SlideShare una empresa de Scribd logo
1 de 14
Descargar para leer sin conexión
9/24/2013
1
Physical Chemistry
for Petroleum Engineering
CHME01C04
Ahmad Mahmoud MohammadAhmad Mahmoud Mohammad
Associate professor
ahmad.mohammad@bue.edu.eg
Room A-03
Reference book
Chemistry: An atoms First
ApproachApproach
Steven S. Zumdahl
and
Susan A ZumdahlSusan A. Zumdahl
2012
Brooks Cole, a part of Cengage Learning
9/24/2013
2
Course Contents
Stoichiometry of Chemical Reactions (Ch 9);
Gases (Kinetic theory and transport properties) (Ch 7);
Chemical kinetics (Ch 12);Chemical kinetics (Ch 12);
======1st in-class test====(Week 6-7)==========
Spontaneity criteria of processes (Ch 6);
Colligative properties (Ch 11);Colligative properties (Ch 11);
Phase Diagram (Ch 8).
======2nd in-class test====(Week 10-11)========
Assessment
A 3h unseen written examination carries 70% of
the total mark
Two class assignments. This method carries 30%
of the total mark.
Attention
In order to achieve an overall passing mark for this
module, students must achieve
(i) 40% for the total module mark and
(ii) at least 30% in the unseen examination
9/24/2013
3
Chemistry is around you all the time
Chemical reactions have a profound effect on our lives:
• Food is converted to energy in the human body.
• Nitrogen and hydrogen are combined to form ammonia,
which is used as a fertilizer.
• Fuels and plastics are produced from petroleum.
• Starch in plants is synthesized from carbon dioxide and water
using energy from sunlight.
• Human insulin is produced in laboratories by bacteria.
• Cancer is induced in humans by substances from our
environment.
The central activity of chemistry is to understand chemical changes
such as these:
Why do reactions occur?
How fast they occur?
Which specific pathways they follow.?
Chemical Reactions
A chemical change involves a reorganization of the atoms in one or
more substances. Mass is conserved in a chemical reaction.
For example, when the methane (CH4) in natural gas combines with
oxygen (O ) in the air and burns carbon dioxide (CO ) and wateroxygen (O2) in the air and burns, carbon dioxide (CO2) and water
(H2O) are formed.
CH4 + O2 → CO2 + H2O (Unbalanced)
Atoms are neither created nor destroyedy
CH4 + 2O2 → CO2 + 2H2O (Balanced)
9/24/2013
4
The Meaning of a Chemical Equation
The chemical equation for a reaction gives important information:
the nature of the reactants and products
the relative numbers of each.
the physical states of the reactants and products:the physical states of the reactants and products:
For Example
HCl (aq) + NaHCO3 (s) → CO2 ( g) + H2O( l) + NaCl (aq)
Reading Chemical Equations
Mass is conserved in a chemical reaction
9/24/2013
5
Balancing Chemical Reactions
The same number of each type of atom must be found among the
reactants and products.
The identities of the reactants and products of a reaction are
determined by experimental observationdetermined by experimental observation.
For example, when liquid ethanol is burned in the presence of
sufficient oxygen gas, the products are always carbon dioxide
and water.
When the equation for this reaction is balanced, the identities of the
reactants and products must not be changed.
The formulas of the compounds must never be changed in
balancing a chemical equation.
The subscripts in a formula cannot be changed, nor can atoms
be added or subtracted from a formula.
Writing and Balancing the Equation for a
Chemical Reaction
1) Determine what reaction is occurring. What are the reactants, the
products, and the physical states involved?
2) Write the unbalanced equation that summarizes the reaction
described in step 1.
3) Balance the equation by inspection, starting with the most
complicated molecule(s) Determine what coefficients arecomplicated molecule(s). Determine what coefficients are
necessary so that the same number of each type of atom appears
on both reactant and product sides. Do not change the identities
(formulas) of any of the reactants or products.
9/24/2013
6
Example
Write and balance the chemical equation corresponding to the
decomposition of solid ammonium dichromate, (NH4)2Cr2O7, by ignition
into solid chromium(III) oxide, nitrogen gas (N2 ), and water vapor.
AnswerAnswer
Unbalanced equation
Balanced equation
Reality Check
Stoichiometric Calculations:
Reaction of propane with oxygen:
“What mass of oxygen will react with 96.1 grams of propane?”
Balance equationBalance equation
Convert masses and moles:
“How many moles of propane are present in 96.1 grams of
propane?” The molar mass of propane is 44 1propane? The molar mass of propane is 44.1.
9/24/2013
7
Number of moles of O2 necessary to react with 2.18 mole
C3H8
Convert from moles to grams O2
Therefore, 349 g O2 is required to burn 96.1 g propane.
What mass of carbon dioxide is produced when 96.1 grams of
propane is combusted with oxygen? (Homework)
Example
Baking soda (NaHCO3) is often used as an antacid. It neutralizes
excess hydrochloric acid secreted by the stomach:
Milk of magnesia, which is an aqueous suspension of magnesium
hydroxide, is also used as an antacid:
Which is the more effective antacid per gram, NaHCO3 or Mg(OH)2?p g 3 g 2
Answer
The no of moles in 1 g NaHCO3
9/24/2013
8
The no of moles of HCl reacting with 1 g NaHCO3
The no of moles in 1 g Mg(OH)22
The no of moles of HCl reacting with 1 g Mg(OH)2
Mg(OH)2 is the more effective antacid.
Calculating Masses of Reactants and
Products in Chemical Reactions
1) Balance the equation for the reaction.
2) C h k f h d l f h2) Convert the known mass of the reactant or product to moles of that
