻄﺒﻴﻌﻲ‬ ‫ﺍﻟﻘﻤﺮ‬ ‫ﺗﺴﺎﺭﻉ‬ ‫ﻟﺸﻌﺎﻉ‬ ‫ﻭﺍﻻﺗﺠﺎﻩ‬ ‫ﻭﺍﻟﺤﺎﻣﻞ‬ ‫ﺍﻟﺘﺄﺛﻴﺮ‬ ‫ﻧﻘﻄﺔ‬ ‫ﻣﻨﺎﺳﺐ‬ ‫ﺑﺮﺳﻢ‬ ‫ﻴﻦ‬
3
-
‫ﺑﺪﻻﻟﺔ‬ ‫ﺍﻟﺘﺴﺎﺭﻉ‬ ‫ﺷﺪﺓ‬ ‫ﻋﺒﺎﺭﺓ‬ ‫ﺃﻋﻂ‬
X
،
r
4
-
‫ﻧﻴ‬ ‫ﻗﺎﻧﻮﻥ‬ ‫ﻁﺒﻖ‬
‫ﺍﻟﻤﺬﻛﻮﺭ‬ ‫ﺍﻟﻘﻤﺮ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﺜﺎﻧﻲ‬ ‫ﻮﺗﻦ‬
.
‫ﺃ‬
(
‫ﻫﻲ‬ ‫ﻣﺪﺍﺭﻩ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﻘﻤﺮ‬ ‫ﺳﺮﻋﺔ‬ ‫ﺃﻥ‬ ‫ﺍﺳﺘﻨﺘﺞ‬
r
m
G M
˜
X
‫ﺏ‬
(
‫ﺗﺮﺑﻂ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺍﻟﻌﻼﻗﺔ‬ ‫ﺃﻭﺟﺪ‬
v
،
r
‫ﻭ‬
P
T
‫ﺣﺮﻛﺔ‬ ‫)ﺩﻭﺭ‬
P
.(‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﻛﻮﻛﺐ‬ ‫ﺣﻮﻝ‬
‫ﺝ‬
(
‫ﺍﻟﻌﻼﻗﺔ‬ ‫ﺻﺤﺔ‬ ‫ﺑﺮﻫﻦ‬
3
2
13
3
2
10
22
,
9 

˜
u m
s
r
Tp
‫ﺩ‬
(
‫ﺍﻟﺪﻭﺭ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬
P
T
.
‫ﻩ‬
(
‫ﺍﻟﻤﺮﻳﺦ؟‬ ‫ﺑﻜﻮﻛﺐ‬ ‫ﻣﺘﺼﻠﺔ‬ ‫ﻟﻤﺤﻄﺔ‬ ‫ﺑﺎﻟﻨﺴﺒﺔ‬ ‫ﻣﺴﺘﻘﺮﺍ‬ ‫ﻳﻜﻮﻥ‬ ‫ﺣﺘﻰ‬ ‫ﺻﻨﺎﻋﻲ‬ ‫ﻗﻤﺮ‬ ‫ﻭﺿﻊ‬ ‫ﻳﺠﺐ‬ ‫ﻣﺴﺘﻮﻯ‬ ‫ﺃﻱ‬ ‫ﻓﻲ‬
‫ﻭ‬
(
‫ﺍﻟﺪﻭﺭ‬ ‫ﻫﻮ‬ ‫ﻣﺎ‬
S
T
‫ﺍﻟﺼﻨﺎﻋﻲ‬ ‫ﺍﻟﻘﻤﺮ‬ ‫ﻫﺬﺍ‬ ‫ﻟﺤﺮﻛﺔ‬
‫؟‬
e
n
c
y
-
e
d
u
c
a
t
i
o
n
.
c
o
m
/
e
x
a
m
s
2
2
(
‫ﻳﺼ‬
‫ﺗﺤﻘﻖ‬ .‫ﺃ‬
.‫ﺃ‬
‫ﺍ‬ .‫ﺏ‬
‫ﺍ‬ .‫ﺏ‬
‫ﺣ‬
‫ﺣ‬
‫ﻗﻴﻤ‬ ‫ﺣﺴﺐ‬
‫ﺣ‬
3
(
‫ﻳﻨﺰﻟﻖ‬
‫ﻳﻨﺰﻟﻖ‬
‫ﻛﺘ‬ ‫ﺁﺧﺮ‬ ‫ﻁﻔﻞ‬
‫ﺁﺧ‬ ‫ﻁﻔﻞ‬
‫اﻟ‬ ‫ﻦ‬
‫ﺜﺎﻟﺚ‬
‫ﺚ‬ ‫ﻟ‬
):
):
04
04
‫ﻧﻘ‬
‫ﻘ‬
‫ﻘﺎ‬
(‫ط‬
e
x
G=6,67x
G=6,6
‫ﺍﻟﺘﺠﺎﺫ‬ ‫ﺛﺎﺑﺖ‬
‫ﺛﺎﺑﺖ‬
‫ﺍﻟﻤﺮ‬ ‫ﻛﻮﻛﺐ‬ ‫ﻣﺮﻛﺰ‬ ‫ﺑﻴﻦ‬ ‫ﻌﺪ‬
‫ﻛﻮﻛﺐ‬ ‫ﻣﺮﻛﺰ‬ ‫ﻦ‬
‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﻛﻮﻛﺐ‬
‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﺐ‬
،
،
p
p
m
mp
p
p
‫ﻛﺘﻠﺔ‬
‫ﻧﻔﺴﻪ‬ ‫ﺣﻮﻝ‬ ‫ﺮﻳﺦ‬
‫ﻧﻔﺴﻪ‬ ‫ﺣﻮﻝ‬
‫ﻳﺦ‬
‫ﺩﺍ‬ ‫ﺑﺤﺮﻛﺔ‬ ‫ﺣﻮﻟﻪ‬ ‫ﻳﺪﻭﺭ‬
‫ﺣﻮﻟﻪ‬ ‫ﻭﺭ‬
‫ﺍﻟﺘ‬ ‫ﺍﻟﻄﺒﻴﻌﻲ‬ ‫ﺍﻟﻘﻤﺮ‬ ‫ﺗﺴﺎﺭﻉ‬
‫ﺍﻟﻄﺒﻴﻌ‬ ‫ﺍﻟﻘﻤﺮ‬ ‫ﺭﻉ‬
3as.ency-education.com
0
‫ﻣﻥ‬
8
0 8 ‫ﺍﻟﺻﻔﺣﺔ‬
‫اﳉﺰ‬
‫ء‬
‫اﻟﺜﺎﱐ‬
‫ﻋﻠﻰ‬ :
)
7
‫ﻧﻘﺎط‬
(
‫ـ‬‫ـ‬‫ـ‬‫ﻴ‬‫اﻟﻜﻤ‬ )
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
‫ـ‬‫ـ‬‫ـ‬‫ـ‬
‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬
(‫ﺎء‬
‫اﻟﺜﺎﻟﺚ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬
:
I
.
): ‫ﻛﺮﺑﻮﻛﺴﻴﻠﻲ‬ ‫ﻟﺤﻤﺾ‬ ‫ﺗﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺩﺭﺍﺳﺔ‬
04
( ‫ﻧﻘﺎﻁ‬
‫ﺍﻟﻤﻮﻟﻲ‬ ‫ﺗﺮﻛﻴﺰﻩ‬ ‫ﺍﻹﻳﺜﺎﻧﻮﻳﻚ‬ ‫ﻟﺤﻤﺾ‬ ‫ﻣﺤﻠﻮﻻ‬ ‫ﻧﻌﺘﺒﺮ‬
0
C
.
1
‫؟‬ ‫ﺍﻟﻤﺎء‬ ‫ﻣﻊ‬ ‫ﺍﻹﻳﺜﺎﻧﻮﻳﻚ‬ ‫ﺣﻤﺾ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺃﻛﺘﺐ‬ ‫ـ‬ (
2
‫ﻋﻦ‬ ‫ﻋﺒﺮ‬ ‫ـ‬ (
f
@
+
O
3
H

‫ﻭ‬
f
@
-
COO
3
CH

‫ﺑﺪﻻﻟﺔ‬
0
C
‫ﺍﻟﻨﻬﺎﺋﻴﺔ‬ ‫ﺍﻟﻨﺴﺒﺔ‬ ‫ﻭ‬
W
‫؟‬ ‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻟﺘﻘﺪﻡ‬
3
‫ﺇﺳﺘﻨﺘﺞ‬ ‫ـ‬ (
f
@
COOH
3
CH

‫ﺑﺪﻻﻟﺔ‬
0
C
‫ﻭ‬
W
‫؟‬
4
‫ﻟﻠﺜﻨﺎﺋﻴﺔ‬ ‫ﺍﻟﺤﻤﻮﺿﺔ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺃﻥ‬ ‫ﺑﻴﻦ‬ ‫ـ‬ (
τ
τ
-
1
C
=
K
2
0
A
5
‫ﻟـ‬ ‫ﻣﺨﺘﻠﻔﺔ‬ ‫ﻗﻴﻢ‬ ‫ﺃﺟﻞ‬ ‫ﻣﻦ‬ ‫ـ‬ (
0
C
‫ﻗﻴﻤﺔ‬ ‫ﺍﻟﻨﺎﻗﻠﻴﺔ‬ ‫ﻗﻴﺎﺱ‬ ‫ﻁﺮﻳﻖ‬ ‫ﻋﻦ‬ ‫ﻧﻌﻴﻦ‬
W
.
‫؟‬ ‫ﺍﻟﺘﺎﻟﻲ‬ ‫ﺍﻟﺠﺪﻭﻝ‬ ‫ﺃﻛﻤﻞ‬ ‫ـ‬ ‫ﺃ‬
‫ـ‬ ‫ﺏ‬
‫ﺍﻟﺒﻴﺎﻥ‬ ‫ﺃﺭﺳﻢ‬
y = f ( x )
‫؟‬
‫ﺠ‬
‫ﻗﻴﻤﺔ‬ ‫ﺇﺳﺘﻨﺘﺞ‬ ‫ـ‬
K
‫؟‬
II
.
‫ﺍﻻﺳﺘﺮ‬ ‫ﺻﻨﺎﻋﺔ‬
):
03
( ‫ﻧﻘﺎﻁ‬
‫ﻣﻦ‬ ‫ﻋﻠﻴﻬﺎ‬ ‫ﺍﻟﺤﺼﻮﻝ‬ ‫ﻳﻤﻜﻦ‬ .... ‫ﺍﻟﻐﺬﺍﺋﻴﺔ‬ ‫ﺍﻟﻤﻮﺍﺩ‬ ‫ﻓﻲ‬ ، ‫ﺍﻟﻤﻌﻄﺮﺍﺕ‬ ‫ﻓﻲ‬ : ‫ﺍﻟﻴﻮﻣﻴﺔ‬ ‫ﺣﻴﺎﺗﻨﺎ‬ ‫ﻓﻲ‬ ‫ﺗﻮﺟﺪ‬ ‫ﺍﻻﺳﺘﺮﺍﺕ‬
‫ﺍ‬
‫ﻟﻨﺒﺎﺕ‬
‫ﻛ‬
‫ﻳﻤﻜﻦ‬ ‫ﻤﺎ‬
‫ﺍﻟﻤﺨﺎﺑﺮ‬ ‫ﻓﻲ‬ ‫ﺇﺻﻄﻨﺎﻋﻬﺎ‬
‫ﻳﺼﻄﻨﻊ‬
‫ﺍﻻﺳﺘﺮ‬
‫ﻣ‬ . ( ‫ﺍﻟﻤﻴﺜﺎﻧﻮﻝ‬ ، ‫ﺍﻟﺒﻨﺰﻭﻳﻚ‬ ‫ﺣﻤﺾ‬ ) ‫ﻟﻠﺠﻤﻠﺔ‬ ‫ﻛﻴﻤﻴﺎﺋﻲ‬ ‫ﺗﺤﻮﻝ‬ ‫ﻣﻦ‬ ‫ﺇﻧﻄﻼﻗﺎ‬ ‫ﺩﺭﺍﺳﺘﻪ‬ ‫ﻧﺮﻳﺪ‬ ‫ﺍﻟﺬﻱ‬
‫ﺫﻟﻚ‬ ‫ﺃﺟﻞ‬ ‫ﻦ‬
‫ﻧﻤﺰﺝ‬
= 12.2 g
1
m
‫ﺣﺠﻢ‬ ‫ﻣﻊ‬ ‫ﺍﻟﺒﻨﺰﻭﻳﻚ‬ ‫ﺣﻤﺾ‬ ‫ﻣﻦ‬
= 30 mL
2
V
‫ﺍﻟﻤﺮﻛﺰ‬ ‫ﺍﻟﻜﺒﺮﻳﺖ‬ ‫ﺣﻤﺾ‬ ‫ﻣﻦ‬ ‫ﻗﻄﺮﺍﺕ‬ ‫ﺑﻮﺟﻮﺩ‬ ‫ﺍﻟﻤﻴﺜﺎﻧﻮﻝ‬ ‫ﻣﻦ‬
‫ﻟﻤﺪﺓ‬ ‫ﺍﻟﻤﺮﺗﺪ‬ ‫ﺑﺎﻟﺘﻘﻄﻴﺮ‬ ‫ﻧﺴﺨﻦ‬
60 min
‫ﺍﻟﺘﺒﺮﻳ‬ ‫ﺑﻌﺪ‬
‫ﺪ‬
‫ﺟﻠﻴ‬ + ‫ﻣﺎء‬ ) ‫ﻋﻠﻰ‬ ‫ﺗﺤﺘﻮﻱ‬ ‫ﺣﺒﺎﺑﺔ‬ ‫ﻓﻲ‬ ‫ﺍﻟﺒﺎﻟﻮﻧﺔ‬ ‫ﻣﺤﺘﻮﻯ‬ ‫ﻧﺴﻜﺐ‬
‫ﻋﻠﻰ‬ ‫ﻟﻨﺤﺼﻞ‬ ( ‫ﺪ‬
‫ﺍﻷﺧﻴﺮ‬ ‫ﻓﻲ‬ ‫ﻟﻨﺤﺼﻞ‬ ‫ﺍﻹﺳﺘﺮ‬ ‫ﻋﻠﻰ‬ ‫ﻳﺤﺘﻮﻱ‬ ‫ﺍﻟﺬﻱ‬ ‫ﺍﻟﻄﻮﺭ‬ ‫ﻧﻌﺰﻝ‬ . ‫ﻣﺨﺘﻠﻔﻴﻦ‬ ‫ﻁﻮﺭﻳﻦ‬
‫ﻛﺘﻠﺔ‬ ‫ﻋﻠﻰ‬
9.52 g
‫ﻣﻦ‬
‫ﺍﻻﺳﺘﺮ‬
.
