Oral Examinations via Videoconference from the Student’s Point of View
1. Oral Examinations
via Videoconference
from the Student’s Point of View
Jörn Loviscach
https://j3L7h.de
31. Mai 2020
English translation by Mathias Magdowski
https://mathiasmagdowski.wordpress.com/
03. Dezember 2021
https://creativecommons.org/licenses/by-nc-sa/3.0/de/
2. Eleanor Examiner Sarah Student Owen Observer
Hello everyone to the exam
in mathematics 2! Ms. S.,
I would like to introduce
Mr. O., who will serve
as exam observer.
Hello!
Hello!
3. Thank you! Then we
can move on to the
first question.
Yes, I am fit!
Eleanor Examiner Owen Observer
I just checked, Ms. S., that you are
still registered. Do you feel in
good health for this exam and
could you show us your ID card?
Sarah Student
5. Sarah Student
Because of the sine. Oh, nonsense! It is linear.
x is in the sine. Linear and inhomogeneous. In-
homogeneous because of the term with the sine.
Why
nonlinear?
This is 2nd
order, nonlinear.
Eleanor Examiner Owen Observer
What type of differential
equation do you see here?
𝑦 3𝑦 sin 5𝑥 0
Shared Screen
6. Sarah Student
... Yes ... uh ... no ... Ah, sine and
cosine of 5x. The frequency does not
change by taking the derivative.
Sine and
cosine of x?
I would use a sum
of sine and cosine.
Eleanor Examiner Owen Observer
How can you find
a special solution
for it?
𝑦 3𝑦 sin 5𝑥 0
Shared Screen
8. Does it make sense?
Sarah Student
On the left and on the right
there are equations of a line.
They are equated.
Eleanor Examiner Owen Observer
Someone wants to determine at
which point two lines intersect
and then writes down this
equation. What do you notice?
Shared Screen
1
2
𝜆
3
4
5
6
𝜆
7
8
9. Sarah Student
Eleanor Examiner Owen Observer
Exactly. Shared Screen
1
2
𝜆
3
4
5
6
𝜆
7
8
... Hmm ... Left and right is lambda.
That is strange. One would require the
point to be the same and still at the
same lambda. That would be nonsense.
On the right could be mu.
10. Sarah Student
Eleanor Examiner Owen Observer
Shared Screen
1
2
𝜆
3
4
5
6
𝜇
7
8
Yes. Then Mr. O. and I will
discuss in private. Meanwhile,
I'll put you in a breakout room.
... Yes ... Because they are not
parallel. The direction vector on the
right is not a multiple of the one on
the left. For example, the right one
would have to have a 6 at the top.
And do
these lines
intersect?
12. Sarah Student
Bye!
Eleanor Examiner Owen Observer
We found your answers almost flawless.
You do have to pay closer attention in a
few places, but everything is in place in
terms of content. You’ve earned a 1.3.
Bye!
See you soon!
That fits!
