1. Characteristics of Sinusoidal
Phasors
Phasor Relationships for R, L and C
Impedance
Parallel and Series Resonance
Examples for Sinusoidal Circuits Analysis
Single Phase AC
2. Sinusoidal Steady State Analysis
• Any steady state voltage or current in a linear circuit with a
sinusoidal source is a sinusoid
– All steady state voltages and currents have the same frequency as
the source
• In order to find a steady state voltage or current, all we need to know
is its magnitude and its phase relative to the source (we already know
its frequency)
• We do not have to find this differential equation from the circuit, nor
do we have to solve it
• Instead, we use the concepts of phasors and complex impedances
• Phasors and complex impedances convert problems involving
differential equations into circuit analysis problems
4. Characteristics of Sinusoids :
tVv mt sin iI1
I1
I1 I1 I1 I1
R1
R1
R
5
5
+
_
IS
E
I1
U1
+
-
U
I
iI1 I1 I1 I1
R1
R1
R
5
5
-
+
IS
E
I1
U1
+
-
U
I
v ,i
tt1 t20
Both the polarity and magnitude of voltage are changing.
5. Radian frequency(Angular frequency): = 2f = 2/T (rad/s)
Time Period: T — Time necessary to go through one cycle. (s)
Frequency: f — Cycles per second. (Hz)
f = 1/T
Amplitude: Vm Im
i = Imsint, v =Vmsint
v ,i
t 20
Vm , Im
Characteristics of Sinusoids :
6. Effective Roof Mean Square (RMS) Value of a Periodic
Waveform — is equal to the value of the direct current which is
flowing through an R-ohm resistor. It delivers the same average
power to the resistor as the periodic current does.
RIRdti
T
T
2
0
21
Effective Value of a Periodic Waveform
T
eff dti
T
I
0
21
22
1
2
2cos1
sin
1 2
0
2
0
22 m
m
T
m
T
meff
IT
I
T
dt
t
T
I
tdtI
T
I
2
1
0
2 m
T
eff
V
dtv
T
V
Characteristics of Sinusoids :
7. Phase (angle)
tIi m sin
sin0 mIi
Phase angle
-8
-6
-4
-2
0
2
4
6
8
0 0.01 0.02 0.03 0.04 0.05
<0
0
Characteristics of Sinusoids :
8. )sin( 1 tVv m
)sin( 2 tIi m
Phase difference
2121 )( ttiv
021 — v(t) leads i(t) by (1 - 2), or i(t) lags v(t) by (1 - 2)
2
21
v, i
t
v
i
21
Out of phase
t
v, i
v
i
v, i
t
v
i
021
In phase
021 — v(t) lags i(t) by (2 - 1), or i(t) leads v(t) by (2 - 1)
Characteristics of Sinusoids :
9. Review
The sinusoidal waves whose phases are compared must:
1. Be written as sine waves or cosine waves.
2. With positive amplitudes.
3. Have the same frequency.
360°—— does not change anything.
90° —— change between sin & cos.
180°—— change between + & -
2
sin cos cos
3 2
cos sin
2
Characteristics of Sinusoids :
10. Phase difference
30314sin22201 tv
9030314sin222030314cos22202 ttv
120314sin2220 t
1501203021
30314cos22202 tv
30314cos22202 tv
18030314cos2220 t
210314360cos2220 t
90150314sin2220 t
60314sin2220 t
30603021
Find ?
30314cos22202 tvIf
Characteristics of Sinusoids :
12. Outline:
1. Complex Numbers
2. Rotating Vector
3. Phasors
A sinusoidal voltage/current at a given frequency, is characterized by only
two parameters : amplitude and phase
A phasor is a Complex Number which represents magnitude and phase of a sinusoid
Phasors
13. e.g. voltage response
A sinusoidal v/i
Complex transform
Phasor transform
By knowing angular
frequency ω rads/s.