substance.
3) Use the balanced equation to set up the appropriate mole ratios.
4) Use the appropriate mole ratios to calculate the number of moles
of the desired reactant or product.
5) Convert from moles back to grams if required by the problem.g q y p
9/24/2013
9
The Concept of Limiting Reagent
Suppose you have a part-time job in a sandwich shop. One very
popular sandwich is always made as follows:
2 slices bread + 3 slices meat + 1 slice cheese → sandwich
Assume that you come to work one day and find the following
quantities of ingredients:
8 slices bread
9 slices meat
5 slices cheese5 slices cheese
How many sandwiches can you make? What will be left over?
To solve this problem, let’s see how many sandwiches we can make
with each component:
Bread
Meat
Cheese
How many sandwiches can you make? The answer is 3.
When you run out of meat, you must stop making sandwiches. The
meat is the limiting ingredientmeat is the limiting ingredient.
What do you have left over? Making 3 sandwiches requires 6 pieces
of bread. You started with 8 slices, so you have 2 slices of bread left.
You also used 3 pieces of cheese for the 3 sandwiches, so you have 2
pieces of cheese left.
9/24/2013
10
The Limiting
reactant (here isreactant (here is
meat) is the
component or
ingredient that
limited the number
of products
(sandwiches) youy
could make.
Nitrogen gas can be prepared by passing gaseous ammonia over solid
copper(II) oxide at high temperatures. The other products of the
reaction are solid copper and water vapor. If a sample containing 18.1 g
of NH3 is reacted with 90.4 g of CuO, which is the limiting reactant?
Example
3
How many grams of N2 will be formed?
Solution
Where are we going?
To find the limiting reactant
To find the mass of N2 produced
Wh d k ?What do we know?
The chemical reaction
18.1 g NH3
90.4 g CuO
9/24/2013
11
What information do we need?
Balanced equation for the reaction
Moles of NH3
Moles of CuO
How do we get there?
To find the limiting reactant
What is the balanced equation?
What are the moles of NH3 and CuO?
To find the moles, we need to know the molar masses.
NH3 =17.03 g/mol
CuO =79.55 g/mol
How many moles of CuO are required to react with 1.06 mol NH3?
Thus 1.59 mol CuO is required to react with 1.06 mol NH3. Since only
1.14 mol CuO is actually present, the amount of CuO is limiting; CuO
ill b f NH d W if hi l i bwill run out before NH3 does. We can verify this conclusion by
comparing the mole ratio of CuO and NH3 required by the balanced
equation:
with the mole ratio actually present:
Since the actual ratio is too small (smaller than 1.5), CuO is the limiting
reactant.
9/24/2013
12
To find the mass of N2 produced
What are the moles of N2 formed?
Because CuO is the limiting reactant, we must use the amount of
CuO to calculate the amount of N2 formed.
What are the moles of N2?
What mass of N2 is produced?
U i h l f N (28 02 / l) l l hUsing the molar mass of N2 (28.02 g/mol), we can calculate the
mass of N2 produced:
Percent yield
The amount of a product formed when the limiting reactant is
completely consumed is called the theoretical yield of that product.
“the maximum amount of product that can be produced from thep p
quantities of reactants used”
Actually, the amount of product predicted by the theoretical yield is
seldom obtained because of side reactions and other complications.
Th l i ld f d i f i f hThe actual yield of product is often given as a percentage of the
theoretical yield. This is called the percent yield:
9/24/2013
13
Solving a Stoichiometry Problem
1) Write and balance the equation for the reaction.
2) Convert the known masses of substances to moles.
3) Determine which reactant is limiting.
4) Using the amount of the limiting reactant and the appropriate mole
ratios, compute the number of moles of the desired product.
5) Convert from moles to grams, using the molar mass.
Example
Methanol (CH3OH) is the simplest alcohol. It is used as a fuel in race
cars and is a potential replacement for gasoline. Methanol can be
manufactured by combining gaseous carbon monoxide and hydrogen.
Suppose 68.5 kg CO(g) is reacted with 8.60 kg H2(g). Calculate thepp g (g) g 2(g)
theoretical yield of methanol. If 3.57 x 104 g CH3OH is actually
produced, what is the percent yield of methanol?
Solution
Write the chemical equation
Balance it
Convert mass to moles
9/24/2013
14
Which is limiting? What amount of CH3OH would be produced by complete
reactions of each of the reactants?
Since complete consumption of the H2 produces the smaller amount of CH3OH, H2
is the limiting reactant.
Calculate the theoretical Yield
Calculate the Percent Yield
Example
Consider the equation 2A + B → A2B. If you mix 1.0 mole of A with 2.0 mole of
B, the number of moles of A2B produced if the reaction is 100% complete is
0.5 , 1.0, 2.0, 3.0
A is the limiting reactant and consequently 0 5 mole A2B producedA is the limiting reactant and consequently 0.5 mole A2B produced
========================================================
Which (if any) of the following is true regarding the limiting reactant in a chemical
reaction?
The limiting reactant has the lowest coefficient in a balanced equation.
The limiting reactant is the reactant for which you have the fewest number
of moles.
The limiting reactant has the lowest ratio of moles available/coefficient in
the balanced equation.
The limiting reactant has the lowest ratio of coefficient in the balanced
equation/moles available.
This is one way to identify the limiting reactant

