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QUARTER 4: WEEK 2
SCIENCE 10
Prepared by:
Aple M. Rigor
Teacher III
Prepare yourselves Dear Student
Bring out your Week 2
Module 1 in Science 10
Let’s do
some Recap
What AM I
?
VOLUME
I am one of the measurable
properties of gas. I am denoted
by the symbol V. I am the
amount of space occupied by a
gas sample. My SI unit is in
liters (L)
What Am I?
Pressure
I am the next important measurable
property of the gas, which is denoted
by the symbol P. I am described as
the force exerted by the gas per unit
area. My unit can be ATM, Torr, Psi,
Pa and mmHg
What am I?
Temperature
I am denoted by the letter T. My value
depends on kinetic energy of gas.
Gases expand when I increased.
I can be expressed in Fahrenheit (◦ F),
Centigrade or Celsius (◦C), and Kelvin (K).
What am I?
The amount of gas
I am another measurable property of
gas. I am related to the number of
moles of gas and is generally
expressed in kilogram (kg) or gram (g).
What am I?
MELC:
•Investigate the relationship between:
•1 volume and pressure at constant temperature of a gas
•2 volume and temperature at constant pressure of a gas
•3 explains these relationships using the kinetic
molecular theory
Lesson 2: Gas
Law
Whats In: Activity 6
Directions: Identify the given pictures below by
choosing the appropriate answers found inside the
word pool.
Activity 6: Match Me
Gas and
volume
Gas and
temperature
Gas and
Pressure
Activity 6: Match Me
Gas and
volume
Gas and
temperature
Gas and
Pressure
Activity 6: Match Me
Gas and
volume
Gas and
temperature
Gas and
Pressure
Activity 6: Match Me
Gas and
volume
Gas and
temperature
Gas and
Pressure
Gas Law
Boyle’s Law
• Robert Boyle, an English chemist was the first to investigate the
relationship between the pressure of a gas and its volume at a
constant temperature.
• Based on his experiment made wherein he trapped a fixed
amount of air in a J-tube and changed the pressure at a
constant temperature,
• He found out that as THE PRESSURE INCREASES, THE
VOLUME DECREASES.
• He then concluded that the volume occupied by the fixed
amount of gas is inversely proportional to its pressure at a
constant temperature
Formula in calculating the relationship
between pressure and volume
In Boyle’s law, the following formulas are to
be used when three variables are given, and
one is unknown:
• P1 = P2V2/V1
• P2 = P1V1/V2
• V1 = P2V2/P1
• V2 = P1V1/P2
A sample of nitrogen gas (N2) has a volume of
12.0 L and a pressure of 760.0 mm Hg. When
the gas is released, it gives 32.0 L of nitrogen.
If the temperature is the same, what is the
new pressure of nitrogen?
First step is to identify the variables
• V1
• V2
• P1
• P2
A sample of
nitrogen gas (N2)
has a volume of
12.0 L and a
pressure of 760.0
mm Hg. When the
gas is released, it
gives 32.0 L of
nitrogen. If the
temperature is the
same, what is the
new pressure of
nitrogen?
• V1= 12.0L
• P1= 760.0mmHg
• V2=32.0L
• P2=?
P1 = P2V2/V1
P2 = P1V1/V2
V1 = P2V2/P1
V2 = P1V1/P2
A sample of
nitrogen gas (N2)
has a volume of
12.0 L and a
pressure of 760.0
mm Hg. When the
gas is released, it
gives 32.0 L of
nitrogen. If the
temperature is the
same, what is the
new pressure of
nitrogen?
• V1= 12.0L
• P1= 760.0mmHg
• V2=32.0L
• P2=?
P2 = P1V1/V2
• V1= 12.0L
• P1= 760.0mmHg
• V2=32.0L
• P2=?
