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CHAPTER 13
FORECASTING
Outline
• Forecasting and Choice of a Forecasting Methods
• Methods for Stationary Series:
– Simple and Weighted Moving Average
– Exponential smoothing
• Trend-Based Methods
– Regression
– Double Exponential Smoothing: Holt’s Method
• A Method for Seasonality and Trend
Forecasting
Decisions Based on Forecasts
• Production
– Aggregate planning,
inventory control,
scheduling
• Marketing
– New product
introduction, sales-
force allocation,
promotions
• Finance
– Plant/equipment
investment, budgetary
planning
• Personnel
– Workforce planning,
hiring, layoff
Characteristics of Forecasts
• Forecasts are always
wrong; so consider
both expected value
and a measure of
forecast error
• Long-term forecasts
are less accurate than
short-term forecasts
• Aggregate forecasts
are more accurate than
disaggregate forecasts
Forecasting
• Components of demand
• Evaluation of forecasts
• Time series: stationary series
• Time series: trend
– Linear regression
– Double exponential smoothing
• Time series: seasonality
Components of Demand
• Average demand
• Trend
– Gradual shift in average demand
• Seasonal pattern
– Periodic oscillation in demand which repeats
• Cycle
– Similar to seasonal patterns, length and
magnitude of the cycle may vary
• Random movements
• Auto-correlation
Qantity
Time
(a) Average: Data cluster about a horizontal line.
Components of Demand
Quantity
Time
(b) Linear trend: Data consistently increase or decrease.
Components of Demand
Components of Demand
Quantity
| | | | | | | | | | | |
J F M A M J J A S O N D
Months
(c) Seasonal influence: Data consistently show
peaks and valleys.
Year 1
Components of Demand
Quantity
| | | | | | | | | | | |
J F M A M J J A S O N D
Months
(c) Seasonal influence: Data consistently show
peaks and valleys.
Year 1
Year 2
Components of Demand
Components of Demand
Quantity
| | | | | |
1 2 3 4 5 6
Years
(c) Cyclical movements: Gradual changes over
extended periods of time.
Components of Demand
Demand
Time
Trend
Random
movement
Demand
Time
Trend with
seasonal pattern
Components of Demand
Snow Skiing
Seasonal
Long term growth trend
Demand for skiing products increased
sharply after the Nagano Olympics
Σ|Et |
nΣEt
2
n
RSFE = ΣEt
MAD =
MSE =
MAPE =
σ = MSE
Σ[|Et | (100)]/At
n
Measures of Forecast Error
Et = At - Ft
Choosing a MethodChoosing a Method
Forecast ErrorForecast Error
Absolute
Error Absolute Percent
Month, Demand, Forecast, Error, Squared, Error, Error,
t At Ft Et Et
2
|Et| (|Et|/At)(100)
1 200 225
2 240 220
3 300 285
4 270 290
5 230 250
6 260 240
7 210 250
8 275 240
-
Total
Choosing a MethodChoosing a Method
Forecast ErrorForecast Error
MSE = =
Measures of Error
MAD = =
MAPE = =
RSFE =
Choosing a MethodChoosing a Method
Forecast ErrorForecast Error
Choosing a MethodChoosing a Method
Forecast ErrorForecast Error
Running Sum Mean Absolute
of Forecast Errors Deviation
Method (RSFE - bias) (MAD)
Simple moving average
Three-week (n = 3) 23.1 17.1
Six-week (n = 6) 69.8 15.5
Weighted moving average
0.70, 0.20, 0.10 14.0 18.4
Exponential smoothing
α = 0.1 65.6 14.8
α = 0.2 41.0 15.3
Choosing a MethodChoosing a Method
Tracking SignalsTracking Signals Tracking signal =
RSFE
MAD
+2.0 —
+1.5 —
+1.0 —
+0.5 —
0 —
- 0.5 —
- 1.0 —
- 1.5 —
| | | | |
0 5 10 15 20 25
Observation number
Trackingsignal
Control limit
Control limit
Choosing a MethodChoosing a Method
Tracking SignalsTracking Signals Tracking signal =
RSFE
MAD
+2.0 —
+1.5 —
+1.0 —
+0.5 —
0 —
- 0.5 —
- 1.0 —
- 1.5 —
| | | | |
0 5 10 15 20 25
Observation number
Trackingsignal
Control limit
Control limit
Out of control
Choosing a MethodChoosing a Method
Tracking SignalsTracking Signals
C o n t r o l L im it
S p r e a d
( N u m b e r o f
M A D )
E q u iv a le n t
N u m b e r o f σ
( σ = 1 .2 5 M A D )
P e r c e n t a g e o f
A r e a w it h in
C o n t r o l L im it s
± 1 .0 ± 0 .8 0 5 7 .6 2
± 1 .5 ± 1 .2 0 7 6 .9 8
± 2 .0 ± 1 .6 0 8 9 .0 4
± 2 .5 ± 2 .0 0 9 5 .4 4
± 3 .0 ± 2 .4 0 9 8 .3 6
± 3 .5 ± 2 .8 0 9 9 .4 8
± 4 .0 ± 3 .2 0 9 9 .8 6
Problem 13-2: Historical demand for a product is:
Month Jan Feb Mar Apr May Jun
Demand 12 11 15 12 16 15
a. Using a weighted moving average with weights of 0.60,
0.30, and 0.10, find the July forecast.
