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TUGAS MATEMATIKA KALKULUS
HALAMAN 33 - 44
Disusun Oleh :
Nama : 1. Barry Alkhafi
2. AchmadTrybuana Kurniasandy
3. AuliaRamadhani
4.Faizal
Kelas : 1 EA
Semester : 2 ( DUA )
POLITEKNIK MANUFAKTUR NEGERI BANGKA BELITUNG
2014/2015
Kawasan Industri Air Kantung, Sungailiat-Bangka 33211
Telp : 0717-93586, 95252 Faks : 0717-93585
E-mail : polman@polman-babel.ac.id
Website : http://polman-babel.ac.id
“ HALAMAN 33-40 “
Jawaban :
1. f(x) = 20ex
fꞌ(x) = 20.
𝒅
𝒅𝒙
(ex)
= 20ex
2. y = e3x
yꞌ(x) = e3x.
𝒅
𝒅𝒙
(5x3)
= 𝒆 𝟓𝒙 𝟑
(15x2)
= 15x2 𝒆 𝟓𝒙 𝟑
3. g(x) = 𝒆 𝟓𝒙 𝟑
gꞌ(x) = 𝒆 𝟓𝒙 𝟑
(.
𝒅
𝒅𝒙
(5x3)
= 𝒆 𝟓𝒙 𝟑
( (15x2)
= 15x2 𝒆 𝟓𝒙 𝟑
4. y = -4𝒆 𝟓𝒙 𝟑
yꞌ= -4.
𝒅
𝒅𝒙
(𝒆 𝟓𝒙 𝟑
)
= -4.𝒆 𝟓𝒙 𝟑
.
𝒅
𝒅𝒙
(5x3)
= -4.𝒆 𝟓𝒙 𝟑
(15x2)
= -60x2 𝒆 𝟓𝒙 𝟑
Temukan turunan dari fungsi yang diberikan
1. f(x) = 20ex 6. f(x) = 15x2 +10ex
2. y = e3x
7. g(x) = 𝒆 𝟕𝒙−𝟐𝒙 𝟑
3. g(x) = 𝒆 𝟓𝒙 𝟑
8. f(t) =
𝟏𝟎𝟎
𝒆−𝟎.𝟓𝒕
4. y = -4𝒆 𝟓𝒙 𝟑
9. g(t) = 2500e2t+1
5. h(x) = 𝒆−𝟏𝟎𝒙 𝟑
10. f(x) =
𝟏
√𝟐𝝅
𝒆
𝒙 𝟐
𝟐
5. h(x) = 𝒆−𝟏𝟎𝒙 𝟑
hꞌ(x) = 𝒆−𝟏𝟎𝒙 𝟑
.
𝒅
𝒅𝒙
(-10x3)
= 𝒆−𝟏𝟎𝒙 𝟑
(-30x2)
= -30x2 𝒆−𝟏𝟎𝒙 𝟑
6. f(x) = 15x2 + 10ex
fꞌ(x) = 15x2 + 10.
𝒅
𝒅𝒙
(ex)
= 30x + 10ex
7. g(x) = 𝒆 𝟕𝒙−𝟐𝒙 𝟑
gꞌ(x) = 𝒆 𝟕𝒙−𝟐𝒙 𝟑
.
𝒅
𝒅𝒙
(7x-2x3)
= 𝒆 𝟕𝒙−𝟐𝒙 𝟑
(7-6x)
= 7-6x𝒆 𝟕𝒙−𝟐𝒙 𝟑
8. f(t) =
𝟏𝟎𝟎
𝐞−𝟎.𝟓𝒕
fꞌ(t) = 100.e0.5t
= 100. e0.5t.
𝒅
𝒅𝒙
(0.5t)
= 100. e0.5t(0.5)
= 50e0.5t
9. g(t) = 2500e2t+1
gꞌ(t) = 2500e2t+1.
𝒅
𝒅𝒙
(2t+1)
= 2500e2t+1.(2)
= 5000e2t+1
10. f(x) =
𝟏
√𝟐𝝅
e
𝒙𝟐
𝟐
fꞌ(x) =
𝟏
√𝟐𝝅
.e
𝟏
𝟐
x2.
𝒅
𝒅𝒙
(
𝟏
𝟐
x2)
=
𝟏
√𝟐𝝅
.e
𝟏
𝟐
x2.(x)
=
𝒙
√𝟐𝝅
.e
𝟏
𝟐
x2
Jawaban :
1. f(x) = 20 ln x
fꞌ(x) = 20 .
𝒅
𝒅𝒙
(ln x)
= 20.
𝟏
𝒙
=
𝟐𝟎
𝒙
2. y = ln 3x
yꞌ =
𝟏
𝟑𝒙
.
𝒅
𝒅𝒙
(3x)
=
𝟏
𝟑𝒙
. (3x)
=
𝟏
𝒙
3. g(x) = ln(5x3)
gꞌ(x) =
𝟏
𝟓𝒙 𝟑 .
𝒅
𝒅𝒙
(5x3)
=
𝟏
𝟓𝒙 𝟑.(15x2)
=
𝟑
𝒙
4. y = - 4 ln (5x3)
yꞌ = - 4.
𝟏
𝟓𝒙 𝟑.
𝒅
𝒅𝒙
(5x3)
= - 4.
𝟏
𝟓𝒙 𝟑.(15x2)
= -4.
𝟑
𝒙
= -
𝟏𝟐
𝒙
Temukan turunan dari fungsi yang diberikan
1. f(x) = 20 ln x 6. f(x) = 15x2 + 10ln x
2. y = ln 3x 7. g(x) = ln(7x-2x3)
3. g(x) = ln(5x3) 8. f(t) = ln(3t2 + 5t – 20)
4. y = -4 ln (5x3) 9. g(t) = ln(et)
5. h(x) = ln(-10x3) 10. f(x) = ln(ln x)
5. h(x) = ln(-10x3)
hꞌ(x) =
𝟏
−𝟏𝟎𝒙 𝟑 .
