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Given:-
d= 30 cm
f1= 15cm
f2= 20cm
The final image[inverted] is obtained halfway between the two lenses, v''= 15 cm
using the lense equation
1/f2= 1/u''+ 1/v''
we get u''= -60 cm , this is the object distance of second lens
so we have the image distance of first lense as v'= -60+30= -30 cm
then applying the lense equation for first lens
we get 1/f1= 1/u'+1/v'
u'=10cm [to the left of the first lens is the original object]
Solution
Given:-
d= 30 cm
f1= 15cm
f2= 20cm
The final image[inverted] is obtained halfway between the two lenses, v''= 15 cm
using the lense equation
1/f2= 1/u''+ 1/v''
we get u''= -60 cm , this is the object distance of second lens
so we have the image distance of first lense as v'= -60+30= -30 cm
then applying the lense equation for first lens
we get 1/f1= 1/u'+1/v'
u'=10cm [to the left of the first lens is the original object]

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Given-d= 30 cmf1= 15cmf2= 20cmThe final image[inverted] is .pdf

  • 1. Given:- d= 30 cm f1= 15cm f2= 20cm The final image[inverted] is obtained halfway between the two lenses, v''= 15 cm using the lense equation 1/f2= 1/u''+ 1/v'' we get u''= -60 cm , this is the object distance of second lens so we have the image distance of first lense as v'= -60+30= -30 cm then applying the lense equation for first lens we get 1/f1= 1/u'+1/v' u'=10cm [to the left of the first lens is the original object] Solution Given:- d= 30 cm f1= 15cm f2= 20cm The final image[inverted] is obtained halfway between the two lenses, v''= 15 cm using the lense equation 1/f2= 1/u''+ 1/v'' we get u''= -60 cm , this is the object distance of second lens so we have the image distance of first lense as v'= -60+30= -30 cm then applying the lense equation for first lens we get 1/f1= 1/u'+1/v' u'=10cm [to the left of the first lens is the original object]