b. Using a simple three-month moving average, find the July
forecast.
c. Using single exponential smoothing with α=0.20 and a June
forecast =13, find the July forecast.
d. Using simple regression analysis, calculate the regression
equation for the preceding demand data
e. Using regression equation in d, calculate the forecast in
July
Problem 13-15: In this problem, you are to test the validity of
your forecasting model. Here are the forecasts for a model
you have been using and the actual demands that
occurred:
Week 1 2 3 4 5 6
Forecast 800 850 950 950 1,000 975
Actual 900 1,000 1,050 900 900 1,100
Compute MAD and tracking signal. Then decide whether the
forecasting model you have been using is giving
reasonable results.
Methods for Stationary Series
Time Series MethodsTime Series Methods
Simple Moving AveragesSimple Moving Averages
Week
450 —
430 —
410 —
390 —
370 —
Patientarrivals
| | | | | |
0 5 10 15 20 25 30
Actual patient
arrivals
Time Series MethodsTime Series Methods
Simple Moving AveragesSimple Moving Averages
Actual patient
arrivals
450 —
430 —
410 —
390 —
370 —
Patientarrivals
Week
| | | | | |
0 5 10 15 20 25 30
Patient
Week Arrivals
1 400
2 380
3 411
Time Series MethodsTime Series Methods
Simple Moving AveragesSimple Moving Averages
Actual patient
arrivals
450 —
430 —
410 —
390 —
370 —
Patientarrivals
Week
| | | | | |
0 5 10 15 20 25 30
Patient
Week Arrivals
1 400
2 380
3 411
F4 =
Time Series MethodsTime Series Methods
Simple Moving AveragesSimple Moving Averages
Actual patient
arrivals
450 —
430 —
410 —
390 —
370 —
Patientarrivals
Week
| | | | | |
0 5 10 15 20 25 30
Patient
Week Arrivals
2 380
3 411
4 415
F5 =
Time Series MethodsTime Series Methods
Simple Moving AveragesSimple Moving Averages
450 —
430 —
410 —
390 —
370 —
Patientarrivals
Week
| | | | | |
0 5 10 15 20 25 30
Actual patient
arrivals
3-week MA
forecast
Time Series MethodsTime Series Methods
Simple Moving AveragesSimple Moving Averages
Week
450 —
430 —
410 —
390 —
370 —
Patientarrivals
| | | | | |
0 5 10 15 20 25 30
Actual patient
arrivals
3-week MA
forecast
6-week MA
forecast
Taco Bell determined that
the demand for each 15-
minute interval
can be estimated from a 6-
week simple moving
average of sales.
The forecast was used to
determine the number of
employees needed.
Time Series MethodsTime Series Methods
Weighted Moving AverageWeighted Moving Average
450 —
430 —
410 —
390 —
370 —
Patientarrivals
Week
| | | | | |
0 5 10 15 20 25 30
Actual patient
arrivals
3-week MA
forecast Weighted Moving Average
Assigned weights
t-1 0.70
t-2 0.20
t-3 0.10
F4 =
Time Series MethodsTime Series Methods
Weighted Moving AverageWeighted Moving Average
450 —
430 —
410 —
390 —
370 —
Patientarrivals
Week
| | | | | |
0 5 10 15 20 25 30
Actual patient
arrivals
3-week MA
forecast Weighted Moving Average
Assigned weights
t-1 0.70
t-2 0.20
t-3 0.10
F5 =
Time Series MethodsTime Series Methods
Exponential SmoothingExponential Smoothing
450 —
430 —
410 —
390 —
370 —
Patientarrivals
Week
| | | | | |
0 5 10 15 20 25 30
Exponential Smoothing
α = 0.10
Ft = α At-1 + (1 - α)Ft - 1
Time Series MethodsTime Series Methods
Exponential SmoothingExponential Smoothing
450 —
430 —
410 —
390 —
370 —
Patientarrivals
Week
| | | | | |
0 5 10 15 20 25 30
Exponential Smoothing
α = 0.10
Ft = α At-1 + (1 - α)Ft - 1
F3 = (400 + 380)/2=390
A3 = 411
Time Series MethodsTime Series Methods
Exponential SmoothingExponential Smoothing
450 —
430 —
410 —
390 —
370 —
Patientarrivals
Week
| | | | | |
0 5 10 15 20 25 30
F4 =
Exponential Smoothing
α = 0.10
Ft = α At-1 + (1 - α)Ft - 1
F3 = (400 + 380)/2=390
A3 = 411
Time Series MethodsTime Series Methods
Exponential SmoothingExponential Smoothing
Week
450 —
430 —
410 —
390 —
370 —
Patientarrivals
| | | | | |
0 5 10 15 20 25 30
F4 =
A4 = 415
Exponential Smoothing
α = 0.10
Ft = α At + (1 - α)Ft - 1
F5 =
Time Series MethodsTime Series Methods
Exponential SmoothingExponential Smoothing
450 —
430 —
410 —
390 —
370 —
Patientarrivals
Week
| | | | | |
0 5 10 15 20 25 30
Comparison of ExponentialComparison of Exponential
Smoothing and Simple MovingSmoothing and Simple Moving
AverageAverage
• Both Methods
– Are designed for stationary demand
– Require a single parameter
– Lag behind a trend, if one exists
– Have the same distribution of forecast error if
)1/(2 +=α N
Comparison of ExponentialComparison of Exponential
Smoothing and Simple MovingSmoothing and Simple Moving
AverageAverage
• Moving average uses only the last N periods
data, exponential smoothing uses all data
• Exponential smoothing uses less memory and
requires fewer steps of computation; store only
the most recent forecast!
