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CODE: import java.util.*; public class test { public static void main(String args[]) { int num, sum=0; Scanner input=new Scanner(System.in); System.out.print(\"Input num : \"); num=input.nextInt(); while(num != 13) { sum=sum+num; System.out.print(\"Input num : \"); num=input.nextInt(); } sum=sum+num; System.out.println(\"Sum = \"+sum); } } save the above file as test.java Output: javac test.java java test Input num : 1 Input num : 2 Input num : 3 Input num : 4 Input num : 5 Input num : 6 Input num : 7 Input num : 8 Input num : 9 Input num : 0 Input num : 13 Sum = 58 Solution CODE: import java.util.*; public class test { public static void main(String args[]) { int num, sum=0; Scanner input=new Scanner(System.in); System.out.print(\"Input num : \"); num=input.nextInt(); while(num != 13) { sum=sum+num; System.out.print(\"Input num : \"); num=input.nextInt(); } sum=sum+num; System.out.println(\"Sum = \"+sum); } } save the above file as test.java Output: javac test.java java test Input num : 1 Input num : 2 Input num : 3 Input num : 4 Input num : 5 Input num : 6 Input num : 7 Input num : 8 Input num : 9 Input num : 0 Input num : 13 Sum = 58.

CODE:
import java.util.*;
public class test {
public static void main(String args[]) {
int num, sum=0;
Scanner input=new Scanner(System.in);
System.out.print("Input num : ");
num=input.nextInt();
while(num != 13) {
sum=sum+num;
System.out.print("Input num : ");
num=input.nextInt();
}
sum=sum+num;
System.out.println("Sum = "+sum);
}
}
save the above file as test.java
Output:
javac test.java
java test
Input num :
1
Input num :
2
Input num :
3
Input num :
4
Input num :
5

Input num :
6
Input num :
7
Input num :
8
Input num :
9
Input num :
0
Input num :
13
Sum = 58
Solution
CODE:
import java.util.*;
public class test {
public static void main(String args[]) {
int num, sum=0;
Scanner input=new Scanner(System.in);
System.out.print("Input num : ");
num=input.nextInt();
while(num != 13) {
sum=sum+num;
System.out.print("Input num : ");
num=input.nextInt();
}

sum=sum+num;
System.out.println("Sum = "+sum);
}
}
save the above file as test.java
Output:
javac test.java
java test
Input num :
1
Input num :
2
Input num :
3
Input num :
4
Input num :
5
Input num :
6
Input num :
7
Input num :
8
Input num :
9
Input num :

0
Input num :
13
Sum = 58

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Code: import java.util.Random; import java.util.Scanner; public class Test{ public static void main(String args[]){ Scanner input = new Scanner(System.in); String bin = \"1\"; int n; System.out.print(\"Enter the number of binary digits : \"); n = input.nextInt(); for(int i = 0; i < n-1; i++){ bin += randomBin(); } System.out.println(bin); } public static String randomBin() { Random rg = new Random(); int n = rg.nextInt(2); return Integer.toBinaryString(n); } } Output: Enter the number of binary digits : 5 10110 Solution Code: import java.util.Random; import java.util.Scanner; public class Test{ public static void main(String args[]){ Scanner input = new Scanner(System.in); String bin = \"1\"; int n; System.out.print(\"Enter the number of binary digits : \"); n = input.nextInt(); for(int i = 0; i < n-1; i++){ bin += randomBin(); } System.out.println(bin); } public static String randomBin() { Random rg = new Random(); int n = rg.nextInt(2); return Integer.toBinaryString(n); } } Output: Enter the number of binary digits : 5 10110.

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Prompt a user to enter a series of integers separated by spaces and accept the input as a String. Display the list of integers and their sum. Save the file as SumIntegersInString.java. I have tried the following code, but it just runs continuously with no opportunity for input. import java.io.*; import java.util.Scanner; class SumIntegersInString { public static void main(String args[]) { Scanner in = new Scanner(System.in); String input = in.nextLine(); int sum = 0; for(String value : input.split(\" \")) { System.out.print(value + \" \"); sum += Integer.parseInt(value); } System.out.println(\"Sum:\" + sum); } } Solution import java.io.*; import java.util.Scanner; public class SumIntegersInString { public static void main(String args[]) { // statement to prompt the user for a series of integers System.out.print(\"Enter a series of integers separated by a space: \"); Scanner in = new Scanner(System.in); String input = in.nextLine(); int sum = 0; for(String value : input.split(\" \")) { System.out.print(value + \" \"); sum += Integer.parseInt(value); } System.out.println(\"\ Sum:\" + sum); } }.

