#7. Consider the following hypothesis test ( =0.0475) H021.85Ha.pdf

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\#7. Consider the following hypothesis test ( =0.0475) : H0:21.85Ha:<21.85 2 A sample of 36 provided a sample mean of 20.86 . The population standard deviation is 4.08 . (1). What is the test statistic? (4 points) (2). What is the critical value? (4 points) (3). What is the p-value? (4 points) (4). For this question, which of the following conclusions is true? [Multiple Choice] (4 points) (A). Because p-value >0.0475, we do not reject H0. (B). There is no conclusion. (C). Because p-value >0.0475, we reject H00. (D). Because p-values 0.0475 , we do not reject H0. (E). Because p-value 0.0475, we reject H0. (F). None of the above. (5). For this question, which of the following conclusions is true? [Multiple Choice] (4 points) (A). Because critical values 0.0475 , we reject H0. (B). Because test statisticseritical value, we reject H0. (C). Because test statisticseritical value, we do not reject H0. (D). Because test statistic > critical value, we reject H. . (E). Because test statistic > critical value, we do not reject H0. (F). None of the above..

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- Problem: Design a simple ALU using VHDL capable of performing the operations listed on the table on the left. - The ALU shall be capable of operating on 12-bit, two's complement binary numbers and activate flags for overflow (O), carry (C), zero (Z), and sign (S) conditions. - Operations shall be specified via a 4-bit opcode (OC) fed to the ALU along with the operands. Operands shall be fed to the ALU in the form of 16-bit values in a sequence of one or two cycles, producing results in the next cycle. - Results shall be in the form [status)[result], where [status] is a 4-bit code in the form [OCZS] in the four most significant bits and a 12-bit result in the remaining bits. - Two-operand functions: Require two input cycles. The first cycle feeds operand A aligned in bits 11 down to 0. Bits 15 down to 12 will include a NOP opcode in the form 1111. Operand B shall be fed in the same fashion as operand A, replacing the NOP bits with the opcode of the requested operation. - Specitying a NOP in the 2nd cycle shall produce an error result Your task is to design and simulate this ALU with all flags set and an all ones result - One-operand functions: Operate only on A with opcode - Implement your ALU using VHDL. Simulate its operation specified in the first cycle instead of NOP. Entering a twousing a file-fed testbench. Verify that the ALU produces operand opcode in the 1st cycle causes the operand to be correct results for all supported operations, including the operated on itself. For example, specitying opcode 0011 (MUL) status flags being set correctly for each operation. in the 1 st cycle produces AA=A2 - Your ALU shall be optimized for speed and perlorm each - Flags shall function as follows: operation within a single clock cycle. The multiplication - Overliow (OF): Shall be set when the result of an operation operation should be implemented using a combinational overtlows the range of values that can be represented in the circuit or a pipeline, as appropriate. ALU output. - Carry (CF): Shall be set when an operation generates a carry. - Ensure that the input and output signals are properly out of the most significant bit position. synchronized with the rising edge of the clock signal. - Zero (ZF): shall be set when the result of an operation is zero. - You should provide a report with a brief description of your - Sign (SF): Shall be set when the result of an operation is design, your VHDL code, the simulation results, and a brief negative. discussion of any challenges or issues that you - Example: Adding A=4A6h to B=54Bh encountered during the design process. - Cycle 0: F4A6h - The instructor will provide a file with 256 random test - Cycle 1:054Bh vectors and operations to assess the functionality of your The next cycle (Cycle 2) shall produce the result 19F1 design..

- Problem Design a simple ALU using VHDL capable of performing the o.pdf

#7. Consider the following hypothesis test ( =0.0475) H021.85Ha.pdf

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#7. Consider the following hypothesis test ( =0.0475) H021.85Ha.pdf