Time domain
Frequency domain
eR v t
Complex form:
cosmv t V t
Phasor form:
j t
mv t V e
Angular frequency ω is
known in the circuit.
|| mVV
|| mVV
Phasors
14. Rotating Vector
tIti m sin)(
i
Im
t1
i
t
Im
t
x
y
max
cos sin
sin
j t
m m m
j t
m m
I e I t jI t
i t I t I I e
A complex coordinates number:
Real value:
i(t1)
Imag
Phasors
16. Complex Numbers
jbaA — Rectangular Coordinates
sincos jAA
j
eAA — Polar Coordinates
j
eAAjbaA
conversion: 22
baA
a
b
arctg
jbaeA j
cosAa
sinAb
a
b
Real axis
Imaginary axis
jjje j
090sin90cos90
Phasors
17. Complex Numbers
Arithmetic With Complex Numbers
Addition: A = a + jb, B = c + jd, A + B = (a + c) + j(b + d)
Real Axis
Imaginary Axis
AB
A + B
Phasors
18. Complex Numbers
Arithmetic With Complex Numbers
Subtraction : A = a + jb, B = c + jd, A - B = (a - c) + j(b - d)
Real
Axis
Imaginary
Axis
AB
A - B
Phasors
19. Complex Numbers
Arithmetic With Complex Numbers
Multiplication : A = Am A, B = Bm B
A B = (Am Bm) (A + B)
Division: A = Am A , B = Bm B
A / B = (Am / Bm) (A - B)
Phasors
20. Phasors
A phasor is a complex number that represents the magnitude and phase of
a sinusoid:
tim cos mI
Phasor Diagrams
• A phasor diagram is just a graph of several phasors on the complex
plane (using real and imaginary axes).
• A phasor diagram helps to visualize the relationships between currents
and voltages.
Phasors
21. )sin()cos()(
tAjtAeAAe tjtj
)cos(||}Re{
tAAe tj
Complex Exponentials
j
eAA
A real-valued sinusoid is the real part of a complex exponential.
Complex exponentials make solving for AC steady state an
algebraic problem.
Phasors
23. Phasor Relationships for R, L and C
v~i relationship for a resistor
_
v
i
R
+
S
tIt
R
V
R
v
i m
m
sinsin
tVv m sin
Relationship between RMS:
R
V
I
Wave and Phasor diagrams:
v、i
t
v
i
I
V
R
V
I
Resistor
Suppose
24. Time domain Frequency domainResistor
With a resistor θ﹦ϕ, v(t) and i(t) are in phase .
)cos()(
)cos()(
wtIti
wtVtv
m
m
IRV
RIV
eRIeV
eRIeV
mm
j
m
j
m
wtj
m
wtj
m
)()(
Phasor Relationships for R, L and C
25. PowerResistor
_
v
i
R
+
P 0
tItVvip mm sinsin tVI mm 2
sin
t
VI mm
2cos1
2
tIVIV 2cos
v, i
t
v
i
P=IV
T
pdt
T
P
0
1
T
VIdttVI
T 0
2cos1
1
R
V
RIIVP
2
2
• Average Power
• Transient Power
Note: I and V are RMS values.
Phasor Relationships for R, L and C
26. Resistor
, R=10,Find i and Ptv 314sin311
V
V
V m
220
2
311
2
A
R
V
I 22
10
220
ti 314sin222 WIVP 484022220
Phasor Relationships for R, L and C
27. v~i relationshipInductor
dt
di
Lvv AB
tLI
dt
tId
L
dt
di
Lv m
m
cos
sin
90sin tLIm
90sin tVm
t
vdt
L
i
1
t
vdt
L
vdt
L 0
0 11
t
vdt
L
i
0
0
1
tIi m sinSuppose
Phasor Relationships for R, L and C
28. v~i relationshipInductor
90sin tLIm
dt
di
Lv
90sin tVm
LIV mm
Relationship between RMS: LIV
L
V
I
fLLXL 2
For DC,f = 0,XL = 0.
