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Lecture Notes – Cell Biology




HKDSE Biology                  1   By Michael Ho~*
Lecture Notes – Cell Biology

Molecules of Life
1.     Water
    Water (H2O) is the most abundant compound on Earth’s surface and it is
     essential for all life on Earth.

    A water molecule consists of two hydrogen atoms covalently bonded to one
     oxygen atom.

    Attractive forces (hydrogen bonds) form between water molecules. These
     hydrogen bonds are sufficiently strong to create many of the properties of water.



Biological Functions

1. Freezing Properties
Ice is less dense than water and hence ice floats on water surface, insulating the
aquatic organisms below. It allows aquatic animals to survive in cold region.

2. High Latent Heat of Fusion
Large amount of energy has to be removed from water to form ice. The aquatic
environment and cell contents are slow to freeze in cold weather.

3. High Latent Heat of Evaporation
Large amount of energy is required for evaporation of water. It increases heat loss
and provides an effective cooling effect to mammals through sweating and plants
through transpiration.

4. High Specific Heat Capacity
Large amount of energy is required to change the temperature. Water helps to keep
the temperature constant and hence provides a stable environment for aquatic life.

5. High Transparency
Light can penetrate through water which allows photosynthesis of underwater plants
and vision for aquatic animals.

6. High Surface Tension and Adhesion
Water molecules are held together by hydrogen bonds which allow formation of a
continuous water column in plants for water transport.




HKDSE Biology                             2                  By Michael Ho~*
Lecture Notes – Cell Biology

7. High Polarity
Water is a universal solvent due to its high polarity. Water can dissolve many
substances and hence facilitates chemical reactions and serves as transport
medium.

8. Incompressibility
Water is incompressible and provides turgidity for plants and support for animals with
hydro-skeleton.




2.      Biomolecules
    A biomolecule is any molecule that is produced by a living organism, including
     Carbohydrates, Proteins, Lipids and nucleic acids.

                                                   Function



     Carbohydrates         as main source of energy - oxidized to release energy




                           as an energy reserve
         Lipids
                           form an insulator under skin to reduce heat loss



       Proteins            build up body tissues for growth and repair
     (polypeptides)        as enzymes to speed up reactions



     Nucleic acids
                           carry genetic information
    (DNA and RNA)




HKDSE Biology                             3                   By Michael Ho~*
Lecture Notes – Cell Biology

3.       Inorganic Ions
    Inorganic ions are vital for cellular activities in animals and plants.



Biological Functions

1. Sodium ions (Na+)
        take part in the transmission of nerve impulse

        maintain osmotic balance

2. Potassium ions (K+)
        take part in the transmission of nerve impulse

        maintain osmotic balance

3. Calcium ions (Ca2+)
        take part in the transmission of nerve impulse

        chemical component of bones and teeth

4. Iron ions (Fe2+)
        chemical component of haemoglobin in red blood cells



5. Magnesium ions (Mg2+)
        chemical component of bones and teeth as well as chlorophyll



6. Nitrate ions (NO3-)
        synthesis of amino acids and nucleotides



7. Phosphate ions (PO4-)
        synthesis of phospholipids, ATPs, bones and teeth




HKDSE Biology                                4                    By Michael Ho~*
Lecture Notes – Cell Biology

Microscope Development and Cell Theory
   Organisms are made up of cells. Cells are very small and cannot be seen with
    the naked eye. People did not even know that cells existed until the microscopes
    were invented.




Discovery of Cell
   In 1665, An Englishman, Robert Hooke, looked at a thin slice of cork through his
    two-lens microscope. He observed some tiny, hollow structures and called them
    ‘cells’.




    Hooke's microscope                      Cork cells under Hook's microscope



   The ‘cells’ Hooke observed were in fact the cell walls of dead cork cells.
    However, no one knew about the existence of cell walls at that time.




HKDSE Biology                           5                  By Michael Ho~*
Lecture Notes – Cell Biology

Cell Theory
   In 1839, Schwann proposed the 'cell theory'.

   The cell theory states that:

    1. All organisms are made up of one or more cells.
    2. The cell is the basic unit of life; it is the smallest unit that
       shows all the characteristics of life.
    3. All cells come from pre-existing cells.




      Modern light microscope                             Electron microscope


    Large organelles in cell are discovered        More organelles are discovered and
                                                           studied in details




        maximum resolution ~0.2 m                   maximum resolution ~200 nm




HKDSE Biology                             6               By Michael Ho~*
Lecture Notes – Cell Biology

Light microscope
   The light microscope can produce an image magnified by up to 1000 times.

   The maximum resolution is about 0.2 m.



Procedure in using the Light Microscope
1. Place the microscope in a well-lit area
2. Position the low power objective lens above the stage hole
3. Adjust the mirror and the diaphragm to provide the best illumination
4. Clip the slide on the stage
5. While watching from the side, turn the coarse focus knob to lower the objective
   lens until it almost touches the slide
6. Look through the eyepiece. Turn the coarse focus knob counter-clockwise to
   bring the low power objective lens until a clear image is seen
7. If necessary, change to a high power objective lens
8. Adjust the fine focus knob to get a sharper image



Preparing Onion Tissue Sample




HKDSE Biology                            7                  By Michael Ho~*
Lecture Notes – Cell Biology

Transmission electron microscope
   The transmission electron microscope makes use of electron beams that pass
    through the specimen to form an image.

