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Applications of Redox and 
Electrochemistry 
By- 
Saurav K. Rawat 
(Rawat DA Greatt) 1
Electrochemistry 
Applications of Redox
Review 
Oxidation reduction reactions involve a 
transfer of electrons. 
OIL- RIG 
Oxidation Involves Loss 
Reduction Involves Gain 
LEO-GER 
Lose Electrons Oxidation 
Gain Electrons Reduction
Solid lead(II) sulfide reacts with oxygen in 
the air at high temperatures to form 
lead(II) oxide and sulfur dioxide. Which 
substance is a reductant (reducing 
agent) and which is an oxidant 
(oxidizing agent)? 
A. PbS, reductant; O2, oxidant 
B. PbS, reductant; SO2, oxidant 
C. Pb2+, reductant; S2- oxidant 
D. PbS, reductant; no oxidant 
E. PbS, oxidant; SO2, reductant
Applications 
Moving electrons is electric current. 
8H++MnO4 
-+ 5Fe+2 +5e- 
® Mn+2 + 5Fe+3 +4H2O 
Helps to break the reactions into half 
reactions. 
8H++MnO4 
-+5e- ® Mn+2 +4H2O 
5(Fe+2 ® Fe+3 + e- ) 
In the same mixture it happens without 
doing useful work, but if separate
Connected this way the reaction starts 
Stops immediately because charge builds 
up. 
H+ 
MnO4 
e-e- 
e-e-e- 
- Fe+2
Galvanic Cell 
H+ 
MnO4 
- Fe+2 
Salt 
Bridge 
allows 
current 
to flow
Electricity travels in a complete circuit 
H+ 
MnO4 
e- 
- Fe+2
Instead of a salt bridge 
H+ 
MnO4 
Porous 
Disk 
- Fe+2
Reducing 
Agent 
Oxidizing 
Agent 
e-e-e- 
e-e-e- 
Anode Cathode
Cell Potential 
Oxidizing agent pulls the electron. 
Reducing agent pushes the electron. 
The push or pull (“driving force”) is called 
the cell potential Ecell 
Also called the electromotive force (emf) 
Unit is the volt(V) 
= 1 joule of work/coulomb of charge 
Measured with a voltmeter
Zn+2 SO4 
- 
2 
1 M HCl 
Anode 
0.76 
1 M ZnSO4 
H+ 
Cl- 
H2 in 
Cathode
Standard Hydrogen Electrode 
This is the reference 
all other oxidations 
are compared to 
Eº = 0 
º indicates standard 
states of 25ºC, 
H+ 
1 atm, 1 M 
solutions. 
Cl- 
1 M HCl 
H2 in
Cell Potential 
Zn(s) + Cu+2 (aq) ® Zn+2(aq) + Cu(s) 
The total cell potential is the sum of the 
potential at each electrode. 
 Eºcell = EºZn® Zn+2 + EºCu+2 ® Cu 
We can look up reduction potentials in a 
table. 
One of the reactions must be reversed, 
so change it sign.
Cell Potential 
 Determine the cell potential for a galvanic 
cell based on the redox reaction. 
 Cu(s) + Fe+3(aq) ® Cu+2(aq) + Fe+2(aq) 
 Fe+3(aq) + e-® Fe+2(aq) Eº = 0.77 V 
 Cu+2(aq)+2e- ® Cu(s) Eº = 0.34 V 
 Cu(s) ® Cu+2(aq)+2e- Eº = -0.34 V 
 2Fe+3(aq) + 2e-® 2Fe+2(aq) Eº = 0.77 V
Reduction potential 
 More negative Eº 
–more easily electron is added 
–More easily reduced 
–Better oxidizing agent 
 More positive Eº 
–more easily electron is lost 
–More easily oxidized 
–Better reducing agent
Line Notation 
 solid½Aqueous½½Aqueous½solid 
 Anode on the left½½Cathode on the right 
 Single line different phases. 
 Double line porous disk or salt bridge. 
