Khusbhoo Shekhawat semester 1

1. SAMRAT PRITHVIRAJ
CHAUHAN GOVERNMENT
COLLEGE
AJMER

2. TOPIC
KINETIC APPLICATION OF
CRYSTAL FIELD THEORY (CFT )
BY
SHEKHAWAT KHUSHBOO NARENDRA
SINGH
MSC PREVIOUS (SEMESTER-l )

3. CONTENT
 Introduction
 Crystal field splitting in octahedral complex
 Square planar complex
 Octahedral complex
 INERT and labile complexes
 Crystal field activation energy
 CFAE of octahedral complex through SN1 mechanism
 CFAE of octahedral complex throught SN2 mechanism
 Examples of inert and labile complexes in octahedral complexes
 Conclusion
 References

4. KINETIC APPLICATION OF CFT
•ORGEL (1952) and JORGENSON (1955)
determined the rate of reaction of complex
compound and pointed out the importance of
crystal field stabilization energy (CFSE )
• CFT assumes the splitting of d - orbital of
metal
•Filling of electrons in them results in difference
in CFSE
•Since the geometries of the reactant and
intermediate are different their splitting and
CFSE are also different

6. SQUARE PLANAR COMPLEX
• Square planar complexes
are always labile
• Because they are not
sterically crowded
• These complexes favours
ligand substitution

7. OCTAHEDRAL COMPLEX
• Due to steric hinderance the
octahedral complex may be inert
or labile
• It depends on electronic
configuration and repulsion
caused between metal orbital and
ligand

8. INERT AND LABILE COMPLEXES
• Depending on the CFSE the complexes may be
inert or labile
• If the CFSE of the complex is greater than that of
activated complex then the complex is inert
• If the CFSE of the complex is less than that of
activated complex then the complex is labile
INERT
 CFSE OF COMPLEX > CFSE OF
ACTIVATED COMPLEX
Labile
 CFSE OF COMPLEX < CFSE OF
ACTIVATED COMPLEX

9. CRYSTAL FIELD ACTIVATION
ENERGY ( CFAE)
• According to HUSH , CFAE is the difference between
CFSE of the intial complex and CFSE of the activated
complex
CFAE = CFSE of intial complex - CFSE of
activated complex

13. CONCLUSION
• If the calculated CFAE is negative or zero
or low the reacting complex will requires
less energy to form intermediate , hence it
will be labile
• If the calculated CFAE is positive or have
high value then the complex will be inert

15. REFERENCES
• UGC ADVANCED INORGANIC
CHEMISTRY ...BY SK AGARWAL AND
KEEMTI LAL
• IN ORGANIC CHEMISTRY ...BY DR
.TRIPATHI SC AND DR . PANDEY
ARCHANA
• WEB SITE = www.gooogle.com