: ‫ﺍﻟﻤﻌﻄﻴﺎﺕ‬
‫ﺍﻟﺤﺠﻤﻴﺔ‬ ‫ﺍﻟﻜﺘﻠﺔ‬
)
1
-
g.L
(
‫ﺍﻟﻤﻮﻟﻴﺔ‬ ‫ﺍﻟﻜﺘﻠﺔ‬
)
1
-
g.mol
(
‫ﺍﻟﺼﻴﻐﺔ‬
‫ﺍﻟﻜﻴﻤﻴﺎﺋﻲ‬ ‫ﺍﻟﻨﻮﻉ‬
1.3
122
COOH
5
H
6
C
‫ﺍﻟﺒﻨﺰﻭﻳﻚ‬ ‫ﺣﻤﺾ‬
0.80
32
OH
-
3
CH
‫ﺍﻟﻤﻴﺜﺎﻧﻮﻝ‬
1.1
136
‫ﺩﺭﺍﺳﺘﻪ‬ ‫ﻣﺮﺍﺩ‬ ‫ﺍﻻﺳﺘﺮ‬
1
‫ﺍﻟﺒﻨﺰﻭﻳﻚ‬ ‫ﻟﺤﻤﺾ‬ ‫ﺍﻟﻤﺎﺩﺓ‬ ‫ﻛﻤﻴﺔ‬ ‫ﻋﻴﻦ‬ ‫ـ‬
‫ﻭ‬
‫؟‬ ‫ﺍﻟﻤﺴﺘﻌﻤﻞ‬ ‫ﻟﻠﻤﻴﺜﺎﻧﻮﻝ‬ ‫ﺍﻟﻤﺎﺩﺓ‬ ‫ﻛﻤﻴﺔ‬
2
‫؟‬ ‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻟﺘﺴﺮﻳﻊ‬ ‫ﺃﺳﺘﻌﻤﻠﺖ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺍﻟﺤﺮﻛﻴﺔ‬ ‫ﺍﻟﻌﻮﺍﻣﻞ‬ ‫ﻋﻴﻦ‬ ‫ـ‬
3
‫؟‬ ‫ﺍﻟﻤﺮﺗﺪ‬ ‫ﺍﻟﺘﻘﻄﻴﺮ‬ ‫ﻣﻊ‬ ‫ﺍﻟﺘﺴﺨﻴﻦ‬ ‫ﺃﺳﺘﻌﻤﻞ‬ ‫ﻟﻤﺎﺫﺍ‬ ‫ـ‬
4
‫ﺇﺻﻄﻨﺎﻉ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺃﻛﺘﺐ‬ ‫ـ‬
‫ﺍﻻﺳﺘﺮ‬
‫؟‬
‫؟‬ ‫ﺍﺳﻤﻪ‬ ‫ﺍﻋﻂ‬
5
‫ـ‬
‫؟‬ ‫ﺍﻟﺘﺤﻮﻝ‬ ‫ﻫﺬﺍ‬ ‫ﺧﺼﺎﺋﺺ‬ ‫ﺍﻋﻂ‬
6
‫ﺛﻢ‬ ‫ﻋﺮﻑ‬ ‫ـ‬
‫؟‬ ‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻣﺮﺩﻭﺩ‬ ‫ﺃﺣﺴﺐ‬
4
-
10
u
5
3
-
10
u
1
3
-
10
u
5
2
-
10
u
1
( mol / L )
0
C
2
-
10
u
16
2
-
10
u
12.5
2
-
10
u
5.6
2
-
10
u
4
W
0
C
1
=
x
τ
τ
-
1
C
=
y
2
0
e
n
c
y
-
e
d
u
c
a
t
i
o
n
.
c
o
m
/
e
x
a
m
s
‫ﺃﻛ‬ ‫ـ‬ (
2
2
‫ﻋﺒﺮ‬ ‫ـ‬ (
‫ـ‬ (
3
3
‫ﺇﺳﺘﻨﺘﺞ‬ ‫ـ‬ (
‫ﺇﺳﺘﻨﺘ‬ ‫ـ‬ (
f
4
‫ﺍﻟﺤ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺃﻥ‬ ‫ﺑﻴﻦ‬ ‫ـ‬ (
‫ﺛﺎﺑ‬ ‫ﺃﻥ‬ ‫ﺑﻴﻦ‬ ‫ـ‬ (
‫ﻟـ‬ ‫ﻣﺨﺘﻠﻔﺔ‬ ‫ﻗﻴﻢ‬ ‫ﺃﺟﻞ‬ ‫ﻣﻦ‬ ‫ـ‬ (
‫ﻣﺨﺘﻠ‬ ‫ﻗﻴﻢ‬ ‫ﺃﺟﻞ‬ ‫ﻦ‬
‫؟‬ ‫ﺍﻟﺘﺎﻟﻲ‬ ‫ﺍﻟﺠﺪﻭﻝ‬ ‫ﺃﻛﻤﻞ‬ ‫ـ‬
‫ﺍﻟﺘﺎﻟ‬ ‫ﺍﻟﺠﺪﻭﻝ‬ ‫ﻤﻞ‬
‫ﻗﻴﻤﺔ‬ ‫ﺇﺳﺘﻨﺘﺞ‬
‫ﻗﻴﻤﺔ‬ ‫ﺞ‬
K
K
‫؟‬
‫؟‬
‫ﺍ‬ ‫ﺍﻟﻤﻮﺍﺩ‬ ‫ﻓﻲ‬ ، ‫ﻟﻤﻌﻄﺮﺍﺕ‬
‫ﺍﻟﻤﻮ‬ ‫ﻓﻲ‬ ، ‫ﺮﺍﺕ‬
‫ﺣﻤﺾ‬ ) ‫ﻟﻠﺠﻤﻠﺔ‬ ‫ﻛﻴﻤﻴﺎﺋﻲ‬ ‫ﻝ‬
‫ﺣﻤ‬ ) ‫ﻟﻠﺠﻤﻠﺔ‬ ‫ﻤﻴﺎﺋﻲ‬
2
V
V
‫ﺑﻮﺟ‬ ‫ﺍﻟﻤﻴﺜﺎﻧﻮﻝ‬ ‫ﻣﻦ‬
‫ﺍﻟﻤﻴﺜﺎﻧﻮﻝ‬ ‫ﻣﻦ‬
‫ﺗﺤﺘ‬ ‫ﺣﺒﺎﺑﺔ‬ ‫ﻓﻲ‬ ‫ﺍﻟﺒﺎﻟﻮﻧﺔ‬ ‫ﻮﻯ‬
‫ﺣﺒﺎﺑ‬ ‫ﻓﻲ‬ ‫ﻟﺒﺎﻟﻮﻧﺔ‬
‫ﺍﻷﺧﻴﺮ‬ ‫ﻓﻲ‬ ‫ﻞ‬
‫ﻷﺧﻴﺮ‬
‫ﻛﺘﻠﺔ‬ ‫ﻋﻠﻰ‬
‫ﻛﺘ‬ ‫ﻋﻠﻰ‬
g
‫ﻐﺔ‬
‫ﺍﻟﻨ‬
‫ﺍﻟ‬
u
c
u
c
u
c
u
c
u
c
u
c
u
c
u
c
u
c
u
c
u
c
C
‫ﺣﻤﺾ‬
‫ﺣ‬
d
u
d
u
u
u
u
u
u
u
u
u
u
u
‫ﺍﻟﻤﻴﺜﺎﻧﻮﻝ‬
‫ﺍﻟﻤﻴ‬
d
d
‫ﺩﺭﺍﺳ‬ ‫ﻣﺮﺍﺩ‬ ‫ﺍﻻﺳﺘﺮ‬
‫ﻣﺮ‬ ‫ﻻﺳﺘﺮ‬
e
d
e
d
-
e
-
e
4
-
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  • 1. 0 ‫ﻣﻥ‬ 8 0 1 ‫ﺍﻟﺻﻔﺣﺔ‬ ‫ﺍﻟﺸﻌﺒﻴﺔ‬ ‫ﺍﻟﺪﻳﻤﻘﺮﺍﻁﻴﺔ‬ ‫ﺍﻟﺠﺰﺍﺋﺮﻳﺔ‬ ‫ﺍﻟﺠﻤﻬﻮﺭﻳﺔ‬ ‫ﺍﻟﺘﺮﺑﻴﺔ‬ ‫ﻣﺪﻳﺮﻳﺔ‬ : : ‫ﻳﻮﻡ‬ : ‫ﺛﺎﻧﻮﻳﺔ‬ ‫ﺩ‬ ‫ﻭﺭﺓ‬ : ‫ﻣـــﺎﻱ‬ 2018 ‫ﺷﻌﺒﺔ‬ : ‫ﺭﻳﺎﺿﻲ‬ ‫ﺗﻘﻨﻲ‬ ‫ﺑﻜﺎﻟﻮﺭﻳﺎ‬ ‫ﺗﺠﺮﻳﺒﻲ‬ ‫ﺍﺧﺘﺒﺎﺭ‬ : ‫ﻣﺎﺩﺓ‬ ‫ﺍﻟﻔﻴﺰﻳﺎﺋﻴﺔ‬ ‫ﺍﻟﻌﻠﻮﻡ‬ : ‫ﺍﻟﻤﺪﺓ‬ 4 ‫ﺳــﺎﻋﺔ‬ ‫ﻭ‬ 30 ‫ﺩﻗﻴﻘﺔ‬ ‫ﺍﻻﻭﻝ‬ ‫ﺍﻟﻤﻮﺿﻮﻉ‬ ‫اﳉﺰ‬ ‫ء‬ ‫اﻻول‬ ‫ﻋﻠﻰ‬ : 13 ‫ﻳ‬‫ﺰ‬‫اﻟﻔﻴ‬ ) ‫ﻧﻘﻄﺔ‬ ‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬ (‫ﺎء‬ ): ‫اﻻول‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬ 04 ‫ﻧﻘ‬ ‫ﺎ‬ ‫ط‬ ( ‫ﻋﻠﻰ‬ ‫ﺗﺤﺘﻮﻱ‬ ‫ﺩﺍﺭﺍﺕ‬ ‫ﻣﻦ‬ ‫ﺗﺘﻜﻮﻥ‬ ‫ﺍﻟﻜﻬﺮﺑﺎﺋﻴﺔ‬ ‫ﺍﻻﺟﻬﺰﺓ‬ ‫ﺍﻥ‬ ‫ﺣﻴﺚ‬ ‫ﺍﻟﻀﺮﻭﺭﻳﺎﺕ‬ ‫ﺍﻫﻢ‬ ‫ﻣﻦ‬ ‫ﺣﺎﻟﻲ‬ ‫ﻭﻗﺘﻨﺎ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻜﻬﺮﺑﺎء‬ ‫ﺗﻌﺘﺒﺮ‬ ‫ﺛﻨﺎﺋﻲ‬ ‫ﻗﻄﺐ‬ - RC - RL - LC - ‫ﺍﻟﻘﻄﺐ‬ ‫ﺛﻨﺎﺋﻲ‬ ‫ﺳﻨﺪﺭﺱ‬ RC ‫ﻭ‬ LC ‫ﺍﻧﻈﺮ‬ ‫ﺍﻟﺸﻜﻞ‬ - 1 - : ‫ﺍﻟﺘﺮﻛﻴﺐ‬ ‫ﻓﻲ‬ ‫ﻣﺴﺘﻌﻤﻠﺔ‬ ‫ﻛﻬﺮﺑﺎﺋﻴﺔ‬ ‫ﻋﻨﺎﺻﺮ‬ ƒ ‫ﺗﻮﺗﺮﻩ‬ ‫ﺣﻘﻴﻘﻲ‬ ‫ﻣﻮﻟﺪ‬ E ‫ﺩﺍﺧﻠﻴﺔ‬ ‫ﻣﻘﺎﻭﻣﺘﻪ‬ r=20Ω . ƒ ‫ﺳﻌﺘﻬﻤﺎ‬ ‫ﻣﻜﺜﻔﺔ‬ C . ƒ ‫ﻣﻘﺎﻭﻣﺘﻪ‬ ‫ﺍﻭﻣﻲ‬ ‫ﻧﺎﻗﻞ‬ R=40Ω . ƒ ‫ﺫﺍﺗﻴﺘﻬﺎ‬ ‫ﻭﺷﻴﻌﺔ‬ L ‫ﺩﺍﺧﻠﻴﺔ‬ ‫ﻣﻘﺎﻭﻣﺘﻬﺎ‬ 0 r . I . ‫ﻗﻄﺐ‬ ‫ﺛﻨﺎﺋﻲ‬ ‫ﺩﺭﺍﺳﺔ‬ RC ): 02 ( ‫ﻧﻘﺎﻁ‬ ‫ﻧ‬ ‫ﻭﺿﻊ‬ ‫ﻓﻲ‬ ‫ﻗﺎﻁﻌﺔ‬ ‫ﻀﻊ‬ 1 : 1 ( ‫ﻣﻜﺜﻔﺔ‬ ‫ﺗﻮﺗﺮ‬ ‫ﻟﺘﻄﻮﺭﺍﺕ‬ ‫ﺍﻟﺘﻔﺎﺿﻠﻴﺔ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺍﻥ‬ ‫ﺑﻴﻦ‬ (t) c U : ‫ﻫﻮ‬ ௗ୙ୡሺ୲ሻ ୢ୲ ൅ ଵ ୖ஼ Ǥ …ሺ–ሻ ൌ ୉ ୖେ 2 ( ‫ﺷﻜﻞ‬ ‫ﻣﻦ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺣﻞ‬ ‫ﻳﻌﻄﻰ‬ : …ሺ–ሻ ൌ ሺͳ െ ‡஑୲ሻ ‫ﺛﻮﺍﺑﺖ‬ ‫ﻋﺒﺎﺭﺓ‬ ‫ﺍﻋﻂ‬ A ‫ﻭ‬ α ‫؟‬ ‫ﻛﻬﺮﺑﺎﺋﻴﺔ‬ ‫ﺩﺍﺭﺓ‬ ‫ﺛﻮﺍﺑﺖ‬ ‫ﺑﺪﻻﻟﺔ‬ 3 ( ‫ﺗﻄﻮﺭﺍﺕ‬ ‫ﻣﻨﺤﻨﻰ‬ ‫ﻣﻬﺒﻄﻲ‬ ‫ﺍﻫﺘﺰﺍﺯ‬ ‫ﺭﺍﺳﻢ‬ ‫ﻳﻌﻄﻰ‬ ‫ﺑﻴﻦ‬ ‫ﺗﻮﺗﺮ‬ ‫ﻣﻜﺜﻔﺔ‬ ‫ﻁﺮﻓﻲ‬ ‫ﺷﻜﻞ‬ - 2 - : ‫ﺍﻭﺟﺪ‬ ‫ﺍﻟﺒﻴﺎﻥ‬ ‫ﺑﺎﺳﺘﻐﻼﻝ‬ ƒ ‫ﻗﻴﻤﺔ‬ E ‫؟‬ ƒ ‫ﺩﺍﺭﺓ‬ ‫ﺯﻣﻦ‬ ‫ﺛﺎﺑﺖ‬ ‫ﻗﻴﻤﺔ‬ τ ‫؟‬ ƒ ‫ﻗﻴﻤﺔ‬ C=….. ‫؟‬ 4 ( ‫ﺗﻴﺎﺭ‬ ‫ﻋﺒﺎﺭﺓ‬ ‫ﺍﻋﻂ‬ i(t) . ‫ﺍﻻﺑﺘﺪﺍﺋﻴﺔ‬ ‫ﻗﻴﻤﺘﻪ‬ ‫ﻣﺎﻫﻲ‬ ‫؟‬ ‫ﺷﻛﻝ‬ – 1 - ‫ﺷﻛﻝ‬ – 2 - ‫ﺷﻛﻝ‬ – 3 - e n c y - e d u c a t i o n . c o m / e x a m s ‫اﳉﺰ‬ ‫اﳉﺰ‬ ‫ء‬ ‫ء‬‫ﺰ‬ ‫ﺰ‬ ‫ﺰ‬ ‫اﻻول‬ ‫اﻻول‬ : m s ): ‫اﻻول‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬ : ‫اﻻول‬ ‫ﻳﻦ‬‫ﺮ‬‫ﺘﻤ‬ 4 a m ‫ﺣ‬ ‫ﻭﻗﺘﻨﺎ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻜﻬﺮﺑﺎء‬ ‫ﻌﺘﺒﺮ‬ ‫ﻭ‬ ‫ﻓﻲ‬ ‫ﻜﻬﺮﺑﺎء‬ RL - - LC LC - ‫ﺛﻨ‬ ‫ﺳﻨﺪﺭﺱ‬ ‫ﺳﻨﺪﺭﺱ‬ ‫ﺍﻟﺘﺮﻛﻴ‬ ‫ﻓﻲ‬ ‫ﻣﺴﺘﻌﻤﻠﺔ‬ ‫ﺑﺎﺋﻴﺔ‬ ‫ﺍﻟﺘﺮﻛﻴ‬ ‫ﻓﻲ‬ ‫ﺴﺘﻌﻤﻠﺔ‬ ‫ﺗﻮﺗﺮﻩ‬ ‫ﻲ‬ ‫ﺗﺮﻩ‬ E E ‫ﺩﺍ‬ ‫ﻣﻘﺎﻭﻣﺘﻪ‬ ‫ﻣﻘﺎﻭ‬ C R=40 R . . ‫ﺩﺍﺧﻠﻴﺔ‬ 0 0 r r . . ( ‫ﻜﺜﻔﺔ‬ (t) ( c c U U ‫ﺘﺒﺎ‬ a 3as.ency-education.com