P2 = P1V1/V2
P2=760 mmHg(12 L)/32 L
P2= 9120 mmHg L/32L
P2= 285 mmHg
• V1= 12.0L
• P1= 760.0mmHg
• V2=32.0L
• P2= 285 mmHg
P2 = P1V1/V2
P2=760 mmHg(12 L)/32 L
P2= 9120 mmHg L/32L
P2= 285 mmHg
THE PRESSURE INCREASES, THE
VOLUME DECREASES vise versa
Charles Law
• French physicist Jacques Charles determined the
volume-temperature relationship in gases.
• From his experiment on balloons, Charles observed that,
at constant pressure, the volume of gas increases
with every increase in temperature. Also, volume
decreases as temperature decreases.
• Charles’ law states that the volume of a fixed amount of
gas maintained at constant pressure is directly
proportional to its absolute temperature
In Charles’ law, the following formulas
are to be used when three variables are
given, and one is unknown:
•V1 = V2T1/T2
•V2 = V1T2/T1
•T1 = V1T2/V2
•T2 = V2T1/V1
• A mountain climber inhales 484.0 mL of air at a
temperature of -10.0oC. What volume (in mL) will the air
occupy in the mountain climber’s lungs if his body
temperature is 37.0 C assuming that the pressure
remains the same?
• Given:
• V1 = 484.0 mL T1 = -10.0 C
• T2 = 37.0 C Find: V2
• A mountain climber inhales 484.0 mL of air at a
temperature of -10.0oC. What volume (in mL) will the air
occupy in the mountain climber’s lungs if his body
temperature is 37.0 C assuming that the pressure
remains the same?
• Solution: Change the temperature to Kelvin when
they are given in Celsius.
• T1 = -10.0 C + 273 = 263 K
• T2 = 37.0 C + 273 = 310 K
V1 = 484.0 mL T1 = -10.0 C (263k)
T2 = 37.0 C (310k) Find: V2
Summary
Boyle’s Law Charles Law
Proponent Robert Boyle Jacques Charles
Constant value Temperature and
amount of gas
Pressure and amount
of gas
Principle As the Pressure
increases the Volume
decreases vise versa
As the Temperature
Increases the Volume
also increases
Formula P1 = P2V2/V1
P2 = P1V1/V2
V1 = P2V2/P1
V2 = P1V1/P2
V1 = V2T1/T2
V2 = V1T2/T1
T1 = V1T2/V2
T2 = V2T1/V1
APPLICATION
•As an application, as you can see if
there is huge fire you will see that
as the temperature brought by the
fire increases the volume of smoke
also increases
DO YOU
UNDERSTAN
D OUR
LESSON?
ASSESSMENT
•Write/type Charles if the
statement is for Charles law and
Boyles if its for Boyles
Charles law
As the Volume of Gas increase
the temperature of Gas increases
vise versa
Boyle’s law
•The Law states that as the
Pressure increases the Volume
decreases vise versa
Boyle’s law
•Temperature and amount of gas
are constant
Charles law
•Pressure and amount of gas are
constant
How was your score?
For your other activities
Please read and analyze you lesson 2 modules and answer the ff.
Activity 8 Crossword puzzle
Activity 9 Problem solving (set a only)
What I have learned page 22-23
Thank you for listening
SCIENCE
4th Quarter:
Week 2

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qtr week 2.pptx

  • 1. QUARTER 4: WEEK 2 SCIENCE 10 Prepared by: Aple M. Rigor Teacher III
  • 3. Bring out your Week 2 Module 1 in Science 10
  • 6. VOLUME I am one of the measurable properties of gas. I am denoted by the symbol V. I am the amount of space occupied by a gas sample. My SI unit is in liters (L) What Am I?
  • 7. Pressure I am the next important measurable property of the gas, which is denoted by the symbol P. I am described as the force exerted by the gas per unit area. My unit can be ATM, Torr, Psi, Pa and mmHg What am I?
  • 8. Temperature I am denoted by the letter T. My value depends on kinetic energy of gas. Gases expand when I increased. I can be expressed in Fahrenheit (◦ F), Centigrade or Celsius (◦C), and Kelvin (K). What am I?
