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What is the average speed of a Formula 1
racing car, if half of the laps are covered at
100 km/h and the other half at 300 km/h?
What is the law of uniform motion?

          v s/t
     We obtain the inversion:

s vt          and        t      s/v
You might think the answer is the average of 100 and 300

               (100+300)/2 = 200 km/h
                     wrong!!!!
If the distance s (half of rpm) is gone at a velocity of 100 km/h it
                      takes the time t1 = s/100;

If the same distance s is gone at a velocity of 300 km/h instead, the
                 necessary time will be t2 = s/300.

    If we divide the total distance of 2s to the total time taken
           t =t1 +t2 = s/100 + s/300 (= 4s/300 = 2s/150)

       we find:  vm = 2s/(2s/150) = 150 km/h
   then we can write: vm = s / (2s/150)/2 = s/ tm
So we divide the common distance to the average time

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Average speed formula1[1]

  • 1. What is the average speed of a Formula 1 racing car, if half of the laps are covered at 100 km/h and the other half at 300 km/h?
  • 2. What is the law of uniform motion? v s/t We obtain the inversion: s vt and t s/v
  • 3. You might think the answer is the average of 100 and 300 (100+300)/2 = 200 km/h wrong!!!!
  • 4. If the distance s (half of rpm) is gone at a velocity of 100 km/h it takes the time t1 = s/100; If the same distance s is gone at a velocity of 300 km/h instead, the necessary time will be t2 = s/300. If we divide the total distance of 2s to the total time taken t =t1 +t2 = s/100 + s/300 (= 4s/300 = 2s/150) we find: vm = 2s/(2s/150) = 150 km/h then we can write: vm = s / (2s/150)/2 = s/ tm So we divide the common distance to the average time