  • 2. 0 ‫ﻣﻥ‬ 8 0 2 ‫ﺍﻟﺻﻔﺣﺔ‬ II . ‫ﺍﻟﻘﻄﺐ‬ ‫ﺛﻨﺎﺋﻲ‬ ‫ﺩﺭﺍﺳﺔ‬ LC ): 02 ( ‫ﻧﻘﺎﻁ‬ ‫ﻭﺿﻊ‬ ‫ﺍﻟﻰ‬ ‫ﺍﻟﻘﺎﻁﻌﺔ‬ ‫ﻭﺿﻊ‬ ‫ﻧﻐﻴﺮ‬ ‫ﺍﻟﺪﺍﺋﻢ‬ ‫ﻟﻨﻈﺎﻡ‬ ‫ﻧﺼﻞ‬ ‫ﻋﻨﺪﻣﺎ‬ 2 ‫ﺍﺯﻣﻨﺔ‬ ‫ﻣﺒﺪﺍ‬ ‫ﻭﻧﻌﺘﺒﺮﻩ‬ t=0 s . 1 ( ‫ﺍﻟﺸﺤﻨﺔ‬ ‫ﻟﺘﻐﻴﺮﺍﺕ‬ ‫ﺗﻔﺎﺿﻠﻴﺔ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺍﻛﺘﺐ‬ q(t) ‫؟‬ ‫ﺩﺍﺭﺓ‬ ‫ﻓﻲ‬ 2 ( ‫؟‬ ‫ﺳﺒﺒﻪ‬ ‫ﻣﻦ‬ ‫؟‬ ‫ﺍﻻﻫﺘﺰﺍﺯ‬ ‫ﻧﻤﻂ‬ ‫ﻣﺎﻫﻮ‬ ‫ﺍﻟﺸﻜﻞ‬ ‫ﺣﺴﺐ‬ 3 ( : ‫ﺍﻭﺟﺪ‬ ‫ﺍﻟﺸﻜﻞ‬ ‫ﺣﺴﺐ‬ ƒ ‫ﺍﻟﺤﺮﻛﺔ‬ ‫ﺩﻭﺭ‬ ‫ﺷﺒﻪ‬ ‫ﻗﻴﻤﺔ‬ T . ƒ ‫ﺍﻟﻨﺒﺾ‬ ‫ﻗﻴﻤﺔ‬ ɘ . ƒ ‫ﺑ‬ ‫ﺈ‬ ‫ﻭﺷﻴﻌﺔ‬ ‫ﺫﺍﺗﻴﺔ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ ‫ﻣﺎﺩﺭﺳﺖ‬ ‫ﻋﻠﻰ‬ ‫ﻋﺘﻤﺎﺩ‬ L ‫اﻟ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬ ‫ﺜﺎﱐ‬ ): 05 ‫ﻧﻘ‬ ‫ﺎ‬ (‫ط‬ I . ‫ﻣﺎﺋﻠﺔ‬ ‫ﻁﺮﻳﻖ‬ ‫ﻋﻠﻰ‬ ‫ﻳﻨﺰﻟﻖ‬ ‫ﺟﺴﻢ‬ ‫ﺣﺮﻛﺔ‬ ‫ﺩﺭﺍﺳﺔ‬ ): 03 ( ‫ﻧﻘﺎﻁ‬ ‫ﺻﻠﺐ‬ ‫ﺟﺴﻢ‬ ‫ﻳﻨﺰﻟﻖ‬ (S) ‫ﻛﺘﻠﺘﻪ‬ m = 100g ‫ﻋﻠﻰ‬ ‫ﺑﺰﺍﻭﻳﺔ‬ ‫ﺍﻷﻓﻖ‬ ‫ﻋﻦ‬ ‫ﻣﺎﺋﻞ‬ ‫ﻣﺴﺘﻮ‬ ‫ﻁﻮﻝ‬ α = 20° ‫ﻭﻓﻖ‬ ‫ﺍﻟﻤﺤﻮﺭ‬ ‫ܤܣ‬ ሬሬሬሬሬԦ ) ‫ﺍﻧﻈﺮ‬ ‫ﺍﻟﻤﺘﻌﺎﻗﺐ‬ ‫ﺑﺎﻟﺘﺼﻮﻳﺮ‬ ‫ﻗﻤﻨﺎ‬ .( ‫ﺍﻟﺸﻜﻞ‬ ‫ﺑﺒﺮﻣﺠﻴﺔ‬ ‫ﺍﻟﻔﻴﺪﻳﻮ‬ ‫ﺷﺮﻳﻂ‬ ‫ﻭﻋﻮﻟﺞ‬ ‫ﺭﻗﻤﻴﺔ‬ ‫ﺑﻜﺎﻣﻴﺮﺍ‬ (Aviméca) ‫ﻋﻠﻰ‬ ‫ﻭﺗﺤﺼﻠﻨﺎ‬ ‫ﺍﻵﻟﻲ‬ ‫ﺍﻹﻋﻼﻡ‬ ‫ﺑﺠﻬﺎﺯ‬ ‫ﺍﻟﺒﻴﺎﻥ‬ ‫ﺭﺳﻢ‬ v=f(t) . 1 – :‫ﺍﻟﺒﻴﺎﻥ‬ ‫ﻋﻠﻰ‬ ‫ﺑﺎﻻﻋﺘﻤﺎﺩ‬ ‫ﺃ‬ – ‫ﺣﺮﻛﺔ‬ ‫ﻁﺒﻴﻌﺔ‬ ‫ﺑﻴﻦ‬ (S) . ‫ﺏ‬ – ‫ﻟﻠﺘﺴﺎﺭﻉ‬ ‫ﺍﻟﺘﺠﺮﻳﺒﻴﺔ‬ ‫ﺍﻟﻘﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ a . ‫ﺝ‬ – ‫ﺍﻟﺴﺮﻋﺔ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ 0 v ‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻓﻲ‬ t=0 . ‫ﺩ‬ – :‫ﺍﻟﻠﺤﻈﺘﻴﻦ‬ ‫ﺑﻴﻦ‬ ‫ﺍﻟﻤﻘﻄﻮﻋﺔ‬ ‫ﺍﻟﻤﺴﺎﻓﺔ‬ ‫ﺍﺣﺴﺐ‬ ) = 0,04s 1 t ‫ﻭ‬ = 0,08s 2 t .( 2 – :‫ﻣﻬﻤﻠﺔ‬ ‫ﺍﻻﺣﺘﻜﺎﻛﺎﺕ‬ ‫ﺃﻥ‬ ‫ﺑﻔﺮﺽ‬ ‫ﺃ‬ – ‫ﺍﻟﻌﺒﺎﺭﺓ‬ ‫ﺃﻭﺟﺪ‬ ‫ﻟﻨﻴﻮﺗﻦ‬ ‫ﺍﻟﺜﺎﻧﻲ‬ ‫ﺍﻟﻘﺎﻧﻮﻥ‬ ‫ﺑﺘﻄﺒﻴﻖ‬ ‫ﻟﻠﺘﺴﺎﺭﻉ‬ ‫ﺍﻟﺤﺮﻓﻴﺔ‬ 0 a .‫ﻗﻴﻤﺘﻪ‬ ‫ﺍﺣﺴﺐ‬ ‫ﺛﻢ‬ ‫ﺏ‬ – ‫ﺑﻴﻦ‬ ‫ﻗﺎﺭﻥ‬ 0 a ‫ﻭ‬ a ‫؟‬ 3 - ‫ﺳﺆﺍﻝ‬ ‫ﻣﻦ‬ 1 ‫ﺳﺆﺍﻝ‬ ‫ﻭ‬ 2 ‫ﺍﻟﻘﻮﺓ‬ ‫ﺷﺪﺓ‬ ‫ﺃﻭﺟﺪ‬ ݂ Ԧ .‫ﺍﻟﻤﺎﺋﻞ‬ ‫ﺍﻟﻤﺴﺘﻮﻱ‬ ‫ﻋﻠﻰ‬ ‫ﻟﻼﺣﺘﻜﺎﻛﺎﺕ‬ ‫ﺍﻟﻤﻨﻤﺬﺟﺔ‬ e n c y - e d u c a t i o n . c o m / e x a m s 3 3 ( ‫ﺣ‬ ƒ ƒ ‫ﻗﻴﻤ‬ ƒ ƒ ‫ﺍﻟﻨﺒﺾ‬ ‫ﻗﻴﻤﺔ‬ ‫ﻗﻴﻤ‬ ƒ ƒ ‫ﺑ‬ ‫ﺑ‬ ‫ﺈ‬ ‫ﺈ‬‫ﺑ‬ ‫ﺑ‬ ‫ﺑ‬ ‫ﻣ‬ ‫ﻋﻠﻰ‬ ‫ﻋﺘﻤﺎﺩ‬ ‫ﻋﻠ‬ ‫ﻋﺘﻤﺎﺩ‬ ‫ﺜﺎﱐ‬ ): ) 05 05 ‫ﻧﻘ‬ ‫ﻧﻘ‬ ‫ﺎ‬ ‫ﺎ‬‫ﻘ‬ ‫ﻘ‬ ‫ﻘ‬ (‫ط‬ (‫ط‬ e x ‫ﻁﺮﻳﻖ‬ ‫ﻋﻠﻰ‬ ‫ﻳﻨﺰﻟﻖ‬ ‫ﺟﺴﻢ‬ ‫ﺣﺮﻛﺔ‬ ‫ﻋﻠﻰ‬ ‫ﻳﻨﺰﻟﻖ‬ ‫ﺴﻢ‬ / e ‫ﺐ‬ (S ( ) S ‫ﻛﺘﻠﺘﻪ‬ ‫ﻛﺘﻠﺘﻪ‬ = 100g 100g ‫ﺑﺰﺍﻭﻳﺔ‬ ‫ﻷﻓﻖ‬ ‫ﺑﺰﺍﻭﻳﺔ‬ α = 20° 20° ‫ﺍﻟﻤﺘﻌﺎﻗﺐ‬ ‫ﺑﺎﻟﺘﺼﻮﻳﺮ‬ ‫ﻗﻤﻨﺎ‬ ‫ﺍﻟﻤﺘﻌ‬ ‫ﻟﺘﺼﻮﻳﺮ‬ ‫ﺑﺒﺮﻣﺠﻴﺔ‬ ‫ﻮ‬ ‫ﺠﻴﺔ‬ ‫ﻋﻠﻰ‬ ‫ﺼﻠﻨﺎ‬ ‫ﻠﻰ‬ 3as.ency-education.com
  • 3. 0 ‫ﻣﻥ‬ 8 0 3 ‫ﺍﻟﺻﻔﺣﺔ‬ II . ‫ﺍﻓﻘﻲ‬ ‫ﻁﺮﻳﻖ‬ ‫ﻋﻠﻰ‬ ‫ﺟﺴﻢ‬ ‫ﺣﺮﻛﺔ‬ ‫ﺩﺭﺍﺳﺔ‬ ): ‫ﺧﺸﻦ‬ 02 ( ‫ﻧﻘﺎﻁ‬ ‫ﻋﻠﻰ‬ ‫ﺣﺮﻛﺘﻪ‬ ‫ﺍﻟﺴﺎﺑﻖ‬ ‫ﺍﻟﺠﺴﻢ‬ ‫ﻳﻮﺍﺻﻞ‬ ‫ﺍﻟ‬ ‫ﻄﺮﻳﻖ‬ ‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻋﻨﺪ‬ ‫ﺍﻻﻓﻘﻲ‬ t= 0.12 s ‫ﻧﻘﻄﺔ‬ ‫ﻣﻦ‬ B ‫ﺍﻟﻨﻘﻄﺔ‬ ‫ﺍﻟﻰ‬ C 1 - ‫ﺍﻟﻨﻘﻄﺔ‬ ‫ﻋﻨﺪ‬ ‫ﺍﻟﺤﺮﻛﻴﺔ‬ ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﻫﻲ‬ ‫ﻛﻢ‬ B ‫؟‬ 2 - ‫؟‬ ‫ﺍﻟﻄﺮﻳﻖ‬ ‫ﻫﺬﺍ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﺠﺴﻢ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﻤﻄﺒﻘﺔ‬ ‫ﺍﻟﻘﻮﺓ‬ ‫ﻣﺜﻞ‬ 3 - ‫ﺍﻟﺘﺴﺎﺭﻉ‬ ‫ﻋﺒﺎﺭﺓ‬ ‫ﺍﻋﻂ‬ a ‫؟‬ 4 - ‫ﺍﻟﻨﻘﻄﺔ‬ ‫ﻋﻨﺪ‬ ‫ﻳﺘﻮﻗﻒ‬ ‫ﺍﻟﺠﺴﻢ‬ ‫ﺍﻥ‬ ‫ﻋﻠﻤﺖ‬ ‫ﺍﺫﺍ‬ C ‫؟‬ ‫ﻟﺬﻟﻚ‬ ‫ﺍﻻﺯﻣﺔ‬ ‫ﺍﻻﺣﺘﻜﺎﻙ‬ ‫ﻗﻮﺓ‬ ‫ﻗﻴﻤﺔ‬ ‫ﻣﺎﻫﻲ‬ :‫ﻳﻌﻄﻰ‬ 2 - g = 10 m.s ‫؛‬ sin 20° = 0,34 . ‫اﻟ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬ ‫ﺜﺎﻟﺚ‬ ): 04 ‫ﻧﻘ‬ ‫ﺎ‬ (‫ط‬ ‫ﺍﻟﻔﻮﺳﻔﻮﺭ‬ 32 15 P ‫ﺇﺷﻌﺎﻋﻪ‬ ‫ﻧﻤﻂ‬ ، ‫ﺍﻟﺰﺍﺋﺪﺓ‬ ‫ﺍﻟﺤﻤﺮﺍء‬ ‫ﺍﻟﻜﺮﻳﺎﺕ‬ ‫ﺧﻼﻳﺎ‬ ‫ﻟﺘﺨﺮﻳﺐ‬ ‫ﺍﻟﻄﺐ‬ ‫ﻓﻲ‬ ‫ﻳﺴﺘﻌﻤﻞ‬ ‫ﻣﺸﻊ‬ ‫ﻧﻈﻴﺮ‬ β ‫ﻋﻤﺮﻩ‬ ‫ﻧﺼﻒ‬ ‫ﺯﻣﻦ‬ ‫ﻭ‬ 1/2 14,3 t j . 1 - ‫ﺍﻟﺠﺴﻴﻢ‬ ‫ﻁﺒﻴﻌﺔ‬ ‫ﻫﻲ‬ ‫ﻣﺎ‬ β ‫ﺍﻟﻤﻨﺒﻌﺚ؟‬ 2 - ‫ﺍ‬ ‫ﺍﻹﺟﺎﺑﺔ‬ ‫ﺗﺒﺮﻳﺮ‬ ‫ﻣﻊ‬ ‫ﺍﻟﺤﺎﺩﺙ‬ ‫ﺍﻹﺷﻌﺎﻋﻲ‬ ‫ﺍﻟﺘﻔﻜﻚ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﻛﺘﺐ‬ :‫ﻳﻌﻄﻰ‬ .‫ﺍﻟﻤﺴﺘﻌﻤﻠﺔ‬ ‫ﺍﻟﻘﻮﺍﻧﻴﻦ‬ ‫ﺑﺬﻛﺮ‬ 14Si ، 15P ، 16S ، 17Cl . 