Más contenido relacionado

La actualidad más candente (20)

Chapter 14
Chapter 14Chapter 14
Chapter 14
 
Chapter4
Chapter4Chapter4
Chapter4
 
Chapter 12 Stoichiometry
Chapter 12 StoichiometryChapter 12 Stoichiometry
Chapter 12 Stoichiometry
 
Unit-1 : Some basic concepts of chemistry
 Unit-1 : Some basic concepts of chemistry Unit-1 : Some basic concepts of chemistry
Unit-1 : Some basic concepts of chemistry
 
Chapter 1.powerpoint 1
Chapter 1.powerpoint 1Chapter 1.powerpoint 1
Chapter 1.powerpoint 1
 
Stoichiometry
StoichiometryStoichiometry
Stoichiometry
 
C05 the mole concept
C05 the mole conceptC05 the mole concept
C05 the mole concept
 
stoichiometric relations
stoichiometric relations stoichiometric relations
stoichiometric relations
 
2. F.sc chemistry chapter#01 "Stoichiometry"
2. F.sc chemistry chapter#01   "Stoichiometry"2. F.sc chemistry chapter#01   "Stoichiometry"
2. F.sc chemistry chapter#01 "Stoichiometry"
 
Ch6 Thermochemistry (updated)
Ch6 Thermochemistry (updated)Ch6 Thermochemistry (updated)
Ch6 Thermochemistry (updated)
 
Tang 07 determining the rate exponent
Tang 07   determining the rate exponentTang 07   determining the rate exponent
Tang 07 determining the rate exponent
 
Chapter 5
Chapter 5Chapter 5
Chapter 5
 
Chemistry - Chp 12 - Stoichiometry - PowerPoint
Chemistry - Chp 12 - Stoichiometry - PowerPointChemistry - Chp 12 - Stoichiometry - PowerPoint
Chemistry - Chp 12 - Stoichiometry - PowerPoint
 
Ch5 Gases
Ch5 GasesCh5 Gases
Ch5 Gases
 
Full answer key to hw2
Full answer key to hw2Full answer key to hw2
Full answer key to hw2
 
Stoikiometri reaksi
Stoikiometri reaksiStoikiometri reaksi
Stoikiometri reaksi
 
B sc_I_General chemistry U-III(B)Molecular formula and empirical formula
B sc_I_General chemistry U-III(B)Molecular formula and empirical formula B sc_I_General chemistry U-III(B)Molecular formula and empirical formula
B sc_I_General chemistry U-III(B)Molecular formula and empirical formula
 
Ch.06 Chemical Equilibrium
Ch.06 Chemical EquilibriumCh.06 Chemical Equilibrium
Ch.06 Chemical Equilibrium
 
Chapter 5
Chapter 5Chapter 5
Chapter 5
 
Chapter 7
Chapter 7Chapter 7
Chapter 7
 

Similar a Physical Chemistry

MDCAT Chemistry Notes | Nearpeer
MDCAT Chemistry Notes | NearpeerMDCAT Chemistry Notes | Nearpeer
MDCAT Chemistry Notes | NearpeerMianAliImtiaz
 
Grade 9 Chemistry ppt.pptx
Grade 9 Chemistry ppt.pptxGrade 9 Chemistry ppt.pptx
Grade 9 Chemistry ppt.pptxSimrgetaAwash1
 