𝒅
𝒅𝒙
(-10x3)
=
𝟏
−𝟏𝟎𝒙 𝟑(-30x2)
=
𝟑
𝒙
6. f(x) = 15x2 + 10ln x
fꞌ(x) = 15x2 + 10.
𝒅
𝒅𝒙
(ln x)
= 30x + 10.
𝟏
𝒙
= 30x +
𝟏𝟎
𝒙
7. g(x) = ln(7x-2x3)
gꞌ(x) =
𝟏
𝟕𝒙−𝟐𝒙 𝟑.
𝒅
𝒅𝒙
(7x-2x3)
=
𝟏
𝟕𝒙−𝟐𝒙 𝟑. (7x-2x3)
=
𝟕−𝟔𝒙 𝟐
𝟕𝒙−𝟐𝒙 𝟑
8. f(t) = ln(3t2 + 5t – 20)
fꞌ(t) =
𝟏
𝟑𝒕 𝟐+𝟓𝒕−𝟐𝟎
.
𝒅
𝒅𝒙
(𝟑𝒕 𝟐
+ 𝟓𝒕 − 𝟐𝟎)
=
𝟏
𝟑𝒕 𝟐+𝟓𝒕−𝟐𝟎
. ( 𝟔𝒕+ 𝟓)
=
𝟔𝒕+𝟓
𝟑𝒕 𝟐+𝟓𝒕−𝟐𝟎
9. g(t) = ln(et)
gꞌ(t) =
𝟏
𝒆 𝒕 .
𝒅
𝒅𝒙
(et)
=
𝟏
𝒆 𝒕(e)
=
𝒆
𝒆 𝒕
10. f(x) = ln(ln x)
fꞌ(x) =
𝟏
𝐥𝐧 𝒙
.
𝒅
𝒅𝒙
(ln x)
=
𝟏
𝐥𝐧 𝒙
. (
𝟏
𝒙
)
=
𝟏
𝐥𝐧 𝒙.𝒙
Jawaban :
1. f(x) = 20 (3x)
fꞌ(x) = 20.
𝒅
𝒅𝒙
(3x)
= 20(ln3)3x
2. y = 53x
yꞌ = (ln 5)53x.
𝒅
𝒅𝒙
(3x)
= (ln 5)53x.(3)
= 3(ln 5)53x
3. g(x) = 𝟐 𝟓𝐱 𝟑
gꞌ(x) = (ln 2)𝟐 𝟓𝐱 𝟑
.
𝒅
𝒅𝒙
(5x3)
= (ln 2)𝟐 𝟓𝐱 𝟑
(15x2)
= 15x2(ln 2) 𝟐 𝟓𝐱 𝟑
4. y = -4(𝟐 𝟓𝐱 𝟑
)
yꞌ = -4.
𝒅
𝒅𝒙
(𝟐 𝟓𝐱 𝟑
)
= -4(ln 2)𝟐 𝟓𝐱 𝟑
.(15x2)
= -60x2(ln 2)𝟐 𝟓𝐱 𝟑
Temukanturunan dari fungsi yang diberikan
1. f(x) = 20 (3x) 6. f(x) = 15x2 + 10(5x3)
2. y = 53x
7. g(x) = 𝟑 𝟕𝒙−𝟐𝒙 𝟑
3. g(x) = 𝟐 𝟓𝒙 𝟑
8. f(t) =
𝟏𝟎𝟎
𝟏𝟎−𝟎.𝟓𝒕
4. y = -4( 𝟐 𝟓𝒙 𝟑
) 9. g(t) = 2500(52t+1)
5. h(x) = 𝟒−𝟏𝟎𝒙 𝟑
10. f(x) = 8
𝒙 𝟐
𝟐
5. h(x) = 𝟒−𝟏𝟎𝐱 𝟑
hꞌ(x) = (ln 4)𝟒−𝟏𝟎𝐱 𝟑
.
𝒅
𝒅𝒙
(-30x2)
= (ln 4)𝟒−𝟏𝟎𝐱 𝟑
. (-30x2)
= -30x2(ln 4)𝟒−𝟏𝟎𝐱 𝟑
6. f(x) = 15x2 + 10(5x3)
fꞌ(x) = 15x2 + 10.
𝒅
𝒅𝒙
(53x)
= 30x + 10(ln 5)53.3
= 30x + 30(ln 5)53
7. g(x) = 𝟑 𝟕𝐱−𝟐𝐱 𝟑
gꞌ(x) = (ln 3)𝟑 𝟕𝐱−𝟐𝐱 𝟑
.
𝒅
𝒅𝒙
(7x-2x3)
= (ln 3)𝟑 𝟕𝐱−𝟐𝐱 𝟑
.(7-6x2)
= 7-6x2(ln 3)𝟑 𝟕𝐱−𝟐𝐱 𝟑
8. f(t) =
𝟏𝟎𝟎
𝟏𝟎−𝟎.𝟓𝒕
fꞌ(t) = 100. 100.5t
= 100.(ln 10)100.5t.
𝒅
𝒅𝒙
(0.5t)
= 100.(ln 10)100.5t. 0.5
= 50(ln 10)100.5t
9. g(t) = 2500(52t+1)
gꞌ(t) = 2500.
𝒅
𝒅𝒙
(52t+1)
= 2500(ln 5)52t+1.
𝒅
𝒅𝒙
(2t+1)
= 2500(ln 5)52t+1.2
= 5000(ln 5)52t+1
10. f(x) = 8
𝒙 𝟐
𝟐
= 8−
𝟏
𝟐
x2
fꞌ(x) = (ln 8)8−
𝟏
𝟐
x2.
𝒅
𝒅𝒙
(−
𝟏
𝟐
x2)
= (ln 8)8−
𝟏
𝟐
x2.(-x)
= (-x).(ln 8)8−
𝟏
𝟐
x2
Jawaban :
1. f(x) = 20log4
fꞌ(x) = 20.
𝒅
𝒅𝒙
(log4x)
= 20.