Problem 13-20: Your manager is trying to determine what
forecasting method to use. Based upon the following historical
data, calculate the following forecast and specify what procedure
you would utilize:
Month 1 2 3 4 5 6 7 8 9 10 11 12
Actual demand 62 65 67 68 71 73 76 78 78 80 84 85
a. Calculate the three-month SMA forecast for periods 4-12
b. Calculate the weighted three-month MA using weights of 0.50,
0.30, and 0.20 for periods 4-12.
c. Calculate the single exponential smoothing forecast for periods 2-
12 using an initial forecast, F1=61 and α=0.30
d. Calculate the exponential smoothing with trend component
forecast for periods 2-12 using T1=1.8,F1=60,α=0.30,δ=0.30
e. Calculate MAD for the forecasts made by each technique in
periods 4-12. Which forecasting method do you prefer?
Trend-Based Methods
Turkeys have a long-term trend for increasing demand with a
seasonal pattern. Sales are highest during September to November
and sales are lowest during December and January.
Linear RegressionLinear Regression
Dependentvariable
Independent variable
X
Y
Linear RegressionLinear Regression
Dependentvariable
Independent variable
X
Y Regression
equation:
Y = a + bX
Linear RegressionLinear Regression
Dependentvariable
Independent variable
X
Y
Actual
value
of Y
Value of X used
to estimate Y
Regression
equation:
Y = a + bX
Linear RegressionLinear Regression
Dependentvariable
Independent variable
X
Y
Actual
value
of Y
Estimate of
Y from
regression
equation
Value of X used
to estimate Y
Regression
equation:
Y = a + bX
Linear RegressionLinear Regression
Dependentvariable
Independent variable
X
Y
Actual
value
of Y
Estimate of
Y from
regression
equation
Value of X used
to estimate Y
Deviation,
or error
{
Regression
equation:
Y = a + bX
Linear RegressionLinear Regression
Sales Advertising
Month (000 units) (000 $)
1 264 2.5
2 116 1.3
3 165 1.4
4 101 1.0
5 209 2.0
Linear RegressionLinear Regression
Sales, y Advertising, x
Month (000 units) (000 $)
1 264 2.5
2 116 1.3
3 165 1.4
4 101 1.0
5 209 2.0
a = y - bx b =
Σxy - nxy
Σx2
- n(x )2
a = y - bx b =
Σxy - nxy
Σx 2
- nx 2
Sales, y Advertising, x
Month (000 units) (000 $) xy x 2
1 264 2.5
2 116 1.3
3 165 1.4
4 101 1.0
5 209 2.0
Total
y= x =
Linear RegressionLinear Regression
300 —
250 —
200 —
150 —
100 —
50
b = 109.229
Y =
Sales(000s)
| | | |
1.0 1.5 2.0 2.5
Linear RegressionLinear Regression
Sales, y Advertising, x
Month (000 units) (000 $) xy x 2
y 2
1 264 2.5 660.0 6.25
2 116 1.3 150.8 1.69
3 165 1.4 231.0 1.96
4 101 1.0 101.0 1.00
5 209 2.0 418.0 4.00
Total 855 8.2 1560.8 14.90
y = 171 x = 1.64
nΣxy - Σx Σy
[nΣx 2
-(Σx) 2
][nΣy 2
- (Σy) 2
]
r =
Linear RegressionLinear Regression
Sales, y Advertising, x
Month (000 units) (000 $) xy x 2
y 2
1 264 2.5 660.0 6.25 69,696
2 116 1.3 150.8 1.69 13,456
3 165 1.4 231.0 1.96 27,225
4 101 1.0 101.0 1.00 10,201
5 209 2.0 418.0 4.00 43,681
Total 855 8.2 1560.8 14.90 164,259
y= 171 x = 1.64
r = 0.98 r 2
= 0.96
Linear RegressionLinear Regression
Forecast for Month 6:
Advertising expenditure = $1750
Y =
Time Series MethodsTime Series Methods
Linear Regression AnalysisLinear Regression Analysis
| | | | | | | | | | | | | | |
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
80 —
70 —
60 —
50 —
40 —
30 —
Patientarrivals
Week
Yn = a + bXn
where
Xn = Weekn
Time Series MethodsTime Series Methods
Linear Regression AnalysisLinear Regression Analysis
| | | | | | | | | | | | | | |
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
80 —
70 —
60 —
50 —
40 —
30 —
Patientarrivals
Week
Yn = a + bXn
where
Xn = Weekn
Time Series MethodsTime Series Methods
Linear Regression AnalysisLinear Regression Analysis
• Standard error of estimate is computed as
follows:
2
)(
1
2
−
−
=
∑=
n
Yy
S
n
i
ii
yx
Time Series MethodsTime Series Methods
Linear Regression AnalysisLinear Regression Analysis
• An use of the standard error of estimate:
– Suppose that a manager forecasts that the demand
for a product is 500 units and Syx is 20. If the
manager wants to accept a stockout only 2% time,
how many additional units should be held in the
inventory?