Chapter12stoichiometry 1229099374861225-1
Chapter12stoichiometry 1229099374861225-1Chapter12stoichiometry 1229099374861225-1
Chapter12stoichiometry 1229099374861225-1Daniel Marco
 
Basics of Chemistry: Chemical stoichiometry
Basics of Chemistry: Chemical stoichiometryBasics of Chemistry: Chemical stoichiometry
Basics of Chemistry: Chemical stoichiometryRAJEEVBAYAN1
 
Chemistry - Chp 12 - Stoichiometry - PowerPoint
Chemistry - Chp 12 - Stoichiometry - PowerPointChemistry - Chp 12 - Stoichiometry - PowerPoint
Chemistry - Chp 12 - Stoichiometry - PowerPointMel Anthony Pepito
 
Gen chem topic 3 guobi
Gen chem topic 3  guobiGen chem topic 3  guobi
Gen chem topic 3 guobiEasyStudy3
 
Stoichiometry
StoichiometryStoichiometry
StoichiometryAmie L
 
Blb12 ch03 lecture
Blb12 ch03 lectureBlb12 ch03 lecture
Blb12 ch03 lectureEric Buday
 
Chem 101 week 5
Chem 101 week 5Chem 101 week 5
Chem 101 week 5tdean1
 
Chapter 12 Stoichiometry
Chapter 12   StoichiometryChapter 12   Stoichiometry
Chapter 12 StoichiometryGalen West
 
Ch03 outline
Ch03 outlineCh03 outline
Ch03 outlineAP_Chem
 
AP Chemistry Chapter 3 Outline
AP Chemistry Chapter 3 OutlineAP Chemistry Chapter 3 Outline
AP Chemistry Chapter 3 OutlineJane Hamze
 

Similar a Physical Chemistry (20)

MDCAT Chemistry Notes | Nearpeer
MDCAT Chemistry Notes | NearpeerMDCAT Chemistry Notes | Nearpeer
MDCAT Chemistry Notes | Nearpeer
 
Grade 9 Chemistry ppt.pptx
Grade 9 Chemistry ppt.pptxGrade 9 Chemistry ppt.pptx
Grade 9 Chemistry ppt.pptx
 
Chapter12stoichiometry 1229099374861225-1
Chapter12stoichiometry 1229099374861225-1Chapter12stoichiometry 1229099374861225-1
Chapter12stoichiometry 1229099374861225-1
 
Stoichiometry
Stoichiometry Stoichiometry
Stoichiometry
 
Stoichiometry
StoichiometryStoichiometry
Stoichiometry
 
Chemistry
ChemistryChemistry
Chemistry
 
Basics of Chemistry: Chemical stoichiometry
Basics of Chemistry: Chemical stoichiometryBasics of Chemistry: Chemical stoichiometry
Basics of Chemistry: Chemical stoichiometry
 
STOICHIMETRY.ppt
STOICHIMETRY.pptSTOICHIMETRY.ppt
STOICHIMETRY.ppt
 
Ch3.ppt
Ch3.pptCh3.ppt
Ch3.ppt
 
Chemistry - Chp 12 - Stoichiometry - PowerPoint
Chemistry - Chp 12 - Stoichiometry - PowerPointChemistry - Chp 12 - Stoichiometry - PowerPoint
Chemistry - Chp 12 - Stoichiometry - PowerPoint
 
Gen chem topic 3 guobi
Gen chem topic 3  guobiGen chem topic 3  guobi
Gen chem topic 3 guobi
 
Adv chem chapt 3
Adv chem chapt 3Adv chem chapt 3
Adv chem chapt 3
 
Stoichiometry
StoichiometryStoichiometry
Stoichiometry
 
Blb12 ch03 lecture
Blb12 ch03 lectureBlb12 ch03 lecture
Blb12 ch03 lecture
 
Chem 101 week 5
Chem 101 week 5Chem 101 week 5
Chem 101 week 5
 
Chapter 12 Stoichiometry
Chapter 12   StoichiometryChapter 12   Stoichiometry
Chapter 12 Stoichiometry
 
Stoichiometry
StoichiometryStoichiometry
Stoichiometry
 
Ch. 5 lecture
Ch. 5 lectureCh. 5 lecture
Ch. 5 lecture
 
Ch03 outline
Ch03 outlineCh03 outline
Ch03 outline
 
AP Chemistry Chapter 3 Outline
AP Chemistry Chapter 3 OutlineAP Chemistry Chapter 3 Outline
AP Chemistry Chapter 3 Outline
 

Último

Measures of Central Tendency: Mean, Median and Mode
Measures of Central Tendency: Mean, Median and ModeMeasures of Central Tendency: Mean, Median and Mode
Measures of Central Tendency: Mean, Median and ModeThiyagu K
 
