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Answer these Questions: ,[object Object],[object Object],[object Object],[object Object],fig1 P H B
 
What Is Trigonometry? ,[object Object],[object Object]
A  trigonometric ratio  is a ratio of the lengths of two sides in a right triangle.  TRIGONOMETRIC RATIO
Three basic trigonometric ratios: sine  cosine tangent each of which is the ratio of one side to  another. .
How to Use Trigonometry ,[object Object],[object Object],[object Object],[object Object],A B C Hypotenuse Base Perpendicular
First, Label the Sides ,[object Object],[object Object],A B C Hypotenuse Base Perpendicular
So, Now the Trigonometry ,[object Object],A B C Hypotenuse Base Perpendicular
Firstly, Sine ,[object Object],[object Object],A B C Hypotenuse Base Perpendicular
Now Cosine ,[object Object],[object Object],A B C Hypotenuse Base Perpendicular
And Finally Tangent ,[object Object],[object Object],A B C Hypotenuse Base Perpendicular
opposite adjacent A B C Hypotenuse Base Perpendicular
S   C   T P  B  P H  H  B Sin P H Cos B H Tan P B
6 8 10 A B C (P) (B) (H)
Identify perpendicular , hypotenuse and base in relation to angle C in given fig. A B C
Other Trigonometric-ratios ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
 
Example 1: Finding the Value of Trigonometric Ratio   sin  A,  cos  A, tan  A,cosec A,sec A and cot A .   A B C 17 15 8
sin  A,  cos  A, tan  A,cosec A,sec A and cot A .   Sin  A Cos  A Tan  A solution A B C 17 15 8
A B C 17 15 8
Find the values of all the trigonometric ratios of   . 4 3 ? Pythagoras Theorem: (3) ² + (4)² = c² 5 = c 5
Example 2:If tan A=4/3 then calculate sinA.cosA SOLUTION A B C Let us first draw a right  ABC As we know   3k 4k Therefore BC=4k,AB=3k, where k is any positive number. Now,by using Pythagoras theorem we have  AC 2  = AB 2  + BC 2 =(3K) 2  +(4K) 2 =9K 2  + 16K 2 AC 2  =25K 2  AC=5K
A B C 4k 3k 5K Answer= 12/25
Students tend to make simple mistakes by mislabeling the perpendicular and base To overcome this mistake first determine the Hypotenuse.  The side opposite to acute angle under  Consideration is the perpendicular. COMMON ERROR ALERT
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],QUESTION 1 A C B 25 24 7
In  ABC right angle at B, if calculate all other trigonometric ratios.  QUESTION 2

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Triginometry

  • 1.
  • 2.  
  • 3.
  • 4. A trigonometric ratio is a ratio of the lengths of two sides in a right triangle. TRIGONOMETRIC RATIO
  • 5. Three basic trigonometric ratios: sine cosine tangent each of which is the ratio of one side to another. .
  • 6.
  • 7.
  • 8.
  • 9.
  • 10.
  • 11.
  • 12. opposite adjacent A B C Hypotenuse Base Perpendicular
  • 13. S C T P B P H H B Sin P H Cos B H Tan P B
  • 14. 6 8 10 A B C (P) (B) (H)
  • 15. Identify perpendicular , hypotenuse and base in relation to angle C in given fig. A B C
  • 16.
  • 17.  
  • 18. Example 1: Finding the Value of Trigonometric Ratio sin A, cos A, tan A,cosec A,sec A and cot A . A B C 17 15 8
  • 19. sin A, cos A, tan A,cosec A,sec A and cot A . Sin A Cos A Tan A solution A B C 17 15 8
  • 20. A B C 17 15 8
  • 21. Find the values of all the trigonometric ratios of  . 4 3 ? Pythagoras Theorem: (3) ² + (4)² = c² 5 = c 5
  • 22. Example 2:If tan A=4/3 then calculate sinA.cosA SOLUTION A B C Let us first draw a right ABC As we know 3k 4k Therefore BC=4k,AB=3k, where k is any positive number. Now,by using Pythagoras theorem we have AC 2 = AB 2 + BC 2 =(3K) 2 +(4K) 2 =9K 2 + 16K 2 AC 2 =25K 2 AC=5K
  • 23. A B C 4k 3k 5K Answer= 12/25
  • 24. Students tend to make simple mistakes by mislabeling the perpendicular and base To overcome this mistake first determine the Hypotenuse. The side opposite to acute angle under Consideration is the perpendicular. COMMON ERROR ALERT
  • 25.
  • 26. In ABC right angle at B, if calculate all other trigonometric ratios. QUESTION 2