• The method uses two smoothing constants α
and δ
Time Series MethodsTime Series Methods
Double Exponential SmoothingDouble Exponential Smoothing
ttt
tttt
ttt
TF
TFFT
AF
+=
−+−=
−+=
−−
−−
FIT
FIT
11
11
)1()(
)1(
δδ
αα
A Comparison of Methods
60
65
70
75
80
85
90
0 5 10 15
Months
Demand
Actual
3-Mo MA
3-Mo WMA
Exp Sm
Double Exp Sm
Methods for Seasonal Series
Quarter Year 1 Year 2 Year 3 Year 4
1 45 70 100 100
2 335 370 585 725
3 520 590 830 1160
4 100 170 285 215
Total 1000 1200 1800 2200
Average 250 300 450 550
Time Series MethodsTime Series Methods
Seasonal InfluencesSeasonal Influences
Quarter Year 1 Year 2 Year 3 Year 4
1 45 70 100 100
2 335 370 585 725
3 520 590 830 1160
4 100 170 285 215
Total 1000 1200 1800 2200
Average 250 300 450 550
Seasonal Index =
Actual Demand
Average Demand
Time Series MethodsTime Series Methods
Seasonal InfluencesSeasonal Influences
Quarter Year 1 Year 2 Year 3 Year 4
1 45 70 100 100
2 335 370 585 725
3 520 590 830 1160
4 100 170 285 215
Total 1000 1200 1800 2200
Average 250 300 450 550
Seasonal Index = =
Time Series MethodsTime Series Methods
Seasonal InfluencesSeasonal Influences
Quarter Year 1 Year 2 Year 3 Year 4
1 45/250 = 70 100 100
2 335 370 585 725
3 520 590 830 1160
4 100 170 285 215
Total 1000 1200 1800 2200
Average 250 300 450 550
Seasonal Index = =
Time Series MethodsTime Series Methods
Seasonal InfluencesSeasonal Influences
Quarter Year 1 Year 2 Year 3 Year 4
1 45/250 = 0.18 70/300 = 0.23 100/450 = 0.22 100/550 = 0.18
2 335/250 = 1.34 370/300 = 1.23 585/450 = 1.30 725/550 = 1.32
3 520/250 = 2.08 590/300 = 1.97 830/450 = 1.84 1160/550 = 2.11
4 100/250 = 0.40 170/300 = 0.57 285/450 = 0.63 215/550 = 0.39
Time Series MethodsTime Series Methods
Seasonal InfluencesSeasonal Influences
Quarter Year 1 Year 2 Year 3 Year 4
1 45/250 = 0.18 70/300 = 0.23 100/450 = 0.22 100/550 = 0.18
2 335/250 = 1.34 370/300 = 1.23 585/450 = 1.30 725/550 = 1.32
3 520/250 = 2.08 590/300 = 1.97 830/450 = 1.84 1160/550 = 2.11
4 100/250 = 0.40 170/300 = 0.57 285/450 = 0.63 215/550 = 0.39
Quarter Average Seasonal Index
1 (0.18 + 0.23 + 0.22 + 0.18)/4 = 0.20
2
3
4
Time Series MethodsTime Series Methods
Seasonal InfluencesSeasonal Influences
Quarter Average Seasonal Index Forecast
1 (0.18 + 0.23 + 0.22 + 0.18)/4 = 0.20
2
3
4
Projected Annual Demand = 2600
Average Quarterly Demand = 2600/4 = 650
Time Series MethodsTime Series Methods
Seasonal InfluencesSeasonal Influences
Seasonal InfluencesSeasonal Influences
Period
Demand
(a) Multiplicative influence
| | | | | | | | | | | | | | | |
0 2 4 5 8 10 12 14 16
Seasonal InfluencesSeasonal Influences
Period
| | | | | | | | | | | | | | | |
0 2 4 5 8 10 12 14 16
Demand
(b) Additive influence
Time Series MethodsTime Series Methods
Seasonal Influences with TrendSeasonal Influences with Trend
Step 1: Determine seasonal factors
– Example: if the demands are quarterly, divide the average demand in
Quarter 1 by the average quarterly demand
Step 2: Deseasonalize the original data
– Divide the original data by the seasonal factors
Step 3: Develop a regression line on deaseasonalized data
– Find parameters a and b in Y=a+bX
– Where
– yi = deseasonalized data (not the original data)
– xi = time; 1, 2, 3, …, n
– n = Number of periods
Time Series MethodsTime Series Methods
Seasonal Influences with TrendSeasonal Influences with Trend
Step 4: Make projection using regression line
– For each i = n+1, n+2, …, compute yi by substituting a, b and xi in
the regression equation yi = a+bxi
Step 5: Reseasonalize projection using seasonal factors
– Multiply the projected values by the seasonal factors
Problem 13-21: Use regression analysis on deseasonalized
demand to forecast demand in summer 2006, given the
following historical demand data:
Year Season Actual Demand
2004 Spring 205
Summer 140
Fall 375
Winter 575
2005 Spring 475
Summer 275
Fall 685
Winter 965
Reading and Exercises
• Chapter 13 pp. 518-539
• Problems 1, 7, 13, 14,16

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Lecture2 forecasting f06_604

  • 1. CHAPTER 13 FORECASTING Outline • Forecasting and Choice of a Forecasting Methods • Methods for Stationary Series: – Simple and Weighted Moving Average – Exponential smoothing • Trend-Based Methods – Regression – Double Exponential Smoothing: Holt’s Method • A Method for Seasonality and Trend
  • 3. Decisions Based on Forecasts • Production – Aggregate planning, inventory control, scheduling • Marketing – New product introduction, sales- force allocation, promotions • Finance – Plant/equipment investment, budgetary planning • Personnel – Workforce planning, hiring, layoff