Disha NEET Physics Guide for classes 11 and 12.pdf
Disha NEET Physics Guide for classes 11 and 12.pdfDisha NEET Physics Guide for classes 11 and 12.pdf
Disha NEET Physics Guide for classes 11 and 12.pdfchloefrazer622
 
Measures of Dispersion and Variability: Range, QD, AD and SD
Measures of Dispersion and Variability: Range, QD, AD and SDMeasures of Dispersion and Variability: Range, QD, AD and SD
Measures of Dispersion and Variability: Range, QD, AD and SDThiyagu K
 
Q4-W6-Restating Informational Text Grade 3
Q4-W6-Restating Informational Text Grade 3Q4-W6-Restating Informational Text Grade 3
Q4-W6-Restating Informational Text Grade 3JemimahLaneBuaron
 
Grant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy ConsultingGrant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy ConsultingTechSoup
 
CARE OF CHILD IN INCUBATOR..........pptx
CARE OF CHILD IN INCUBATOR..........pptxCARE OF CHILD IN INCUBATOR..........pptx
CARE OF CHILD IN INCUBATOR..........pptxGaneshChakor2
 
Beyond the EU: DORA and NIS 2 Directive's Global Impact
Beyond the EU: DORA and NIS 2 Directive's Global ImpactBeyond the EU: DORA and NIS 2 Directive's Global Impact
Beyond the EU: DORA and NIS 2 Directive's Global ImpactPECB
 
Mastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory InspectionMastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory InspectionSafetyChain Software
 
Organic Name Reactions for the students and aspirants of Chemistry12th.pptx
Organic Name Reactions  for the students and aspirants of Chemistry12th.pptxOrganic Name Reactions  for the students and aspirants of Chemistry12th.pptx
Organic Name Reactions for the students and aspirants of Chemistry12th.pptxVS Mahajan Coaching Centre
 
Introduction to Nonprofit Accounting: The Basics
Introduction to Nonprofit Accounting: The BasicsIntroduction to Nonprofit Accounting: The Basics
Introduction to Nonprofit Accounting: The BasicsTechSoup
 
Nutritional Needs Presentation - HLTH 104
Nutritional Needs Presentation - HLTH 104Nutritional Needs Presentation - HLTH 104
Nutritional Needs Presentation - HLTH 104misteraugie
 
Web & Social Media Analytics Previous Year Question Paper.pdf
Web & Social Media Analytics Previous Year Question Paper.pdfWeb & Social Media Analytics Previous Year Question Paper.pdf
Web & Social Media Analytics Previous Year Question Paper.pdfJayanti Pande
 
SOCIAL AND HISTORICAL CONTEXT - LFTVD.pptx
SOCIAL AND HISTORICAL CONTEXT - LFTVD.pptxSOCIAL AND HISTORICAL CONTEXT - LFTVD.pptx
SOCIAL AND HISTORICAL CONTEXT - LFTVD.pptxiammrhaywood
 
9548086042 for call girls in Indira Nagar with room service
9548086042  for call girls in Indira Nagar  with room service9548086042  for call girls in Indira Nagar  with room service
9548086042 for call girls in Indira Nagar with room servicediscovermytutordmt
 
microwave assisted reaction. General introduction
microwave assisted reaction. General introductionmicrowave assisted reaction. General introduction
microwave assisted reaction. General introductionMaksud Ahmed
 
Activity 01 - Artificial Culture (1).pdf
Activity 01 - Artificial Culture (1).pdfActivity 01 - Artificial Culture (1).pdf
Activity 01 - Artificial Culture (1).pdfciinovamais
 
Sanyam Choudhary Chemistry practical.pdf
Sanyam Choudhary Chemistry practical.pdfSanyam Choudhary Chemistry practical.pdf
Sanyam Choudhary Chemistry practical.pdfsanyamsingh5019
 
1029 - Danh muc Sach Giao Khoa 10 . pdf
1029 -  Danh muc Sach Giao Khoa 10 . pdf1029 -  Danh muc Sach Giao Khoa 10 . pdf
1029 - Danh muc Sach Giao Khoa 10 . pdfQucHHunhnh
 

Último (20)

Código Creativo y Arte de Software | Unidad 1
Código Creativo y Arte de Software | Unidad 1Código Creativo y Arte de Software | Unidad 1
Código Creativo y Arte de Software | Unidad 1
 
Measures of Central Tendency: Mean, Median and Mode
Measures of Central Tendency: Mean, Median and ModeMeasures of Central Tendency: Mean, Median and Mode
Measures of Central Tendency: Mean, Median and Mode
 
Disha NEET Physics Guide for classes 11 and 12.pdf
Disha NEET Physics Guide for classes 11 and 12.pdfDisha NEET Physics Guide for classes 11 and 12.pdf
Disha NEET Physics Guide for classes 11 and 12.pdf
 
