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Newton’s
Laws of
MotionI. Law of Inertia
II. F=ma
III. Action-Reaction
Newton’s Laws of Motion
 1st Law – Inertia
 2nd Law – F=ma
 3rd Law – Action-Reaction
2nd Law
2nd Law
The net force of an object is
equal to the object’s mass times
its acceleration, or F=ma.
2nd Law (F = m x a)
 How much force is needed to accelerate a 1400
kilogram car 2 meters per second/per second?
 Write the formula
 F = m x a
 Fill in given numbers and units
 F = 1400 kg x 2 m/s/s
 Solve for the unknown
 2800 kg m/s/s or 2800 N
2nd Law
 One newton is equal to the force required to
accelerate one kilogram of mass at one
meter/second/second.
 N = kg m/s/s
Gravity
• F = m a
• Fg = m g
– g is the acceleration due
to gravity
– G is 9.8 m/s/s for
everything.
• Everything accelerates
at the same rate when it
is falling
• Fg = Force of gravity on
an objects is the object’s
weight
Newton’s 2nd Law proves that different masses
accelerate to the earth at the same rate, but with
different forces.
• We know that objects
with different masses
accelerate to the
ground at the same
rate.
• However, because of
the 2nd Law we know
that they don’t hit the
ground with the same
force.
F = ma
98 N = 10 kg x 9.8 m/s/s
F = ma
9.8 N = 1 kg x 9.8 m/s/s
Check Your Understanding
 1. What acceleration will result when a 12 N net force applied to a 3 kg
object? A 6 kg object?
 2. A net force of 16 N causes a mass to accelerate at a rate of 5 m/s2.
Determine the mass.
 3. How much force is needed to accelerate a 66 kg skier 1 m/sec/sec?
 4. What is the force on a 1000 kg elevator that is falling freely at 9.8
m/sec/sec?
Check Your Understanding
 1. What acceleration will result when a 12 N net force applied to a 3 kg object?
12 N = 3 kg x 4 m/s/s
 2. A net force of 16 N causes a mass to accelerate at a rate of 5 m/s2. Determine the
mass.
16 N = 3.2 kg x 5 m/s/s
 3. How much force is needed to accelerate a 66 kg skier 1 m/sec/sec?
66 kg-m/sec/sec or 66 N
 4. What is the force on a 1000 kg elevator that is falling freely at 9.8 m/sec/sec?
 9800 kg-m/sec/sec or 9800 N

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Newtons laws of_motion - 2nd law

  • 1. Newton’s Laws of MotionI. Law of Inertia II. F=ma III. Action-Reaction
  • 2. Newton’s Laws of Motion  1st Law – Inertia  2nd Law – F=ma  3rd Law – Action-Reaction
  • 4. 2nd Law The net force of an object is equal to the object’s mass times its acceleration, or F=ma.
  • 5. 2nd Law (F = m x a)  How much force is needed to accelerate a 1400 kilogram car 2 meters per second/per second?  Write the formula  F = m x a  Fill in given numbers and units  F = 1400 kg x 2 m/s/s  Solve for the unknown  2800 kg m/s/s or 2800 N
  • 6. 2nd Law  One newton is equal to the force required to accelerate one kilogram of mass at one meter/second/second.  N = kg m/s/s
  • 7. Gravity • F = m a • Fg = m g – g is the acceleration due to gravity – G is 9.8 m/s/s for everything. • Everything accelerates at the same rate when it is falling • Fg = Force of gravity on an objects is the object’s weight
  • 8. Newton’s 2nd Law proves that different masses accelerate to the earth at the same rate, but with different forces. • We know that objects with different masses accelerate to the ground at the same rate. • However, because of the 2nd Law we know that they don’t hit the ground with the same force. F = ma 98 N = 10 kg x 9.8 m/s/s F = ma 9.8 N = 1 kg x 9.8 m/s/s
  • 9. Check Your Understanding  1. What acceleration will result when a 12 N net force applied to a 3 kg object? A 6 kg object?  2. A net force of 16 N causes a mass to accelerate at a rate of 5 m/s2. Determine the mass.  3. How much force is needed to accelerate a 66 kg skier 1 m/sec/sec?  4. What is the force on a 1000 kg elevator that is falling freely at 9.8 m/sec/sec?
  • 10. Check Your Understanding  1. What acceleration will result when a 12 N net force applied to a 3 kg object? 12 N = 3 kg x 4 m/s/s  2. A net force of 16 N causes a mass to accelerate at a rate of 5 m/s2. Determine the mass. 16 N = 3.2 kg x 5 m/s/s  3. How much force is needed to accelerate a 66 kg skier 1 m/sec/sec? 66 kg-m/sec/sec or 66 N  4. What is the force on a 1000 kg elevator that is falling freely at 9.8 m/sec/sec?  9800 kg-m/sec/sec or 9800 N