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BRACKETING or CLOSED METHODS BISECTION METHOD & FALSE POSITION METHOD!!!!!
BISECTION METHOD! The Bisection Method is a numerical method for estimating the roots of a polynomialf(x).   It is one of the simplest and most reliable but it is not the fastest method.   Assume that f(x) is continuous.
LET’S DO IT STEP BY STEP! Given a continuous function f(x) 1-  Find points a and b such that a < b and f(a) * f(b) < 0. 2- Take the interval [a, b] and find its midpoint x1. 3-   If f(x1) = 0 then x1 is an exact root, else if f(x1) * f(b) < 0 then let a = x1, else if f(a) * f(x1) < 0 then let b = x1.  4-   Repeat steps 2 & 3 until f(xi) = 0 or |f(xi)| <= DOA, where DOA stands for degree of accuracy.
LET’S DO IT STEP BY STEP!
LET’S DO IT STEP BY STEP! For the ith iteration, where i = 1, 2, . . . , n, the interval width is xi = 0.5 xi–1 = ( 0.5 )i ( b – a )  and the new midpoint is xi = ai–1 + xi
EXAMPLE! Consider f(x) = x3 + 3x – 5,  where [a = 1, b = 2] and DOA = 0.001.
THANKS!!!CHECK THE NEXT VIDEO AND PROVE YOUR KNOWLEDGE…………… SOURCE: http://www2.lv.psu.edu/ojj/courses/cmpsc-201/numerical/bisection.html

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Bracketing or closed methods

  • 1. BRACKETING or CLOSED METHODS BISECTION METHOD & FALSE POSITION METHOD!!!!!
  • 2. BISECTION METHOD! The Bisection Method is a numerical method for estimating the roots of a polynomialf(x).   It is one of the simplest and most reliable but it is not the fastest method.   Assume that f(x) is continuous.
  • 3. LET’S DO IT STEP BY STEP! Given a continuous function f(x) 1- Find points a and b such that a < b and f(a) * f(b) < 0. 2- Take the interval [a, b] and find its midpoint x1. 3- If f(x1) = 0 then x1 is an exact root, else if f(x1) * f(b) < 0 then let a = x1, else if f(a) * f(x1) < 0 then let b = x1. 4- Repeat steps 2 & 3 until f(xi) = 0 or |f(xi)| <= DOA, where DOA stands for degree of accuracy.
  • 4. LET’S DO IT STEP BY STEP!
  • 5. LET’S DO IT STEP BY STEP! For the ith iteration, where i = 1, 2, . . . , n, the interval width is xi = 0.5 xi–1 = ( 0.5 )i ( b – a ) and the new midpoint is xi = ai–1 + xi
  • 6. EXAMPLE! Consider f(x) = x3 + 3x – 5, where [a = 1, b = 2] and DOA = 0.001.
  • 7.
  • 8. THANKS!!!CHECK THE NEXT VIDEO AND PROVE YOUR KNOWLEDGE…………… SOURCE: http://www2.lv.psu.edu/ojj/courses/cmpsc-201/numerical/bisection.html