Measures of Dispersion and Variability: Range, QD, AD and SD
Measures of Dispersion and Variability: Range, QD, AD and SDMeasures of Dispersion and Variability: Range, QD, AD and SD
Measures of Dispersion and Variability: Range, QD, AD and SD
 
Q4-W6-Restating Informational Text Grade 3
Q4-W6-Restating Informational Text Grade 3Q4-W6-Restating Informational Text Grade 3
Q4-W6-Restating Informational Text Grade 3
 
Grant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy ConsultingGrant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy Consulting
 
CARE OF CHILD IN INCUBATOR..........pptx
CARE OF CHILD IN INCUBATOR..........pptxCARE OF CHILD IN INCUBATOR..........pptx
CARE OF CHILD IN INCUBATOR..........pptx
 
Mattingly "AI & Prompt Design: Structured Data, Assistants, & RAG"
Mattingly "AI & Prompt Design: Structured Data, Assistants, & RAG"Mattingly "AI & Prompt Design: Structured Data, Assistants, & RAG"
Mattingly "AI & Prompt Design: Structured Data, Assistants, & RAG"
 
Beyond the EU: DORA and NIS 2 Directive's Global Impact
Beyond the EU: DORA and NIS 2 Directive's Global ImpactBeyond the EU: DORA and NIS 2 Directive's Global Impact
Beyond the EU: DORA and NIS 2 Directive's Global Impact
 
Mastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory InspectionMastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory Inspection
 
Organic Name Reactions for the students and aspirants of Chemistry12th.pptx
Organic Name Reactions  for the students and aspirants of Chemistry12th.pptxOrganic Name Reactions  for the students and aspirants of Chemistry12th.pptx
Organic Name Reactions for the students and aspirants of Chemistry12th.pptx
 
Introduction to Nonprofit Accounting: The Basics
Introduction to Nonprofit Accounting: The BasicsIntroduction to Nonprofit Accounting: The Basics
Introduction to Nonprofit Accounting: The Basics
 
Nutritional Needs Presentation - HLTH 104
Nutritional Needs Presentation - HLTH 104Nutritional Needs Presentation - HLTH 104
Nutritional Needs Presentation - HLTH 104
 
Web & Social Media Analytics Previous Year Question Paper.pdf
Web & Social Media Analytics Previous Year Question Paper.pdfWeb & Social Media Analytics Previous Year Question Paper.pdf
Web & Social Media Analytics Previous Year Question Paper.pdf
 
SOCIAL AND HISTORICAL CONTEXT - LFTVD.pptx
SOCIAL AND HISTORICAL CONTEXT - LFTVD.pptxSOCIAL AND HISTORICAL CONTEXT - LFTVD.pptx
SOCIAL AND HISTORICAL CONTEXT - LFTVD.pptx
 
9548086042 for call girls in Indira Nagar with room service
9548086042  for call girls in Indira Nagar  with room service9548086042  for call girls in Indira Nagar  with room service
9548086042 for call girls in Indira Nagar with room service
 
microwave assisted reaction. General introduction
microwave assisted reaction. General introductionmicrowave assisted reaction. General introduction
microwave assisted reaction. General introduction
 
Activity 01 - Artificial Culture (1).pdf
Activity 01 - Artificial Culture (1).pdfActivity 01 - Artificial Culture (1).pdf
Activity 01 - Artificial Culture (1).pdf
 
Sanyam Choudhary Chemistry practical.pdf
Sanyam Choudhary Chemistry practical.pdfSanyam Choudhary Chemistry practical.pdf
Sanyam Choudhary Chemistry practical.pdf
 
1029 - Danh muc Sach Giao Khoa 10 . pdf
1029 -  Danh muc Sach Giao Khoa 10 . pdf1029 -  Danh muc Sach Giao Khoa 10 . pdf
1029 - Danh muc Sach Giao Khoa 10 . pdf
 

