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not sure what this question is asking to be honest if someonecould do say for a = 2 and 3, I'm
thinking I could figure itout
not sure what this question is asking to be honest if someonecould do say for a = 2 and 3, I'm
thinking I could figure itout
Solution
since 5 has an order of 6, wouldn't 5^5 be the most you canreduce it in mod 7?, whereas 6^5 is
congruent to 6(mod7) since itsorder is 2

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not sure what this question is asking to be honest if someonecould.pdf

  • 1. not sure what this question is asking to be honest if someonecould do say for a = 2 and 3, I'm thinking I could figure itout not sure what this question is asking to be honest if someonecould do say for a = 2 and 3, I'm thinking I could figure itout Solution since 5 has an order of 6, wouldn't 5^5 be the most you canreduce it in mod 7?, whereas 6^5 is congruent to 6(mod7) since itsorder is 2