𝟏
(𝐥𝐧 𝟒)𝒙
=
𝟐𝟎
𝒙 𝐥𝐧 𝟒
2. y = log10 3x
yꞌ =
𝟏
(𝐥𝐧 𝟏𝟎) 𝟑𝒙
.
𝒅
𝒅𝒙
(3x)
=
𝟏
(𝐥𝐧 𝟏𝟎) 𝟑𝒙
(3)
=
𝟑
𝒙 𝐥𝐧 𝟏𝟎
Temukanturunan dari fungsi yang diberikan
1. f(x) = 20log4 6. f(x) = 15x2 + 10log2 x
2. y = log10 3x 7. g(x) = log6(7x-2x3)
3. g(x) = log8(5x3) 8. f(t) = log16(3t2+5t – 20)
4. y = -4log8(5x3) 9. g(t) = log2(et)
5. h(x) = log5(-10x3) 10. f(x) = log10(log10x)
3. g(x) = log8(5x3)
gꞌ(x) =
𝟏
(𝐥𝐧 𝟖)𝟓𝒙 𝟑
.
𝒅
𝒅𝒙
(5x3
)
=
𝟏
(𝐥𝐧 𝟖)𝟓𝒙 𝟑
. (𝟏𝟓𝒙 𝟐
)
=
𝟑
𝒙 𝐥𝐧 𝟖
4. y = -4log8 (5x3)
yꞌ =
𝟒
(𝐥𝐧 𝟖)𝟓𝒙 𝟑
.
𝒅
𝒅𝒙
(5x3
)
=
𝟒
(𝐥𝐧 𝟖)𝟓𝒙 𝟑
.(15x2
)
=
−𝟔𝟎 𝒙 𝟐
(𝐥𝐧 𝟖)𝟓𝒙 𝟑
=
−𝟏𝟐
𝒙 𝐥𝐧 𝟖
5. h(x) = log5(-10x3)
hꞌ(x) =
𝟏
(𝐥𝐧 𝟓)−𝟏𝟎𝒙 𝟑.
𝒅
𝒅𝒙
(-10x3)
=
𝟏
(𝐥𝐧 𝟓)−𝟏𝟎𝒙 𝟑.(-30x2)
=
𝟑
𝒙 𝐥𝐧 𝟓
6. f(x) = 15x2 + 10log2 x
fꞌ(x) = 15x2 + 10.
𝒅
𝒅𝒙
.(log2 x)
= 30x + 10.
𝟏
(𝐥𝐧 𝟐)𝒙
= 30x +
𝟏𝟎
𝒙 𝒍𝒏𝟐
7. g(x) = log6(7x-2x3)
gꞌ(x) =
𝟏
(𝐥𝐧 𝟔)𝟕𝒙−𝟐𝒙 𝟑.
𝒅
𝒅𝒙
(7x-2x)
=
𝟕−𝟔𝒙 𝟐
(𝐥𝐧 𝟔)𝟕𝒙−𝟐𝒙 𝟑
=
𝟕−𝟔𝒙 𝟐
𝟕𝒙−𝟐𝒙 𝟑(𝐥𝐧 𝟔)
8. f(t) = log16(3t2+5t – 20)
fꞌ(t) =
𝒅
𝒅𝒙
(log16(3t2+5t-20)
=
𝟏
(𝐥𝐧 𝟏𝟔)𝟑𝐭𝟐+𝟓𝐭−𝟐𝟎
.
𝒅
𝒅𝒙
(3t2+5t-20)
=
𝟏
(𝐥𝐧 𝟏𝟔)𝟑𝐭𝟐+𝟓𝐭−𝟐𝟎
.(6t + 5)
=
𝟔𝒕+𝟓
𝟑𝐭𝟐+𝟓𝐭−𝟐𝟎(𝐥𝐧 𝟔)
9. g(t) = log2(et)
gꞌ(t) =
𝒅
𝒅𝒙
.( log2(et))
=
𝟏
(𝐥𝐧 𝟐) 𝒆 𝒕.
𝒅
𝒅𝒙
(et)
=
𝟏
(𝐥𝐧 𝟐) 𝒆 𝒕. (et)
=
𝟏
(𝐥𝐧 𝟐)
10. f(x) = log10(log10x)
fꞌ(x) =
𝒅
𝒅𝒙
(log10(log10x))
=
𝟏
(𝐥𝐧 𝟏𝟎).(𝐥𝐨𝐠 𝟏𝟎 𝒙)
.
𝒅
𝒅𝒙
(log10 x)
=
𝟏
(𝐥𝐧 𝟏𝟎).(𝐥𝐨𝐠 𝟏𝟎 𝒙)
.
𝟏
(𝐥𝐧 𝟏𝟎).(𝐥𝐨𝐠 𝟏𝟎 𝒙)
.
𝒅
𝒅𝒙
(x)
=
𝟏
(𝐥𝐧 𝟏𝟎) 𝟐.(𝐥𝐨𝐠 𝟐 𝟏𝟎 𝒙)
Temukan turunan dari fungsi yang diberikan
1. f(x) = 5 sin 3x 6. s(t) = 4 cot5t
2. y =
𝟏
𝟒
cos(2x2) 7. g(x) = 6tan3(
𝟐𝒙
𝟑
)-20√ 𝒙
3. g(x) = 5tan(
𝟑𝒙
𝟓
) 8. f(x) = 2xsinx+cos2x
4. f(x) = 10sec2x 9. h(x) =
𝒔𝒊𝒏𝟑𝒙
𝟏+𝒔𝒊𝒏𝟑𝒙
5. y =
𝟐
𝟑
sec(2x3) 10. f(x) = e4xsin2x
Jawaban :
1. f(x) = 5sin3x
fꞌ(x) = 5 cos3x
𝒅
𝒅𝒙
(3x)
= 15 cos 3x
2. f(x) =
𝟏
𝟒
cos(2x2)
fꞌ(x) =
𝟏
𝟒
-sin 2x2 𝒅
𝒅𝒙
(2x2)
=
𝟏
𝟒
-sin 2x2.4x
= −
𝟒𝒙
𝟒
sin2x2
= -xsin2x2
3. g(x) = 5tan(
𝟑𝒙
𝟓
)
gꞌ(x) = 5 sec2(
𝟑𝒙
𝟓
)
𝒅
𝒅𝒙
(
𝟑𝒙
𝟓
)
= 5 sec2(
𝟑𝒙
𝟓
).
