1. Learning Outcomes
Perform mixed operations with money up to a value
of RM 10 million.
Solve problems in real context involving
computation of money.

2. Perform mixed operations with money up to a value of RM10 million
EXAMPLE 1
RM8000 + RM1254 ─ RM5555 =
Step 1 : Check winner’s platform.
( )
×÷
÷×
1 +─
2
─+
3
Note : + and ─ are on the same scale. So
calculate as in the order given.
Step 2: Step 3:
RM8000 RM9254
+ RM1254 ─ RM5555
RM9254 RM3699

3. EXAMPLE 2
(RM125 × 8) ─ (RM40 × 8) =
Step 1 : Check winner’s platform.
( )
×÷
÷×
1 +─
2
3 +
─
Note : Do the operations that are in the brackets
first (x) then do the subtraction.
Step 2: Step 3: Step 4:
RM125 RM40 RM1000
× 8 × 8 ─ RM 320
RM1000 RM320 RM 680

4. Solve problems in real context involving computation of money
IMPORTANT KEY WORDS
Savings
Income
Expenditure
Investments
Cost Price
Selling Price
Profit
Loss
Discount
Computation
IMPORTANT FORMULAS
PROFIT = SELLING PRICE (SP) ─ COST PRICE(CP)
LOSS = COST PRICE ─ SELLING PRICE

5. Example 1:
The cost price of a television is RM1 357. Rahim sold
each television for RM1 475. He sold 15 televisions.
W is his profit?
W
What
Step 1 :
Read and understand question. As you read, underline the
key words.
The cost price of a television is RM1 357. Rahim sold
each television for RM1 475. He sold 15 televisions. What
is his p
profit?
Step 2 :
Write the operation / formula the keywords signify.
The cost price of a television is RM1 357. Rahim
×
sold each television for RM1 475. He sold 15
SP - CP
?
televisions. What is his profit?
Step 3 : Find the profit of a TV Step 4 :Profit of 15 TV
RM1 475 RM118 × 15 = RM1 770
- RM1357
RM 118

6. EXAMPLE 2
Kumari bought a gold chain and a gold bracelet. The
gold chain costs RM3 518 and the gold bracelet costs
RM755 less than the gold chain. How much did she pay
a
altogether?
Step 1 :
Read and understand question. As you read, underline the
key words.
Kumari bought a gold chain and a gold bracelet. The
gold chain costs RM3 518 and the gold bracelet costs
RM755 less than the gold chain. How much did she pay
a
altogether?
Step 2 :
Write the operation / formula the keywords signify.
Kumari bought a gold chain and a gold bracelet. The
gold chain costs RM3 518 and the gold bracelet costs
─
RM755 less than the gold chain. How much did she
Chain + Bracelet
Pay altogether? ?
Step 3 : Find the bracelet’s price Step 4 : Chain + Bracelet
RM3 518 RM3 518
─RM 755 + RM2 763
RM2 763 RM6 281

7. EXAMPLE 3
A packet of health food supplements costs RM690.
There is a discount of RM15.90 per packet. Yoong
bought 7 packets of the supplements. How much did he
p
pay?
Step 1 :
Read and understand question. As you read, underline the
key words.
A packet of health food supplements costs RM690. There
is a discount of RM15.90 per packet. Yoong bought 7
packets of the supplements. How much did he p pay?
Step 2 :
Write the operation / formula the keywords signify.
A packet of health food supplements costs RM690.
─ ×
There is a discount of RM15.90 per packet. Yoong bought
7 packets of the supplements. How much did he p
pay?
Step 3 : Step 4 :
Find the price after Discount price × 7
discount of a packet.
RM690.00 RM674.10
─RM 15.90 × 7
RM674.10 RM4 718.70