3 - ‫ﻧ‬ ‫ﻛﺘﻠﺔ‬ ‫ﻋﻠﻰ‬ ‫ﺗﺤﺘﻮﻱ‬ ‫ﺍﻟﺼﻮﺩﻳﻮﻡ‬ ‫ﻓﻮﺳﻔﺎﺕ‬ ‫ﻣﻦ‬ ‫ﺟﺮﻋﺔ‬ ‫ﺍﻟﻮﺭﻳﺪ‬ ‫ﻓﻲ‬ ‫ﻟﻠﻤﺮﻳﺾ‬ ‫ﺤﻘﻦ‬ 8 0 10 m g ‫ﺍﻟﻔﻮﺳﻔﻮﺭ‬ ‫ﻣﻦ‬ 32 . ‫ﺃ‬ - ‫ﺍﻹﺑﺘﺪﺍﺋﻴﺔ‬ ‫ﺍﻷﻧﻮﻳﺔ‬ ‫ﻋﺪﺩ‬ ‫ﺃﺣﺴﺐ‬ 0 N ‫ﻟﻠﻔﻮﺳﻔﻮﺭ‬ 32 . ‫ﺏ‬ - ‫ﻋﺒﺎﺭﺓ‬ ‫ﺃﻛﺘﺐ‬ λ ‫ﺑﺪﻻﻟﺔ‬ 1/2 t ‫ﺑـ‬ ‫ﻗﻴﻤﺘﻪ‬ ‫ﺍﺣﺴﺐ‬ ‫ﺛﻢ‬ 1 s . ‫ﺟـ‬ - ‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻋﺮﻑ‬ ( ) A t ‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻋﻨﺪ‬ ‫ﺍﻟﻤﺸﻌﺔ‬ ‫ﻟﻠﻌﻴﻨﺔ‬ t ‫ﺑﻴﻦ‬ ‫ﺍﻟﻌﻼﻗﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ ‫ﻭ‬ ، ( ) A t ‫ﺍﻷﻧﻮﻳﺔ‬ ‫ﻋﺪﺩ‬ ‫ﻭ‬ ( ) N t ‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻓﻲ‬ t . ‫ﺩ‬ - ‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ 0 A .‫ﺍﻟﻤﺮﻳﺾ‬ ‫ﺗﻠﻘﺎﻫﺎ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺍﻟﻔﻮﺳﻔﻮﺭ‬ ‫ﻟﻌﻴﻨﺔ‬ ‫ﻫـ‬ - ‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﺍﺣﺴﺐ‬ 1 t ‫ﻋﺸﺮ‬ ‫ﻳﺴﺎﻭﻱ‬ ‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻓﻴﻬﺎ‬ ‫ﻳﺼﺒﺢ‬ ‫ﺍﻟﺘﻲ‬ ) 10 1 ( ‫ﺍﻟﻘﻴﻤﺔ‬ 0 A . 3 - ‫ﺃ‬ - ‫ﺃ‬ :‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻓﻲ‬ ‫ﺃﻧﻪ‬ ‫ﺛﺒﺖ‬ 1/2 t nt ‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻋﺒﺎﺭﺓ‬ ‫ﺗﻜﻮﻥ‬ ( ) A t :‫ﻳﻠﻲ‬ ‫ﻛﻤﺎ‬ 0 ( ) 2n A A t ‫ﺣﻴﺚ‬ ، 0 A . ‫ﺍﻹﺑﺘﺪﺍﺋﻲ‬ ‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻫﻮ‬ ‫ﺏ‬ - ‫ﺍﻟﻤﻨﺤﻨﻰ‬ ‫ﺃﺭﺳﻢ‬ ( ) A t ‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻗﻴﻢ‬ ‫ﺗﻤﺜﻴﻞ‬ ‫ﻣﻊ‬ ، ‫ﺍﻟﺤﺎﺳﺒﺔ‬ ‫ﺍﻵﻟﺔ‬ ‫ﺍﺳﺘﻌﻤﺎﻝ‬ ‫ﺩﻭﻥ‬ ( ) A t :‫ﻟﻠﺤﻈﺎﺕ‬ ‫ﺍﻟﻤﻮﺍﻓﻘﺔ‬ 1/2 t ، 1/2 2t ، 1/2 3t ، 1/2 4t . :‫ﺃﻓﻮﻏﺎﺩﺭﻭ‬ ‫ﻋﺪﺩ‬ :‫ﻳﻌﻄﻰ‬ 23 1 6,02 10 . A N mol u 3 - 4 4 - ‫ﻋﻠﻤ‬ ‫ﺍﺫﺍ‬ ‫ﺍﺫ‬ :‫ﻳﻌﻄﻰ‬ ‫ﻳﻌﻄﻰ‬ 2 - m.s ‫اﻟ‬ ‫ﻳﻦ‬‫ﺮ‬ ‫ﻟ‬ ‫ﺜﺎﻟﺚ‬ ‫ﻟﺜﺎﻟﺚ‬‫ﻟ‬ ): ): 04 04 ‫ﻧﻘ‬ ‫ﻧﻘ‬ ‫ﻘﺎ‬ (‫ط‬ x a 3 ‫ﻓﻲ‬ ‫ﻳﺴﺘﻌﻤﻞ‬ ‫ﻣﺸﻊ‬ ‫ﻧﻈﻴﺮ‬ ‫ﻓﻲ‬ ‫ﻳﺴﺘﻌﻤﻞ‬ ‫ﻣﺸﻊ‬ ‫ﻈﻴﺮ‬ β ‫ﺍﻟﻤﻨﺒﻌﺚ؟‬ ‫ﺍﻟﻤﻨﺒﻌﺚ؟‬ ‫ﺍﻹﺟ‬ ‫ﺗﺒﺮﻳﺮ‬ ‫ﻣﻊ‬ ‫ﺍﻟﺤﺎﺩﺙ‬ ‫ﻋﻲ‬ ‫ﺗﺒﺮﻳ‬ ‫ﻣﻊ‬ ‫ﺎﺩﺙ‬ ‫ﺗﺤ‬ ‫ﺍﻟﺼﻮﺩﻳﻮﻡ‬ ‫ﻓﻮﺳﻔﺎﺕ‬ ‫ﻣﻦ‬ ‫ﺍﻟﺼﻮ‬ ‫ﻮﺳﻔﺎﺕ‬ 32 . ‫ﺑﻴﻦ‬ ‫ﺍﻟﻌﻼﻗﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ ‫ﺑﻴﻦ‬ ‫ﺍﻟﻌﻼﻗﺔ‬ ‫ﺞ‬ ( ) ) A( ‫ﻤﺔ‬ 0 A A . ( ) A A( ‫ﺣﻴﺚ‬ ، ‫ﺣﻴﺚ‬ ، 0 0 A A ‫ﺍﻟﻨ‬ ‫ﻫﻮ‬ ‫ﻫ‬ :‫ﻟﻠﺤﻈﺎﺕ‬ ‫ﻘﺔ‬ :‫ﺤﻈﺎﺕ‬ 1/2 1/2 t t ، ، 1/2 1/2 2t 2 ، 2 3as.ency-education.com
  • 4. 0 ‫ﻣﻥ‬ 8 0 4 ‫ﺍﻟﺻﻔﺣﺔ‬ ‫اﳉﺰ‬ ‫ء‬ ‫اﻟﺜﺎﱐ‬ ‫ﻋﻠﻰ‬ : ) 7 ‫ﻧﻘﺎط‬ ( ‫ـ‬‫ـ‬‫ـ‬‫ﻴ‬‫اﻟﻜﻤ‬ ) ‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬ ‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬ ‫ـ‬‫ـ‬‫ـ‬‫ـ‬ ‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬ (‫ﺎء‬ ‫اﻟﺜﺎﻟﺚ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬ : ‫ﺍﻟﺪﺭﺟﺔ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﺤﺎﻟﻴﻞ‬ ‫ﻛﻞ‬ ‫ﺗﺆﺧﺬ‬ 25°C . ‫ﺍﻹﺟﻤﺎﻟﻴﺔ‬ ‫ﺍﻟﺠﺰﻳﺌﻴﺔ‬ ‫ﺻﻴﻐﺘﻪ‬ ‫ﻛﺮﺑﻮﻛﺴﻴﻠﻲ‬ ‫ﺣﻤﺾ‬ ‫ﺍﻹﻳﺒﻮﺑﺮﻭﻓﻴﻦ‬ ‫ܥ‬ଵଷ‫ܪ‬ଵ଼ܱଶ ‫ﺷﺒﻴﻪ‬ ،‫ﻟﻼﻟﺘﻬﺎﺑﺎﺕ‬ ‫ﺍﻟﻤﻀﺎﺩﺍﺕ‬ ‫ﻣﻦ‬ ‫ﻳﻌﺘﺒﺮ‬ ‫ﺩﻭﺍء‬ ، ‫ﺃﻛﻴﺎﺱ‬ ‫ﻓﻲ‬ ‫ﻣﺴﺤﻮﻕ‬ ‫ﺷﻜﻞ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﺼﻴﺪﺍﻟﻴﺎﺕ‬ ‫ﻓﻲ‬ ‫ﺍﻹﻳﺒﻮﺑﺮﻭﻓﻴﻦ‬ ‫ﻣﺴﺘﺤﻀﺮﺍﺕ‬ ‫ﺗﺒﺎﻉ‬ .‫ﻟﻠﺤﺮﺍﺭﺓ‬ ‫ﻭﻣﺨﻔﺾ‬ ‫ﻟﻶﻻﻡ‬ ‫ﻣﺴﻜﻦ‬ ،‫ﺑﺎﻷﺳﺒﺮﻳﻦ‬ ‫ﺍﻟﻤﻘﺪﺍﺭ‬ ‫ﺗﺤﻤﻞ‬ 200 mg ‫ﺑـ‬ ‫ﺍﻹﻳﺒﻮﺑﺮﻭﻓﻴﻦ‬ ‫ﻟﺤﻤﺾ‬ ‫ﻧﺮﻣﺰ‬ ‫ﺍﻟﻨﺸﺎﻁ‬ ‫ﻫﺬﺍ‬ ‫ﻛﻞ‬ ‫ﻓﻲ‬ .‫ﺍﻟﻤﺎء‬ ‫ﻓﻲ‬ ‫ﻳﺬﻭﺏ‬ ܴ‫ܪܱܱܥ‬ ‫ﺍﻟﻤﺮﺍﻓﻖ‬ ‫ﻭﻷﺳﺎﺳﻪ‬ ‫ﺑﺎﻟﺮﻣﺰ‬ ܴ‫ܱܱܥ‬ି :‫ﻳﻌﻄﻰ‬ . ‫ܯ‬ሺܴ‫ܪܱܱܥ‬ሻ ൌ ʹͲ͸݃Ȁ݉‫݈݋‬ . ): ‫ﻛﺮﺑﻮﻛﺴﻴﻠﻲ‬ ‫ﻟﺤﻤﺾ‬ ‫ﺗﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺩﺭﺍﺳﺔ‬ 03.5 ( ‫ﻧﻘﺎﻁ‬ ‫ﺍﻹﻳﺒﻮﺑﺮﻭﻓﻴﻦ‬ ‫ﻛﻴﺲ‬ ‫ﻣﺤﺘﻮﻯ‬ ‫ﻧﺬﻳﺐ‬ mg 200 ‫ﻣﺎﺋﻲ‬ ‫ﻣﺤﻠﻮﻝ‬ ‫ﻋﻠﻰ‬ ‫ﻓﻨﺤﺼﻞ‬ ‫ﻣﺎء‬ ‫ﺑﻪ‬ ‫ﺑﻴﺸﺮ‬ ‫ﻓﻲ‬ ‫ﺍﻟﺤﻤﺾ‬ ‫ﻣﻦ‬ 0 S ‫ﺍﻟﻤﻮ‬ ‫ﺗﺮﻛﻴﺰﻩ‬ ‫ﻟﻲ‬ 0 C ‫ﻭﺣﺠﻤﻪ‬ =500 ml 0 V . 1 – : ‫ﺃﻥ‬ ‫ﻣﻦ‬ ‫ﺗﺄﻛﺪ‬ = 0.002 mol/l 0 C . 2 – ‫ﻗﻴﺎﺱ‬ ‫ﺃﻋﻄﻰ‬ pH ‫ﺍﻟﻤﺤﻠﻮﻝ‬ 0 S ‫ﺍﻟﻘﻴﻤﺔ‬ pH =3,5 . ‫ﺃ‬ – ‫ﺗ‬ .‫ﻣﺤﺪﻭﺩ‬ ‫ﺍﻟﻤﺎء‬ ‫ﻣﻊ‬ ‫ﺍﻹﻳﺒﻮﺑﺮﻭﻓﻴﻦ‬ ‫ﺣﻤﺾ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﺃﻥ‬ ‫ﺍﻟﺘﻘﺪﻡ‬ ‫ﻝ‬ ّ‫ﺑﺠﺪﻭ‬ ‫ﺑﺎﺳﺘﻌﺎﻧﺘﻚ‬ ‫ﺤﻘﻖ‬ ‫ﺏ‬ – ‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻛﺴﺮ‬ ‫ﺍﻛﺘﺐ‬ r Q .