   It produces two-dimensional, black and white
    images magnified by up to 800,000 times.




Scanning electron microscope
   The scanning electron microscope makes use of an electron beam to scan over
    the surface of a specimen.

   It produces three-dimensional, black and white
    images magnified by up to 30,000 times.




Advantages of electron microscopy
   electrons have a shorter wavelength than light, providing a higher resolution
   the maximum useful magnification is higher than that of light microscope


Disadvantages of electron microscopy
   Specimens are always dead and so the structure of a living specimen using
    electron microscope can NEVER be studied
   The processes involved in preparing specimens might damage / distort their true
    structure




HKDSE Biology                            8                   By Michael Ho~*
Lecture Notes – Cell Biology
Resolution and Magnification
Resolution: The ability to distinguish between structures that are very close together
Magnification: The ratio of the size of an object and its image


                       Magnification =



      Unit of length                     Symbol                      Factor
       Gigametre                           Gm
       Megametre                           Mm
        Kilometre                          km
          Metre                             m
       Centimetre                          cm
        Millimetre                         mm
       Micrometre                          m
       Nanometre                           nm
       Picometre                           pm



Concept Check
1.    The following is the compound light microscope.




Eyepiece of 50x and objective of 100x was used,
the magnification of the image would be ________________ = ________


HKDSE Biology                              9                  By Michael Ho~*
Lecture Notes – Cell Biology
2.   The following shows the images produced by 2 types of microscope.




            _________________                _________________




                     ______________________________



HKDSE Biology                        10                 By Michael Ho~*
Lecture Notes – Cell Biology
3.




     (a)       What is the type of microscope used for studying this cell?                                          (1 mark)


     ..............................................................................................................................

     (b)       The cell was stained with uranium salts in preparation for a
               transmission electron microscope. Explain how this stain caused the
               nucleus to show a dark shade compared to the light shade of the
               cytoplasm.                                                 (4 marks)


     ..............................................................................................................................

     ..............................................................................................................................

     ..............................................................................................................................
      (c)      Calculate the actual length of the nucleus.                                                        (2 marks)


     ..............................................................................................................................
      (d)      Distinguish the terms resolution and magnification.                                                (2 marks)


     ..............................................................................................................................

     ..............................................................................................................................
      (e)      Determine the magnification of this micrograph.                                                    (2 marks)


     ..............................................................................................................................


HKDSE Biology                                              11                              By Michael Ho~*
Lecture Notes – Cell Biology

Prokaryotae and Eukaryotae
              Prokaryotae                                Eukaryotae

lack a distinct nucleus bounded by a have a true nucleus that is separated
membrane                             from cytoplasm by a nuclear envelope

lack membrane-bound organelles such cytoplasm         contains   membrane-bound
as mitochondria and chloroplasts    organelles

infolding of cell membrane        forms mitochondria for respiration
mesosomes for respiration

Single circular DNA and some small Genetic material (DNA) is carried on a
circular DNA called plasmids in number of chromosomes
cytoplasm



Prokaryotic cell
Prokaryotae are a kingdom of organisms including the bacteria and cyanobacteria.




HKDSE Biology                          12                  By Michael Ho~*
Lecture Notes – Cell Biology

Eukaryotic Cell




HKDSE Biology                  13   By Michael Ho~*
Lecture Notes – Cell Biology
1. Nucleus
  a) Structure

        It is enclosed by a nuclear membrane of double membranes that is
         perforated by nuclear pore.

        It contains chromatin.

        It is enclosed by a nuclear membrane of double membranes that is
         perforated by nuclear pore.

        It contains chromatin.




HKDSE Biology                     14               By Michael Ho~*
Lecture Notes – Cell Biology




  b) General functions of nucleus

            It contains genetic materials (DNA) and can be able to synthesize DNA.

            It synthesizes genetic messages (mRNA) to be transported to cytoplasm
             through nuclear pore for protein synthesis.



2. Cytoplasm
         It contains water and dissolved substances.

         Function: It is the site of cellular activities.



3. Endoplasmic Reticulum (ER)
  a) Structure

            It is the complex network of folded membranes running throughout the
             cytoplasm. It consists of two types: rough ER and smooth ER.

            Rough ER has many ribosomes attached on the outer surface while
             smooth ER has none.




HKDSE Biology                                  15            By Michael Ho~*
Lecture Notes – Cell Biology
  b) Function

  (i)      Rough ER
          Rough ER is concerned with the transport of protein synthesized by ribosomes
           on its surface.




  (ii)     Smooth ER
          Smooth ER is concerned with the synthesis and transport of lipids and steroids.




