The following are hypothetical configurations for a nitrogen atom.
1. 1s 2 2s 2 2p 3
2. 1s 2 2s 1 2p 4
3. 1s 3 2s 2 2p 2
4. 1s 2 1p 5
5. 1s 2 2p 5
6. 1s 2 2s 3 2p 2
Which use nonexistent orbitals? Select all possible answers.
Which are forbidden by the Pauli principle? Select all possible answers.
Which are excited states? Select all possible answers.
Which is the ground state configuration?
Solution
Non existent orbitals:
4 is contained non existent orbitals.
1P orbital is not existed. And also 2S orbital was missed.
According to Pauli principle any two electrons in an atom should no posses same number of quantum numbesn.
In option 3, the 1S orbitals has 3 electrons and 2 electrons have the same spin quantum numbers +1/2 and in option 6, the 2S orbital have 3 electrons and two electrons have same spin quantum numbers. So this is not possible by Pauli principle.
2 and 5 are in excited configurations. In option 1, one of the 2S electrons is moved to 3P orbital. In option 5, both 2S electrons are moved to 3P orbitals.
Option 1 is the ground state configuration of nitrogen. Which satifies all principles.
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Measures of Central Tendency: Mean, Median and Mode
The following are hypothetical configurations for a nitrogen atom- 1-.docx
1. The following are hypothetical configurations for a nitrogen atom.
1. 1s 2
2s 2
2p 3
2. 1s 2
2s 1
2p 4
3. 1s 3
2s 2
2p 2
4. 1s 2
1p 5
5. 1s 2
2p 5
6. 1s 2
2s 3
2p 2
Which use nonexistent orbitals? Select all possible answers.
Which are forbidden by the Pauli principle? Select all possible answers.
Which are excited states? Select all possible answers.
Which is the ground state configuration?
Solution
Non existent orbitals:
4 is contained non existent orbitals.
1P orbital is not existed. And also 2S orbital was missed.
According to Pauli principle any two electrons in an atom should no posses same number of
quantum numbesn.
In option 3, the 1S orbitals has 3 electrons and 2 electrons have the same spin quantum numbers
+1/2 and in option 6, the 2S orbital have 3 electrons and two electrons have same spin quantum
numbers. So this is not possible by Pauli principle.
2 and 5 are in excited configurations. In option 1, one of the 2S electrons is moved to 3P orbital.
In option 5, both 2S electrons are moved to 3P orbitals.
Option 1 is the ground state configuration of nitrogen. Which satifies all principles.