‫ﻝ‬ ّ‫ﺍﻟﺘﺤﻮ‬ ‫ﻟﻬﺬﺍ‬ ‫ﺝ‬ – ‫ﻋﺒﺎﺭﺓ‬ ‫ﺃﻥ‬ ‫ّﻦ‬‫ﻴ‬‫ﺑ‬ r Q :‫ﺍﻟﺸﻜﻞ‬ ‫ﻋﻠﻰ‬ ‫ﺗﻜﺘﺐ‬ ‫ﺍﻟﺘﻮﺍﺯﻥ‬ ‫ﻋﻨﺪ‬ ܳ௥Ǥé௤ ൌ ௑೘ೌೣǤఛ೑ మ ௏బǤሺଵିఛ೑ሻ . ‫ﺣﻴﺚ‬ f τ ‫ﻭ‬ ‫ﻟﻠﺘﻔﺎﻋﻞ‬ ‫ﺍﻟﻨﻬﺎﺋﻲ‬ ‫ﺍﻟﺘﻘﺪﻡ‬ ‫ﻧﺴﺒﺔ‬ : max X ‫ﺑـ‬ ‫ﻋﻨﻪ‬ ‫ﻭﻳﻌﺒﺮ‬ ‫ﺍﻷﻋﻈﻤﻲ‬ ‫ﺍﻟﺘﻘﺪﻡ‬ : mol . ‫ﺩ‬ – ‫ﺍﻟﺘﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ K . II . ‫ﺍﻟﺘﺠﺎﺭﻱ‬ ‫ﺍﻟﺨﻞ‬ ‫ﺣﻤﻀﻴﺔ‬ ‫ﺩﺭﺟﺔ‬ ): 03.5 ( ‫ﻧﻘﺎﻁ‬ ‫ﺣﺠﻤﺎ‬ ‫ﻧﺄﺧﺬ‬ ، ‫ﺍﻟﻜﻴﺲ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﻤﺴﺠﻞ‬ ‫ﺍﻟﻤﻘﺪﺍﺭ‬ ‫ﺻﺤﺔ‬ ‫ﻣﻦ‬ ‫ﻟﻠﺘﺤﻘﻖ‬ =100 ml b V ‫ﻣﺎﺋﻲ‬ ‫ﻣﺤﻠﻮﻝ‬ ‫ﻣﻦ‬ b S ‫ﺍﻟﺼﻮﺩﻳﻮﻡ‬ ‫ﻟﻬﻴﺪﺭﻭﻛﺴﻴﺪ‬ ሺܰܽାሺƒ“ሻ ൅ ିሺƒ“ሻሻ ‫ﺍﻟﻤﻮﻟﻲ‬ ‫ﺗﺮﻛﻴﺰﻩ‬. =0.02 mol/l b C ‫ﻣﺎﺋﻲ‬ ‫ﻣﺤﻠﻮﻝ‬ ‫ﻋﻠﻰ‬ ‫ﻓﻨﺤﺼﻞ‬ ‫ﺍﻟﻜﻴﺲ‬ ‫ﻣﺤﺘﻮﻯ‬ ‫ﻛﻠﻴﺎ‬ ‫ﻓﻴﻪ‬ ‫ﻭﻧﺬﻳﺐ‬ S ‫ﻧﻌﺘﺒﺮ‬ ) ‫ﺍﻟﻤﺤﻠﻮﻝ‬ ‫ﺣﺠﻢ‬ ‫ﺃﻥ‬ S ‫ﻫﻮ‬ b V ‫ﻧﺄﺧﺬ‬ .( ml 20 ‫ﺍﻟﻤﺤﻠﻮﻝ‬ ‫ﻣﻦ‬ S ‫ﻭﻧﻀﻌﻪ‬ ‫ﺍﻟﻬﻴﺪﺭﻭﺟﻴﻦ‬ ‫ﻛﻠﻮﺭ‬ ‫ﺣﻤﺾ‬ ‫ﺑﻤﺤﻠﻮﻝ‬ ‫ﻭﻧﻌﺎﻳﺮﻩ‬ ‫ﺑﻴﺸﺮ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﻮﻟﻲ‬ ‫ﺗﺮﻛﻴﺰﻩ‬ = 0.02 mol/l a C ‫ﺍﻟﻤﻨﺤﻨﻰ‬ ‫ﻋﻠﻰ‬ ‫ﻓﻨﺤﺼﻞ‬ ‫ﺍﻟﺒﻴﺎﻧﻲ‬ ‫ﺍﻟﺸﻜﻞ‬ – 9 :‫ﻫﻲ‬ ‫ﺍﻟﻤﻌﺎﻳﺮﺓ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ، ‫ܪ‬ଷܱାሺܽ‫ݍ‬ሻ ൅‫ܱܪ‬ିሺܽ‫ݍ‬ሻ ൌʹ‫ܪ‬ଶܱሺℓሻ . 1 – .‫ﺍﻟﻤﻌﺎﻳﺮﺓ‬ ‫ﻋﻤﻠﻴﺔ‬ ‫ﺗﺨﻄﻴﻄﻲ‬ ‫ﺑﺸﻜﻞ‬ ‫ﺍﺭﺳﻢ‬ 2 – ‫ﺍﻟﻨﻘﻄﺔ‬ ‫ﻫﺬﻩ‬ ‫ﺇﺣﺪﺍﺛﻴﺘﻲ‬ ‫ﺣﺪﺩ‬ ّ‫ﻢ‬‫ﺛ‬ ،‫ﺍﻟﺘﻜﺎﻓﺆ‬ ‫ﻧﻘﻄﺔ‬ ‫ﻑ‬ّ‫ﻋﺮ‬ E . 3 – ‫ﻟﺸﻮﺍﺭﺩ‬ ‫ﺍﻟﻤﺎﺩﺓ‬ ‫ﻛﻤﻴﺔ‬ ‫ﺟﺪ‬ ‫ܱܪ‬ି ሺܽ‫ݍ‬ሻ .‫ﻣﻌﺎﻳﺮﺗﻬﺎ‬ ‫ﺗﻤﺖ‬ ‫ﺍﻟﺘﻲ‬ 4 – ‫ﺟﺪ‬ ‫ﻟﺸﻮﺍﺭﺩ‬ ‫ﺍﻷﺻﻠﻴﺔ‬ ‫ﺍﻟﻤﺎﺩﺓ‬ ‫ﻛﻤﻴﺔ‬ ‫ܱܪ‬ି ሺܽ‫ݍ‬ሻ ‫ﺍﻟﺤﻤﺾ‬ ‫ﻣﻊ‬ ‫ﺗﻔﺎﻋﻠﺖ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺗﻠﻚ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ ‫ﺛﻢ‬ ، RCOOH .‫ﺍﻟﻜﻴﺲ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﺘﻮﺍﺟﺪ‬ 5 – ‫ﺍﺣﺴﺐ‬ m .‫ﺍﻟﻜﻴﺲ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﺘﻮﺍﺟﺪﺓ‬ ‫ﺍﻟﺤﻤﺾ‬ ‫ﻛﺘﻠﺔ‬ ‫ﺗﺴﺘﻨﺘﺞ؟‬ ‫ﻣﺎﺫﺍ‬ e n c y - e d u c a t i o n . c o m / e x a m s ‫ﺑﺎﻷﺳ‬ ‫ﺍ‬ ‫ﺗﺤﻤﻞ‬ ‫ﺗ‬ ‫ﺑﺎﻟﺮﻣﺰ‬ ‫ﺑﺎﻟﺮﻣ‬ ܱି ‫ﻟﺤﻤ‬ ‫ﺗﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺩﺭﺍﺳﺔ‬ ‫ﺗﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺭﺍﺳﺔ‬ m ‫ﻛﻴﺲ‬ ‫ﻣﺤﺘﻮﻯ‬ ‫ﻧﺬﻳﺐ‬ ‫ﻣﺤﺘﻮﻯ‬ ‫ﻧﺬﻳﺐ‬ 0 0 C C ‫ﻭﺣﺠﻤﻪ‬ ‫ﻭﺣﺠﻤﻪ‬ 0 ml – : ‫ﺃﻥ‬ ‫ﻣﻦ‬ ‫ﺗﺄﻛﺪ‬ : ‫ﺃﻥ‬ ‫ﻣﻦ‬ ‫ﻛﺪ‬ mol/l ‫ﻗﻴﺎﺱ‬ ‫ﻄﻰ‬ ‫ﻗﻴﺎﺱ‬ pH pH ‫ﺍﻟﻤﺤﻠﻮﻝ‬ ‫ﺍﻟﻤﺤﻠﻮﻝ‬ ‫ﺍﻟﺘﻘﺪﻡ‬ ‫ﻝ‬ ‫ﺍﻟ‬ ‫ﺑﺠﺪﻭﻝ‬ ‫ﺑﺎﺳﺘﻌﺎﻧﺘﻚ‬ ‫ﺑﺠﺪﻭ‬ ‫ﻌﺎﻧﺘﻚ‬ ّّ ‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﺮ‬ ‫ﻋﻞ‬ r r Q Q ‫ﺍﻟﺘﺤﻮ‬ ‫ﻟﻬﺬﺍ‬ ‫ﺍﻟ‬ ‫ﻟﻬﺬﺍ‬ ‫ﻋﻠﻰ‬ ‫ﺗﻜﺘﺐ‬ ‫ﺍﻟﺘﻮﺍﺯﻥ‬ ‫ﻋﻨﺪ‬ ‫ﺗﻜﺘﺐ‬ ‫ﺘﻮﺍﺯﻥ‬ ‫ﻭ‬ ‫ﻟﻠﺘﻔﺎﻋﻞ‬ ‫ﻲ‬ ‫ﻋﻞ‬ max max Xm ‫ﺍﻟﺘﻘ‬ : ‫ﺣﺠﻤﺎ‬ =100 ml =100 m b b V V ‫ﻣ‬ ‫ﻣﻦ‬ ‫ﻣﻦ‬ = b C ‫ﺮ‬ .‫ﺍﻟﻜﻴﺲ‬ ‫ﺲ‬ 3as.ency-education.com
  • 5. 0 ‫ﻣﻥ‬ 8 0 5 ‫ﺍﻟﺻﻔﺣﺔ‬ ‫ﺍﻟﺜﺎﻧﻲ‬ ‫ﻣﻮﺿﻮﻉ‬ ‫اﳉﺰ‬ ‫ء‬ ‫اﻻول‬ : ‫ﻋﻠﻰ‬ 13 ‫ﻧﻘﻄﺔ‬ ‫ﻳ‬‫ﺰ‬‫اﻟﻔﻴ‬ ) ‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬ (‫ﺎء‬ ‫اﻟ‬ ‫اﻻول‬ ‫ﻳﻦ‬‫ﺮ‬‫ﺘﻤ‬ : ) 04 (‫ﻧﻘﻄﺔ‬ I . ): ‫ﻣﻜﺜﻔﺔ‬ ‫ﻭﺗﻔﺮﻳﻎ‬ ‫ﺷﺤﻦ‬ ‫ﺩﺭﺍﺳﺔ‬ 03 ( ‫ﻧﻘﺎﻁ‬ ‫ﺳﻌﺘﻬﺎ‬ ‫ﻣﻜﺜﻔﺔ‬ C ) ‫ﺛﺎﺑﺖ‬ ‫ﺗﻮﺗﺮ‬ ‫ﺗﺤﺖ‬ ‫ﺷﺤﻨﻬﺎ‬ ‫ﺗﻢ‬ E = 12V ‫ﺛﻢ‬ . ( ‫ﻣﻘﺎﻭﻣﺘﻪ‬ ‫ﺃﻭﻣﻲ‬ ‫ﻧﺎﻗﻞ‬ ‫ﻓﻲ‬ ‫ﺗﻔﺮﻳﻐﻬﺎ‬ ‫ﺃﻋﻴﺪ‬ : 5 R = 10 . 1 - / ‫ﺍﻟﻘﺎﻁﻌﺔ‬ ‫ﻧﻌﺘﺒﺮ‬ ) ‫ﻭﺿﻊ‬ ‫ﻓﻲ‬ 1 ( ‫ﺣﻘﻴﻘﻲ‬ ‫ﺑﻞ‬ ‫ﻣﺜﺎﻟﻲ‬ ‫ﻟﻴﺲ‬ ‫ﻭﺍﻟﻤﻮﻟﺪ‬ ) Ω r=10 ( . 1 - 1 ‫ﻟﺘﻮﺗﺮ‬ ‫ﺍﻟﺘﻔﺎﺿﻠﻴﺔ‬ ‫ﺍﻟﻤﻌﺎﺩﻟﺔ‬ ‫ﺍﻋﻂ‬ ‫ﺗﻮﺗﺮﺍﺕ‬ ‫ﻗﺎﻧﻮﻥ‬ ‫ﺑﺎﺳﺘﻌﻤﺎﻝ‬ Uc ‫؟‬ ‫ﺍﻟﻤﻜﺜﻔﺔ‬ ‫ﻁﺮﻓﻲ‬ ‫ﺑﻴﻦ‬ 1 - 2 ‫ﻋﻨﺪ‬ t=0 ‫ﺍﻟﺘﻴﺎﺭ‬ ‫ﺷﺪﺓ‬ ‫ﺗﻜﻮﻥ‬ ‫ﻛﻢ‬ 0 I ‫؟‬ ‫ﺩﺍﺭﺓ‬ ‫ﻓﻲ‬ 2 - / ) ‫ﻭﺿﻊ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻘﺎﻁﻌﺔ‬ ‫ﻧﻌﺘﺒﺮ‬ 2 ‫ﺍﻟﺴﺎﺑﻖ‬ ‫ﺍﻟﺸﻜﻞ‬ ‫ﻓﻲ‬ ( . 2 - 1 ‫ﺑﺪﻻﻟﺔ‬ ‫ﻟﻠﺪﺍﺭﺓ‬ ‫ﺍﻟﺘﻔﺎﺿﻠﻴﺔ‬ ‫ﺍﻟﻤﻌﺎﺩﻟﺔ‬ ‫ﺃﻛﺘﺐ‬ q ( t ) ‫؟‬ ‫ﺍﻟﺘﻔﺮﻳﻎ‬ ‫ﺧﻼﻝ‬ 2 - 2 ‫ﻫﻮ‬ ‫ﺣﻠﻬﺎ‬ ‫ﺃﻥ‬ ‫ﺑﻴﻦ‬ W t/ - e 0 = Q q( t ) ‫؟‬ 2 - 3 ‫؟‬ ‫ﺍﻟﺰﻣﻦ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺑﻴﺎﻧﻴﺎ‬ ‫ﻋﻴﻦ‬ 2 - 4 ‫ﺍﻟﻤﻜﺜﻔﺔ‬ ‫ﺳﻌﺔ‬ ‫ﺃﺣﺴﺐ‬ C ‫؟‬ 6 ‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻋﻨﺪ‬ ‫ﺍﻟﻤﻜﺜﻔﺔ‬ ‫ﺷﺤﻨﺔ‬ ‫ﺃﺣﺴﺐ‬ ‫ـ‬ ( t = 0 ‫؟‬ 7 ‫ﺃ‬ ‫ـ‬ ( ‫ﺍﻟﻠﺤﻈ‬ ‫ﻧﻔﺲ‬ ‫ﻋﻨﺪ‬ ‫ﺍﻟﺘﻴﺎﺭ‬ ‫ﺷﺪﺓ‬ ‫ﺣﺴﺐ‬ ‫ﺔ‬ ‫؟‬ ‫ﺩﺭﺍﺳﺔ‬ ‫ﺍﻟﻬﻴﺪﺭﻭﺟﻴﻦ‬ ‫ﻧﻈﺎﺋﺮ‬ ‫ﻧﻮﺍﺗﻲ‬ ‫ﺍﻧﺪﻣﺎﺝ‬ ): 02 ( ‫ﻧﻘﺎﻁ‬ ‫ﺗﻘﺎﺭﺏ‬ ‫ﺍﻟﻨﺠﻮﻡ‬ ‫ﻫﺬﻩ‬ ‫ﺣﺮﺍﺭﺓ‬ ‫ﺩﺭﺟﺔ‬ ‫ﺗﻜﻮﻥ‬ ‫ﻋﻨﺪﻣﺎ‬ . ‫ﺍﻟﻬﻴﺪﺭﻭﺟﻴﻦ‬ ‫ﻣﻦ‬ ‫ﺃﺳﺎﺳﺎ‬ ‫ﺗﺘﻜﻮﻥ‬ ‫ﺍﻟﺸﻤﺲ‬ ‫ﻣﺜﻞ‬ ‫ﺍﻟﺼﻔﺮﺍء‬ ‫ﺍﻟﻨﺠﻮﻡ‬ K 7 10 5 . 