Calculate the estimate for the standard error of the difference between two proportions for each of the following cases: a. n1 = 40, p1 = 0.8, n2 = 50, and p2 = 0.8 b. n1 = 33, p1 = 0.6, n2 = 38, and p2 = 0.65 Solution Standard Error Formula = Square Root of [p1*(1-p1)/n1 + p2*(1-p2)/n2] a) So plugging in values: sqrt [0.8*(1-0.8)/40 + 0.8*(1-0.8)/50] = 0.08485 b) Same, plug and chug: sqrt [0.6*(1-0.6)/33 + 0.65*(1-0.65)/38] = 0.11515 Hope this helps!.