  • 4. Characteristics of Forecasts • Forecasts are always wrong; so consider both expected value and a measure of forecast error • Long-term forecasts are less accurate than short-term forecasts • Aggregate forecasts are more accurate than disaggregate forecasts
  • 5. Forecasting • Components of demand • Evaluation of forecasts • Time series: stationary series • Time series: trend – Linear regression – Double exponential smoothing • Time series: seasonality
  • 6. Components of Demand • Average demand • Trend – Gradual shift in average demand • Seasonal pattern – Periodic oscillation in demand which repeats • Cycle – Similar to seasonal patterns, length and magnitude of the cycle may vary • Random movements • Auto-correlation
  • 7. Qantity Time (a) Average: Data cluster about a horizontal line. Components of Demand
  • 8. Quantity Time (b) Linear trend: Data consistently increase or decrease. Components of Demand
  • 9. Components of Demand Quantity | | | | | | | | | | | | J F M A M J J A S O N D Months (c) Seasonal influence: Data consistently show peaks and valleys. Year 1
  • 10. Components of Demand Quantity | | | | | | | | | | | | J F M A M J J A S O N D Months (c) Seasonal influence: Data consistently show peaks and valleys. Year 1 Year 2
  • 12. Components of Demand Quantity | | | | | | 1 2 3 4 5 6 Years (c) Cyclical movements: Gradual changes over extended periods of time.
  • 15. Snow Skiing Seasonal Long term growth trend Demand for skiing products increased sharply after the Nagano Olympics
  • 16. Σ|Et | nΣEt 2 n RSFE = ΣEt MAD = MSE = MAPE = σ = MSE Σ[|Et | (100)]/At n Measures of Forecast Error Et = At - Ft Choosing a MethodChoosing a Method Forecast ErrorForecast Error
  • 17. Absolute Error Absolute Percent Month, Demand, Forecast, Error, Squared, Error, Error, t At Ft Et Et 2 |Et| (|Et|/At)(100) 1 200 225 2 240 220 3 300 285 4 270 290 5 230 250 6 260 240 7 210 250 8 275 240 - Total Choosing a MethodChoosing a Method Forecast ErrorForecast Error
  • 18. MSE = = Measures of Error MAD = = MAPE = = RSFE = Choosing a MethodChoosing a Method Forecast ErrorForecast Error
  • 19. Choosing a MethodChoosing a Method Forecast ErrorForecast Error Running Sum Mean Absolute of Forecast Errors Deviation Method (RSFE - bias) (MAD) Simple moving average Three-week (n = 3) 23.1 17.1 Six-week (n = 6) 69.8 15.5 Weighted moving average 0.70, 0.20, 0.10 14.0 18.4 Exponential smoothing α = 0.1 65.6 14.8 α = 0.2 41.0 15.3
  • 20. Choosing a MethodChoosing a Method Tracking SignalsTracking Signals Tracking signal = RSFE MAD +2.0 — +1.5 — +1.0 — +0.5 — 0 — - 0.5 — - 1.0 — - 1.5 — | | | | | 0 5 10 15 20 25 Observation number Trackingsignal Control limit Control limit
  • 21. Choosing a MethodChoosing a Method Tracking SignalsTracking Signals Tracking signal = RSFE MAD +2.0 — +1.5 — +1.0 — +0.5 — 0 — - 0.5 — - 1.0 — - 1.5 — | | | | | 0 5 10 15 20 25 Observation number Trackingsignal Control limit Control limit Out of control
  • 22. Choosing a MethodChoosing a Method Tracking SignalsTracking Signals C o n t r o l L im it S p r e a d ( N u m b e r o f M A D ) E q u iv a le n t N u m b e r o f σ ( σ = 1 .2 5 M A D ) P e r c e n t a g e o f A r e a w it h in C o n t r o l L im it s ± 1 .0 ± 0 .8 0 5 7 .6 2 ± 1 .5 ± 1 .2 0 7 6 .9 8 ± 2 .0 ± 1 .6 0 8 9 .0 4 ± 2 .5 ± 2 .0 0 9 5 .4 4 ± 3 .0 ± 2 .4 0 9 8 .3 6 ± 3 .5 ± 2 .8 0 9 9 .4 8 ± 4 .0 ± 3 .2 0 9 9 .8 6
  • 23. Problem 13-2: Historical demand for a product is: Month Jan Feb Mar Apr May Jun Demand 12 11 15 12 16 15 a. Using a weighted moving average with weights of 0.60, 0.30, and 0.10, find the July forecast. b. Using a simple three-month moving average, find the July forecast. c. Using single exponential smoothing with α=0.20 and a June forecast =13, find the July forecast. d. Using simple regression analysis, calculate the regression equation for the preceding demand data e. Using regression equation in d, calculate the forecast in July
  • 24. Problem 13-15: In this problem, you are to test the validity of your forecasting model. Here are the forecasts for a model you have been using and the actual demands that occurred: Week 1 2 3 4 5 6 Forecast 800 850 950 950 1,000 975 Actual 900 1,000 1,050 900 900 1,100 Compute MAD and tracking signal. Then decide whether the forecasting model you have been using is giving reasonable results.