1 u ‫ﺗﺤﺪﺙ‬ ‫ﺍﻧﺪﻣﺎﺝ‬ ‫ﺗﻔﺎﻋﻼﺕ‬ ‫ﻧﻮﺍﺓ‬ ‫ﻓﺘﻌﻄﻲ‬ ‫ﺍﻟﺒﺮﻭﺗﻮﻧﺎﺕ‬ ‫ﺑﻴﻦ‬ Y A Z / / : ‫ﺍﻟﺘﺎﻟﻴﺔ‬ ‫ﺍﻟﺴﻠﺴﻠﺔ‬ ‫ﺣﺴﺐ‬ ) 3 ........( 2 ) 2 .....( .......... ) 1 .......( .......... 1 1 / / 3 2 3 2 3 2 1 1 0 1 1 1 1 1 H Y H H H X H e X H H A Z e e e A Z A Z o o o J 1 / - ‫ﺍﻧ‬ ‫ﺍﻟﻨﻮﺍﺗﻴﻦ‬ ‫ﻋﻠﻰ‬ ‫ﺗﻌﺮﻑ‬ ‫ﺍﻟﻤﻌﺎﺩﻻﺕ‬ ‫ﻫﺬﻩ‬ ‫ﻣﻦ‬ ‫ﻄﻼﻗﺎ‬ Y ‫ﻭ‬ X A Z A Z / / 2 / - ‫ﺍﻛ‬ ‫ﺍﻟﻨﻮﺍﺓ‬ ‫ﻟﺘﺸﻜﻞ‬ ‫ﺍﻹﺟﻤﺎﻟﻲ‬ ‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺘﺐ‬ Y A Z / / ‫ﺍﻻﻧﺪﻣﺎﺝ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻋﺮﻑ‬ . ‫ﺍﻟﻬﻴﺪﺭﻭﺟﻴﻦ‬ ‫ﺍﻧﻮﻳﺔ‬ ‫ﻣﻦ‬ ‫ﺍﻧﻄﻼﻗﺎ‬ . 3 / - ‫ﺗﻔﺎ‬ ‫ﺍﻻﻥ‬ ‫ﻧﻌﺘﺒﺮ‬ : ‫ﺍﻟﺘﺎﻟﻲ‬ ‫ﺍﻻﻧﺪﻣﺎﺝ‬ ‫ﻋﻞ‬ J 2 2 4 0 1 4 2 1 1 o e H H e ‫ﺃ‬ - ‫ﺍﻟﻜﺘﻠﺔ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻨﻘﺺ‬ ‫ﺍﺣﺴﺐ‬ ‫ﻟ‬ ‫ﻠﺘﻔﺎﻋﻞ‬ ‫ﺍ‬ ‫ﻧﻜﻠﻴﻮﻥ‬ ‫ﻟﻜﻞ‬ ‫ﺍﻟﻤﺤﺮﺭﺓ‬ ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ ‫ﻭ‬ ‫ﺍﻟﻤﺤﺮﺭﺓ‬ ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﺛﻢ‬ ‫ﺍﻻﻧﺪﻣﺎ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﺛﻨﺎء‬ ‫ﻫﺬﺍ‬ ‫ﺝ‬ ‫ﺑـ‬ Mev . ‫ﺏ‬ - ‫ﺍﻟﻤﺤﺮ‬ ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﺍﺣﺴﺐ‬ ‫ﻋﻠﻰ‬ ‫ﻟﻠﺤﺼﻮﻝ‬ ‫ﺭﺓ‬ 1g ‫ﺍﻟﻬﻠﻴﻮﻡ‬ ‫ﻣﻦ‬ 4 ‫ﺑـ‬ Mev ‫ﺑـ‬ ‫ﺛﻢ‬ ‫ﺍﻟﺠﻮﻝ‬ ‫ﺑـ‬ ، (T.e.p) ‫ﺍﻟﺒﺘﺮﻭﻝ‬ ‫ﻣﻦ‬ ‫ﺍﻟﻤﻜﺎﻓﺊ‬ ‫)ﺍﻟﻄﻦ‬ (T.e.p) ‫ﺍﻟﺼﻨﺎﻋﺔ‬ ‫ﻣﺠﺎﻝ‬ ‫ﻓﻲ‬ ‫ﺗﺴﺘﻌﻤﻞ‬ ، ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﻟﻘﻴﺎﺱ‬ ‫ﻭﺣﺪﺓ‬ ‫ﻫﻲ‬ ( e n c y - e d u c a t i o n . c o m / e x a m s I ‫ﺳﻌ‬ ‫ﻣﻜﺜﻔﺔ‬ ‫ﻣﻜﺜﻔﺔ‬ ‫ﻓﻲ‬ ‫ﺗﻔﺮﻳﻐﻬﺎ‬ ‫ﺃﻋﻴﺪ‬ ‫ﺗﻔﺮﻳﻐ‬ ‫ﺃﻋﻴﺪ‬ 1 - / / ‫ﺍﻟﻘﺎﻁﻌﺔ‬ ‫ﻧﻌﺘﺒﺮ‬ ‫ﺍﻟﻘﺎﻁ‬ ‫ﻌﺘﺒﺮ‬ ‫ﻓﻲ‬ Ω r=10 r= ( ( . . ‫ﺍ‬ ‫ﺗﻮﺗﺮﺍﺕ‬ ‫ﻗﺎﻧﻮﻥ‬ ‫ﺳﺘﻌﻤﺎﻝ‬ ‫ﺗﻮﺗﺮ‬ ‫ﻗﺎﻧﻮﻥ‬ ‫ﺎﻝ‬ ‫؟‬ ‫ﻤﻜﺜﻔﺔ‬ ‫ﺍﻟﺘﻴﺎﺭ‬ ‫ﺷﺪﺓ‬ ‫ﺗﻜﻮﻥ‬ ‫ﺍﻟﺘﻴﺎﺭ‬ ‫ﺷﺪﺓ‬ ‫ﻥ‬ 0 0 I I ‫ﺩ‬ ‫ﻓﻲ‬ ) ‫ﺿﻊ‬ ) 2 2 ‫ﺍﻟﺴﺎﺑﻖ‬ ‫ﺍﻟﺸﻜﻞ‬ ‫ﻓﻲ‬ ( ‫ﺍ‬ ‫ﺍﻟﺸﻜﻞ‬ ‫ﻓﻲ‬ ( ‫ﺑﺪﻻﻟﺔ‬ ‫ﻟﻠﺪﺍﺭﺓ‬ ‫ﺑﺪﻻﻟﺔ‬ ‫ﺭﺓ‬ q ( t ) q ( t ) ‫ﺧﻼ‬ q( ‫؟‬ ‫؟‬ ‫ﺍﻟﻨﺠ‬ ‫ﻫﺬﻩ‬ ‫ﺣﺮﺍﺭﺓ‬ ‫ﺩﺭﺟﺔ‬ ‫ﻮﻥ‬ ‫ﺣﺮﺍﺭﺓ‬ ‫ﺭﺟﺔ‬ ....... .......... ........ 0 0 1e e X X A X Z Z o ‫ﺍﻻﻧﺪﻣﺎﺝ‬ ‫ﺝ‬ . . ‫ﻫﺬﺍ‬ ‫ﺝ‬ ‫ﺑـ‬ ‫ﺑـ‬ M Mev ev . 3as.ency-education.com
  • 6. 0 ‫ﻣﻥ‬ 8 0 6 ‫ﺍﻟﺻﻔﺣﺔ‬ ‫ﺝ‬ - ‫ﺍ‬ ‫؟‬ ‫ﺗﺴﺘﻨﺘﺞ‬ ‫ﻣﺎﺫﺍ‬ . ‫ﺍﻟﻄﺎﻗﺔ‬ ‫ﻧﻔﺲ‬ ‫ﺗﺤﺮﺭ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺍﻟﺒﺘﺮﻭﻝ‬ ‫ﻛﺘﻠﺔ‬ ‫ﺣﺴﺐ‬ e H 4 2 e H 3 2 H 2 1 H 1 1 e 0 1 ‫ﺍﻟﻨﻮﺍﺓ‬ 4.0015 3.0149 2.0134 1.0073 0.0006 ) (u m X A Z 2 Kg = 931.5Mev/c 27 - u = 1.661.10 1 1 - mol 23 =6.02 . 10 A N , J 13 - 10 . Mev = 1.6 1 , J 9 T.e.p = 42 10 1 ): ‫اﻟﺜﺎﱐ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬ 05 (‫ﻧﻘﻄﺔ‬ I . ‫ﺩﺭﺍﺳﺔ‬ ‫ﺣﺮﻛﺔ‬ ‫ﻁﻔﻞ‬ ‫ﻣﺎﺋﻠﺔ‬ ‫ﻁﺮﻳﻖ‬ ‫ﻋﻠﻰ‬ ‫ﻳﻨﺰﻟﻖ‬ : ) 02 ( ‫ﻧﻘﺎﻁ‬ ‫ﻋﻄﺎﻟﺘﻪ‬ ‫ﻣﺮﻛﺰ‬ ‫ﻁﻔﻞ‬ ‫ﻳﻨﺰﻟﻖ‬ G ‫ﻭﻛﺘﻠﺘﻪ‬ m ‫ﺟﺰء‬ ‫ﻣﻦ‬ ‫ﻣﻜﻮﻧﺔ‬ ‫ﻣﺴﺒﺢ‬ ‫ﻣﺰﻟﻘﺔ‬ ‫ﻓﻮﻕ‬ AB ‫ﺑﺰﺍﻭﻳﺔ‬ ‫ﺍﻷﻓﻖ‬ ‫ﻋﻦ‬ ‫ﻣﺎﺋﻞ‬ ‫ﻣﺴﺘﻮ‬ α ‫ﻭﺟﺰء‬ BC ‫ﻣﺴﺘﻮ‬ ‫ﺍﻻﺭﺗﻔﺎﻉ‬ ‫ﻋﻠﻰ‬ ‫ﻳﻮﺟﺪ‬ ‫ﺃﻓﻘﻲ‬ h ‫ﺍﻟﺸﻜﻞ‬ ) ‫ﺍﻟﻤﺴﺒﺢ‬ ‫ﻣﺎء‬ ‫ﺳﻄﺢ‬ ‫ﻣﻦ‬ - 1 .( :‫ﺍﻟﻤﻌﻄﻴﺎﺕ‬ ، ‫ﻣﻬﻤﻠﺔ‬ ‫ﺍﻻﺣﺘﻜﺎﻛﺎﺕ‬ g=10(si) ، AB=10m ، CE=h=1,8m . ‫ﺍﻟﻠﺤﻈﺔ‬ ‫ﻋﻨﺪ‬ ‫ﺍﻟﻄﻔﻞ‬ ‫ﻳﻨﻄﻠﻖ‬ t=0 ‫ﺍﻟﻤﻮﺿﻊ‬ ‫ﻣﻦ‬ ‫ﺍﺑﺘﺪﺍﺋﻴﺔ‬ ‫ﺳﺮﻋﺔ‬ ‫ﺑﺪﻭﻥ‬ A ‫ﻋﻠﻰ‬ ‫ﻓﻴﻨﺰﻟﻖ‬ ، AB ‫ﺣﺮﻛﺔ‬ ‫ﻟﺪﺭﺍﺳﺔ‬ ، G ‫ﻣﻌ‬ ‫ﻧﺨﺘﺎﺭ‬ ، ‫ﻠﻤﺎ‬ ሺ‫ܣ‬ǡ ଓ Ԧሻ ‫ﺣﻴﺚ‬ ‫ﺑﺎﻷﺭﺽ‬ ‫ﻣﺮﺗﺒﻄﺎ‬ =0 A =X G X ‫ﻋﻨﺪ‬ ) t=0 ( . 1 ( ‫ﺍﻟﻤﻌﺎﺩﻟﺔ‬ ‫ﺃﻥ‬ ‫ﺃﺛﺒﺖ‬ ،‫ﻟﻨﻴﻮﺗﻦ‬ ‫ﺍﻟﺜﺎﻧﻲ‬ ‫ﺍﻟﻘﺎﻧﻮﻥ‬ ‫ﺑﺘﻄﺒﻴﻖ‬ ‫ﺍﻟﻔﺎﺻﻠﺔ‬ ‫ﺗﺤﻘﻘﻬﺎ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺍﻟﺘﻔﺎﺿﻠﻴﺔ‬ G X ‫ﻋﻄﺎﻟﺔ‬ ‫ﻟﻤﺮﻛﺰ‬ :‫ﻳﻠﻲ‬ ‫ﻛﻤﺎ‬ ‫ﺗﻜﺘﺐ‬ ‫ﺍﻟﻄﻔﻞ‬ ௗమ௑ಸ ௗ௧మ ൌ ‰Ǥ •‹α ‫ﺣﺮﻛﺔ‬ ‫ﻁﺒﻴﻌﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ . G . 2 ( ‫ﺭﻗﻤﻴﺔ‬ ‫ﻛﺎﻣﻴﺮﺍ‬ ‫ﺑﻮﺍﺳﻄﺔ‬ ‫ﺍﻟﻄﻔﻞ‬ ‫ﺣﺮﻛﺔ‬ ‫ﺗﺼﻮﻳﺮ‬ ‫ﺑﻌﺪ‬ ‫ﺗﻢ‬ ‫ﻣﻨﺎﺳﺐ‬ ‫ﺑﺮﻧﺎﻣﺞ‬ ‫ﺑﻮﺍﺳﻄﺔ‬ ‫ﺍﻟﻤﻌﻄﻴﺎﺕ‬ ‫ﻭﻣﻌﺎﻟﺠﺔ‬ ‫ﺍﻟﻌﻄﺎﻟﺔ‬ ‫ﻟﻤﺮﻛﺰ‬ ‫ﺍﻟﺴﺮﻋﺔ‬ ‫ﻣﺨﻄﻂ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﺤﺼﻮﻝ‬ G ‫)ﺍﻟﺸﻜﻞ‬ - 2 .( ‫ﺃ‬ . ‫ﺍﻟﺘﺴﺎﺭﻉ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺑﻴﺎﻧﻴﺎ‬ ‫ﺃﻭﺟﺪ‬ G a . ‫ﺏ‬ . ‫ﺍﻟﺠﺰء‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﻤﺴﺘﻐﺮﻗﺔ‬ ‫ﺍﻟﺰﻣﻨﻴﺔ‬ ‫ﺍﻟﻤﺪﺓ‬ ‫ﺣﺪﺩ‬ AB . e n c y - e d u c a t i o n AB= ، ، CE=h=1,8m E=h=1,8m ‫ﻤﻮﺿﻊ‬ ‫ﺿﻊ‬ A A / e x a m s Mev/c ): ‫اﻟﺜﺎﱐ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬ ‫اﻟﺜﺎ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬ m s I . ‫ﺩﺭﺍﺳﺔ‬ ‫ﺭﺍﺳﺔ‬ ‫ﺣﺮﻛﺔ‬ a m ‫ﻋﻄﺎﻟﺘﻪ‬ ‫ﻣﺮﻛﺰ‬ ‫ﻁﻔﻞ‬ ‫ﻖ‬ ‫ﻋﻄﺎﻟ‬ ‫ﻣﺮﻛﺰ‬ ‫ﻔﻞ‬ G ‫ﺍﻻﺭﺗﻔﺎﻉ‬ ‫ﻋﻠﻰ‬ ‫ﺪ‬ ‫ﺍﻻﺭﺗﻔﺎﻉ‬ ‫ﻰ‬ h h ‫ﺳﻄ‬ ‫ﻣﻦ‬ ‫ﻋﻠﻰ‬ ‫ﻓﻴﻨﺰﻟﻖ‬ ، ‫ﻋ‬ ‫ﻓﻴﻨﺰﻟﻖ‬ ، 3as.ency-education.com