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1. INTRODUCTION We are currently living in the so-called information age which can be described as an era were economic activities are mainly information based (an age of informationalization). This is due to the development and use of technology. The main characteristics of this era can be summarized as a rise in the number of knowledge workers, a world that has become more open - in the sense of communication (global village/Gutenberg galaxy) and internationalization (trans-border flow of data). This paradigm shift brings new ethical and juridical problems which are mainly related to issues such as the right of access to information, the right of privacy which is threatened by the emphasis on the free flow of information, and the protection of the economic interest of the owners of intellectual property. In this paper the ethical questions related to the right to privacy of the individual which is threatened by the use of technology will be discussed. Specific attention will be given to the challenges these ethical problems pose to the information professional. A number of practical guidelines, based on ethical norms will be laid down. 2. ETHICS The ethical actions of a person can be described in general terms as those actions which are performed within the criterium of what is regarded as good. It relates thus to the question of what is good or bad in terms of human actions. According to Spinello (1995, p. 14) the purpose of ethics is to help us behave honorably and attain those basic goods that make us more fully human. 3. THE CONCEPT OF PRIVACY 3.1. Definition of Privacy Privacy can be defined as an individual condition of life characterized by exclusion from publicity (Neetling et al., 1996, p. 36). The concept follows from the right to be left alone (Stair, 1992, p. 635; Shank, 1986, p. 12)1 . Shank (1986, p. 13) states that such a perception of privacy set the course for passing of privacy laws in the United States for the ninety years that followed. As such privacy could be regarded as a natural right which provides the foundation for the legal right. The right to privacy is therefore protected under private law. The legal right to privacy is constitutionally protected in most democratic societies. This constitutional right is expressed in a variety of legislative forms. Examples include the Privacy Act (1974) in the USA, the proposed Open Democracy Act in South Africa (1996) and the Data Protection Act in England. During 1994 Australia also accepted a Privacy Charter containing 18 privacy principles which describe the right of a citizen concerning personal privacy as effected by handling of information by the state (Collier, 1994, p. 44-45). The Organization for Economic and Coordination and Development (OECD) also accepted in 1980 the Guidelines for the Protection of Privacy and Transborder Flow of Personal Data (Collier, 1994, p. 41). Privacy is an important right because it is a necessary condition for other rights such as freedo.

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1) we can see the universe mostly in the form hydrogen and helium. So it is protonic. 2) a) Light from when the Universe became transparent very soon after the Big bang. 3) The cosmological principle limits the faintness of distant objects. 4) These group elementys are made by adding oxygen nuclei which is the third most commen element in the universe. Solution 1) we can see the universe mostly in the form hydrogen and helium. So it is protonic. 2) a) Light from when the Universe became transparent very soon after the Big bang. 3) The cosmological principle limits the faintness of distant objects. 4) These group elementys are made by adding oxygen nuclei which is the third most commen element in the universe..

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1) Pen R contains penicillin resistance gene .Usually + or - is not denoted for antibiotics. therefore the answer is option e. 2) a) conjugation is the exchange of genetic material by cell-cell contact via sex-pili. 3)a) High-Frequency recombination bacteria have F plasmid integrated into its chromosome and transfers part of the chromosome along with F+ gene ,thereby resulting in F\' cells. 4) e) an F\' lac- E.coli when mates with F- Lac cell, the result will be F+, Lac-(from F\'), Lac+(already present in recipient cell) 5) a) true, transformation is the transfer of an exogenous genetic material(DNA). Solution 1) Pen R contains penicillin resistance gene .Usually + or - is not denoted for antibiotics. therefore the answer is option e. 2) a) conjugation is the exchange of genetic material by cell-cell contact via sex-pili. 3)a) High-Frequency recombination bacteria have F plasmid integrated into its chromosome and transfers part of the chromosome along with F+ gene ,thereby resulting in F\' cells. 4) e) an F\' lac- E.coli when mates with F- Lac cell, the result will be F+, Lac-(from F\'), Lac+(already present in recipient cell) 5) a) true, transformation is the transfer of an exogenous genetic material(DNA)..

