(1)

1) To Calculate Number Of Bytes Needed for each
Instruction, then the Total Size of Memory Occupied
by the Program will be Known.
2) To Calculate Number of Clock Cycles Needed for each
Instruction, then the Estimated Execution Time for
the Program will be Known.
3) Help the Programmers to Chose the Optimal
Instructions, Specially for Time-Critic (Real Time
process) Applications.

T = 200 ns for 5MHz Clock Frequency
*So the Time needed to execute a 2-clock
Instruction is 2-clockX200ns=400ns.

MOD

TOTAL BYTE
TOTAL CLK
TRANSFER
CLOCKS
OPCODE
OP2
OP1
INST.
LABLE
3
4
-------
4
B8 02 F8
F802
AX,
MOV
START:
1
11+1=12
1
11
50
-------
AX
PUSH
2
2
-------
2
8B CB
BX
CX
MOV
2
2
-------
2
8B D1
CX
DX
MOV
2
9+5=14
-------
9+EA
03 04
[SI]
AX
ADD
4
4
-------
4
81 C6 86 80
8086
SI
ADD
2
15
-------
15
EB F0
-------
START
JMP
16 BYTES
53 CLK
SUM
53*200ns=10600n
TOTAL TIME TO EXECUTE SINGLE LOOP FOR 5MHz CLK
16 BYTS
TOTAL PROGRAM MEMORY SIZE NEEDED