  • 7. 0 ‫ﻣﻥ‬ 8 0 7 ‫ﺍﻟﺻﻔﺣﺔ‬ II . ‫ﻗﺬﻳﻔﺔ‬ ‫ﺷﻜﻞ‬ ‫ﻋﻠﻰ‬ ‫ﻁﻔﻞ‬ ‫ﺣﺮﻛﺔ‬ ‫ﺩﺭﺍﺳﺔ‬ ): 03 ( ‫ﻧﻘﺎﻁ‬ ‫ﺍﻟﻤﻮﺿﻊ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﺰﻟﻘﺔ‬ ‫ﺍﻟﻄﻔﻞ‬ ‫ﻋﻄﺎﻟﺔ‬ ‫ﻣﺮﻛﺰ‬ ‫ﻳﻐﺎﺩﺭ‬ C ‫ﺑﺎﻟﺴﺮﻋﺔ‬ 1 - =11 m.s c V ‫ﻣﺎء‬ ‫ﻓﻲ‬ ‫ﻟﻴﺴﻘﻂ‬ ‫ﺍﻷﺯﻣﻨﺔ‬ ‫ﻣﺒﺪﺃ‬ ‫ﻫﺎ‬ ‫ﻧﻌﺘﺒﺮ‬ ‫ﻟﺤﻈﺔ‬ ‫ﻋﻨﺪ‬ ‫ﺣﺮﻛﺔ‬ ‫ﻧﺪﺭﺱ‬ .‫ﺍﻟﻤﺴﺒﺢ‬ G ‫ﺍﻟﻤﻌﻠﻢ‬ ‫ﻓﻲ‬ ሺ‫ܥ‬ǡ ଓ Ԧǡ ଔ Ԧሻ . 1 ( ‫ﺍﻟﺰﻣﻨﻴﺘﻴﻦ‬ ‫ﺍﻟﻤﻌﺎﺩﻟﺘﻴﻦ‬ ‫ﻋﺒﺎﺭﺓ‬ ‫ﺃﻭﺟﺪ‬ ،‫ﺍﻟﺜﺎﻧﻲ‬ ‫ﻧﻴﻮﺗﻦ‬ ‫ﻗﺎﻧﻮﻥ‬ ‫ﺑﺘﻄﺒﻴﻖ‬ x(t) ‫ﻭ‬ y(t) ‫ﻟﺤﺮﻛﺔ‬ G ‫ﺍﺳﺘﻨﺘﺞ‬ . ‫ﻣﻌﺎﺩﻟﺔ‬ .‫ﺍﻟﻤﺴﺎﺭ‬ 2 ( ‫ﻳﺼﻞ‬ G ‫ﺍﻟﻤﻮﺿﻊ‬ ‫ﻓﻲ‬ ‫ﺍﻟﻤﺎء‬ ‫ﺳﻄﺢ‬ ‫ﺇﻟﻰ‬ I ‫ﺑﺎﻟﺴﺮﻋﺔ‬ ‫ݒ‬ூ ሬሬሬԦ . ‫ﻭﺻﻮﻝ‬ ‫ﻟﺤﻈﺔ‬ ‫ﺃﻥ‬ ‫ﺗﺤﻘﻖ‬ .‫ﺃ‬ G ‫ﺇﻟﻰ‬ I ‫ﻫﻲ‬ =0,6s I t . ‫ﺍ‬ .‫ﺏ‬ ‫ﺣ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺴﺐ‬ ‫ݒ‬ூ ‫ﺍﻟﻤﺴﺎﻓﺔ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺣﺪﺩ‬ . EI . 3 ( ‫ﻳﻨﺰﻟﻖ‬ ‫ﻛﺘﻠﺘﻪ‬ ‫ﺁﺧﺮ‬ ‫ﻁﻔﻞ‬ m’ ‫ﻣﻦ‬ ‫ﺃﻛﺒﺮ‬ m ‫ﺍﻟﻤﺴﺎﺭ‬ ‫ﻧﻔﺲ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﻤﺴﺎﻓﺔ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺗﺘﻐﻴﺮ‬ ‫ﻫﻞ‬ EI .‫ﻋﻠﻞ‬ ‫؟‬ ‫اﻟ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬ ‫ﺜﺎﻟﺚ‬ ): 04 ‫ﻧﻘ‬ ‫ﺎ‬ (‫ط‬ 2 - N.m.Kg 11 - G=6,67x10 .‫ﺍﻟﻜﻮﻧﻲ‬ ‫ﺍﻟﺘﺠﺎﺫﺏ‬ ‫ﺛﺎﺑﺖ‬ Km 3 R=9,38x10 ‫ﺗﻮﺍﺑﻌﻪ‬ ‫ﺃﺣﺪ‬ ‫ﻭﻣﺮﻛﺰ‬ ‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﻛﻮﻛﺐ‬ ‫ﻣﺮﻛﺰ‬ ‫ﺑﻴﻦ‬ ‫ﺍﻟﺒﻌﺪ‬ ) P ( Kg 23 =6,42x10 M m ‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﻛﻮﻛﺐ‬ ‫ﻛﺘﻠﺔ‬ ، p m ‫ﺍﻟﻤﺪﺭﻭﺱ‬ ‫ﺗﺎﺑﻌﻪ‬ ‫ﻛﺘﻠﺔ‬ . =24h37min M T ‫ﻧﻔﺴﻪ‬ ‫ﺣﻮﻝ‬ ‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﻛﻮﻛﺐ‬ ‫ﺩﻭﺭ‬ ‫ﻁﺒﻴﻌﻴﺎ‬ ‫ﻗﻤﺮﺍ‬ ‫ﻧﻌﺘﺒﺮ‬ ) P ( ‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﻟﻜﻮﻛﺐ‬ ‫ﺗﺎﺑﻌﺎ‬ ‫ﺑﺴﺮﻋﺔ‬ ‫ﻣﻨﺘﻈﻤﺔ‬ ‫ﺩﺍﺋﺮﻳﺔ‬ ‫ﺑﺤﺮﻛﺔ‬ ‫ﺣﻮﻟﻪ‬ ‫ﻳﺪﻭﺭ‬ X I :‫ﻣﺪﺍﺭﻩ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﻄﺒﻴﻌﻲ‬ ‫ﺍﻟﻘﻤﺮ‬ ‫ﺗﻮﺍﺯﻥ‬ ‫ﺩﺭﺍﺳﺔ‬ 1 - ‫ﺍﻟﺪﺍﺋ‬ ‫ﺍﻟﺤﺮﻛﺔ‬ ‫ﺗﻌﺮﻳﻒ‬ ‫ﺃﻋﻂ‬ .‫ﺍﻟﻤﻨﺘﻈﻤﺔ‬ ‫ﺮﻳﺔ‬ 2 - ‫ﺑ‬ ‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﻟﻜﻮﻛﺐ‬ ‫ﺍﻟﺘﺎﺑﻊ‬ ‫ﺍﻟﻄﺒﻴﻌﻲ‬ ‫ﺍﻟﻘﻤﺮ‬ ‫ﺗﺴﺎﺭﻉ‬ ‫ﻟﺸﻌﺎﻉ‬ ‫ﻭﺍﻻﺗﺠﺎﻩ‬ ‫ﻭﺍﻟﺤﺎﻣﻞ‬ ‫ﺍﻟﺘﺄﺛﻴﺮ‬ ‫ﻧﻘﻄﺔ‬ ‫ﻣﻨﺎﺳﺐ‬ ‫ﺑﺮﺳﻢ‬ ‫ﻴﻦ‬ 3 - ‫ﺑﺪﻻﻟﺔ‬ ‫ﺍﻟﺘﺴﺎﺭﻉ‬ ‫ﺷﺪﺓ‬ ‫ﻋﺒﺎﺭﺓ‬ ‫ﺃﻋﻂ‬ X ، r 4 - ‫ﻧﻴ‬ ‫ﻗﺎﻧﻮﻥ‬ ‫ﻁﺒﻖ‬ ‫ﺍﻟﻤﺬﻛﻮﺭ‬ ‫ﺍﻟﻘﻤﺮ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﺜﺎﻧﻲ‬ ‫ﻮﺗﻦ‬ . ‫ﺃ‬ ( ‫ﻫﻲ‬ ‫ﻣﺪﺍﺭﻩ‬ ‫ﻋﻠﻰ‬ ‫ﺍﻟﻘﻤﺮ‬ ‫ﺳﺮﻋﺔ‬ ‫ﺃﻥ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ r m G M ˜ X ‫ﺏ‬ ( ‫ﺗﺮﺑﻂ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺍﻟﻌﻼﻗﺔ‬ ‫ﺃﻭﺟﺪ‬ v ، r ‫ﻭ‬ P T ‫ﺣﺮﻛﺔ‬ ‫)ﺩﻭﺭ‬ P .(‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﻛﻮﻛﺐ‬ ‫ﺣﻮﻝ‬ ‫ﺝ‬ ( ‫ﺍﻟﻌﻼﻗﺔ‬ ‫ﺻﺤﺔ‬ ‫ﺑﺮﻫﻦ‬ 3 2 13 3 2 10 22 , 9 ˜ u m s r Tp ‫ﺩ‬ ( ‫ﺍﻟﺪﻭﺭ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺍﺳﺘﻨﺘﺞ‬ P T . ‫ﻩ‬ ( ‫ﺍﻟﻤﺮﻳﺦ؟‬ ‫ﺑﻜﻮﻛﺐ‬ ‫ﻣﺘﺼﻠﺔ‬ ‫ﻟﻤﺤﻄﺔ‬ ‫ﺑﺎﻟﻨﺴﺒﺔ‬ ‫ﻣﺴﺘﻘﺮﺍ‬ ‫ﻳﻜﻮﻥ‬ ‫ﺣﺘﻰ‬ ‫ﺻﻨﺎﻋﻲ‬ ‫ﻗﻤﺮ‬ ‫ﻭﺿﻊ‬ ‫ﻳﺠﺐ‬ ‫ﻣﺴﺘﻮﻯ‬ ‫ﺃﻱ‬ ‫ﻓﻲ‬ ‫ﻭ‬ ( ‫ﺍﻟﺪﻭﺭ‬ ‫ﻫﻮ‬ ‫ﻣﺎ‬ S T ‫ﺍﻟﺼﻨﺎﻋﻲ‬ ‫ﺍﻟﻘﻤﺮ‬ ‫ﻫﺬﺍ‬ ‫ﻟﺤﺮﻛﺔ‬ ‫؟‬ e n c y - e d u c a t i o n . c o m / e x a m s 2 2 ( ‫ﻳﺼ‬ ‫ﺗﺤﻘﻖ‬ .‫ﺃ‬ .‫ﺃ‬ ‫ﺍ‬ .‫ﺏ‬ ‫ﺍ‬ .‫ﺏ‬ ‫ﺣ‬ ‫ﺣ‬ ‫ﻗﻴﻤ‬ ‫ﺣﺴﺐ‬ ‫ﺣ‬ 3 ( ‫ﻳﻨﺰﻟﻖ‬ ‫ﻳﻨﺰﻟﻖ‬ ‫ﻛﺘ‬ ‫ﺁﺧﺮ‬ ‫ﻁﻔﻞ‬ ‫ﺁﺧ‬ ‫ﻁﻔﻞ‬ ‫اﻟ‬ ‫ﻦ‬ ‫ﺜﺎﻟﺚ‬ ‫ﺚ‬ ‫ﻟ‬ ): ): 04 04 ‫ﻧﻘ‬ ‫ﻘ‬ ‫ﻘﺎ‬ (‫ط‬ e x G=6,67x G=6,6 ‫ﺍﻟﺘﺠﺎﺫ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺍﻟﻤﺮ‬ ‫ﻛﻮﻛﺐ‬ ‫ﻣﺮﻛﺰ‬ ‫ﺑﻴﻦ‬ ‫ﻌﺪ‬ ‫ﻛﻮﻛﺐ‬ ‫ﻣﺮﻛﺰ‬ ‫ﻦ‬ ‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﻛﻮﻛﺐ‬ ‫ﺍﻟﻤﺮﻳﺦ‬ ‫ﺐ‬ ، ، p p m mp p p ‫ﻛﺘﻠﺔ‬ ‫ﻧﻔﺴﻪ‬ ‫ﺣﻮﻝ‬ ‫ﺮﻳﺦ‬ ‫ﻧﻔﺴﻪ‬ ‫ﺣﻮﻝ‬ ‫ﻳﺦ‬ ‫ﺩﺍ‬ ‫ﺑﺤﺮﻛﺔ‬ ‫ﺣﻮﻟﻪ‬ ‫ﻳﺪﻭﺭ‬ ‫ﺣﻮﻟﻪ‬ ‫ﻭﺭ‬ ‫ﺍﻟﺘ‬ ‫ﺍﻟﻄﺒﻴﻌﻲ‬ ‫ﺍﻟﻘﻤﺮ‬ ‫ﺗﺴﺎﺭﻉ‬ ‫ﺍﻟﻄﺒﻴﻌ‬ ‫ﺍﻟﻘﻤﺮ‬ ‫ﺭﻉ‬ 3as.ency-education.com