  • 9. The amount of gas I am another measurable property of gas. I am related to the number of moles of gas and is generally expressed in kilogram (kg) or gram (g). What am I?
  • 10. MELC: •Investigate the relationship between: •1 volume and pressure at constant temperature of a gas •2 volume and temperature at constant pressure of a gas •3 explains these relationships using the kinetic molecular theory
  • 12. Whats In: Activity 6 Directions: Identify the given pictures below by choosing the appropriate answers found inside the word pool.
  • 13. Activity 6: Match Me Gas and volume Gas and temperature Gas and Pressure
  • 14. Activity 6: Match Me Gas and volume Gas and temperature Gas and Pressure
  • 15. Activity 6: Match Me Gas and volume Gas and temperature Gas and Pressure
  • 16. Activity 6: Match Me Gas and volume Gas and temperature Gas and Pressure
  • 18. Boyle’s Law • Robert Boyle, an English chemist was the first to investigate the relationship between the pressure of a gas and its volume at a constant temperature. • Based on his experiment made wherein he trapped a fixed amount of air in a J-tube and changed the pressure at a constant temperature, • He found out that as THE PRESSURE INCREASES, THE VOLUME DECREASES. • He then concluded that the volume occupied by the fixed amount of gas is inversely proportional to its pressure at a constant temperature
  • 19. Formula in calculating the relationship between pressure and volume In Boyle’s law, the following formulas are to be used when three variables are given, and one is unknown: • P1 = P2V2/V1 • P2 = P1V1/V2 • V1 = P2V2/P1 • V2 = P1V1/P2
  • 20. A sample of nitrogen gas (N2) has a volume of 12.0 L and a pressure of 760.0 mm Hg. When the gas is released, it gives 32.0 L of nitrogen. If the temperature is the same, what is the new pressure of nitrogen? First step is to identify the variables • V1 • V2 • P1 • P2
  • 21. A sample of nitrogen gas (N2) has a volume of 12.0 L and a pressure of 760.0 mm Hg. When the gas is released, it gives 32.0 L of nitrogen. If the temperature is the same, what is the new pressure of nitrogen? • V1= 12.0L • P1= 760.0mmHg • V2=32.0L • P2=? P1 = P2V2/V1 P2 = P1V1/V2 V1 = P2V2/P1 V2 = P1V1/P2
  • 22. A sample of nitrogen gas (N2) has a volume of 12.0 L and a pressure of 760.0 mm Hg. When the gas is released, it gives 32.0 L of nitrogen. If the temperature is the same, what is the new pressure of nitrogen? • V1= 12.0L • P1= 760.0mmHg • V2=32.0L • P2=? P2 = P1V1/V2
  • 23. • V1= 12.0L • P1= 760.0mmHg • V2=32.0L • P2=? P2 = P1V1/V2 P2=760 mmHg(12 L)/32 L P2= 9120 mmHg L/32L P2= 285 mmHg
  • 24. • V1= 12.0L • P1= 760.0mmHg • V2=32.0L • P2= 285 mmHg P2 = P1V1/V2 P2=760 mmHg(12 L)/32 L P2= 9120 mmHg L/32L P2= 285 mmHg THE PRESSURE INCREASES, THE VOLUME DECREASES vise versa
  • 25. Charles Law • French physicist Jacques Charles determined the volume-temperature relationship in gases. • From his experiment on balloons, Charles observed that, at constant pressure, the volume of gas increases with every increase in temperature. Also, volume decreases as temperature decreases. • Charles’ law states that the volume of a fixed amount of gas maintained at constant pressure is directly proportional to its absolute temperature
  • 26. In Charles’ law, the following formulas are to be used when three variables are given, and one is unknown: •V1 = V2T1/T2 •V2 = V1T2/T1 •T1 = V1T2/V2 •T2 = V2T1/V1
  • 27. • A mountain climber inhales 484.0 mL of air at a temperature of -10.0oC. What volume (in mL) will the air occupy in the mountain climber’s lungs if his body temperature is 37.0 C assuming that the pressure remains the same? • Given: • V1 = 484.0 mL T1 = -10.0 C • T2 = 37.0 C Find: V2