fXL
v(t) leads i(t) by 90º, or i(t) lags v(t) by 90º
Phasor Relationships for R, L and C
29. v ~ i relationshipInductor
v, i
t
v
i
eL
V
I
LXIjV
Wave and Phasor diagrams:
Phasor Relationships for R, L and C
30. PowerInductor
vip tItV mm sin90sin
ttIV mm sincos
t
IV mm
2sin
2
tVI 2sin
P
t
v, i
t
v
i
++
--22
max
2
1
LILIW m
2
00 2
1
LiLidividtW
it
Energy stored:
T T
tdtVI
T
pdt
T
P
0 0
02sin
11
Average Power
Reactive Power
L
L
X
V
XIIVQ
2
2
(Var)
Phasor Relationships for R, L and C
31. Inductor
L = 10mH,v = 100sint,Find iL when f = 50Hz and 50kHz.
14.310105022 3
fLX L
Atti
A
X
V
I
L
L
90sin25.22
5.22
14.3
2/100
50
31401010105022 33
fLX L
mAtti
mA
X
V
I
L
L
k
90sin25.22
5.22
14.3
2/100
50
Phasor Relationships for R, L and C
32. v ~ i relationshipCapacitor
_
v
i
+
C
dt
dv
C
dt
dq
i
tVv m sinSuppose:
90sincos tCVtCVi mm
90sin tIm
t tt
idt
c
vidt
c
idt
c
idt
c
v
0
0
0
0
1111
i(t) leads v(t) by 90º, or v(t) lags i(t) by 90º
Relationship between RMS:
CX
V
C
V
CVI
1
fCC
XC
2
11
For DC,f = 0, XC
f
XC
1
mm CVI
Phasor Relationships for R, L and C
33. _
v
i
+
C
tj
m
tj
m
eCVj
dt
edV
C
dt
tdv
Cti
)(
)(
v(t) = Vm ejt
Represent v(t) and i(t) as phasors:
CjX
V
VCωjI ==
• The derivative in the relationship between v(t) and i(t) becomes a
multiplication by in the relationship between and .
• The time-domain differential equation has become the algebraic equation in the
frequency-domain.
• Phasors allow us to express current-voltage relationships for inductors and
capacitors much like we express the current-voltage relationship for a resistor.
v ~ i relationshipCapacitor
V I
wC
j
Phasor Relationships for R, L and C
34. v ~ i relationshipCapacitor
v, i
t
v
i
I
V
CXIjV
Wave and Phasor diagrams:
Phasor Relationships for R, L and C
35. PowerCapacitor
Average Power: P = 0
Reactive Power
C
C
X
V
XIIVQ
2
2
(Var)
90sinsin tItVvip mm tVIt
IV mm
2sin2sin
2
P
t
v, i
t
v
i
++
--
Energy stored:
t vv
CvCvdvdt
dt
dv
CvvidtW
0 0
2
0 2
1
22
max
2
1
CVCVW m
Phasor Relationships for R, L and C
36. Capacitor
Suppose C=20F,AC source v=100sint,Find XC and I for f = 50Hz,
50kHz。
159
2
11
Hz50
fCC
Xf c
A44.0
2
c
m
c X
V
X
V
I
159.0
2
11
KHz50
fCC
Xf c
A440
2
c
m
c X
V
X
V
I
Phasor Relationships for R, L and C
37. Review (v – i Relationship)
Time domain Frequency domain
iRv IRV
I
Cj
V
1
ILjV
dt
di
LvL
dt
dv
CiC
C
XC
1
LXL ,
,
, v and i are in phase.
, v leads i by 90°.
, v lags i by 90°.
R
C
L
Phasor Relationships for R, L and C
38. Summary:
R: RX R 0
L: ffLLXL 2
2
iv
C:
ffcc
XC
1
2
11
2
iv
IXV
Frequency characteristics of an Ideal Inductor and Capacitor:
A capacitor is an open circuit to DC currents;
A Inductor is a short circuit to DC currents.