 If all the substances on one side are 
aqueous, a platinum electrode is 
indicated.
For the last reaction 
 Cu(s)½Cu+2(aq)½½Fe+2(aq),Fe+3(aq)½Pt(s) 
Cu2+ Fe+2
In a galvanic cell, the electrode that 
acts as a source of electrons to the 
solution is called the __________; 
the chemical change that occurs at 
this electrode is called________. 
a. cathode, oxidation 
b. anode, reduction 
c. anode, oxidation 
d. cathode, reduction
Under standard conditions, which of 
the following is the net reaction that 
occurs in the cell? 
Cd|Cd2+ || Cu2+|Cu 
a. Cu2+ + Cd → Cu + Cd2+ 
b. Cu + Cd → Cu2+ + Cd2+ 
c. Cu2+ + Cd2+ → Cu + Cd 
d. Cu + Cd 2+ → Cd + Cu2+
Galvanic Cell 
 The reaction always runs 
spontaneously in the direction that 
produced a positive cell potential. 
 Four things for a complete description. 
1) Cell Potential 
2) Direction of flow 
3) Designation of anode and cathode 
4) Nature of all the components-electrodes 
and ions
Practice 
 Completely describe the galvanic cell 
based on the following half-reactions 
under standard conditions. 
 MnO4 
- + 8 H+ +5e- ® Mn+2 + 4H2O 
Eº=1.51 V 
 Fe+3 +3e- ® Fe(s) Eº=0.036V
Potential, Work and DG 
 emf = potential (V) = work (J) / Charge(C) 
 E = work done by system / charge 
 E = -w/q 
 Charge is measured in coulombs. 
 -w = q E 
 Faraday = 96,485 C/mol e- 
 q = nF = moles of e- x charge/mole e- 
 w = -qE = -nFE = DG
Potential, Work and DG 
 DGº = -nFEº 
 if Eº  0, then DGº  0 spontaneous 
 if Eº 0, then DGº  0 nonspontaneous 
 In fact, reverse is spontaneous. 
 Calculate DGº for the following reaction: 
 Cu+2(aq)+ Fe(s) ® Cu(s)+ Fe+2(aq) 
 Fe+2(aq) + e-® Fe(s) Eº = 0.44 V 
 Cu+2(aq)+2e- ® Cu(s) Eº = 0.34 V
Cell Potential and 
Concentration 
 Qualitatively - Can predict direction of 
change in E from LeChâtelier. 
 2Al(s) + 3Mn+2(aq) ® 2Al+3(aq) + 3Mn(s) 
 Predict if Ecell will be greater or less than 
Eºcell if [Al+3] = 1.5 M and [Mn+2] = 1.0 M 
 if [Al+3] = 1.0 M and [Mn+2] = 1.5M 
 if [Al+3] = 1.5 M and [Mn+2] = 1.5 M
The Nernst Equation 
 DG = DGº +RTln(Q) 
 -nFE = -nFEº + RTln(Q) 
 E = Eº - RTln(Q) 
nF 
 2Al(s) + 3Mn+2(aq) ® 2Al+3(aq) + 3Mn(s) 
Eº = 0.48 V 
 Always have to figure out n by balancing. 
 If concentration can gives voltage, then 
from voltage we can tell concentration.
The Nernst Equation 
 As reactions proceed concentrations of 
products increase and reactants 
decrease. 
 Reach equilibrium where Q = K and 
Ecell = 0 
 0 = Eº - RTln(K) 
nF 
 Eº = RTln(K) 
nF 
 nF Eº = ln(K) 
RT
Batteries are Galvanic Cells 
 Car batteries are lead storage batteries. 
 Pb +PbO2 +H2SO4 ®PbSO4(s) +H2O
Batteries are Galvanic Cells 
Dry Cell 
Zn + NH4 
+ +MnO2 ® 
Zn+2 + NH3 + H2O + Mn2O3
Batteries are Galvanic Cells 
Alkaline 
Zn +MnO2 ® ZnO+ Mn2O3 (in base)
Batteries are Galvanic Cells 
NiCad 
 NiO2 + Cd + 2H2O ® Cd(OH)2 +Ni(OH)2
Corrosion 
Rusting - spontaneous oxidation. 