Physical Chemistry

  • 1. 9/24/2013 1 Physical Chemistry for Petroleum Engineering CHME01C04 Ahmad Mahmoud MohammadAhmad Mahmoud Mohammad Associate professor ahmad.mohammad@bue.edu.eg Room A-03 Reference book Chemistry: An atoms First ApproachApproach Steven S. Zumdahl and Susan A ZumdahlSusan A. Zumdahl 2012 Brooks Cole, a part of Cengage Learning
  • 2. 9/24/2013 2 Course Contents Stoichiometry of Chemical Reactions (Ch 9); Gases (Kinetic theory and transport properties) (Ch 7); Chemical kinetics (Ch 12);Chemical kinetics (Ch 12); ======1st in-class test====(Week 6-7)========== Spontaneity criteria of processes (Ch 6); Colligative properties (Ch 11);Colligative properties (Ch 11); Phase Diagram (Ch 8). ======2nd in-class test====(Week 10-11)======== Assessment A 3h unseen written examination carries 70% of the total mark Two class assignments. This method carries 30% of the total mark. Attention In order to achieve an overall passing mark for this module, students must achieve (i) 40% for the total module mark and (ii) at least 30% in the unseen examination
  • 3. 9/24/2013 3 Chemistry is around you all the time Chemical reactions have a profound effect on our lives: • Food is converted to energy in the human body. • Nitrogen and hydrogen are combined to form ammonia, which is used as a fertilizer. • Fuels and plastics are produced from petroleum. • Starch in plants is synthesized from carbon dioxide and water using energy from sunlight. • Human insulin is produced in laboratories by bacteria. • Cancer is induced in humans by substances from our environment. The central activity of chemistry is to understand chemical changes such as these: Why do reactions occur? How fast they occur? Which specific pathways they follow.? Chemical Reactions A chemical change involves a reorganization of the atoms in one or more substances. Mass is conserved in a chemical reaction. For example, when the methane (CH4) in natural gas combines with oxygen (O ) in the air and burns carbon dioxide (CO ) and wateroxygen (O2) in the air and burns, carbon dioxide (CO2) and water (H2O) are formed. CH4 + O2 → CO2 + H2O (Unbalanced) Atoms are neither created nor destroyedy CH4 + 2O2 → CO2 + 2H2O (Balanced)
  • 4. 9/24/2013 4 The Meaning of a Chemical Equation The chemical equation for a reaction gives important information: the nature of the reactants and products the relative numbers of each. the physical states of the reactants and products:the physical states of the reactants and products: For Example HCl (aq) + NaHCO3 (s) → CO2 ( g) + H2O( l) + NaCl (aq) Reading Chemical Equations Mass is conserved in a chemical reaction
  • 5. 9/24/2013 5 Balancing Chemical Reactions The same number of each type of atom must be found among the reactants and products. The identities of the reactants and products of a reaction are determined by experimental observationdetermined by experimental observation. For example, when liquid ethanol is burned in the presence of sufficient oxygen gas, the products are always carbon dioxide and water. When the equation for this reaction is balanced, the identities of the reactants and products must not be changed. The formulas of the compounds must never be changed in balancing a chemical equation. The subscripts in a formula cannot be changed, nor can atoms be added or subtracted from a formula. Writing and Balancing the Equation for a Chemical Reaction 1) Determine what reaction is occurring. What are the reactants, the products, and the physical states involved? 2) Write the unbalanced equation that summarizes the reaction described in step 1. 3) Balance the equation by inspection, starting with the most complicated molecule(s) Determine what coefficients arecomplicated molecule(s). Determine what coefficients are necessary so that the same number of each type of atom appears on both reactant and product sides. Do not change the identities (formulas) of any of the reactants or products.
  • 6. 9/24/2013 6 Example Write and balance the chemical equation corresponding to the decomposition of solid ammonium dichromate, (NH4)2Cr2O7, by ignition into solid chromium(III) oxide, nitrogen gas (N2 ), and water vapor. AnswerAnswer Unbalanced equation Balanced equation Reality Check Stoichiometric Calculations: Reaction of propane with oxygen: “What mass of oxygen will react with 96.1 grams of propane?” Balance equationBalance equation Convert masses and moles: “How many moles of propane are present in 96.1 grams of propane?” The molar mass of propane is 44 1propane? The molar mass of propane is 44.1.
  • 7. 9/24/2013 7 Number of moles of O2 necessary to react with 2.18 mole C3H8 Convert from moles to grams O2 Therefore, 349 g O2 is required to burn 96.1 g propane. What mass of carbon dioxide is produced when 96.1 grams of propane is combusted with oxygen? (Homework) Example Baking soda (NaHCO3) is often used as an antacid. It neutralizes excess hydrochloric acid secreted by the stomach: Milk of magnesia, which is an aqueous suspension of magnesium hydroxide, is also used as an antacid: Which is the more effective antacid per gram, NaHCO3 or Mg(OH)2?p g 3 g 2 Answer The no of moles in 1 g NaHCO3
  • 8. 9/24/2013 8 The no of moles of HCl reacting with 1 g NaHCO3 The no of moles in 1 g Mg(OH)22 The no of moles of HCl reacting with 1 g Mg(OH)2 Mg(OH)2 is the more effective antacid. Calculating Masses of Reactants and Products in Chemical Reactions 1) Balance the equation for the reaction. 2) C h k f h d l f h2) Convert the known mass of the reactant or product to moles of that substance. 3) Use the balanced equation to set up the appropriate mole ratios. 4) Use the appropriate mole ratios to calculate the number of moles of the desired reactant or product. 5) Convert from moles back to grams if required by the problem.g q y p