  • 28. • A mountain climber inhales 484.0 mL of air at a temperature of -10.0oC. What volume (in mL) will the air occupy in the mountain climber’s lungs if his body temperature is 37.0 C assuming that the pressure remains the same? • Solution: Change the temperature to Kelvin when they are given in Celsius. • T1 = -10.0 C + 273 = 263 K • T2 = 37.0 C + 273 = 310 K
  • 29. V1 = 484.0 mL T1 = -10.0 C (263k) T2 = 37.0 C (310k) Find: V2
  • 30. Summary Boyle’s Law Charles Law Proponent Robert Boyle Jacques Charles Constant value Temperature and amount of gas Pressure and amount of gas Principle As the Pressure increases the Volume decreases vise versa As the Temperature Increases the Volume also increases Formula P1 = P2V2/V1 P2 = P1V1/V2 V1 = P2V2/P1 V2 = P1V1/P2 V1 = V2T1/T2 V2 = V1T2/T1 T1 = V1T2/V2 T2 = V2T1/V1
  • 31. APPLICATION •As an application, as you can see if there is huge fire you will see that as the temperature brought by the fire increases the volume of smoke also increases
  • 33. ASSESSMENT •Write/type Charles if the statement is for Charles law and Boyles if its for Boyles
  • 34. Charles law As the Volume of Gas increase the temperature of Gas increases vise versa
  • 35. Boyle’s law •The Law states that as the Pressure increases the Volume decreases vise versa
  • 36. Boyle’s law •Temperature and amount of gas are constant
  • 37. Charles law •Pressure and amount of gas are constant
  • 38. How was your score?
  • 39. For your other activities Please read and analyze you lesson 2 modules and answer the ff. Activity 8 Crossword puzzle Activity 9 Problem solving (set a only) What I have learned page 22-23
  • 40. Thank you for listening SCIENCE 4th Quarter: Week 2

Notas del editor

  1. RADIO TEACHER: Good Afternoon, Grade 10 learners. You are still listening to 87.6 TATAK CHS CAMPUS RADIO, School-on-Air. I am Teacher APLE M. RIGOR from Junior HS department Calibungan High School to give you interesting topics in Science 10
  2. BIZ: MSC UP FOR 3 SECS THEN FADE UNDER RADIO TEACHER: Let us begin by preparing yourselves for 35 mins broadcast of learning in Science 10. First, check your headsets or speakers if they are functioning well so you could hear clearly this broadcast. Second, find a comfortable place to study…away from distractions. Third, prepare your learning materials in Science 10. Did you follow my instructions? (PAUSE) Good! Now, we are all set BIZ: MSC UP FOR 5 SECS THEN FADE UNDER
  3. BIZ: MSC UP FOR 5 SECS THEN FADE UNDER RADIO TEACHER: At this point I want you to bring out your Quarter 4 Week 2 Module 1 in Science 10. (PAUSE) BIZ: MSC UP FOR 3 SECS THEN FADE UNDER Are you holding now your Modules? Alright! Lets get started.
  4. I know that you are all excited to learn our new lesson But before that let us do some recall What are things that we’ve discuss last session Type your answer on our comment section BIZ: MSC UP FOR 3 SECS THEN FADE UNDER
  5. Now Let us see how well you remembered our last lesson Ready? Lets play What am I? I am going to read a clue and you will identify what is being asked. For those student viewing online you may type your answer on our comment section And for those who are listening in the radio please write your answer on a sheet of paper Are you ready?
  6. Let us begin Number 1 I am one of the measurable properties of gas. I am denoted by the symbol V. I am the amount of space occupied by a gas sample. My SI unit is in liters (L) What Am I? I AM THE VOLUME Did you get the correct answer? Well done grade 10
  7. Number 2 I am the next important measurable property of the gas, which is denoted by the symbol P. I am described as the force exerted by the gas per unit area. My unit can be ATM, Torr, Psi, Pa and mmHg What am I? I am the pressure Did you get it right? Very Good!