𝟑
𝟓
= 3 sec2(
𝟑𝒙
𝟓
)
4. f(x) = 10 sec 2x
fꞌ(x) = 10 sec 2x tan 2x
𝒅
𝒅𝒙
(2x)
= 20 sec 2x tan 2x
5. y =
𝟐
𝟑
sec(2x3)
yꞌ =
𝟐
𝟑
sec 2x3 tan 2x3 𝒅
𝒅𝒙
(2x3)
=
𝟐
𝟑
sec 2x3 tan 2x3.6x2
= 4x2sec 2x3 tan 2x3
6. s(t) = 4 cot 5t
sꞌ(t) = -4 csc2 5t
𝒅
𝒅𝒕
(5t)
= -20 csc2 5t
7. g(x) = 6tan3(
𝟐𝒙
𝟑
)-20√ 𝒙
gꞌ(x) = 6 sec6(
𝟐𝒙
𝟑
)
𝒅
𝒅𝒙
(
𝟐𝒙
𝟑
)-10𝒙
−𝟏
𝟐⁄
= 6 sec6(
𝟐𝒙
𝟑
).(
𝟐𝒙
𝟑
) − 𝟏𝟎𝒙
−𝟏
𝟐⁄
= 4 sec6(
𝟐𝒙
𝟑
)-
𝟏𝟎
√ 𝒙
8. f(x) = 2x sinx + cos 2x
fꞌ(x) = 2 cos x
𝒅
𝒅𝒙
(x) + (-sin 2x)
𝒅
𝒅𝒙
(2x)
= 2 cos x – 2 sin 2x
9. h(x) =
𝒔𝒊𝒏𝟑𝒙
𝟏+𝒔𝒊𝒏𝟑𝒙
hꞌ(x) =
𝒄𝒐𝒔 𝟑𝒙
𝒅
𝒅𝒙
(𝟑𝒙)
𝒄𝒐𝒔 𝟑𝒙
𝒅
𝒅𝒙
(𝟑𝒙)
=
𝟑 𝒄𝒐𝒔 𝟑𝒙
𝟑 𝒄𝒐𝒔 𝟑𝒙
= 1
10. f(x) = e4xsin2x
fꞌ(x) = e4x 𝒅
𝒅𝒙
(4x). cos 2x
𝒅
𝒅𝒙
(2x)
= 4e4x.2cos 2x
Temukan turunan dari fungsi yang diberikan
1. f(x) = sin-1( -x3) 6. f(x) = cos-1(x2)
2. h(x) = cos -1(ex) 7. h(x) = csc-1(2x)
3. g(x) = tan-1(x2) 8. g(x) = 4 sec-1(
𝒙
𝟐
)
4. f(x) = cot-1(7x-5) 9. f(x) = x sin-1(7x2)
5. y =
𝟏
𝟓
sin-1(5x3) 10. y = arcsin(√𝟏 − 𝒙 𝟐)
Jawaban :
1. f(x) = 𝑺𝒊𝒏−𝟏
(−𝒙 𝟑
)
fꞌ(x) =
−𝟏
√ 𝟏−(−𝒙 𝟑 ) 𝟐
.
𝒅
𝒅𝒙
.(−𝒙 𝟑
)
=
−𝟑𝒙 𝟐
√ 𝟏−𝒙 𝟗
2. h(x) = cos -1(ex)
hꞌ(x) =
−𝟏
√ 𝟏−(𝒆 𝒙) 𝟐
.
𝒅
𝒅𝒙
(ex)
=
−𝒆 𝒙
√ 𝟏−(𝒆 𝒙) 𝟐
3. g(x) = tan-1(x2)
gꞌ(x) =
𝟏
𝟏+ (𝒙 𝟐) 𝟐.
𝒅
𝒅𝒙
(x2)
=
𝟐𝒙
𝟏+ 𝒙 𝟒
4. f(x) = cot-1(7x-5)
fꞌ(x) =
−𝟏
𝟏+(𝟕𝑿−𝟓) 𝟐.
𝒅
𝒅𝒙
(7x-5)
=
−𝟕
𝟒𝟗𝑿 𝟐− 𝟕𝟎𝑿+𝟐𝟓
5. y =
𝟏
𝟓
sin-1(5x3)
yꞌ =
𝟏
√ 𝟏+ (𝟓𝒙 𝟑 ) 𝟐
.
𝒅
𝒅𝒙
(5𝒙 𝟑
).
𝟏
𝟏𝟓
=
𝟏
√ 𝟏+𝟐𝟓𝒙 𝟔
.15x2.
𝟏
𝟏𝟓
=
𝟏𝟓𝒙 𝟐
√ 𝟏+𝟐𝟓𝒙 𝟔.𝟏𝟓
6. f(x) = cos-1(x2)
fꞌ(x) =
𝟏
√ 𝟏− (𝒙 𝟐 ) 𝟐
.
𝒅
𝒅𝒙
(x2)
=
−𝟐𝒙
√ 𝟏+𝒙 𝟒
7. h(x) = csc-1(2x)
hꞌ(x) =
−𝟏
| 𝟐𝒙|√(𝟐𝒙) 𝟐− 𝟏
.
𝒅
𝒅𝒙
. (2x)
= -
𝟐
𝟐𝒙 √ 𝟒𝒙 𝟐 − 𝟏
8. g(x) = 4 sec-1(
𝒙
𝟐
)
gꞌ(x) = 4.
−𝟏
|
𝒙
𝟐
|√(
𝒙
𝟐
)
𝟐
.