HKDSE Biology                             16                 By Michael Ho~*
Lecture Notes – Cell Biology
4. Mitochondrion




  a) Structure

        rod-shaped, bounded by a double membrane.

        outer membrane is smooth while inner membrane is highly folded.
  b) Function

        it carries out aerobic respiration, producing ATP molecules which are the
         form of energy to drive cellular activity.




HKDSE Biology                         17                 By Michael Ho~*
Lecture Notes – Cell Biology
5. Chloroplast (found in some plant cells only)




  a) Structure

            It contains chlorophyll to absorb light for photosynthesis.

            It is surrounded by double membranes and contains a system of flattened
             membrane-bond sacs to hold chlorophyll.
  b) Function

          It is the site of photosynthesis producing sugars from carbon dioxide and
           water using light energy trapped by chlorophyll.

          it converts light energy to chemical energy.



HKDSE Biology                               18                   By Michael Ho~*
Lecture Notes – Cell Biology
6. Vacuole
    a) Structure

           It is a fluid-filled sac bounded by a membrane.

           Plant cells usually have a large central vacuole which is surrounded by a
            membrane called tonoplast and contains a fluid called cell sap.
    b) Functions

           It helps keep plant cells in a turgid state.

           Osmotic uptake of water results in cell expansion during cell growth.

           It is used for the storage of water and food, etc.

           It provides a place to hold harmful substances or metabolic wastes so as
            not to interfere the normal metabolism of the cytoplasm.



7. Cell Wall
    It is made up of cellulose and is therefore rigid.

    It is fully permeable.

    Function: gives shape, support and protection to the cell.




Structural Differences between a Plant Cell and an Animal Cell
                 Plant cell                                      Animal cell

               has cell wall                                 has NO cell wall

            has large vacuole                              has NO large vacuole

             has chloroplasts                              has NO chloroplasts




HKDSE Biology                               19                     By Michael Ho~*
Lecture Notes – Cell Biology
Concept Check




HKDSE Biology                  20   By Michael Ho~*
Lecture Notes – Cell Biology

Cell Membrane
1. Chemical composition
   membranes isolated from red blood cells were chemically analyzed and found to
    be composed of phospholipids and proteins.




HKDSE Biology                         21                 By Michael Ho~*
Lecture Notes – Cell Biology
2. Model of membrane structure
    Cell membranes are actually phospholipid bilayers. Such a bilayer could exist as
     a stable boundary between 2 aqueous media, because the molecular
     arrangement shelters the hydrophobic tails from water, while exposing the
     hydrophilic heads to water.

    Fluid Mosaic Model




     The membrane is a fluid phospholipid bilayer with a mosaic of protein
      molecules floats in it.

     Both phospholipid and protein molecules are mobile to varying degree within
      the membrane which is therefore, regarded as a fluid structure.

     Proteins penetrate into the hydrophobic interior of the membrane - some
      penetrate only part of the way into the membrane while others penetrate all
      the way through.

     The arrangement of proteins varies according to the type and function of the
      membrane.

HKDSE Biology                            22                 By Michael Ho~*
Lecture Notes – Cell Biology
3. Properties of membranes
    Selective permeability

     Hydrophobic / non-polar / water-insoluble substances and simple, small
      molecules can move across the phospholipid bilayer freely.

     Ions / water / water-soluble substances can move across the membrane
      through the channel proteins or carrier proteins.

    Fluidity of membranes

     The phospholipid and some protein molecules can move laterally.

     It allows the membrane to change its shape and fuse itself during cell division.

    Specific in function
     Different membranes have their unique collections of proteins which determine
     most of the membrane’s specific functions.



Functions of membrane proteins:

    Membrane protein                                  Function


      channel protein         to transport certain ions and water-soluble substances



       carrier protein        needed in active transport



      receptor protein        to receive chemical signals



          enzyme              to speed up reactions in the cell


                              with antigen molecules attached to form glycoprotein for
    recognition protein
                              recognition purposes




HKDSE Biology                             23                      By Michael Ho~*
Lecture Notes – Cell Biology

Mechanisms of Membrane Transport
1. By diffusion




   Diffusion is the net movement of particles down a concentration gradient / from
    a region of higher concentration to a region of lower concentration.

   When the particles have become evenly distributed (i.e. concentration gradient =
    0), there will be no net movement of particles.

   No metabolic energy is required, hence no ATP is required.

   The diffusion of a substance will be unaffected by concentration differences of
    other substances.

   The diffusion rate is determined by:
    1. diffusion distance
    2. temperature
    3. size
    4. shape                     of the substance
    5. electrical charges




HKDSE Biology                              24              By Michael Ho~*
Lecture Notes – Cell Biology
2. By active transport




   It is the movement of substances across the cell membrane in the expense of
    energy from respiration (ATP is required).

   Substances can be moved against a concentration gradient, i.e. from a region of
    lower concentration to a region of higher concentration.

   The substance is moved in one direction only.

   Specific carriers (proteins) are required.




