Short Inter-Frame Spacing 7. What is the Exposed station problem (mul.pdf

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The document discusses the exposed station problem in wireless networks and solutions to it. The exposed station problem arises when a transmitting station is prevented from sending frames due to interference with another transmitting station. It occurs specifically when two nodes waiting to transmit each to a different target node are aware of each other but not of the other's target. The exposed station problem can be solved by the MAC layer protocol IEEE 802.11 RTS/CTS under certain conditions.

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Short Inter-Frame Spacing 7. What is the Exposed station problem (multiple answers)? * a
transmission problem that solved by the TCP/IP layer protocol a transmission problem that arises
when a transmitting station is prevented from sending frames due to interhtrence with another
transmitting station a transmission problem that occurs when two nodes waiting to transmit, each
to a different target node, are aware of each other but not of the other's target a transmission
problem that solved by the MAC (medium access control) layer protocol IEEE 802.11 RTS/CTS,
with the condition that the stations are synchronized and frame sizes and data speed are the same
8. Choice please Logical Link Control Layer Services (multiple choice) *

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Step 1:You need to run the JAVA programs in sections 3.3 and 3.5 for selection sort and insertion sort. You need to attach the output results. Step 2: You need to modify these two programs, save them, submit them, and add some comments and explanations to them to sort the list elements from high to low value. The index should be IndexHighest instead IndexSmallest. Step3: Run the modified programs and print out the results and submit them. In the end, you need the running results for original JAVA programs (selection and insertion sort JAVA programs), the two modified programs to sort the values from high to low value for selection and insertion sorts, and the results for the modified programs. This program uses the selection sort algorithm to sort an array. The code has been modified to also calculate how many item comparisons are done. You can try running the program with different arrays to see how the total number of comparisons changes (or doesn't change). CODE 3.3 --- import java.util.Arrays; public class SelectionSortDemo { private static int selectionSort(int[] numbers) { // A variable to hold the number of item comparisons int comparisons = 0; for (int i = 0; i < numbers.length - 1; i++) { // Find index of smallest remaining element int indexSmallest = i; for (int j = i + 1; j < numbers.length; j++) { comparisons++; if (numbers[j] < numbers[indexSmallest]) { indexSmallest = j; } } // Swap numbers[i] and numbers[indexSmallest] int temp = numbers[i]; numbers[i] = numbers[indexSmallest]; numbers[indexSmallest] = temp; } return comparisons; } public static void main(String[] args) { // Create an array of numbers to sort int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 }; // Display the contents of the array System.out.println("UNSORTED: " + Arrays.toString(numbers)); // Call the selectionSort method int comparisons = selectionSort(numbers); // Display the sorted contents of the array System.out.println("SORTED: " + Arrays.toString(numbers)); System.out.println("Total comparisons: " + comparisons); } } CODE 3.5 --- import java.util.Arrays; public class InsertionSortDemo { private static void insertionSort(int[] numbers) { for (int i = 1; i < numbers.length; i++) { int j = i; while (j > 0 && numbers[j] < numbers[j - 1]) { // Swap numbers[j] and numbers [j - 1] int temp = numbers[j]; numbers[j] = numbers[j - 1]; numbers[j - 1] = temp; j--; } } } public static void main(String[] args) { // Create an array of numbers to sort int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 }; // Display the contents of the array System.out.println("UNSORTED: " + Arrays.toString(numbers)); // Call the insertionSort method insertionSort(numbers); // Display the sorted contents of the array System.out.println("SORTED: " + Arrays.toString(numbers)); } }.

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