𝒅
𝒅𝒙
.(
𝒙
𝟐
)
=
−𝟒
𝒙
𝟐
√ 𝒙 𝟐
𝟒
− 𝟏
.
𝟏
𝟒
=
−𝟒
𝒙
𝟐
√ 𝒙 𝟐
𝟒
– 𝟏 .𝟒
9. f(x) = x sin-1(7x2)
fꞌ(x) = 1.
𝟏
√ 𝟏− (𝟕𝒙 𝟐 ) 𝟐
.
𝒅
𝒅𝒙
.7x2
=
𝟏𝟒𝒙
√ 𝟏−𝟒𝟗𝒙 𝟒
10. y = arcsin(√𝟏 − 𝒙 𝟐)
yꞌ =
𝟏
√ 𝟏− (√ 𝟏− 𝒙 𝟐 )
𝟐
.
𝒅
𝒅𝒙
.√𝟏 − 𝒙 𝟐
=
𝟏
√𝟏− ( 𝟏−𝒙 𝟐 )
. 𝟏
𝟐⁄ (1 – x2)
=
𝟏−𝒙 𝟐
𝟐√ 𝒙 𝟐
Temukan turunan dari fungsi yang diberikan
1. f(x) = x7 + 2x10 , Temukan fꞌꞌꞌ(x) 6. s(t) = 16t2-
𝟐𝒕
𝟑
+10 , Temukan sꞌꞌ(t)
2. h(x) = √ 𝒙𝟑
, Temukan hꞌꞌ(x) 7. g(x) = ln3x , Temukan 𝑫 𝒙
𝟑[ 𝒈(𝒙)]
3. g(x) = 2x , Temukan g(5)(x) 8. f(t) =
𝟏𝟎
𝒙 𝟓 +
𝒙 𝟑
𝟓
, Temukan f(4)(x)
4. f(x) = 5ex , Temukan f(4)(x) 9. f(x) = 32x , Temukan fꞌꞌꞌ(x)
5. y(x) = sin3x , Temukan
𝒅 𝟑
𝒚
𝒅 𝟑 𝒙
10. y = 𝒍𝒐𝒈 𝟐5x , Temukan
𝒅 𝟒
𝒚
𝒅 𝟒 𝒙
Jawaban
1. f(x) = x7 + 2x10
fꞌ(x) = 7x6 + 20x9
fꞌꞌ(x) = 42x5 + 180x8
fꞌꞌꞌ(x) = 210x4 + 1440x7
2. h(x) = √ 𝒙𝟑
= 𝒙
𝟏
𝟑⁄
hꞌ(x) = 𝟏
𝟑⁄ 𝒙
𝟐
𝟑⁄
hꞌꞌ(x) =
−𝟐
𝟗
𝒙
−𝟓
𝟑⁄
3. g(x) = 2x
gꞌ(x) = 2
gꞌꞌ(x) = 0
gꞌꞌꞌ(x) = 0
g4(x) = 0
4. f(x) = 5ex
fꞌ(x) = 5ex.1
fꞌꞌ(x) = 5ex.1 = 5ex
fꞌꞌꞌ(x) = 5ex.1
=
𝒅 𝟑
𝒈
𝒅 𝟑 𝒙
= 5ex
5. y = sin 3x
𝒅 𝟏
𝒚
𝒅 𝟏 𝒙
= 3 cos 3x
𝒅 𝟐
𝒚
𝒅 𝟐 𝒙
= -9 sin 3x
𝒅 𝟑
𝒚
𝒅 𝟑 𝒙
= - 27 cos 3x
6. s(t) = 16t2 -
𝟐𝒕
𝟑
+ 10
sꞌ(t) = 32t -
𝟐
𝟑
sꞌꞌ(t) = 32
7. g(x) = ln 3x
D1(x)[ 𝒈(𝒙)] =
𝟑
𝟑𝒙
=
𝟏
𝒙
= 𝒙−𝟏
D2(x)[ 𝒈(𝒙)] = −𝒙−𝟐
D3(x)[ 𝒈(𝒙)] = 𝟐𝒙−𝟑
8. f(x) =
𝟏𝟎
𝒙 𝟓 +
𝒙 𝟑
𝟓
= 𝟏𝟎𝒙−𝟓
+
𝟏
𝟓
𝒙 𝟑
fꞌ(x) = -50 𝒙−𝟔
+
𝟑
𝟓
𝒙 𝟐
fꞌꞌ(x) = 300 x-7 +
𝟔
𝟓
x
fꞌꞌꞌ(x) = -2100 x-8 +
𝟔
𝟓
f4(x) = 16800 x-9
9. f(x) = 32x
fꞌ(x) = 32x ln 3 . 2
fꞌꞌ(x) = 32x ln 3 .
𝟐
𝟑
fꞌꞌꞌ(x) = 32x ln 3 . 2 .
𝟏
𝟑
= 32x ln 3 .
𝟐
𝟗
10. g = log2 5x
𝒅ꞌ𝒚
𝒅ꞌ𝒙
=
𝟏
𝟓𝒙 𝐥𝐧 𝟐
. 5 =
𝟓
𝟓𝒙 𝐥𝐧 𝟐
𝒅ꞌꞌ𝒚
𝒅ꞌꞌ𝒙
=
𝟓
𝟓
.