Examples:
- food absorption at the small intestine: By _______________ + ________________
- absorption of some minerals by roots: By _______________ + ________________




HKDSE Biology                             25               By Michael Ho~*
Lecture Notes – Cell Biology
3. By phagocytosis
   It is the intake of large solid particles (e.g. cells) by invagination of cell
    membrane, forming a food vacuole.




   It is carried out by some single-celled organisms (e.g. Amoeba) and certain
    types of white blood cells.

   It requires energy and must involve the cell membrane.


4. By osmosis




   It refers to the net movement of water molecules from a region of higher water
    potential to a region of lower water potential (down a potential gradient)
    across a selectively permeable membrane.



HKDSE Biology                          26                    By Michael Ho~*
Lecture Notes – Cell Biology
  a) Water potential ()
     It is the tendency of water molecules to move.

     The more solute dissolved in water, the lower is its water potential.

     Since the water potential of pure water is defined as zero, the water
      potential of solutions always a negative value.




  b) Water relations in animal cells
     In hypotonic solution:
       1. water potential of the external solution is higher than that if the cell
       2. water enters the cell by osmosis
       3. cell becomes swell and then burst



     In hypertonic solution:
       1. water potential of the external solution is lower than that of the cell
       2. water leaves the cell by osmosis
       3. cell becomes shrinks



     In isotonic solution: cell has no change in size and shape




HKDSE Biology                           27                   By Michael Ho~*
Lecture Notes – Cell Biology
     c) Water relations in plant cells
        In hypotonic solution: The cell becomes turgid

          ∵ The rigid cell wall prevents the cell form bursting



        In hypertonic solution:
          The cell becomes plasmolysed (its cytoplasm shrinks and detaches from
          the cell wall)



        In isotonic solution: The cell becomes flaccid




Concept Check
1.     One end of the middle portion of a spring onion leaf has been cut lengthwise
       into 4 sections and then immersed in different concentration of sucrose
       solution. Arrange the solutions in ascending concentration.




2.     Why is it incorrect to say that 'sea water is a hypertonic solution'.   (1 mark)




HKDSE Biology                              28                    By Michael Ho~*
Lecture Notes – Cell Biology




In hypotonic solution                   In isotonic solution            In hypertonic solution


 In the cells of the epidermis of the leaf of certain plants that contain colored pigment,
 the liquid inside the vacuoles are colored. They can be seen under the microscope
 without staining.




        Normal condition                                         Plasmolysed condition


 Concept Check
 Why can plasmolysis not take place in an animal cell?                         (2 marks)




 HKDSE Biology                              29                   By Michael Ho~*
Lecture Notes – Cell Biology
Type 1 – Dialysis Tubing
Dialysis tubing:




        differentially permeable

        has many small pores which allow small molecules (e.g. water, glucose, ions) to
         pass through but not large ones (e.g. sucrose, proteins)

    Before carrying out the experiment, make sure that
    1.      the knot of the dialysis tubing should be tied tightly
    2.      the outside of the dialysis tubing should be rinsed with distilled water
    3.      the dialysis tubing should be examined for any damage




(a)        Describe and explain the change in the water level of the capillary tube in set-
           up A.                                                                (3 marks)


........................................................................................................................................
........................................................................................................................................
........................................................................................................................................
(b)        Describe and explain the change in the water level of the capillary tube in set-
           up B.                                                                (3 marks)


........................................................................................................................................
........................................................................................................................................
........................................................................................................................................


HKDSE Biology                                                    30                              By Michael Ho~*
Lecture Notes – Cell Biology
Type 2 – Potato Container




(a)       Explain the level of solution inside the 'potato bowl' in set-up A after 12 hours.
                                                                                 (4 marks)


........................................................................................................................................

........................................................................................................................................

........................................................................................................................................

........................................................................................................................................


(b)       Explain the level of solution inside the 'potato bowl' in set-up B after 12 hours.
                                                                                 (4 marks)


........................................................................................................................................

........................................................................................................................................

........................................................................................................................................

........................................................................................................................................




HKDSE Biology                                                    31                              By Michael Ho~*
Lecture Notes – Cell Biology
Type 3 – Potato Strip
A 10cm long potato strip was placed in a sugar solution. Its length was measured at
regular intervals over a period of 3 hours. The results are shown in the table below:

                       Time (hour)                            Length of the potato strip (cm)

                              0                                                   10.0
                             0.5                                                   9.7
                             1.0                                                   9.4
                             1.5                                                   9.1
                             2.0                                                   8.9
                             2.5                                                   8.8
                             3.0                                                   8.8

(a)       Explain the change in length of the potato strip in the first hour.                                         (4 marks)


........................................................................................................................................

........................................................................................................................................

........................................................................................................................................

........................................................................................................................................
(b)       (i)        Which period of time does the length of potato strip remain unchanged?
                                                                                                                      (1 mark)


........................................................................................................................................

          (ii)       Explain why there was no change in length during this period?
                                                                                                                      (2 marks)


........................................................................................................................................

........................................................................................................................................

(c)       What perimeter can be measured instead of the length of potato strip?
                                                                                                                      (1 mark)


........................................................................................................................................