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UV radiation has shorter wavelength than visible .pdf

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(1) C A genetic model organism needs to have all the above features to facilitate the genetic research on it, like small genome, short generation time, large number of progeny, should adapt to lab environment, propagation and maintaining them should be inexpensive. (2) B On chromosomes, we can find genes and these are nothing but long pieces of DNA associated with histone. For every gene we will have two alleles and will be located on different chromosomes but at the same place or loci and these are an alternate form of a gene. (3) D Blending inheritance theory is considered as the current theory of genetic inheritance as it states that the egg and sperm from two parents will combine to form zygote and here the genetic material from both parents will blend and will have an influence on genetic makeup of the developing of offspring. (4) C C. elegans is traditionally considered as a classical genetic organism and it has been used to study the gene function and variety mutagens were used on it to study the effect of different mutations and their effect on protein function. (5) A. The number of chromosomes will be the same in the G1 phase, but in S phase only the number of chromatids will double in its number. Solution (1) C A genetic model organism needs to have all the above features to facilitate the genetic research on it, like small genome, short generation time, large number of progeny, should adapt to lab environment, propagation and maintaining them should be inexpensive. (2) B On chromosomes, we can find genes and these are nothing but long pieces of DNA associated with histone. For every gene we will have two alleles and will be located on different chromosomes but at the same place or loci and these are an alternate form of a gene. (3) D Blending inheritance theory is considered as the current theory of genetic inheritance as it states that the egg and sperm from two parents will combine to form zygote and here the genetic material from both parents will blend and will have an influence on genetic makeup of the developing of offspring. (4) C C. elegans is traditionally considered as a classical genetic organism and it has been used to study the gene function and variety mutagens were used on it to study the effect of different mutations and their effect on protein function. (5) A. The number of chromosomes will be the same in the G1 phase, but in S phase only the number of chromatids will double in its number..

(1) CA genetic model organism needs to have all the above features.pdf

(1) CA genetic model organism needs to have all the above features.pdf

(1) CA genetic model organism needs to have all the above features.pdf

The relation in partSolution The relation in part.pdf

The relation in partSolution The relation in part.pdf

The relation in partSolution The relation in part.pdf

Step1 Concentration of hydroxide ion = 2x.00500=..pdf

Step1 Concentration of hydroxide ion = 2x.00500=..pdf

Step1 Concentration of hydroxide ion = 2x.00500=..pdf

molality = (11258.5)1 = 1.914 m Percent mass =.pdf

molality = (11258.5)1 = 1.914 m Percent mass =.pdf

molality = (11258.5)1 = 1.914 m Percent mass =.pdf

NADPH is a reducing agent that act as an electron.pdf

NADPH is a reducing agent that act as an electron.pdf

NADPH is a reducing agent that act as an electron.pdf

moleculesions geometry hybridization ClF3 T-shap.pdf

moleculesions geometry hybridization ClF3 T-shap.pdf

moleculesions geometry hybridization ClF3 T-shap.pdf

The major shortcoming was that the electrons were thought to have fixed orbits like planets around the sun. Now they are thought to occupy orbitals and have probabilities for being within given distances from the nucleus. The orbitals (solutions to the Schroedinger Equation) have shapes like hourglasses, spheres, hollowed out spheres, and more complicated shapes. As a very distant side note Prof Carlos Stroud at the University of Rochester was able to excite atoms and put their electrons into orbits much like those predicted by the Rutherford Model. Solution The major shortcoming was that the electrons were thought to have fixed orbits like planets around the sun. Now they are thought to occupy orbitals and have probabilities for being within given distances from the nucleus. The orbitals (solutions to the Schroedinger Equation) have shapes like hourglasses, spheres, hollowed out spheres, and more complicated shapes. As a very distant side note Prof Carlos Stroud at the University of Rochester was able to excite atoms and put their electrons into orbits much like those predicted by the Rutherford Model..

The major shortcoming was that the electrons were.pdf

The major shortcoming was that the electrons were.pdf

The major shortcoming was that the electrons were.pdf

The ball is an atom, the stick is a bond. You pu.pdf

The ball is an atom, the stick is a bond. You pu.pdf

The ball is an atom, the stick is a bond. You pu.pdf

The anion is a good leaving group because it is probably the most negative of the anion. I assume the Xs represent an electronegative atom such as oxygen; therefore, it would have the greatest repulision force (because it has so many electrons). Thus, it but be beneficial if the most negative anion (the one with the most electrons) left because it would allow the molecule to be under less stress and allow the remaining anions to spread out more (spread out more spatially around the central C atom) (On the really long molecule with the bunch of Me atoms) The most acidic hydrogen would be the one hanging off the second N from the left (it has a think line pointing from the H to the N). It is the most acidic because the N is very electronegative (more so than the carbons found in other molecules). The O atom is more electronegative but it cannot lose the H because the OH is a polyatomic ion...u cannot split them up! Thus the H hanging of the N is the most acidic! Solution The anion is a good leaving group because it is probably the most negative of the anion. I assume the Xs represent an electronegative atom such as oxygen; therefore, it would have the greatest repulision force (because it has so many electrons). Thus, it but be beneficial if the most negative anion (the one with the most electrons) left because it would allow the molecule to be under less stress and allow the remaining anions to spread out more (spread out more spatially around the central C atom) (On the really long molecule with the bunch of Me atoms) The most acidic hydrogen would be the one hanging off the second N from the left (it has a think line pointing from the H to the N). It is the most acidic because the N is very electronegative (more so than the carbons found in other molecules). The O atom is more electronegative but it cannot lose the H because the OH is a polyatomic ion...u cannot split them up! Thus the H hanging of the N is the most acidic!.