𝟏
𝟐
.1
𝒅ꞌꞌꞌ𝒚
𝒅ꞌꞌꞌ𝒙
= 0 =
𝒅 𝟒
𝒚
𝒅 𝟒 𝒙
= 0

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Tugasmatematikakelompok 150715235527-lva1-app6892

  • 1. TUGAS MATEMATIKA KALKULUS HALAMAN 33 - 44 Disusun Oleh : Nama : 1. Barry Alkhafi 2. AchmadTrybuana Kurniasandy 3. AuliaRamadhani 4.Faizal Kelas : 1 EA Semester : 2 ( DUA ) POLITEKNIK MANUFAKTUR NEGERI BANGKA BELITUNG 2014/2015 Kawasan Industri Air Kantung, Sungailiat-Bangka 33211 Telp : 0717-93586, 95252 Faks : 0717-93585 E-mail : polman@polman-babel.ac.id Website : http://polman-babel.ac.id
  • 2. “ HALAMAN 33-40 “ Jawaban : 1. f(x) = 20ex fꞌ(x) = 20. 𝒅 𝒅𝒙 (ex) = 20ex 2. y = e3x yꞌ(x) = e3x. 𝒅 𝒅𝒙 (5x3) = 𝒆 𝟓𝒙 𝟑 (15x2) = 15x2 𝒆 𝟓𝒙 𝟑 3. g(x) = 𝒆 𝟓𝒙 𝟑 gꞌ(x) = 𝒆 𝟓𝒙 𝟑 (. 𝒅 𝒅𝒙 (5x3) = 𝒆 𝟓𝒙 𝟑 ( (15x2) = 15x2 𝒆 𝟓𝒙 𝟑 4. y = -4𝒆 𝟓𝒙 𝟑 yꞌ= -4. 𝒅 𝒅𝒙 (𝒆 𝟓𝒙 𝟑 ) = -4.𝒆 𝟓𝒙 𝟑 . 𝒅 𝒅𝒙 (5x3) = -4.𝒆 𝟓𝒙 𝟑 (15x2) = -60x2 𝒆 𝟓𝒙 𝟑 Temukan turunan dari fungsi yang diberikan 1. f(x) = 20ex 6. f(x) = 15x2 +10ex 2. y = e3x 7. g(x) = 𝒆 𝟕𝒙−𝟐𝒙 𝟑 3. g(x) = 𝒆 𝟓𝒙 𝟑 8. f(t) = 𝟏𝟎𝟎 𝒆−𝟎.𝟓𝒕 4. y = -4𝒆 𝟓𝒙 𝟑 9. g(t) = 2500e2t+1 5. h(x) = 𝒆−𝟏𝟎𝒙 𝟑 10. f(x) = 𝟏 √𝟐𝝅 𝒆 𝒙 𝟐 𝟐
  • 3. 5. h(x) = 𝒆−𝟏𝟎𝒙 𝟑 hꞌ(x) = 𝒆−𝟏𝟎𝒙 𝟑 . 𝒅 𝒅𝒙 (-10x3) = 𝒆−𝟏𝟎𝒙 𝟑 (-30x2) = -30x2 𝒆−𝟏𝟎𝒙 𝟑 6. f(x) = 15x2 + 10ex fꞌ(x) = 15x2 + 10. 𝒅 𝒅𝒙 (ex) = 30x + 10ex 7. g(x) = 𝒆 𝟕𝒙−𝟐𝒙 𝟑 gꞌ(x) = 𝒆 𝟕𝒙−𝟐𝒙 𝟑 . 𝒅 𝒅𝒙 (7x-2x3) = 𝒆 𝟕𝒙−𝟐𝒙 𝟑 (7-6x) = 7-6x𝒆 𝟕𝒙−𝟐𝒙 𝟑 8. f(t) = 𝟏𝟎𝟎 𝐞−𝟎.𝟓𝒕 fꞌ(t) = 100.e0.5t = 100. e0.5t. 𝒅 𝒅𝒙 (0.5t) = 100. e0.5t(0.5) = 50e0.5t 9. g(t) = 2500e2t+1 gꞌ(t) = 2500e2t+1. 𝒅 𝒅𝒙 (2t+1) = 2500e2t+1.(2) = 5000e2t+1 10. f(x) = 𝟏 √𝟐𝝅 e 𝒙𝟐 𝟐 fꞌ(x) = 𝟏 √𝟐𝝅 .e 𝟏 𝟐 x2. 𝒅 𝒅𝒙 ( 𝟏 𝟐 x2) = 𝟏 √𝟐𝝅 .e 𝟏 𝟐 x2.(x) = 𝒙 √𝟐𝝅 .e 𝟏 𝟐 x2
  • 4. Jawaban : 1. f(x) = 20 ln x fꞌ(x) = 20 . 𝒅 𝒅𝒙 (ln x) = 20. 𝟏 𝒙 = 𝟐𝟎 𝒙 2. y = ln 3x yꞌ = 𝟏 𝟑𝒙 . 𝒅 𝒅𝒙 (3x) = 𝟏 𝟑𝒙 . (3x) = 𝟏 𝒙 3. g(x) = ln(5x3) gꞌ(x) = 𝟏 𝟓𝒙 𝟑 . 𝒅 𝒅𝒙 (5x3) = 𝟏 𝟓𝒙 𝟑.(15x2) = 𝟑 𝒙 4. y = - 4 ln (5x3) yꞌ = - 4. 𝟏 𝟓𝒙 𝟑. 𝒅 𝒅𝒙 (5x3) = - 4. 𝟏 𝟓𝒙 𝟑.(15x2) = -4. 𝟑 𝒙 = - 𝟏𝟐 𝒙 Temukan turunan dari fungsi yang diberikan 1. f(x) = 20 ln x 6. f(x) = 15x2 + 10ln x 2. y = ln 3x 7. g(x) = ln(7x-2x3) 3. g(x) = ln(5x3) 8. f(t) = ln(3t2 + 5t – 20) 4. y = -4 ln (5x3) 9. g(t) = ln(et) 5. h(x) = ln(-10x3) 10. f(x) = ln(ln x)