HKDSE Biology                                                    32                              By Michael Ho~*

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Similar a 1. Light microscope2. Scanning electron microscope produces 3D images while transmission electron microscope produces higher resolution 2D images. 3. (a) Transmission electron microscope (b) Uranium salts are electron dense stains. They absorb more electrons in the transmission electron microscope. The nucleus which contains DNA absorbs more stain compared to the cytoplasm. This makes the nucleus appear darker than the lighter stained cytoplasm. (c) Actual length of nucleus = Length shown in image x Magnification = 1.2 μm x 30,000 = 36,000 nm = 36 μm (d) Resolution is the ability to distinguish between structures that are very close together. Magnification is the ratio of the size

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1. Light microscope2. Scanning electron microscope produces 3D images while transmission electron microscope produces higher resolution 2D images. 3. (a) Transmission electron microscope (b) Uranium salts are electron dense stains. They absorb more electrons in the transmission electron microscope. The nucleus which contains DNA absorbs more stain compared to the cytoplasm. This makes the nucleus appear darker than the lighter stained cytoplasm. (c) Actual length of nucleus = Length shown in image x Magnification = 1.2 μm x 30,000 = 36,000 nm = 36 μm (d) Resolution is the ability to distinguish between structures that are very close together. Magnification is the ratio of the size