  8. Next no. 3 I am denoted by the letter T. My value depends on kinetic energy of gas. Gases expand when I increased. I can be expressed in Fahrenheit (◦ F), Centigrade or Celsius (◦C), and Kelvin (K). What am I? I am the Temperature Who got the correct answer? good job grade 10
  9. I am another measurable property of gas. I am related to the number of moles of gas and is generally expressed in kilogram (kg) or gram (g). What am I? I am the amount of gas Did you get the correct answer Grade 10 I can see the most of you got the correct answer Good job These are the units that we will use in the next 30 mins of our lesson
  10. Our Objective for this afternoon is to: Investigate the relationship between: 1 volume and pressure at constant temperature of a gas 2 volume and temperature at constant pressure of a gas 3 explains these relationships using the kinetic molecular theory Are you Ready?
  11. For this session we will be dealing with Gas Law Please make sure you have extra sheet of paper and calculator For our computations are you ready? Lets do our first activity
  12. Lets do activity 6 what’s in You can open your module lesson 2 so you will have your guide You will Identify the given pictures below by choosing the appropriate answers found inside the word pool Ready? Lets begin
  13. Number 1 Picture is it Gas and Volume Gas and Temperature Gas and Pressure Or Gas and amount of gas The correct answer is a. Gas and pressure
  14. Number 2 Picture is it Gas and Volume Gas and Temperature Gas and Pressure Or Gas and amount of gas The correct answer is b. Gas and volume
  15. Number 3 Picture is it Gas and Volume Gas and Temperature Gas and Pressure Or Gas and amount of gas The correct answer is c. Gas and temperature
  16. Number 4 Picture is it Gas and Volume Gas and Temperature Gas and Pressure Or Gas and amount of gas The correct answer is d. Gas and amount of gas Did you get the correct answers? Send heart if you do Good job grade 10
  17. As we recall in our last lesson, gases can be describe through its different properties and this properties were conceptualized and proposed as the Kinetic molecular theory. For this afternoon we will, discuss some Gas Laws that was proposed by different scientist And somehow relate it to the kinetic molecular theory of gas Are you ready Grade 10 the first theory is
  18. Boyles law by Robert Boyle Robert Boyle, an English chemist was the first to investigate the relationship between the pressure of a gas and its volume at a constant temperature. Based on his experiment made wherein he trapped a fixed amount of air in a J-tube and changed the pressure at a constant temperature, he found out that as the pressure increases, the volume decreases. He then concluded that the volume occupied by the fixed amount of gas is inversely proportional to its pressure at a constant temperature
  19. In the Law proposed by Robert Boyle amount of gas and temperature are constant Therefore the formula will only have two quantity the pressure and volume Kindly take down notes for the formula for Boyle’s Law P1 = P2V2/V1 P2 = P1V1/V2 V1 = P2V2/P1 V2 = P1V1/P2 Were P1 is the initial pressure and P2 is the final pressure While V1 is the initial volume and V2 is the final volume Now let us do some exercises
  20. A sample of nitrogen gas (N2) has a volume of 12.0 L and a pressure of 760.0 mm Hg. When the gas is released, it gives 32.0 L of nitrogen. If the temperature is the same, what is the new pressure of nitrogen? Our First Step is to identify the Variables
  21. A sample of nitrogen gas (N2) has a volume of 12.0 L and a pressure of 760.0 mm Hg. When the gas is released, it gives 32.0 L of nitrogen. If the temperature is the same, what is the new pressure of nitrogen? What will be our first volume? Our volume 1 is ? How about our pressure 1? How about our volume 2? How about our pressure 2? Now knowing the missing variable what will be our formula?