  • 5. 5. h(x) = ln(-10x3) hꞌ(x) = 𝟏 −𝟏𝟎𝒙 𝟑 . 𝒅 𝒅𝒙 (-10x3) = 𝟏 −𝟏𝟎𝒙 𝟑(-30x2) = 𝟑 𝒙 6. f(x) = 15x2 + 10ln x fꞌ(x) = 15x2 + 10. 𝒅 𝒅𝒙 (ln x) = 30x + 10. 𝟏 𝒙 = 30x + 𝟏𝟎 𝒙 7. g(x) = ln(7x-2x3) gꞌ(x) = 𝟏 𝟕𝒙−𝟐𝒙 𝟑. 𝒅 𝒅𝒙 (7x-2x3) = 𝟏 𝟕𝒙−𝟐𝒙 𝟑. (7x-2x3) = 𝟕−𝟔𝒙 𝟐 𝟕𝒙−𝟐𝒙 𝟑 8. f(t) = ln(3t2 + 5t – 20) fꞌ(t) = 𝟏 𝟑𝒕 𝟐+𝟓𝒕−𝟐𝟎 . 𝒅 𝒅𝒙 (𝟑𝒕 𝟐 + 𝟓𝒕 − 𝟐𝟎) = 𝟏 𝟑𝒕 𝟐+𝟓𝒕−𝟐𝟎 . ( 𝟔𝒕+ 𝟓) = 𝟔𝒕+𝟓 𝟑𝒕 𝟐+𝟓𝒕−𝟐𝟎 9. g(t) = ln(et) gꞌ(t) = 𝟏 𝒆 𝒕 . 𝒅 𝒅𝒙 (et) = 𝟏 𝒆 𝒕(e) = 𝒆 𝒆 𝒕 10. f(x) = ln(ln x) fꞌ(x) = 𝟏 𝐥𝐧 𝒙 . 𝒅 𝒅𝒙 (ln x) = 𝟏 𝐥𝐧 𝒙 . ( 𝟏 𝒙 ) = 𝟏 𝐥𝐧 𝒙.𝒙
  • 6. Jawaban : 1. f(x) = 20 (3x) fꞌ(x) = 20. 𝒅 𝒅𝒙 (3x) = 20(ln3)3x 2. y = 53x yꞌ = (ln 5)53x. 𝒅 𝒅𝒙 (3x) = (ln 5)53x.(3) = 3(ln 5)53x 3. g(x) = 𝟐 𝟓𝐱 𝟑 gꞌ(x) = (ln 2)𝟐 𝟓𝐱 𝟑 . 𝒅 𝒅𝒙 (5x3) = (ln 2)𝟐 𝟓𝐱 𝟑 (15x2) = 15x2(ln 2) 𝟐 𝟓𝐱 𝟑 4. y = -4(𝟐 𝟓𝐱 𝟑 ) yꞌ = -4. 𝒅 𝒅𝒙 (𝟐 𝟓𝐱 𝟑 ) = -4(ln 2)𝟐 𝟓𝐱 𝟑 .(15x2) = -60x2(ln 2)𝟐 𝟓𝐱 𝟑 Temukanturunan dari fungsi yang diberikan 1. f(x) = 20 (3x) 6. f(x) = 15x2 + 10(5x3) 2. y = 53x 7. g(x) = 𝟑 𝟕𝒙−𝟐𝒙 𝟑 3. g(x) = 𝟐 𝟓𝒙 𝟑 8. f(t) = 𝟏𝟎𝟎 𝟏𝟎−𝟎.𝟓𝒕 4. y = -4( 𝟐 𝟓𝒙 𝟑 ) 9. g(t) = 2500(52t+1) 5. h(x) = 𝟒−𝟏𝟎𝒙 𝟑 10. f(x) = 8 𝒙 𝟐 𝟐
  • 7. 5. h(x) = 𝟒−𝟏𝟎𝐱 𝟑 hꞌ(x) = (ln 4)𝟒−𝟏𝟎𝐱 𝟑 . 𝒅 𝒅𝒙 (-30x2) = (ln 4)𝟒−𝟏𝟎𝐱 𝟑 . (-30x2) = -30x2(ln 4)𝟒−𝟏𝟎𝐱 𝟑 6. f(x) = 15x2 + 10(5x3) fꞌ(x) = 15x2 + 10. 𝒅 𝒅𝒙 (53x) = 30x + 10(ln 5)53.3 = 30x + 30(ln 5)53 7. g(x) = 𝟑 𝟕𝐱−𝟐𝐱 𝟑 gꞌ(x) = (ln 3)𝟑 𝟕𝐱−𝟐𝐱 𝟑 . 𝒅 𝒅𝒙 (7x-2x3) = (ln 3)𝟑 𝟕𝐱−𝟐𝐱 𝟑 .(7-6x2) = 7-6x2(ln 3)𝟑 𝟕𝐱−𝟐𝐱 𝟑 8. f(t) = 𝟏𝟎𝟎 𝟏𝟎−𝟎.𝟓𝒕 fꞌ(t) = 100. 100.5t = 100.(ln 10)100.5t. 𝒅 𝒅𝒙 (0.5t) = 100.(ln 10)100.5t. 0.5 = 50(ln 10)100.5t 9. g(t) = 2500(52t+1) gꞌ(t) = 2500. 𝒅 𝒅𝒙 (52t+1) = 2500(ln 5)52t+1. 𝒅 𝒅𝒙 (2t+1) = 2500(ln 5)52t+1.2 = 5000(ln 5)52t+1