The anion is a good leaving group because it is p.pdf

The anion is a good leaving group because it is p.pdf

The anion is a good leaving group because it is p.pdf

Más de anurag1231 (20)

a. The alleles are as followsaa - AlbinismAa AA - Normal pigm.pdf

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9933Solution9933.pdf

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1. INTRODUCTIONWe are currently living in the so-called informatio.pdf

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1. d.) Organisms using oxygenic photosynthesis release oxygen into t.pdf

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1. d.) Organisms using oxygenic photosynthesis release oxygen into t.pdf

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1)we can see the universe mostly in the form hydrogen and helium. .pdf

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1)we can see the universe mostly in the form hydrogen and helium. .pdf

1)D. Bacteria.2)B. Nuclear envelope3)A. Similar in function and .pdf

1)D. Bacteria.2)B. Nuclear envelope3)A. Similar in function and .pdf

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1) Pen R contains penicillin resistance gene .Usually + or - is not .pdf

1) Pen R contains penicillin resistance gene .Usually + or - is not .pdf

1) Pen R contains penicillin resistance gene .Usually + or - is not .pdf

0.8726Solution0.8726.pdf

0.8726Solution0.8726.pdf

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UV radiation has shorter wavelength than visible .pdf

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(1) CA genetic model organism needs to have all the above features.pdf

(1) CA genetic model organism needs to have all the above features.pdf

(1) CA genetic model organism needs to have all the above features.pdf

The relation in partSolution The relation in part.pdf

The relation in partSolution The relation in part.pdf

The relation in partSolution The relation in part.pdf

Step1 Concentration of hydroxide ion = 2x.00500=..pdf

Step1 Concentration of hydroxide ion = 2x.00500=..pdf

Step1 Concentration of hydroxide ion = 2x.00500=..pdf

molality = (11258.5)1 = 1.914 m Percent mass =.pdf

molality = (11258.5)1 = 1.914 m Percent mass =.pdf

molality = (11258.5)1 = 1.914 m Percent mass =.pdf

NADPH is a reducing agent that act as an electron.pdf

NADPH is a reducing agent that act as an electron.pdf

NADPH is a reducing agent that act as an electron.pdf

moleculesions geometry hybridization ClF3 T-shap.pdf

moleculesions geometry hybridization ClF3 T-shap.pdf

moleculesions geometry hybridization ClF3 T-shap.pdf

The major shortcoming was that the electrons were.pdf

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The major shortcoming was that the electrons were.pdf

The ball is an atom, the stick is a bond. You pu.pdf

The ball is an atom, the stick is a bond. You pu.pdf

The ball is an atom, the stick is a bond. You pu.pdf

The anion is a good leaving group because it is p.pdf

The anion is a good leaving group because it is p.pdf

The anion is a good leaving group because it is p.pdf

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CODEimport java.util.; public class test { public static voi.pdf

1. CODE: import java.util.*; public class test { public static void main(String args[]) { int num, sum=0; Scanner input=new Scanner(System.in); System.out.print("Input num : "); num=input.nextInt(); while(num != 13) { sum=sum+num; System.out.print("Input num : "); num=input.nextInt(); } sum=sum+num; System.out.println("Sum = "+sum); } } save the above file as test.java Output: javac test.java java test Input num : 1 Input num : 2 Input num : 3 Input num : 4 Input num : 5

2. Input num : 6 Input num : 7 Input num : 8 Input num : 9 Input num : 0 Input num : 13 Sum = 58 Solution CODE: import java.util.*; public class test { public static void main(String args[]) { int num, sum=0; Scanner input=new Scanner(System.in); System.out.print("Input num : "); num=input.nextInt(); while(num != 13) { sum=sum+num; System.out.print("Input num : "); num=input.nextInt(); }

3. sum=sum+num; System.out.println("Sum = "+sum); } } save the above file as test.java Output: javac test.java java test Input num : 1 Input num : 2 Input num : 3 Input num : 4 Input num : 5 Input num : 6 Input num : 7 Input num : 8 Input num : 9 Input num :

4. 0 Input num : 13 Sum = 58