  • 26. Time Series MethodsTime Series Methods Simple Moving AveragesSimple Moving Averages Week 450 — 430 — 410 — 390 — 370 — Patientarrivals | | | | | | 0 5 10 15 20 25 30 Actual patient arrivals
  • 27. Time Series MethodsTime Series Methods Simple Moving AveragesSimple Moving Averages Actual patient arrivals 450 — 430 — 410 — 390 — 370 — Patientarrivals Week | | | | | | 0 5 10 15 20 25 30 Patient Week Arrivals 1 400 2 380 3 411
  • 28. Time Series MethodsTime Series Methods Simple Moving AveragesSimple Moving Averages Actual patient arrivals 450 — 430 — 410 — 390 — 370 — Patientarrivals Week | | | | | | 0 5 10 15 20 25 30 Patient Week Arrivals 1 400 2 380 3 411 F4 =
  • 29. Time Series MethodsTime Series Methods Simple Moving AveragesSimple Moving Averages Actual patient arrivals 450 — 430 — 410 — 390 — 370 — Patientarrivals Week | | | | | | 0 5 10 15 20 25 30 Patient Week Arrivals 2 380 3 411 4 415 F5 =
  • 30. Time Series MethodsTime Series Methods Simple Moving AveragesSimple Moving Averages 450 — 430 — 410 — 390 — 370 — Patientarrivals Week | | | | | | 0 5 10 15 20 25 30 Actual patient arrivals 3-week MA forecast
  • 31. Time Series MethodsTime Series Methods Simple Moving AveragesSimple Moving Averages Week 450 — 430 — 410 — 390 — 370 — Patientarrivals | | | | | | 0 5 10 15 20 25 30 Actual patient arrivals 3-week MA forecast 6-week MA forecast
  • 32. Taco Bell determined that the demand for each 15- minute interval can be estimated from a 6- week simple moving average of sales. The forecast was used to determine the number of employees needed.
  • 33. Time Series MethodsTime Series Methods Weighted Moving AverageWeighted Moving Average 450 — 430 — 410 — 390 — 370 — Patientarrivals Week | | | | | | 0 5 10 15 20 25 30 Actual patient arrivals 3-week MA forecast Weighted Moving Average Assigned weights t-1 0.70 t-2 0.20 t-3 0.10 F4 =
  • 34. Time Series MethodsTime Series Methods Weighted Moving AverageWeighted Moving Average 450 — 430 — 410 — 390 — 370 — Patientarrivals Week | | | | | | 0 5 10 15 20 25 30 Actual patient arrivals 3-week MA forecast Weighted Moving Average Assigned weights t-1 0.70 t-2 0.20 t-3 0.10 F5 =
  • 35. Time Series MethodsTime Series Methods Exponential SmoothingExponential Smoothing 450 — 430 — 410 — 390 — 370 — Patientarrivals Week | | | | | | 0 5 10 15 20 25 30 Exponential Smoothing α = 0.10 Ft = α At-1 + (1 - α)Ft - 1
  • 36. Time Series MethodsTime Series Methods Exponential SmoothingExponential Smoothing 450 — 430 — 410 — 390 — 370 — Patientarrivals Week | | | | | | 0 5 10 15 20 25 30 Exponential Smoothing α = 0.10 Ft = α At-1 + (1 - α)Ft - 1 F3 = (400 + 380)/2=390 A3 = 411
  • 37. Time Series MethodsTime Series Methods Exponential SmoothingExponential Smoothing 450 — 430 — 410 — 390 — 370 — Patientarrivals Week | | | | | | 0 5 10 15 20 25 30 F4 = Exponential Smoothing α = 0.10 Ft = α At-1 + (1 - α)Ft - 1 F3 = (400 + 380)/2=390 A3 = 411
  • 38. Time Series MethodsTime Series Methods Exponential SmoothingExponential Smoothing Week 450 — 430 — 410 — 390 — 370 — Patientarrivals | | | | | | 0 5 10 15 20 25 30 F4 = A4 = 415 Exponential Smoothing α = 0.10 Ft = α At + (1 - α)Ft - 1 F5 =
  • 39. Time Series MethodsTime Series Methods Exponential SmoothingExponential Smoothing 450 — 430 — 410 — 390 — 370 — Patientarrivals Week | | | | | | 0 5 10 15 20 25 30
  • 40. Comparison of ExponentialComparison of Exponential Smoothing and Simple MovingSmoothing and Simple Moving AverageAverage • Both Methods – Are designed for stationary demand – Require a single parameter – Lag behind a trend, if one exists – Have the same distribution of forecast error if )1/(2 +=α N
  • 41. Comparison of ExponentialComparison of Exponential Smoothing and Simple MovingSmoothing and Simple Moving AverageAverage • Moving average uses only the last N periods data, exponential smoothing uses all data • Exponential smoothing uses less memory and requires fewer steps of computation; store only the most recent forecast!