  • 9. 9/24/2013 9 The Concept of Limiting Reagent Suppose you have a part-time job in a sandwich shop. One very popular sandwich is always made as follows: 2 slices bread + 3 slices meat + 1 slice cheese → sandwich Assume that you come to work one day and find the following quantities of ingredients: 8 slices bread 9 slices meat 5 slices cheese5 slices cheese How many sandwiches can you make? What will be left over? To solve this problem, let’s see how many sandwiches we can make with each component: Bread Meat Cheese How many sandwiches can you make? The answer is 3. When you run out of meat, you must stop making sandwiches. The meat is the limiting ingredientmeat is the limiting ingredient. What do you have left over? Making 3 sandwiches requires 6 pieces of bread. You started with 8 slices, so you have 2 slices of bread left. You also used 3 pieces of cheese for the 3 sandwiches, so you have 2 pieces of cheese left.
  • 10. 9/24/2013 10 The Limiting reactant (here isreactant (here is meat) is the component or ingredient that limited the number of products (sandwiches) youy could make. Nitrogen gas can be prepared by passing gaseous ammonia over solid copper(II) oxide at high temperatures. The other products of the reaction are solid copper and water vapor. If a sample containing 18.1 g of NH3 is reacted with 90.4 g of CuO, which is the limiting reactant? Example 3 How many grams of N2 will be formed? Solution Where are we going? To find the limiting reactant To find the mass of N2 produced Wh d k ?What do we know? The chemical reaction 18.1 g NH3 90.4 g CuO
  • 11. 9/24/2013 11 What information do we need? Balanced equation for the reaction Moles of NH3 Moles of CuO How do we get there? To find the limiting reactant What is the balanced equation? What are the moles of NH3 and CuO? To find the moles, we need to know the molar masses. NH3 =17.03 g/mol CuO =79.55 g/mol How many moles of CuO are required to react with 1.06 mol NH3? Thus 1.59 mol CuO is required to react with 1.06 mol NH3. Since only 1.14 mol CuO is actually present, the amount of CuO is limiting; CuO ill b f NH d W if hi l i bwill run out before NH3 does. We can verify this conclusion by comparing the mole ratio of CuO and NH3 required by the balanced equation: with the mole ratio actually present: Since the actual ratio is too small (smaller than 1.5), CuO is the limiting reactant.
  • 12. 9/24/2013 12 To find the mass of N2 produced What are the moles of N2 formed? Because CuO is the limiting reactant, we must use the amount of CuO to calculate the amount of N2 formed. What are the moles of N2? What mass of N2 is produced? U i h l f N (28 02 / l) l l hUsing the molar mass of N2 (28.02 g/mol), we can calculate the mass of N2 produced: Percent yield The amount of a product formed when the limiting reactant is completely consumed is called the theoretical yield of that product. “the maximum amount of product that can be produced from thep p quantities of reactants used” Actually, the amount of product predicted by the theoretical yield is seldom obtained because of side reactions and other complications. Th l i ld f d i f i f hThe actual yield of product is often given as a percentage of the theoretical yield. This is called the percent yield:
  • 13. 9/24/2013 13 Solving a Stoichiometry Problem 1) Write and balance the equation for the reaction. 2) Convert the known masses of substances to moles. 3) Determine which reactant is limiting. 4) Using the amount of the limiting reactant and the appropriate mole ratios, compute the number of moles of the desired product. 5) Convert from moles to grams, using the molar mass. Example Methanol (CH3OH) is the simplest alcohol. It is used as a fuel in race cars and is a potential replacement for gasoline. Methanol can be manufactured by combining gaseous carbon monoxide and hydrogen. Suppose 68.5 kg CO(g) is reacted with 8.60 kg H2(g). Calculate thepp g (g) g 2(g) theoretical yield of methanol. If 3.57 x 104 g CH3OH is actually produced, what is the percent yield of methanol? Solution Write the chemical equation Balance it Convert mass to moles
  • 14. 9/24/2013 14 Which is limiting? What amount of CH3OH would be produced by complete reactions of each of the reactants? Since complete consumption of the H2 produces the smaller amount of CH3OH, H2 is the limiting reactant. Calculate the theoretical Yield Calculate the Percent Yield Example Consider the equation 2A + B → A2B. If you mix 1.0 mole of A with 2.0 mole of B, the number of moles of A2B produced if the reaction is 100% complete is 0.5 , 1.0, 2.0, 3.0 A is the limiting reactant and consequently 0 5 mole A2B producedA is the limiting reactant and consequently 0.5 mole A2B produced ======================================================== Which (if any) of the following is true regarding the limiting reactant in a chemical reaction? The limiting reactant has the lowest coefficient in a balanced equation. The limiting reactant is the reactant for which you have the fewest number of moles. The limiting reactant has the lowest ratio of moles available/coefficient in the balanced equation. The limiting reactant has the lowest ratio of coefficient in the balanced equation/moles available. This is one way to identify the limiting reactant