  • 1. Lecture Notes – Cell Biology HKDSE Biology 1 By Michael Ho~*
  • 2. Lecture Notes – Cell Biology Molecules of Life 1. Water  Water (H2O) is the most abundant compound on Earth’s surface and it is essential for all life on Earth.  A water molecule consists of two hydrogen atoms covalently bonded to one oxygen atom.  Attractive forces (hydrogen bonds) form between water molecules. These hydrogen bonds are sufficiently strong to create many of the properties of water. Biological Functions 1. Freezing Properties Ice is less dense than water and hence ice floats on water surface, insulating the aquatic organisms below. It allows aquatic animals to survive in cold region. 2. High Latent Heat of Fusion Large amount of energy has to be removed from water to form ice. The aquatic environment and cell contents are slow to freeze in cold weather. 3. High Latent Heat of Evaporation Large amount of energy is required for evaporation of water. It increases heat loss and provides an effective cooling effect to mammals through sweating and plants through transpiration. 4. High Specific Heat Capacity Large amount of energy is required to change the temperature. Water helps to keep the temperature constant and hence provides a stable environment for aquatic life. 5. High Transparency Light can penetrate through water which allows photosynthesis of underwater plants and vision for aquatic animals. 6. High Surface Tension and Adhesion Water molecules are held together by hydrogen bonds which allow formation of a continuous water column in plants for water transport. HKDSE Biology 2 By Michael Ho~*
  • 3. Lecture Notes – Cell Biology 7. High Polarity Water is a universal solvent due to its high polarity. Water can dissolve many substances and hence facilitates chemical reactions and serves as transport medium. 8. Incompressibility Water is incompressible and provides turgidity for plants and support for animals with hydro-skeleton. 2. Biomolecules  A biomolecule is any molecule that is produced by a living organism, including Carbohydrates, Proteins, Lipids and nucleic acids. Function Carbohydrates  as main source of energy - oxidized to release energy  as an energy reserve Lipids  form an insulator under skin to reduce heat loss Proteins  build up body tissues for growth and repair (polypeptides)  as enzymes to speed up reactions Nucleic acids  carry genetic information (DNA and RNA) HKDSE Biology 3 By Michael Ho~*
  • 4. Lecture Notes – Cell Biology 3. Inorganic Ions  Inorganic ions are vital for cellular activities in animals and plants. Biological Functions 1. Sodium ions (Na+)  take part in the transmission of nerve impulse  maintain osmotic balance 2. Potassium ions (K+)  take part in the transmission of nerve impulse  maintain osmotic balance 3. Calcium ions (Ca2+)  take part in the transmission of nerve impulse  chemical component of bones and teeth 4. Iron ions (Fe2+)  chemical component of haemoglobin in red blood cells 5. Magnesium ions (Mg2+)  chemical component of bones and teeth as well as chlorophyll 6. Nitrate ions (NO3-)  synthesis of amino acids and nucleotides 7. Phosphate ions (PO4-)  synthesis of phospholipids, ATPs, bones and teeth HKDSE Biology 4 By Michael Ho~*
  • 5. Lecture Notes – Cell Biology Microscope Development and Cell Theory  Organisms are made up of cells. Cells are very small and cannot be seen with the naked eye. People did not even know that cells existed until the microscopes were invented. Discovery of Cell  In 1665, An Englishman, Robert Hooke, looked at a thin slice of cork through his two-lens microscope. He observed some tiny, hollow structures and called them ‘cells’. Hooke's microscope Cork cells under Hook's microscope  The ‘cells’ Hooke observed were in fact the cell walls of dead cork cells. However, no one knew about the existence of cell walls at that time. HKDSE Biology 5 By Michael Ho~*
  • 6. Lecture Notes – Cell Biology Cell Theory  In 1839, Schwann proposed the 'cell theory'.  The cell theory states that: 1. All organisms are made up of one or more cells. 2. The cell is the basic unit of life; it is the smallest unit that shows all the characteristics of life. 3. All cells come from pre-existing cells. Modern light microscope Electron microscope Large organelles in cell are discovered More organelles are discovered and studied in details maximum resolution ~0.2 m maximum resolution ~200 nm HKDSE Biology 6 By Michael Ho~*
  • 7. Lecture Notes – Cell Biology Light microscope  The light microscope can produce an image magnified by up to 1000 times.  The maximum resolution is about 0.2 m. Procedure in using the Light Microscope 1. Place the microscope in a well-lit area 2. Position the low power objective lens above the stage hole 3. Adjust the mirror and the diaphragm to provide the best illumination 4. Clip the slide on the stage 5. While watching from the side, turn the coarse focus knob to lower the objective lens until it almost touches the slide 6. Look through the eyepiece. Turn the coarse focus knob counter-clockwise to bring the low power objective lens until a clear image is seen 7. If necessary, change to a high power objective lens 8. Adjust the fine focus knob to get a sharper image Preparing Onion Tissue Sample HKDSE Biology 7 By Michael Ho~*
  • 8. Lecture Notes – Cell Biology Transmission electron microscope  The transmission electron microscope makes use of electron beams that pass through the specimen to form an image.  It produces two-dimensional, black and white images magnified by up to 800,000 times. Scanning electron microscope  The scanning electron microscope makes use of an electron beam to scan over the surface of a specimen.  It produces three-dimensional, black and white images magnified by up to 30,000 times. Advantages of electron microscopy  electrons have a shorter wavelength than light, providing a higher resolution  the maximum useful magnification is higher than that of light microscope Disadvantages of electron microscopy  Specimens are always dead and so the structure of a living specimen using electron microscope can NEVER be studied  The processes involved in preparing specimens might damage / distort their true structure HKDSE Biology 8 By Michael Ho~*
  • 9. Lecture Notes – Cell Biology Resolution and Magnification Resolution: The ability to distinguish between structures that are very close together Magnification: The ratio of the size of an object and its image Magnification = Unit of length Symbol Factor Gigametre Gm Megametre Mm Kilometre km Metre m Centimetre cm Millimetre mm Micrometre m Nanometre nm Picometre pm Concept Check 1. The following is the compound light microscope. Eyepiece of 50x and objective of 100x was used, the magnification of the image would be ________________ = ________ HKDSE Biology 9 By Michael Ho~*
  • 10. Lecture Notes – Cell Biology 2. The following shows the images produced by 2 types of microscope. _________________ _________________ ______________________________ HKDSE Biology 10 By Michael Ho~*