Most structural metals have reduction 
potentials that are less positive than O2 . 
Fe ® Fe+2 +2e- Eº= 0.44 V 
O2 + 2H2O + 4e- ® 4OH-Eº= 0.40 V 
Fe+2 + O2 + H2O ® Fe2O3 + H+ 
Reactions happens in two places.
Salt speeds up process by increasing 
conductivity 
Water 
Rust 
Iron Dissolves- 
Fe ® Fe+2 
e- 
Fe2+ 
O2 + 2H2O +4e- ® 4OH-Fe2+ 
+ O2 + 2H2O ® Fe2O3 + 8 H+
Preventing Corrosion 
Coating to keep out air and water. 
Galvanizing - Putting on a zinc coat 
Has a lower reduction potential, so it is 
more easily oxidized. 
Alloying with metals that form oxide 
coats. 
Cathodic Protection - Attaching large 
pieces of an active metal like magnesium 
that get oxidized instead.
Electrolysis 
Running a galvanic cell backwards. 
Put a voltage bigger than the potential 
and reverse the direction of the redox 
reaction. 
Used for electroplating.
1.10 
e- e- 
Zn Cu 
1.0 M 
Zn+2 
1.0 M 
Cu+2 
Anode Cathode
A battery 
1.10V 
e- e- 
Zn Cu 
1.0 M 
Zn+2 
1.0 M 
Cu+2 
Cathode Anode
Calculating plating 
Have to count charge. 
Measure current I (in amperes) 
1 amp = 1 coulomb of charge per second 
q = I x t 
q/nF = moles of metal 
Mass of plated metal 
How long must 5.00 amp current be 
applied to produce 15.5 g of Ag from Ag+
Calculating plating 
1. Current x time = charge 
2. Charge ∕Faraday = mole of e- 
3. Mol of e- to mole of element or 
compound 
4. Mole to grams of compound 
Or the reverse if you want time to plate
Calculate the mass of copper which can be 
deposited by the passage of 12.0 A for 
25.0 min through a solution of copper(II) 
sulfate.
How long would it take to plate 5.00 g Fe 
from an aqueous solution of Fe(NO3)3 at a 
current of 2.00 A?
Other uses 
Electrolysis of water. 
Separating mixtures of ions. 
More positive reduction potential means 
the reaction proceeds forward. 
We want the reverse. 
Most negative reduction potential is 
easiest to plate out of solution.
Redox 
Know the table 
2. Recognized by change in oxidation 
state. 
3. “Added acid” 
4. Use the reduction potential table on the 
front cover. 
5. Redox can replace. (single replacement)
6. Combination Oxidizing agent of one 
element will react with the reducing agent 
of the same element to produce the free 
element. 
I- + IO- + H+ ® I+ HO 
3 
2 27. Decomposition. 
a) peroxides to oxides 
b) Chlorates to chlorides 
c) Electrolysis into elements. 
d) carbonates to oxides
45 
Examples 
A piece of solid bismuth is heated strongly 
in oxygen. 
A strip or copper metal is added to a 
concentrated solution of sulfuric acid. 
Dilute hydrochloric acid is added to a 
solution of potassium carbonate.
46 
Hydrogen peroxide solution is added to a 
solution of iron (II) sulfate. 
Propanol is burned completely in air. 
A piece of lithium metal is dropped into a 
container of nitrogen gas. 
Chlorine gas is bubbled into a solution of 
potassium iodide.
A stream of chlorine gas is passed through 
47 
a solution of cold, dilute sodium 
hydroxide. 
A solution of tin ( II ) chloride is added to 
an acidified solution of potassium 
permanganate 
A solution of potassium iodide is added to 
an acidified solution of potassium 
dichromate.
