Ina survey of women (ages 20-29) the mean height 64.2 inches with a standard deviation of 2.94 inches. Answer the following questions about the specified normal distribution.A What height represents the 99th percentile? B.. What height represents the first quartile? Solution The 99th percentile corresponds to a z-score of 2.326. Hence, X= mean+sd*2.326 = 64.2+2.94*2.326 = 71.04 The first quartile corresponds to a z-score of -0.674. Hence, X=mean+sd*(-0.674)= 64.2+2.94*(-0.674)= 62.22.