Suppose that a motorboat is moving at 76 ft/s when its motor suddenly quits, and that 16 s later the boat has slowed to 29 ft/s. Assume that the resistance it encounters while coasting is proportional to the square of its velocity so thatdv/dt=-kv2 where k>0. How far will the boat coast in the first 4 minutes after its motor quits? Note: Please find the distance. I keep getting answers submitted as velocity.... Solution INITIAL VELOCITY OF BOAT = 76 FPS THE MOTOR TRIPS AT T=0 VELOCITY OF THE BOAT AFTER 16 SEC = 29 FPS DV/DT = - KV^2.