Phasor Relationships for R, L and C
40. • AC steady-state analysis using phasors allows us to express the
relationship between current and voltage using a formula that looks
likes Ohm’s law:
ZIV
Complex voltage, Complex current, Complex Impedance
vm
j
m VeVV v
im
j
m IeII i
ZeZe
I
V
I
V
Z jj
m
m iv )(
‘Z’ is called impedance
measured in ohms ()
Impedance (Z)
41. Complex Impedance
ZeZe
I
V
I
V
Z jj
m
m iv )(
Complex impedance describes the relationship between the voltage
across an element (expressed as a phasor) and the current through the
element (expressed as a phasor).
Impedance is a complex number and is not a phasor (why?).
Impedance depends on frequency.
Impedance (Z)
42. Complex Impedance
ZR = R = 0; or ZR = R 0
Resistor——The impedance is R
c
j
c jX
C
j
e
C
Z
21
)
2
(
iv
or
90
1
C
ZC
Capacitor——The impedance is 1/jωC
L
j
L jXLjLeZ
2
)
2
(
iv
or
90 LZL
Inductor——The impedance is jωL
Impedance (Z)
43. Complex Impedance
Impedance in series/parallel can be combined as resistors.
_
U
U
Z1
+
Z2 Zn
I
n
k
kn ZZZZZ
1
21 ...
_
US
In
I1
I1
I1 I1 I1 I1
R1
R1
Zn
5
5
5 5
+
+
_
US
IS
U1
+
-
U
I
Z2Z1
n
k kn ZZZZZ 121
11
...
111
21
1
2
21
2
1
ZZ
Z
II
ZZ
Z
II
Current divider:
n
k
k
i
i
Z
Z
VV
1
Voltage divider:
Impedance (Z)
44. Complex Impedance
_
+
V
I
1IZ1
Z2 Z
2121
2
2121
2
1
2
1
1
2
2
1
11
ZZZZZZ
ZV
I
ZZZZZZ
ZZV
ZZ
Z
V
I
ZZ
Z
II
Impedance (Z)
45. Complex Impedance
Phasors and complex impedance allow us to use Ohm’s law with
complex numbers to compute current from voltage and voltage
from current
20kW
+
-
1mF10V 0 VC
+
-
w = 377
Find VC
• How do we find VC?
• First compute impedances for resistor and capacitor:
ZR = 20kW = 20kW 0
ZC = 1/j (377 *1mF) = 2.65kW -90
Impedance (Z)
46. Complex Impedance
20kW
+
-
1mF10V 0 VC
+
-
w = 377
Find VC
20kW 0
+
-
2.65kW -
90
10V 0 VC
+
-
Now use the voltage divider to find VC:
46.82V31.1
54.717.20
9065.2
010VCV
)
0209065.2
9065.2
(010
kk
k
VVC
Impedance (Z)
47. Impedance allows us to use the same solution techniques
for AC steady state as we use for DC steady state.
• All the analysis techniques we have learned for the linear circuits are
applicable to compute phasors
– KCL & KVL
– node analysis / loop analysis
– Superposition
– Thevenin equivalents / Norton equivalents
– source exchange
• The only difference is that now complex numbers are used.
Complex Impedance
Impedance (Z)
48. Kirchhoff’s Laws
KCL and KVL hold as well in phasor domain.
KVL: 0
1
n
k
kv vk- Transient voltage of the #k branch
0
1
n
k
kV
KCL: 0
1
n
k
ki
0
1
n
k
kI
ik- Transient current of the #k branch
Impedance (Z)
49. Admittance
• I = YV, Y is called admittance, the reciprocal of
impedance, measured in Siemens (S)
• Resistor:
– The admittance is 1/R
• Inductor:
– The admittance is 1/jL
• Capacitor:
– The admittance is jC
Impedance (Z)
50. Phasor Diagrams
• A phasor diagram is just a graph of several phasors on the complex
plane (using real and imaginary axes).