  • 11. Lecture Notes – Cell Biology 3. (a) What is the type of microscope used for studying this cell? (1 mark) .............................................................................................................................. (b) The cell was stained with uranium salts in preparation for a transmission electron microscope. Explain how this stain caused the nucleus to show a dark shade compared to the light shade of the cytoplasm. (4 marks) .............................................................................................................................. .............................................................................................................................. .............................................................................................................................. (c) Calculate the actual length of the nucleus. (2 marks) .............................................................................................................................. (d) Distinguish the terms resolution and magnification. (2 marks) .............................................................................................................................. .............................................................................................................................. (e) Determine the magnification of this micrograph. (2 marks) .............................................................................................................................. HKDSE Biology 11 By Michael Ho~*
  • 12. Lecture Notes – Cell Biology Prokaryotae and Eukaryotae Prokaryotae Eukaryotae lack a distinct nucleus bounded by a have a true nucleus that is separated membrane from cytoplasm by a nuclear envelope lack membrane-bound organelles such cytoplasm contains membrane-bound as mitochondria and chloroplasts organelles infolding of cell membrane forms mitochondria for respiration mesosomes for respiration Single circular DNA and some small Genetic material (DNA) is carried on a circular DNA called plasmids in number of chromosomes cytoplasm Prokaryotic cell Prokaryotae are a kingdom of organisms including the bacteria and cyanobacteria. HKDSE Biology 12 By Michael Ho~*
  • 13. Lecture Notes – Cell Biology Eukaryotic Cell HKDSE Biology 13 By Michael Ho~*
  • 14. Lecture Notes – Cell Biology 1. Nucleus a) Structure  It is enclosed by a nuclear membrane of double membranes that is perforated by nuclear pore.  It contains chromatin.  It is enclosed by a nuclear membrane of double membranes that is perforated by nuclear pore.  It contains chromatin. HKDSE Biology 14 By Michael Ho~*
  • 15. Lecture Notes – Cell Biology b) General functions of nucleus  It contains genetic materials (DNA) and can be able to synthesize DNA.  It synthesizes genetic messages (mRNA) to be transported to cytoplasm through nuclear pore for protein synthesis. 2. Cytoplasm  It contains water and dissolved substances.  Function: It is the site of cellular activities. 3. Endoplasmic Reticulum (ER) a) Structure  It is the complex network of folded membranes running throughout the cytoplasm. It consists of two types: rough ER and smooth ER.  Rough ER has many ribosomes attached on the outer surface while smooth ER has none. HKDSE Biology 15 By Michael Ho~*
  • 16. Lecture Notes – Cell Biology b) Function (i) Rough ER  Rough ER is concerned with the transport of protein synthesized by ribosomes on its surface. (ii) Smooth ER  Smooth ER is concerned with the synthesis and transport of lipids and steroids. HKDSE Biology 16 By Michael Ho~*
  • 17. Lecture Notes – Cell Biology 4. Mitochondrion a) Structure  rod-shaped, bounded by a double membrane.  outer membrane is smooth while inner membrane is highly folded. b) Function  it carries out aerobic respiration, producing ATP molecules which are the form of energy to drive cellular activity. HKDSE Biology 17 By Michael Ho~*
  • 18. Lecture Notes – Cell Biology 5. Chloroplast (found in some plant cells only) a) Structure  It contains chlorophyll to absorb light for photosynthesis.  It is surrounded by double membranes and contains a system of flattened membrane-bond sacs to hold chlorophyll. b) Function  It is the site of photosynthesis producing sugars from carbon dioxide and water using light energy trapped by chlorophyll.  it converts light energy to chemical energy. HKDSE Biology 18 By Michael Ho~*
  • 19. Lecture Notes – Cell Biology 6. Vacuole a) Structure  It is a fluid-filled sac bounded by a membrane.  Plant cells usually have a large central vacuole which is surrounded by a membrane called tonoplast and contains a fluid called cell sap. b) Functions  It helps keep plant cells in a turgid state.  Osmotic uptake of water results in cell expansion during cell growth.  It is used for the storage of water and food, etc.  It provides a place to hold harmful substances or metabolic wastes so as not to interfere the normal metabolism of the cytoplasm. 7. Cell Wall  It is made up of cellulose and is therefore rigid.  It is fully permeable.  Function: gives shape, support and protection to the cell. Structural Differences between a Plant Cell and an Animal Cell Plant cell Animal cell has cell wall has NO cell wall has large vacuole has NO large vacuole has chloroplasts has NO chloroplasts HKDSE Biology 19 By Michael Ho~*
  • 20. Lecture Notes – Cell Biology Concept Check HKDSE Biology 20 By Michael Ho~*
  • 21. Lecture Notes – Cell Biology Cell Membrane 1. Chemical composition  membranes isolated from red blood cells were chemically analyzed and found to be composed of phospholipids and proteins. HKDSE Biology 21 By Michael Ho~*
  • 22. Lecture Notes – Cell Biology 2. Model of membrane structure  Cell membranes are actually phospholipid bilayers. Such a bilayer could exist as a stable boundary between 2 aqueous media, because the molecular arrangement shelters the hydrophobic tails from water, while exposing the hydrophilic heads to water.  Fluid Mosaic Model  The membrane is a fluid phospholipid bilayer with a mosaic of protein molecules floats in it.  Both phospholipid and protein molecules are mobile to varying degree within the membrane which is therefore, regarded as a fluid structure.  Proteins penetrate into the hydrophobic interior of the membrane - some penetrate only part of the way into the membrane while others penetrate all the way through.  The arrangement of proteins varies according to the type and function of the membrane. HKDSE Biology 22 By Michael Ho~*
  • 23. Lecture Notes – Cell Biology 3. Properties of membranes  Selective permeability  Hydrophobic / non-polar / water-insoluble substances and simple, small molecules can move across the phospholipid bilayer freely.  Ions / water / water-soluble substances can move across the membrane through the channel proteins or carrier proteins.  Fluidity of membranes  The phospholipid and some protein molecules can move laterally.  It allows the membrane to change its shape and fuse itself during cell division.  Specific in function Different membranes have their unique collections of proteins which determine most of the membrane’s specific functions. Functions of membrane proteins: Membrane protein Function channel protein to transport certain ions and water-soluble substances carrier protein needed in active transport receptor protein to receive chemical signals enzyme to speed up reactions in the cell with antigen molecules attached to form glycoprotein for recognition protein recognition purposes HKDSE Biology 23 By Michael Ho~*
  • 24. Lecture Notes – Cell Biology Mechanisms of Membrane Transport 1. By diffusion  Diffusion is the net movement of particles down a concentration gradient / from a region of higher concentration to a region of lower concentration.  When the particles have become evenly distributed (i.e. concentration gradient = 0), there will be no net movement of particles.  No metabolic energy is required, hence no ATP is required.  The diffusion of a substance will be unaffected by concentration differences of other substances.  The diffusion rate is determined by: 1. diffusion distance 2. temperature 3. size 4. shape of the substance 5. electrical charges HKDSE Biology 24 By Michael Ho~*