  • 8. 0 ‫ﻣﻥ‬ 8 0 8 ‫ﺍﻟﺻﻔﺣﺔ‬ ‫اﳉﺰ‬ ‫ء‬ ‫اﻟﺜﺎﱐ‬ ‫ﻋﻠﻰ‬ : ) 7 ‫ﻧﻘﺎط‬ ( ‫ـ‬‫ـ‬‫ـ‬‫ﻴ‬‫اﻟﻜﻤ‬ ) ‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬ ‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬ ‫ـ‬‫ـ‬‫ـ‬‫ـ‬ ‫ـ‬‫ـ‬‫ـ‬‫ـ‬‫ـ‬ (‫ﺎء‬ ‫اﻟﺜﺎﻟﺚ‬ ‫ﻳﻦ‬‫ﺮ‬‫اﻟﺘﻤ‬ : I . ): ‫ﻛﺮﺑﻮﻛﺴﻴﻠﻲ‬ ‫ﻟﺤﻤﺾ‬ ‫ﺗﻮﺍﺯﻥ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺩﺭﺍﺳﺔ‬ 04 ( ‫ﻧﻘﺎﻁ‬ ‫ﺍﻟﻤﻮﻟﻲ‬ ‫ﺗﺮﻛﻴﺰﻩ‬ ‫ﺍﻹﻳﺜﺎﻧﻮﻳﻚ‬ ‫ﻟﺤﻤﺾ‬ ‫ﻣﺤﻠﻮﻻ‬ ‫ﻧﻌﺘﺒﺮ‬ 0 C . 1 ‫؟‬ ‫ﺍﻟﻤﺎء‬ ‫ﻣﻊ‬ ‫ﺍﻹﻳﺜﺎﻧﻮﻳﻚ‬ ‫ﺣﻤﺾ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺃﻛﺘﺐ‬ ‫ـ‬ ( 2 ‫ﻋﻦ‬ ‫ﻋﺒﺮ‬ ‫ـ‬ ( f @ + O 3 H ‫ﻭ‬ f @ - COO 3 CH ‫ﺑﺪﻻﻟﺔ‬ 0 C ‫ﺍﻟﻨﻬﺎﺋﻴﺔ‬ ‫ﺍﻟﻨﺴﺒﺔ‬ ‫ﻭ‬ W ‫؟‬ ‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻟﺘﻘﺪﻡ‬ 3 ‫ﺇﺳﺘﻨﺘﺞ‬ ‫ـ‬ ( f @ COOH 3 CH ‫ﺑﺪﻻﻟﺔ‬ 0 C ‫ﻭ‬ W ‫؟‬ 4 ‫ﻟﻠﺜﻨﺎﺋﻴﺔ‬ ‫ﺍﻟﺤﻤﻮﺿﺔ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺃﻥ‬ ‫ﺑﻴﻦ‬ ‫ـ‬ ( τ τ - 1 C = K 2 0 A 5 ‫ﻟـ‬ ‫ﻣﺨﺘﻠﻔﺔ‬ ‫ﻗﻴﻢ‬ ‫ﺃﺟﻞ‬ ‫ﻣﻦ‬ ‫ـ‬ ( 0 C ‫ﻗﻴﻤﺔ‬ ‫ﺍﻟﻨﺎﻗﻠﻴﺔ‬ ‫ﻗﻴﺎﺱ‬ ‫ﻁﺮﻳﻖ‬ ‫ﻋﻦ‬ ‫ﻧﻌﻴﻦ‬ W . ‫؟‬ ‫ﺍﻟﺘﺎﻟﻲ‬ ‫ﺍﻟﺠﺪﻭﻝ‬ ‫ﺃﻛﻤﻞ‬ ‫ـ‬ ‫ﺃ‬ ‫ـ‬ ‫ﺏ‬ ‫ﺍﻟﺒﻴﺎﻥ‬ ‫ﺃﺭﺳﻢ‬ y = f ( x ) ‫؟‬ ‫ﺠ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺇﺳﺘﻨﺘﺞ‬ ‫ـ‬ K ‫؟‬ II . ‫ﺍﻻﺳﺘﺮ‬ ‫ﺻﻨﺎﻋﺔ‬ ): 03 ( ‫ﻧﻘﺎﻁ‬ ‫ﻣﻦ‬ ‫ﻋﻠﻴﻬﺎ‬ ‫ﺍﻟﺤﺼﻮﻝ‬ ‫ﻳﻤﻜﻦ‬ .... ‫ﺍﻟﻐﺬﺍﺋﻴﺔ‬ ‫ﺍﻟﻤﻮﺍﺩ‬ ‫ﻓﻲ‬ ، ‫ﺍﻟﻤﻌﻄﺮﺍﺕ‬ ‫ﻓﻲ‬ : ‫ﺍﻟﻴﻮﻣﻴﺔ‬ ‫ﺣﻴﺎﺗﻨﺎ‬ ‫ﻓﻲ‬ ‫ﺗﻮﺟﺪ‬ ‫ﺍﻻﺳﺘﺮﺍﺕ‬ ‫ﺍ‬ ‫ﻟﻨﺒﺎﺕ‬ ‫ﻛ‬ ‫ﻳﻤﻜﻦ‬ ‫ﻤﺎ‬ ‫ﺍﻟﻤﺨﺎﺑﺮ‬ ‫ﻓﻲ‬ ‫ﺇﺻﻄﻨﺎﻋﻬﺎ‬ ‫ﻳﺼﻄﻨﻊ‬ ‫ﺍﻻﺳﺘﺮ‬ ‫ﻣ‬ . ( ‫ﺍﻟﻤﻴﺜﺎﻧﻮﻝ‬ ، ‫ﺍﻟﺒﻨﺰﻭﻳﻚ‬ ‫ﺣﻤﺾ‬ ) ‫ﻟﻠﺠﻤﻠﺔ‬ ‫ﻛﻴﻤﻴﺎﺋﻲ‬ ‫ﺗﺤﻮﻝ‬ ‫ﻣﻦ‬ ‫ﺇﻧﻄﻼﻗﺎ‬ ‫ﺩﺭﺍﺳﺘﻪ‬ ‫ﻧﺮﻳﺪ‬ ‫ﺍﻟﺬﻱ‬ ‫ﺫﻟﻚ‬ ‫ﺃﺟﻞ‬ ‫ﻦ‬ ‫ﻧﻤﺰﺝ‬ = 12.2 g 1 m ‫ﺣﺠﻢ‬ ‫ﻣﻊ‬ ‫ﺍﻟﺒﻨﺰﻭﻳﻚ‬ ‫ﺣﻤﺾ‬ ‫ﻣﻦ‬ = 30 mL 2 V ‫ﺍﻟﻤﺮﻛﺰ‬ ‫ﺍﻟﻜﺒﺮﻳﺖ‬ ‫ﺣﻤﺾ‬ ‫ﻣﻦ‬ ‫ﻗﻄﺮﺍﺕ‬ ‫ﺑﻮﺟﻮﺩ‬ ‫ﺍﻟﻤﻴﺜﺎﻧﻮﻝ‬ ‫ﻣﻦ‬ ‫ﻟﻤﺪﺓ‬ ‫ﺍﻟﻤﺮﺗﺪ‬ ‫ﺑﺎﻟﺘﻘﻄﻴﺮ‬ ‫ﻧﺴﺨﻦ‬ 60 min ‫ﺍﻟﺘﺒﺮﻳ‬ ‫ﺑﻌﺪ‬ ‫ﺪ‬ ‫ﺟﻠﻴ‬ + ‫ﻣﺎء‬ ) ‫ﻋﻠﻰ‬ ‫ﺗﺤﺘﻮﻱ‬ ‫ﺣﺒﺎﺑﺔ‬ ‫ﻓﻲ‬ ‫ﺍﻟﺒﺎﻟﻮﻧﺔ‬ ‫ﻣﺤﺘﻮﻯ‬ ‫ﻧﺴﻜﺐ‬ ‫ﻋﻠﻰ‬ ‫ﻟﻨﺤﺼﻞ‬ ( ‫ﺪ‬ ‫ﺍﻷﺧﻴﺮ‬ ‫ﻓﻲ‬ ‫ﻟﻨﺤﺼﻞ‬ ‫ﺍﻹﺳﺘﺮ‬ ‫ﻋﻠﻰ‬ ‫ﻳﺤﺘﻮﻱ‬ ‫ﺍﻟﺬﻱ‬ ‫ﺍﻟﻄﻮﺭ‬ ‫ﻧﻌﺰﻝ‬ . ‫ﻣﺨﺘﻠﻔﻴﻦ‬ ‫ﻁﻮﺭﻳﻦ‬ ‫ﻛﺘﻠﺔ‬ ‫ﻋﻠﻰ‬ 9.52 g ‫ﻣﻦ‬ ‫ﺍﻻﺳﺘﺮ‬ . : ‫ﺍﻟﻤﻌﻄﻴﺎﺕ‬ ‫ﺍﻟﺤﺠﻤﻴﺔ‬ ‫ﺍﻟﻜﺘﻠﺔ‬ ) 1 - g.L ( ‫ﺍﻟﻤﻮﻟﻴﺔ‬ ‫ﺍﻟﻜﺘﻠﺔ‬ ) 1 - g.mol ( ‫ﺍﻟﺼﻴﻐﺔ‬ ‫ﺍﻟﻜﻴﻤﻴﺎﺋﻲ‬ ‫ﺍﻟﻨﻮﻉ‬ 1.3 122 COOH 5 H 6 C ‫ﺍﻟﺒﻨﺰﻭﻳﻚ‬ ‫ﺣﻤﺾ‬ 0.80 32 OH - 3 CH ‫ﺍﻟﻤﻴﺜﺎﻧﻮﻝ‬ 1.1 136 ‫ﺩﺭﺍﺳﺘﻪ‬ ‫ﻣﺮﺍﺩ‬ ‫ﺍﻻﺳﺘﺮ‬ 1 ‫ﺍﻟﺒﻨﺰﻭﻳﻚ‬ ‫ﻟﺤﻤﺾ‬ ‫ﺍﻟﻤﺎﺩﺓ‬ ‫ﻛﻤﻴﺔ‬ ‫ﻋﻴﻦ‬ ‫ـ‬ ‫ﻭ‬ ‫؟‬ ‫ﺍﻟﻤﺴﺘﻌﻤﻞ‬ ‫ﻟﻠﻤﻴﺜﺎﻧﻮﻝ‬ ‫ﺍﻟﻤﺎﺩﺓ‬ ‫ﻛﻤﻴﺔ‬ 2 ‫؟‬ ‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻟﺘﺴﺮﻳﻊ‬ ‫ﺃﺳﺘﻌﻤﻠﺖ‬ ‫ﺍﻟﺘﻲ‬ ‫ﺍﻟﺤﺮﻛﻴﺔ‬ ‫ﺍﻟﻌﻮﺍﻣﻞ‬ ‫ﻋﻴﻦ‬ ‫ـ‬ 3 ‫؟‬ ‫ﺍﻟﻤﺮﺗﺪ‬ ‫ﺍﻟﺘﻘﻄﻴﺮ‬ ‫ﻣﻊ‬ ‫ﺍﻟﺘﺴﺨﻴﻦ‬ ‫ﺃﺳﺘﻌﻤﻞ‬ ‫ﻟﻤﺎﺫﺍ‬ ‫ـ‬ 4 ‫ﺇﺻﻄﻨﺎﻉ‬ ‫ﺗﻔﺎﻋﻞ‬ ‫ﻣﻌﺎﺩﻟﺔ‬ ‫ﺃﻛﺘﺐ‬ ‫ـ‬ ‫ﺍﻻﺳﺘﺮ‬ ‫؟‬ ‫؟‬ ‫ﺍﺳﻤﻪ‬ ‫ﺍﻋﻂ‬ 5 ‫ـ‬ ‫؟‬ ‫ﺍﻟﺘﺤﻮﻝ‬ ‫ﻫﺬﺍ‬ ‫ﺧﺼﺎﺋﺺ‬ ‫ﺍﻋﻂ‬ 6 ‫ﺛﻢ‬ ‫ﻋﺮﻑ‬ ‫ـ‬ ‫؟‬ ‫ﺍﻟﺘﻔﺎﻋﻞ‬ ‫ﻣﺮﺩﻭﺩ‬ ‫ﺃﺣﺴﺐ‬ 4 - 10 u 5 3 - 10 u 1 3 - 10 u 5 2 - 10 u 1 ( mol / L ) 0 C 2 - 10 u 16 2 - 10 u 12.5 2 - 10 u 5.6 2 - 10 u 4 W 0 C 1 = x τ τ - 1 C = y 2 0 e n c y - e d u c a t i o n . c o m / e x a m s ‫ﺃﻛ‬ ‫ـ‬ ( 2 2 ‫ﻋﺒﺮ‬ ‫ـ‬ ( ‫ـ‬ ( 3 3 ‫ﺇﺳﺘﻨﺘﺞ‬ ‫ـ‬ ( ‫ﺇﺳﺘﻨﺘ‬ ‫ـ‬ ( f 4 ‫ﺍﻟﺤ‬ ‫ﺛﺎﺑﺖ‬ ‫ﺃﻥ‬ ‫ﺑﻴﻦ‬ ‫ـ‬ ( ‫ﺛﺎﺑ‬ ‫ﺃﻥ‬ ‫ﺑﻴﻦ‬ ‫ـ‬ ( ‫ﻟـ‬ ‫ﻣﺨﺘﻠﻔﺔ‬ ‫ﻗﻴﻢ‬ ‫ﺃﺟﻞ‬ ‫ﻣﻦ‬ ‫ـ‬ ( ‫ﻣﺨﺘﻠ‬ ‫ﻗﻴﻢ‬ ‫ﺃﺟﻞ‬ ‫ﻦ‬ ‫؟‬ ‫ﺍﻟﺘﺎﻟﻲ‬ ‫ﺍﻟﺠﺪﻭﻝ‬ ‫ﺃﻛﻤﻞ‬ ‫ـ‬ ‫ﺍﻟﺘﺎﻟ‬ ‫ﺍﻟﺠﺪﻭﻝ‬ ‫ﻤﻞ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺇﺳﺘﻨﺘﺞ‬ ‫ﻗﻴﻤﺔ‬ ‫ﺞ‬ K K ‫؟‬ ‫؟‬ ‫ﺍ‬ ‫ﺍﻟﻤﻮﺍﺩ‬ ‫ﻓﻲ‬ ، ‫ﻟﻤﻌﻄﺮﺍﺕ‬ ‫ﺍﻟﻤﻮ‬ ‫ﻓﻲ‬ ، ‫ﺮﺍﺕ‬ ‫ﺣﻤﺾ‬ ) ‫ﻟﻠﺠﻤﻠﺔ‬ ‫ﻛﻴﻤﻴﺎﺋﻲ‬ ‫ﻝ‬ ‫ﺣﻤ‬ ) ‫ﻟﻠﺠﻤﻠﺔ‬ ‫ﻤﻴﺎﺋﻲ‬ 2 V V ‫ﺑﻮﺟ‬ ‫ﺍﻟﻤﻴﺜﺎﻧﻮﻝ‬ ‫ﻣﻦ‬ ‫ﺍﻟﻤﻴﺜﺎﻧﻮﻝ‬ ‫ﻣﻦ‬ ‫ﺗﺤﺘ‬ ‫ﺣﺒﺎﺑﺔ‬ ‫ﻓﻲ‬ ‫ﺍﻟﺒﺎﻟﻮﻧﺔ‬ ‫ﻮﻯ‬ ‫ﺣﺒﺎﺑ‬ ‫ﻓﻲ‬ ‫ﻟﺒﺎﻟﻮﻧﺔ‬ ‫ﺍﻷﺧﻴﺮ‬ ‫ﻓﻲ‬ ‫ﻞ‬ ‫ﻷﺧﻴﺮ‬ ‫ﻛﺘﻠﺔ‬ ‫ﻋﻠﻰ‬ ‫ﻛﺘ‬ ‫ﻋﻠﻰ‬ g ‫ﻐﺔ‬ ‫ﺍﻟﻨ‬ ‫ﺍﻟ‬ u c u c u c u c u c u c u c u c u c u c u c C ‫ﺣﻤﺾ‬ ‫ﺣ‬ d u d u u u u u u u u u u u ‫ﺍﻟﻤﻴﺜﺎﻧﻮﻝ‬ ‫ﺍﻟﻤﻴ‬ d d ‫ﺩﺭﺍﺳ‬ ‫ﻣﺮﺍﺩ‬ ‫ﺍﻻﺳﺘﺮ‬ ‫ﻣﺮ‬ ‫ﻻﺳﺘﺮ‬ e d e d - e - e 4 - 10 10 u u 5 5 x a e 1 u 16 16 2 2 - - 10 e e e x / e / e / e / e / e m o 3as.ency-education.com