Magnesium metal is burned in 
nitrogen gas. 
Lead foil is immersed in silver nitrate 
solution. 
Magnesium turnings are added to a 
solution of iron (III) chloride. 
Pellets of lead are dropped into hot 
sulfuric acid 
Powdered Iron is added to a solution of 
iron(III) sulfate. 
48
A way to remember 
 An Ox – anode is where oxidation occurs 
 Red Cat – Reduction occurs at cathode 
 Galvanic cell- spontaneous- anode is 
negative 
 Electrolytic cell- voltage applied to make 
anode positive
A student places a copper electrode in a 1 
M solution of CuSO4 and in another 
beaker places a silver electrode in a 1 M 
solution of AgNO3. A salt bridge 
composed of Na2SO4 connects the two 
beakers. The voltage measured across 
the electrodes is found to be + 0.42 volt. 
 (a) Draw a diagram of this cell. 
 (b) Describe what is happening at the 
cathode (Include any equations that may 
be useful.)
A student places a copper electrode in a 1 
M solution of CuSO4 and in another 
beaker places a silver electrode in a 1 M 
solution of AgNO3. A salt bridge 
composed of Na2SO4 connects the two 
beakers. The voltage measured across 
the electrodes is found to be + 0.42 volt. 
 (c) Describe what is happening at the 
anode. (Include any equations that may 
be useful.)
A student places a copper electrode in a 1 
M solution of CuSO4 and in another 
beaker places a silver electrode in a 1 M 
solution of AgNO3. A salt bridge 
composed of Na2SO4 connects the two 
beakers. The voltage measured across 
the electrodes is found to be + 0.42 volt. 
 (d) Write the balanced overall cell 
equation. 
 (e) Write the standard cell notation.
A student places a copper electrode in a 1 M 
solution of CuSO4 and in another beaker places 
a silver electrode in a 1 M solution of AgNO3. A 
salt bridge composed of Na2SO4 connects the 
two beakers. The voltage measured across the 
electrodes is found to be + 0.42 volt. 
(f) The student adds 4 M ammonia to the 
copper sulfate solution, producing the complex 
ion Cu(NH3)+ (aq). The student remeasures the 
cell potential and discovers the voltage to be 
0.88 volt. What is the Cu2+ (aq) concentration in 
the cell after the ammonia has been added?
Rawat’s Creation-rwtdgreat@ 
gmail.com 
rwtdgreat@yahoo.co.uk 
RawatDAgreatt/LinkedIn 
www.slideshare.net/ 
RawatDAgreatt 
Google+/blogger/Facebook 
/ 
Twitter-@RawatDAgreatt 
+919808050301 
+919958249693

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Electrochemistry apps of redox

  • 1. Applications of Redox and Electrochemistry By- Saurav K. Rawat (Rawat DA Greatt) 1
  • 3. Review Oxidation reduction reactions involve a transfer of electrons. OIL- RIG Oxidation Involves Loss Reduction Involves Gain LEO-GER Lose Electrons Oxidation Gain Electrons Reduction
  • 4. Solid lead(II) sulfide reacts with oxygen in the air at high temperatures to form lead(II) oxide and sulfur dioxide. Which substance is a reductant (reducing agent) and which is an oxidant (oxidizing agent)? A. PbS, reductant; O2, oxidant B. PbS, reductant; SO2, oxidant C. Pb2+, reductant; S2- oxidant D. PbS, reductant; no oxidant E. PbS, oxidant; SO2, reductant