  22. Our formula to be used will be P2=P1V1/V2
  23. Now using our formula let us solve for the missing variable Let us do substitution Using the formula p2=p1v1/v2 p2= 760mmhg multiply by 12 L Divided by 32 L 76 mmHg multiply by 12 will be 9120 mmHg L Next step divide 9120mmHg L to 32 L Cancel the same unit which is L The answer will be 285 mmHg
  24. As you can see the volume of gas increases from 12 L to 32 L According to the rule as the pressure increases the volume decreases or vise versa now as we analyze the volume of gas increases that is why the value of our p2 decreases Do you follow grade 10? Please send a heart if you were able to understand the first Gas Law
  25. Our Next Law is the Charles law French physicist Jacques Charles determined the volume-temperature relationship in gases. From his experiment on balloons, Charles observed that, at constant pressure, the volume of gas increases with every increase in temperature. Also, volume decreases as temperature decreases. Charles’ law states that the volume of a fixed amount of gas maintained at constant pressure is directly proportional to its absolute temperature
  26. In Charles’ law, the following formulas are to be used when three variables are given, and one is unknown: V1 = V2T1/T2 V2 = V1T2/T1 T1 = V1T2/V2 T2 = V2T1/V1 Were V1 is the initial volume and T1 is temperature 1 While V2 is the final volume and T2 is final temperature Now let us answer sample problem
  27. A mountain climber inhales 484.0 mL of air at a temperature of -10.0oC. What volume (in mL) will the air occupy in the mountain climber’s lungs if his body temperature is 37.0 C assuming that the pressure remains the same? Now let us analyze the given Our first volume is 484.0 mL How about Volume 2? Next what is our Temperature 1? Our temperature 1 is -10 c How about our temp 2? It is? 37 C
  28. A mountain climber inhales 484.0 mL of air at a temperature of -10.0oC. What volume (in mL) will the air occupy in the mountain climber’s lungs if his body temperature is 37.0 C assuming that the pressure remains the same? Now in Gases scientist use kelvin as the unit for temperature therefore we need to convert 10 C and 37 C to Kelvin How will we convert it? By simply adding 273 to the temperature express in Celsius Meaning to say 10 plus 273 our t 1 will be 263 K Then 37 plus 273 our t2 will be 310k
  29. Using the formula V2=V1T2/ T1 Then let us substitute for the values of known variable V2= 484 ml multiply by 310 K is one hundred fifty thousand forty divided by temperature 1 which is 263k The answer will be 570.49 ml Now using the value that we calculate what can you say about the value of our quantity We can say that As the temperature increases the value of our volume also increases
  30. To sum it up In boyles law temperature is constant while in Charles pressure is constant In boyles law As the Pressure increases the Volume decreases vise versa, while in Charles law As the Temperature Increases the Volume also increases
  31. As an application, as you can see if there is huge fire you will see that as the temperature brought by the fire increases the volume of smoke also increases
  32. DO YOU UNDERSTAND OUR LESSON about Gas Law? If yes pls send a heart Everyone is sending a heart therefore I conclude that you all understood our lesson Now LET US SEE HOW WELL YOU UNDERSTOOD OUR LESSON
  33. Let us see how well you understood the lesson I am going to flash a principle and you will identify if it is Charles law or Boyles law Write/type Charles if the statement is for Charles law and Boyles if its for Boyles Ready?
  34. As the Volume of Gas increase the temperature of Gas increases vise versa The answer is Charles Law
  35. Next The Law states that as the Pressure increases the Volume decreases vise versa The answer is Boyle’s law
  36. Next Temperature and amount of gas are constant The answer is boyles
  37. Next Pressure and amount of gas are constant The answer is Charles law
  38. How was your score? Did you get it right? Good job Grade 10!
  39. For your other activities Please read and analyze you lesson 2 modules and answer the ff. Activity 8 Crossword puzzle Activity 9 Problem solving (set a only) What I have learned page 22-23
  40. I do hope that you will master our lesson for today.(PAUSE)   Once again This has been your teacher broadcaster on air, Maam Aple M. Rigor   leaving you with the saying never stop learning because life never stop teaching   a blessed afternoon   This is 87.6 tatak chs campus radio Makinig, manood at matuto Aral na Chsians!