  • 25. Lecture Notes – Cell Biology 2. By active transport  It is the movement of substances across the cell membrane in the expense of energy from respiration (ATP is required).  Substances can be moved against a concentration gradient, i.e. from a region of lower concentration to a region of higher concentration.  The substance is moved in one direction only.  Specific carriers (proteins) are required. Examples: - food absorption at the small intestine: By _______________ + ________________ - absorption of some minerals by roots: By _______________ + ________________ HKDSE Biology 25 By Michael Ho~*
  • 26. Lecture Notes – Cell Biology 3. By phagocytosis  It is the intake of large solid particles (e.g. cells) by invagination of cell membrane, forming a food vacuole.  It is carried out by some single-celled organisms (e.g. Amoeba) and certain types of white blood cells.  It requires energy and must involve the cell membrane. 4. By osmosis  It refers to the net movement of water molecules from a region of higher water potential to a region of lower water potential (down a potential gradient) across a selectively permeable membrane. HKDSE Biology 26 By Michael Ho~*
  • 27. Lecture Notes – Cell Biology a) Water potential ()  It is the tendency of water molecules to move.  The more solute dissolved in water, the lower is its water potential.  Since the water potential of pure water is defined as zero, the water potential of solutions always a negative value. b) Water relations in animal cells  In hypotonic solution: 1. water potential of the external solution is higher than that if the cell 2. water enters the cell by osmosis 3. cell becomes swell and then burst  In hypertonic solution: 1. water potential of the external solution is lower than that of the cell 2. water leaves the cell by osmosis 3. cell becomes shrinks  In isotonic solution: cell has no change in size and shape HKDSE Biology 27 By Michael Ho~*
  • 28. Lecture Notes – Cell Biology c) Water relations in plant cells  In hypotonic solution: The cell becomes turgid ∵ The rigid cell wall prevents the cell form bursting  In hypertonic solution: The cell becomes plasmolysed (its cytoplasm shrinks and detaches from the cell wall)  In isotonic solution: The cell becomes flaccid Concept Check 1. One end of the middle portion of a spring onion leaf has been cut lengthwise into 4 sections and then immersed in different concentration of sucrose solution. Arrange the solutions in ascending concentration. 2. Why is it incorrect to say that 'sea water is a hypertonic solution'. (1 mark) HKDSE Biology 28 By Michael Ho~*
  • 29. Lecture Notes – Cell Biology In hypotonic solution In isotonic solution In hypertonic solution In the cells of the epidermis of the leaf of certain plants that contain colored pigment, the liquid inside the vacuoles are colored. They can be seen under the microscope without staining. Normal condition Plasmolysed condition Concept Check Why can plasmolysis not take place in an animal cell? (2 marks) HKDSE Biology 29 By Michael Ho~*
  • 30. Lecture Notes – Cell Biology Type 1 – Dialysis Tubing Dialysis tubing:  differentially permeable  has many small pores which allow small molecules (e.g. water, glucose, ions) to pass through but not large ones (e.g. sucrose, proteins) Before carrying out the experiment, make sure that 1. the knot of the dialysis tubing should be tied tightly 2. the outside of the dialysis tubing should be rinsed with distilled water 3. the dialysis tubing should be examined for any damage (a) Describe and explain the change in the water level of the capillary tube in set- up A. (3 marks) ........................................................................................................................................ ........................................................................................................................................ ........................................................................................................................................ (b) Describe and explain the change in the water level of the capillary tube in set- up B. (3 marks) ........................................................................................................................................ ........................................................................................................................................ ........................................................................................................................................ HKDSE Biology 30 By Michael Ho~*
  • 31. Lecture Notes – Cell Biology Type 2 – Potato Container (a) Explain the level of solution inside the 'potato bowl' in set-up A after 12 hours. (4 marks) ........................................................................................................................................ ........................................................................................................................................ ........................................................................................................................................ ........................................................................................................................................ (b) Explain the level of solution inside the 'potato bowl' in set-up B after 12 hours. (4 marks) ........................................................................................................................................ ........................................................................................................................................ ........................................................................................................................................ ........................................................................................................................................ HKDSE Biology 31 By Michael Ho~*
  • 32. Lecture Notes – Cell Biology Type 3 – Potato Strip A 10cm long potato strip was placed in a sugar solution. Its length was measured at regular intervals over a period of 3 hours. The results are shown in the table below: Time (hour) Length of the potato strip (cm) 0 10.0 0.5 9.7 1.0 9.4 1.5 9.1 2.0 8.9 2.5 8.8 3.0 8.8 (a) Explain the change in length of the potato strip in the first hour. (4 marks) ........................................................................................................................................ ........................................................................................................................................ ........................................................................................................................................ ........................................................................................................................................ (b) (i) Which period of time does the length of potato strip remain unchanged? (1 mark) ........................................................................................................................................ (ii) Explain why there was no change in length during this period? (2 marks) ........................................................................................................................................ ........................................................................................................................................ (c) What perimeter can be measured instead of the length of potato strip? (1 mark) ........................................................................................................................................ HKDSE Biology 32 By Michael Ho~*