  • 5. Applications Moving electrons is electric current. 8H++MnO4 -+ 5Fe+2 +5e- ® Mn+2 + 5Fe+3 +4H2O Helps to break the reactions into half reactions. 8H++MnO4 -+5e- ® Mn+2 +4H2O 5(Fe+2 ® Fe+3 + e- ) In the same mixture it happens without doing useful work, but if separate
  • 6. Connected this way the reaction starts Stops immediately because charge builds up. H+ MnO4 e-e- e-e-e- - Fe+2
  • 7. Galvanic Cell H+ MnO4 - Fe+2 Salt Bridge allows current to flow
  • 8. Electricity travels in a complete circuit H+ MnO4 e- - Fe+2
  • 9. Instead of a salt bridge H+ MnO4 Porous Disk - Fe+2
  • 10. Reducing Agent Oxidizing Agent e-e-e- e-e-e- Anode Cathode
  • 11. Cell Potential Oxidizing agent pulls the electron. Reducing agent pushes the electron. The push or pull (“driving force”) is called the cell potential Ecell Also called the electromotive force (emf) Unit is the volt(V) = 1 joule of work/coulomb of charge Measured with a voltmeter
  • 12. Zn+2 SO4 - 2 1 M HCl Anode 0.76 1 M ZnSO4 H+ Cl- H2 in Cathode
  • 13. Standard Hydrogen Electrode This is the reference all other oxidations are compared to Eº = 0 º indicates standard states of 25ºC, H+ 1 atm, 1 M solutions. Cl- 1 M HCl H2 in
  • 14. Cell Potential Zn(s) + Cu+2 (aq) ® Zn+2(aq) + Cu(s) The total cell potential is the sum of the potential at each electrode. Eºcell = EºZn® Zn+2 + EºCu+2 ® Cu We can look up reduction potentials in a table. One of the reactions must be reversed, so change it sign.
  • 15. Cell Potential Determine the cell potential for a galvanic cell based on the redox reaction. Cu(s) + Fe+3(aq) ® Cu+2(aq) + Fe+2(aq) Fe+3(aq) + e-® Fe+2(aq) Eº = 0.77 V Cu+2(aq)+2e- ® Cu(s) Eº = 0.34 V Cu(s) ® Cu+2(aq)+2e- Eº = -0.34 V 2Fe+3(aq) + 2e-® 2Fe+2(aq) Eº = 0.77 V
  • 16. Reduction potential More negative Eº –more easily electron is added –More easily reduced –Better oxidizing agent More positive Eº –more easily electron is lost –More easily oxidized –Better reducing agent
  • 17. Line Notation solid½Aqueous½½Aqueous½solid Anode on the left½½Cathode on the right Single line different phases. Double line porous disk or salt bridge. If all the substances on one side are aqueous, a platinum electrode is indicated.
  • 18. For the last reaction Cu(s)½Cu+2(aq)½½Fe+2(aq),Fe+3(aq)½Pt(s) Cu2+ Fe+2
  • 19. In a galvanic cell, the electrode that acts as a source of electrons to the solution is called the __________; the chemical change that occurs at this electrode is called________. a. cathode, oxidation b. anode, reduction c. anode, oxidation d. cathode, reduction
  • 20. Under standard conditions, which of the following is the net reaction that occurs in the cell? Cd|Cd2+ || Cu2+|Cu a. Cu2+ + Cd → Cu + Cd2+ b. Cu + Cd → Cu2+ + Cd2+ c. Cu2+ + Cd2+ → Cu + Cd d. Cu + Cd 2+ → Cd + Cu2+
  • 21. Galvanic Cell The reaction always runs spontaneously in the direction that produced a positive cell potential. Four things for a complete description. 1) Cell Potential 2) Direction of flow 3) Designation of anode and cathode 4) Nature of all the components-electrodes and ions
  • 22. Practice Completely describe the galvanic cell based on the following half-reactions under standard conditions. MnO4 - + 8 H+ +5e- ® Mn+2 + 4H2O Eº=1.51 V Fe+3 +3e- ® Fe(s) Eº=0.036V