  • 42. Problem 13-20: Your manager is trying to determine what forecasting method to use. Based upon the following historical data, calculate the following forecast and specify what procedure you would utilize: Month 1 2 3 4 5 6 7 8 9 10 11 12 Actual demand 62 65 67 68 71 73 76 78 78 80 84 85 a. Calculate the three-month SMA forecast for periods 4-12 b. Calculate the weighted three-month MA using weights of 0.50, 0.30, and 0.20 for periods 4-12. c. Calculate the single exponential smoothing forecast for periods 2- 12 using an initial forecast, F1=61 and α=0.30 d. Calculate the exponential smoothing with trend component forecast for periods 2-12 using T1=1.8,F1=60,α=0.30,δ=0.30 e. Calculate MAD for the forecasts made by each technique in periods 4-12. Which forecasting method do you prefer?
  • 44. Turkeys have a long-term trend for increasing demand with a seasonal pattern. Sales are highest during September to November and sales are lowest during December and January.
  • 46. Linear RegressionLinear Regression Dependentvariable Independent variable X Y Regression equation: Y = a + bX
  • 47. Linear RegressionLinear Regression Dependentvariable Independent variable X Y Actual value of Y Value of X used to estimate Y Regression equation: Y = a + bX
  • 48. Linear RegressionLinear Regression Dependentvariable Independent variable X Y Actual value of Y Estimate of Y from regression equation Value of X used to estimate Y Regression equation: Y = a + bX
  • 49. Linear RegressionLinear Regression Dependentvariable Independent variable X Y Actual value of Y Estimate of Y from regression equation Value of X used to estimate Y Deviation, or error { Regression equation: Y = a + bX
  • 50. Linear RegressionLinear Regression Sales Advertising Month (000 units) (000 $) 1 264 2.5 2 116 1.3 3 165 1.4 4 101 1.0 5 209 2.0
  • 51. Linear RegressionLinear Regression Sales, y Advertising, x Month (000 units) (000 $) 1 264 2.5 2 116 1.3 3 165 1.4 4 101 1.0 5 209 2.0 a = y - bx b = Σxy - nxy Σx2 - n(x )2
  • 52. a = y - bx b = Σxy - nxy Σx 2 - nx 2 Sales, y Advertising, x Month (000 units) (000 $) xy x 2 1 264 2.5 2 116 1.3 3 165 1.4 4 101 1.0 5 209 2.0 Total y= x = Linear RegressionLinear Regression
  • 53. 300 — 250 — 200 — 150 — 100 — 50 b = 109.229 Y = Sales(000s) | | | | 1.0 1.5 2.0 2.5
  • 54. Linear RegressionLinear Regression Sales, y Advertising, x Month (000 units) (000 $) xy x 2 y 2 1 264 2.5 660.0 6.25 2 116 1.3 150.8 1.69 3 165 1.4 231.0 1.96 4 101 1.0 101.0 1.00 5 209 2.0 418.0 4.00 Total 855 8.2 1560.8 14.90 y = 171 x = 1.64 nΣxy - Σx Σy [nΣx 2 -(Σx) 2 ][nΣy 2 - (Σy) 2 ] r =
  • 55. Linear RegressionLinear Regression Sales, y Advertising, x Month (000 units) (000 $) xy x 2 y 2 1 264 2.5 660.0 6.25 69,696 2 116 1.3 150.8 1.69 13,456 3 165 1.4 231.0 1.96 27,225 4 101 1.0 101.0 1.00 10,201 5 209 2.0 418.0 4.00 43,681 Total 855 8.2 1560.8 14.90 164,259 y= 171 x = 1.64 r = 0.98 r 2 = 0.96
  • 56. Linear RegressionLinear Regression Forecast for Month 6: Advertising expenditure = $1750 Y =
  • 57. Time Series MethodsTime Series Methods Linear Regression AnalysisLinear Regression Analysis | | | | | | | | | | | | | | | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 80 — 70 — 60 — 50 — 40 — 30 — Patientarrivals Week Yn = a + bXn where Xn = Weekn
  • 58. Time Series MethodsTime Series Methods Linear Regression AnalysisLinear Regression Analysis | | | | | | | | | | | | | | | 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 80 — 70 — 60 — 50 — 40 — 30 — Patientarrivals Week Yn = a + bXn where Xn = Weekn
  • 59. Time Series MethodsTime Series Methods Linear Regression AnalysisLinear Regression Analysis • Standard error of estimate is computed as follows: 2 )( 1 2 − − = ∑= n Yy S n i ii yx
  • 60. Time Series MethodsTime Series Methods Linear Regression AnalysisLinear Regression Analysis • An use of the standard error of estimate: – Suppose that a manager forecasts that the demand for a product is 500 units and Syx is 20. If the manager wants to accept a stockout only 2% time, how many additional units should be held in the inventory?
