The document discusses a group project on data logging. The group members are listed. It also discusses using an oxygen gas sensor and data logger to monitor the rate of reaction between hydrogen peroxide and different concentrations of the enzyme catalase. As the concentration of enzyme catalase increases, the rate of oxygen production and the slope of the graphs increase.

1. DATA LOGGING
Group Members:
1. Tuan Nurul Shahira Bt Tuan Yacob 037520
2. Syafiqah Bt Razale 037538
3. Wan Nurulfarhah Bt Awang @ Hasan 037532

2. The Effect of Catalyst On
Rate of Reaction

3. Scientific Concept
 Catalyst is a substance that increases the rate of
a chemical reaction.
 Catalyst speeds up a chemical reaction but is not
consumed by the reaction.
 The higher the concentration enzyme catalase,
the higher the amount of oxygen released by the
destroyed hydrogen peroxides.
 The higher the enzymes catalase, the higher rate
of colliding collision between enzyme catalase
and hydrogen peroxide, more hydrogen peroxide
being destroyed and released oxygen gas.
+

4. Engage
Statement: You are given two different pictures about the ways for
student to their lecturer room which is located on the 6th floor. Observe
the picture carefully.
Based on the picture, which one is faster? Give reason.
What substance have similar representation with the elevator for this
situation?
What will happen if the amount of that substance increased?

5. Empower
Planning And Doing Your Experiment
3% of
Pressure Hydrogen
Water Test tube
Sensor Peroxide
Enzyme Test Tube
Catalase Rack

6. Empower
Planning And Doing Your Experiment
Procedure:
1. Connect the Oxygen Gas Sensor to the computer
interface. Prepare the computer for data collection by
opening the file “02 (O2) Enzyme” from the Advanced
Biology with Vernier folder of LoggerPro.
2. Click „Length‟ menu .
3. Change the length to 180 s, then click „ok‟
4. Place four test tubes in a rack and label them 1, 2, 3 and 4.

7. 5. Fill each test tube with 3 ml of water and 3 ml of 3% of .
6. Connect the plastic tubing of the pressure sensor with the gentle half turned.
7. Initiate the enzyme catalase reaction as follow:
a) Placed 1 drop of enzyme catalase into test tube 1
b) Quickly stopper the tube.
c) Swirled the test tube gently.
d) Connect the other plastic tubing to the
top of the stopper.

8. e) Then, start the data collection. Continue to swirled 3
minutes of data collection.
f) Once, data collector is
finished, removed the stopper
from the top of the test tube.
8. To determine the rate at which oxygen was produced, click analyze menu and
choose curve fit, and then click pressure
9. Fold down fit equation menu and choose linear, then click „ok‟.
10. The slope will represent the rate at which
oxygen was produced.

9. 11. Repeat the experiment with different enzyme catalase concentration with 2, 3
and 4 drops of enzyme catalase into test tube 2, 3 and 4 labeled test tubes.
12. After completing the experiment, you can show all rums of experiment by choose
„Run 4‟ and then click „All runs‟.
13. Compared all the graphs.

10. Empower
Result: Graph of Oxygen Produced

11. Question :
1. Which type of catalyst that being used in this experiment?
2. Which concentration of enzyme catalase having the highest rate of reaction?
3. What type of gas being produced?
4. What is the equation can be form for the production of that type of gas?
5. Compare the four graphs and give reasons.
Answer :
1. Positive catalyst. This is because a positive type of catalyst will increasethe rate
of reaction.
2. 4 drops of enzyme catalase.
3. Oxygen gas.
4. ( l) ( l) + (g)
5. Based the four graphs, we can see that the graph for 4 drops of enzyme
catalase is more slope followed by the 3 drops of enzymes catalase, 2 drops of
enzymes and the last one is graph for 1 drop of enzyme catalase. From this
results it shows that the higher concentration of enzyme catalase, the higher the
pressure of oxygen gas being detected by the pressure sensor, the graph also
more slope. In conclusion, the higher the concentration of enzyme catalase, the
higher the production of oxygen gas.

12. Enhance
Cloth 1 Cloth 2
Statement: There are clothes that dirty with oily food residue. Which one is
better to wash the cloth that dirty with cooking oil either the larger amount of
powder detergent or the small amount of powder detergent? Explain.

13. Answer:
Cloth 2 is clean better because it use the larger amount of powder detergent
to clean the cloth that dirty with oily food residue. The increase amount of
powder detergent would increase the rate of reaction to occur. The cloth 1 is
slow reaction occur because the small amount of the powder detergent is use
to clean a cloth. The detergent contains protein enzymes that classified as
proteases. These enzymes increase the cleaning action of household
detergent by accelerating the hydrolysis of oily food residues, so that they
could be more rapidly dispersed and emulsified in water. The rate of reaction
in hydrolysis of food residue is increase due the larger amount of the
detergent is use. The enzyme proteases are photolytic enzymes that
degraded protein by cleaving the peptide bonds, thus assisting in the removal
of protein-based stain such as blood and many types of food.

14. Unique Feature of This Activity
 We can stopped the data logger whenever we want
because before start the experiment, we had set the
time and when the time for the experiment had finished
it will stopped automatically.
 The rate of reaction cannot be detected by our naked
eyes. So, by using the data logger the reading of rate of
reaction between enzyme catalase and hydrogen
peroxide can be record every one minutes per hour.