  • 23. Potential, Work and DG emf = potential (V) = work (J) / Charge(C) E = work done by system / charge E = -w/q Charge is measured in coulombs. -w = q E Faraday = 96,485 C/mol e- q = nF = moles of e- x charge/mole e- w = -qE = -nFE = DG
  • 24. Potential, Work and DG DGº = -nFEº if Eº 0, then DGº 0 spontaneous if Eº 0, then DGº 0 nonspontaneous In fact, reverse is spontaneous. Calculate DGº for the following reaction: Cu+2(aq)+ Fe(s) ® Cu(s)+ Fe+2(aq) Fe+2(aq) + e-® Fe(s) Eº = 0.44 V Cu+2(aq)+2e- ® Cu(s) Eº = 0.34 V
  • 25. Cell Potential and Concentration Qualitatively - Can predict direction of change in E from LeChâtelier. 2Al(s) + 3Mn+2(aq) ® 2Al+3(aq) + 3Mn(s) Predict if Ecell will be greater or less than Eºcell if [Al+3] = 1.5 M and [Mn+2] = 1.0 M if [Al+3] = 1.0 M and [Mn+2] = 1.5M if [Al+3] = 1.5 M and [Mn+2] = 1.5 M
  • 26. The Nernst Equation DG = DGº +RTln(Q) -nFE = -nFEº + RTln(Q) E = Eº - RTln(Q) nF 2Al(s) + 3Mn+2(aq) ® 2Al+3(aq) + 3Mn(s) Eº = 0.48 V Always have to figure out n by balancing. If concentration can gives voltage, then from voltage we can tell concentration.
  • 27. The Nernst Equation As reactions proceed concentrations of products increase and reactants decrease. Reach equilibrium where Q = K and Ecell = 0 0 = Eº - RTln(K) nF Eº = RTln(K) nF nF Eº = ln(K) RT
  • 28. Batteries are Galvanic Cells Car batteries are lead storage batteries. Pb +PbO2 +H2SO4 ®PbSO4(s) +H2O
  • 29. Batteries are Galvanic Cells Dry Cell Zn + NH4 + +MnO2 ® Zn+2 + NH3 + H2O + Mn2O3
  • 30. Batteries are Galvanic Cells Alkaline Zn +MnO2 ® ZnO+ Mn2O3 (in base)
  • 31. Batteries are Galvanic Cells NiCad NiO2 + Cd + 2H2O ® Cd(OH)2 +Ni(OH)2
  • 32. Corrosion Rusting - spontaneous oxidation. Most structural metals have reduction potentials that are less positive than O2 . Fe ® Fe+2 +2e- Eº= 0.44 V O2 + 2H2O + 4e- ® 4OH-Eº= 0.40 V Fe+2 + O2 + H2O ® Fe2O3 + H+ Reactions happens in two places.
  • 33. Salt speeds up process by increasing conductivity Water Rust Iron Dissolves- Fe ® Fe+2 e- Fe2+ O2 + 2H2O +4e- ® 4OH-Fe2+ + O2 + 2H2O ® Fe2O3 + 8 H+
  • 34. Preventing Corrosion Coating to keep out air and water. Galvanizing - Putting on a zinc coat Has a lower reduction potential, so it is more easily oxidized. Alloying with metals that form oxide coats. Cathodic Protection - Attaching large pieces of an active metal like magnesium that get oxidized instead.
  • 35. Electrolysis Running a galvanic cell backwards. Put a voltage bigger than the potential and reverse the direction of the redox reaction. Used for electroplating.
  • 36. 1.10 e- e- Zn Cu 1.0 M Zn+2 1.0 M Cu+2 Anode Cathode
  • 37. A battery 1.10V e- e- Zn Cu 1.0 M Zn+2 1.0 M Cu+2 Cathode Anode
  • 38. Calculating plating Have to count charge. Measure current I (in amperes) 1 amp = 1 coulomb of charge per second q = I x t q/nF = moles of metal Mass of plated metal How long must 5.00 amp current be applied to produce 15.5 g of Ag from Ag+
  • 39. Calculating plating 1. Current x time = charge 2. Charge ∕Faraday = mole of e- 3. Mol of e- to mole of element or compound 4. Mole to grams of compound Or the reverse if you want time to plate
  • 40. Calculate the mass of copper which can be deposited by the passage of 12.0 A for 25.0 min through a solution of copper(II) sulfate.