  • 61. • The method uses two smoothing constants α and δ Time Series MethodsTime Series Methods Double Exponential SmoothingDouble Exponential Smoothing ttt tttt ttt TF TFFT AF += −+−= −+= −− −− FIT FIT 11 11 )1()( )1( δδ αα
  • 62. A Comparison of Methods 60 65 70 75 80 85 90 0 5 10 15 Months Demand Actual 3-Mo MA 3-Mo WMA Exp Sm Double Exp Sm
  • 64. Quarter Year 1 Year 2 Year 3 Year 4 1 45 70 100 100 2 335 370 585 725 3 520 590 830 1160 4 100 170 285 215 Total 1000 1200 1800 2200 Average 250 300 450 550 Time Series MethodsTime Series Methods Seasonal InfluencesSeasonal Influences
  • 65. Quarter Year 1 Year 2 Year 3 Year 4 1 45 70 100 100 2 335 370 585 725 3 520 590 830 1160 4 100 170 285 215 Total 1000 1200 1800 2200 Average 250 300 450 550 Seasonal Index = Actual Demand Average Demand Time Series MethodsTime Series Methods Seasonal InfluencesSeasonal Influences
  • 66. Quarter Year 1 Year 2 Year 3 Year 4 1 45 70 100 100 2 335 370 585 725 3 520 590 830 1160 4 100 170 285 215 Total 1000 1200 1800 2200 Average 250 300 450 550 Seasonal Index = = Time Series MethodsTime Series Methods Seasonal InfluencesSeasonal Influences
  • 67. Quarter Year 1 Year 2 Year 3 Year 4 1 45/250 = 70 100 100 2 335 370 585 725 3 520 590 830 1160 4 100 170 285 215 Total 1000 1200 1800 2200 Average 250 300 450 550 Seasonal Index = = Time Series MethodsTime Series Methods Seasonal InfluencesSeasonal Influences
  • 68. Quarter Year 1 Year 2 Year 3 Year 4 1 45/250 = 0.18 70/300 = 0.23 100/450 = 0.22 100/550 = 0.18 2 335/250 = 1.34 370/300 = 1.23 585/450 = 1.30 725/550 = 1.32 3 520/250 = 2.08 590/300 = 1.97 830/450 = 1.84 1160/550 = 2.11 4 100/250 = 0.40 170/300 = 0.57 285/450 = 0.63 215/550 = 0.39 Time Series MethodsTime Series Methods Seasonal InfluencesSeasonal Influences
  • 69. Quarter Year 1 Year 2 Year 3 Year 4 1 45/250 = 0.18 70/300 = 0.23 100/450 = 0.22 100/550 = 0.18 2 335/250 = 1.34 370/300 = 1.23 585/450 = 1.30 725/550 = 1.32 3 520/250 = 2.08 590/300 = 1.97 830/450 = 1.84 1160/550 = 2.11 4 100/250 = 0.40 170/300 = 0.57 285/450 = 0.63 215/550 = 0.39 Quarter Average Seasonal Index 1 (0.18 + 0.23 + 0.22 + 0.18)/4 = 0.20 2 3 4 Time Series MethodsTime Series Methods Seasonal InfluencesSeasonal Influences
  • 70. Quarter Average Seasonal Index Forecast 1 (0.18 + 0.23 + 0.22 + 0.18)/4 = 0.20 2 3 4 Projected Annual Demand = 2600 Average Quarterly Demand = 2600/4 = 650 Time Series MethodsTime Series Methods Seasonal InfluencesSeasonal Influences
  • 71. Seasonal InfluencesSeasonal Influences Period Demand (a) Multiplicative influence | | | | | | | | | | | | | | | | 0 2 4 5 8 10 12 14 16
  • 72. Seasonal InfluencesSeasonal Influences Period | | | | | | | | | | | | | | | | 0 2 4 5 8 10 12 14 16 Demand (b) Additive influence
  • 73. Time Series MethodsTime Series Methods Seasonal Influences with TrendSeasonal Influences with Trend Step 1: Determine seasonal factors – Example: if the demands are quarterly, divide the average demand in Quarter 1 by the average quarterly demand Step 2: Deseasonalize the original data – Divide the original data by the seasonal factors Step 3: Develop a regression line on deaseasonalized data – Find parameters a and b in Y=a+bX – Where – yi = deseasonalized data (not the original data) – xi = time; 1, 2, 3, …, n – n = Number of periods
  • 74. Time Series MethodsTime Series Methods Seasonal Influences with TrendSeasonal Influences with Trend Step 4: Make projection using regression line – For each i = n+1, n+2, …, compute yi by substituting a, b and xi in the regression equation yi = a+bxi Step 5: Reseasonalize projection using seasonal factors – Multiply the projected values by the seasonal factors
  • 75. Problem 13-21: Use regression analysis on deseasonalized demand to forecast demand in summer 2006, given the following historical demand data: Year Season Actual Demand 2004 Spring 205 Summer 140 Fall 375 Winter 575 2005 Spring 475 Summer 275 Fall 685 Winter 965
  • 76. Reading and Exercises • Chapter 13 pp. 518-539 • Problems 1, 7, 13, 14,16

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