• A phasor diagram helps to visualize the relationships between currents
and voltages.
2mA 40
–
1mF VC
+
–
1kW VR
+
+
–
V
I = 2mA 40, VR = 2V 40
VC = 5.31V -50, V = 5.67V -29.37
Real Axis
Imaginary Axis
VR
VC
V
Impedance (Z)
51. Parallel and Series Resonance
Outline:
RLC Circuit,
Series Resonance
Parallel Resonance
52. v
vR
vL
vC
CLR vvvv
CLR VVVV Phasor
I
V
LV
CV
RV
IZ
XRI
XXRI
IXIXIR
VVVV
CL
CL
CLR
22
22
22
22
)(
)()(
)(
)CL XXX (
22
XRZ
22
)
1
(
c
LR
(2nd Order RLC Circuit )Series RLC Circuit
Parallel and Series Resonance :
53. 22
XRZ
22
)
1
(
c
LR
IZVVVV CLR 22
)(
Z
X = XL-XC
R
V
RV
CLX VVV R
XX
V
VV
CL
R
CL
1
1
tan
-
tan
Phase difference:
XL>XC >0,v leads i by — Inductance Circuit
XL<XC <0,v lags i by — Capacitance Circuit
XL=XC =0,v and i in phase — Resistors Circuit
Series RLC Circuit
Parallel and Series Resonance :
54. CLR VVVV CL XIjXIjRI
ZIjXRIXXjRI CL
)()]((
)( CL XXjR
I
V
Z
ZjXRZ
22
)( CL XXRZ
R
XX CL
1
tan
iv
v
vR
vL
vC
Series RLC Circuit
Parallel and Series Resonance :
55. Series Resonance (2nd Order RLC Circuit )
CLR VVVV CL XIjXIjRI
R
XX
arctg
V
VV
arctg CL
R
CL
CLCL VVL
C
XXWhen
1
,
VVR 0and —— Series Resonance
Resonance condition
I
LV
CV
VVR
LC
for
LC
2
11
00
f0 f
X
Cf
XC
2
1
fLXL 2
Resonant frequency
Parallel and Series Resonance :
56. Series Resonance
R
V
Z
V
IRXXRZ CL
0
0
22
0 )(•
Zmin;when V = constant, I = Imax= I0
RXX CL RIXIXI CL 000 VVV CL
• Quality factor Q,
R
X
R
X
V
V
V
V
Q CLCL
CLCL VVL
C
XX )
1
(
Resonance condition:
When,
Parallel and Series Resonance :
57. Parallel RLC Circuit
V
I
LI
CI
)(
1
/
11
222222
LR
L
Cj
LR
R
Cj
LjRLjR
LjR
Cj
LjRCjLjR
Y
Parallel Resonance
Parallel Resonance frequency
L
CR
LC
2
0 1
1
LXR In generally )
2
1
( 0
LC
f
LC
1
0
0)( 222
LR
L
C
When 2220
LR
R
Y
,
In phase withV I
V
L
RC
C
L
R
R
V
L
LC
R
R
V
LR
R
VVYII
222
22
0
200
1
Zmax Imin:
Parallel and Series Resonance :
58. Parallel RLC Circuit
V
I
LI
CI
V
L
C
j
L
V
j
LjR
VIL
00
1
V
L
C
jVCjIC
0
0|||||| 0 III CL
Z .
RCR
L
Q
0
0 1
0IjQIL
0IjQIC
•Quality factor Q,
0000 Y
Y
Y
Y
I
I
I
I
Q CLLC
Parallel and Series Resonance :
59. Parallel RLC Circuit
Review
For sinusoidal circuit, Series : 21 vvv 21 VVV
21 iii 21 III
?
Two Simple Methods:
Phasor Diagrams and Complex Numbers
Parallel :
Parallel and Series Resonance :