  • 41. How long would it take to plate 5.00 g Fe from an aqueous solution of Fe(NO3)3 at a current of 2.00 A?
  • 42. Other uses Electrolysis of water. Separating mixtures of ions. More positive reduction potential means the reaction proceeds forward. We want the reverse. Most negative reduction potential is easiest to plate out of solution.
  • 43. Redox Know the table 2. Recognized by change in oxidation state. 3. “Added acid” 4. Use the reduction potential table on the front cover. 5. Redox can replace. (single replacement)
  • 44. 6. Combination Oxidizing agent of one element will react with the reducing agent of the same element to produce the free element. I- + IO- + H+ ® I+ HO 3 2 27. Decomposition. a) peroxides to oxides b) Chlorates to chlorides c) Electrolysis into elements. d) carbonates to oxides
  • 45. 45 Examples A piece of solid bismuth is heated strongly in oxygen. A strip or copper metal is added to a concentrated solution of sulfuric acid. Dilute hydrochloric acid is added to a solution of potassium carbonate.
  • 46. 46 Hydrogen peroxide solution is added to a solution of iron (II) sulfate. Propanol is burned completely in air. A piece of lithium metal is dropped into a container of nitrogen gas. Chlorine gas is bubbled into a solution of potassium iodide.
  • 47. A stream of chlorine gas is passed through 47 a solution of cold, dilute sodium hydroxide. A solution of tin ( II ) chloride is added to an acidified solution of potassium permanganate A solution of potassium iodide is added to an acidified solution of potassium dichromate.
  • 48. Magnesium metal is burned in nitrogen gas. Lead foil is immersed in silver nitrate solution. Magnesium turnings are added to a solution of iron (III) chloride. Pellets of lead are dropped into hot sulfuric acid Powdered Iron is added to a solution of iron(III) sulfate. 48
  • 49. A way to remember An Ox – anode is where oxidation occurs Red Cat – Reduction occurs at cathode Galvanic cell- spontaneous- anode is negative Electrolytic cell- voltage applied to make anode positive
  • 50. A student places a copper electrode in a 1 M solution of CuSO4 and in another beaker places a silver electrode in a 1 M solution of AgNO3. A salt bridge composed of Na2SO4 connects the two beakers. The voltage measured across the electrodes is found to be + 0.42 volt. (a) Draw a diagram of this cell. (b) Describe what is happening at the cathode (Include any equations that may be useful.)
  • 51. A student places a copper electrode in a 1 M solution of CuSO4 and in another beaker places a silver electrode in a 1 M solution of AgNO3. A salt bridge composed of Na2SO4 connects the two beakers. The voltage measured across the electrodes is found to be + 0.42 volt. (c) Describe what is happening at the anode. (Include any equations that may be useful.)
  • 52. A student places a copper electrode in a 1 M solution of CuSO4 and in another beaker places a silver electrode in a 1 M solution of AgNO3. A salt bridge composed of Na2SO4 connects the two beakers. The voltage measured across the electrodes is found to be + 0.42 volt. (d) Write the balanced overall cell equation. (e) Write the standard cell notation.
  • 53. A student places a copper electrode in a 1 M solution of CuSO4 and in another beaker places a silver electrode in a 1 M solution of AgNO3. A salt bridge composed of Na2SO4 connects the two beakers. The voltage measured across the electrodes is found to be + 0.42 volt. (f) The student adds 4 M ammonia to the copper sulfate solution, producing the complex ion Cu(NH3)+ (aq). The student remeasures the cell potential and discovers the voltage to be 0.88 volt. What is the Cu2+ (aq) concentration in the cell after the ammonia has been added?
  • 54. Rawat’s Creation-rwtdgreat@ gmail.com rwtdgreat@yahoo.co.uk RawatDAgreatt/LinkedIn www.slideshare.net/ RawatDAgreatt Google+/blogger/Facebook / Twitter-@RawatDAgreatt +919808050301 +919958249693