  • 8. 10. f(x) = 8 𝒙 𝟐 𝟐 = 8− 𝟏 𝟐 x2 fꞌ(x) = (ln 8)8− 𝟏 𝟐 x2. 𝒅 𝒅𝒙 (− 𝟏 𝟐 x2) = (ln 8)8− 𝟏 𝟐 x2.(-x) = (-x).(ln 8)8− 𝟏 𝟐 x2 Jawaban : 1. f(x) = 20log4 fꞌ(x) = 20. 𝒅 𝒅𝒙 (log4x) = 20. 𝟏 (𝐥𝐧 𝟒)𝒙 = 𝟐𝟎 𝒙 𝐥𝐧 𝟒 2. y = log10 3x yꞌ = 𝟏 (𝐥𝐧 𝟏𝟎) 𝟑𝒙 . 𝒅 𝒅𝒙 (3x) = 𝟏 (𝐥𝐧 𝟏𝟎) 𝟑𝒙 (3) = 𝟑 𝒙 𝐥𝐧 𝟏𝟎 Temukanturunan dari fungsi yang diberikan 1. f(x) = 20log4 6. f(x) = 15x2 + 10log2 x 2. y = log10 3x 7. g(x) = log6(7x-2x3) 3. g(x) = log8(5x3) 8. f(t) = log16(3t2+5t – 20) 4. y = -4log8(5x3) 9. g(t) = log2(et) 5. h(x) = log5(-10x3) 10. f(x) = log10(log10x)
  • 9. 3. g(x) = log8(5x3) gꞌ(x) = 𝟏 (𝐥𝐧 𝟖)𝟓𝒙 𝟑 . 𝒅 𝒅𝒙 (5x3 ) = 𝟏 (𝐥𝐧 𝟖)𝟓𝒙 𝟑 . (𝟏𝟓𝒙 𝟐 ) = 𝟑 𝒙 𝐥𝐧 𝟖 4. y = -4log8 (5x3) yꞌ = 𝟒 (𝐥𝐧 𝟖)𝟓𝒙 𝟑 . 𝒅 𝒅𝒙 (5x3 ) = 𝟒 (𝐥𝐧 𝟖)𝟓𝒙 𝟑 .(15x2 ) = −𝟔𝟎 𝒙 𝟐 (𝐥𝐧 𝟖)𝟓𝒙 𝟑 = −𝟏𝟐 𝒙 𝐥𝐧 𝟖 5. h(x) = log5(-10x3) hꞌ(x) = 𝟏 (𝐥𝐧 𝟓)−𝟏𝟎𝒙 𝟑. 𝒅 𝒅𝒙 (-10x3) = 𝟏 (𝐥𝐧 𝟓)−𝟏𝟎𝒙 𝟑.(-30x2) = 𝟑 𝒙 𝐥𝐧 𝟓 6. f(x) = 15x2 + 10log2 x fꞌ(x) = 15x2 + 10. 𝒅 𝒅𝒙 .(log2 x) = 30x + 10. 𝟏 (𝐥𝐧 𝟐)𝒙 = 30x + 𝟏𝟎 𝒙 𝒍𝒏𝟐 7. g(x) = log6(7x-2x3) gꞌ(x) = 𝟏 (𝐥𝐧 𝟔)𝟕𝒙−𝟐𝒙 𝟑. 𝒅 𝒅𝒙 (7x-2x) = 𝟕−𝟔𝒙 𝟐 (𝐥𝐧 𝟔)𝟕𝒙−𝟐𝒙 𝟑 = 𝟕−𝟔𝒙 𝟐 𝟕𝒙−𝟐𝒙 𝟑(𝐥𝐧 𝟔)
  • 10. 8. f(t) = log16(3t2+5t – 20) fꞌ(t) = 𝒅 𝒅𝒙 (log16(3t2+5t-20) = 𝟏 (𝐥𝐧 𝟏𝟔)𝟑𝐭𝟐+𝟓𝐭−𝟐𝟎 . 𝒅 𝒅𝒙 (3t2+5t-20) = 𝟏 (𝐥𝐧 𝟏𝟔)𝟑𝐭𝟐+𝟓𝐭−𝟐𝟎 .(6t + 5) = 𝟔𝒕+𝟓 𝟑𝐭𝟐+𝟓𝐭−𝟐𝟎(𝐥𝐧 𝟔) 9. g(t) = log2(et) gꞌ(t) = 𝒅 𝒅𝒙 .( log2(et)) = 𝟏 (𝐥𝐧 𝟐) 𝒆 𝒕. 𝒅 𝒅𝒙 (et) = 𝟏 (𝐥𝐧 𝟐) 𝒆 𝒕. (et) = 𝟏 (𝐥𝐧 𝟐) 10. f(x) = log10(log10x) fꞌ(x) = 𝒅 𝒅𝒙 (log10(log10x)) = 𝟏 (𝐥𝐧 𝟏𝟎).(𝐥𝐨𝐠 𝟏𝟎 𝒙) . 𝒅 𝒅𝒙 (log10 x) = 𝟏 (𝐥𝐧 𝟏𝟎).(𝐥𝐨𝐠 𝟏𝟎 𝒙) . 𝟏 (𝐥𝐧 𝟏𝟎).(𝐥𝐨𝐠 𝟏𝟎 𝒙) . 𝒅 𝒅𝒙 (x) = 𝟏 (𝐥𝐧 𝟏𝟎) 𝟐.(𝐥𝐨𝐠 𝟐 𝟏𝟎 𝒙) Temukan turunan dari fungsi yang diberikan 1. f(x) = 5 sin 3x 6. s(t) = 4 cot5t 2. y = 𝟏 𝟒 cos(2x2) 7. g(x) = 6tan3( 𝟐𝒙 𝟑 )-20√ 𝒙 3. g(x) = 5tan( 𝟑𝒙 𝟓 ) 8. f(x) = 2xsinx+cos2x 4. f(x) = 10sec2x 9. h(x) = 𝒔𝒊𝒏𝟑𝒙 𝟏+𝒔𝒊𝒏𝟑𝒙 5. y = 𝟐 𝟑 sec(2x3) 10. f(x) = e4xsin2x
  • 11. Jawaban : 1. f(x) = 5sin3x fꞌ(x) = 5 cos3x 𝒅 𝒅𝒙 (3x) = 15 cos 3x 2. f(x) = 𝟏 𝟒 cos(2x2) fꞌ(x) = 𝟏 𝟒 -sin 2x2 𝒅 𝒅𝒙 (2x2) = 𝟏 𝟒 -sin 2x2.4x = − 𝟒𝒙 𝟒 sin2x2 = -xsin2x2 3. g(x) = 5tan( 𝟑𝒙 𝟓 ) gꞌ(x) = 5 sec2( 𝟑𝒙 𝟓 ) 𝒅 𝒅𝒙 ( 𝟑𝒙 𝟓 ) = 5 sec2( 𝟑𝒙 𝟓 ). 𝟑 𝟓 = 3 sec2( 𝟑𝒙 𝟓 ) 4. f(x) = 10 sec 2x fꞌ(x) = 10 sec 2x tan 2x 𝒅 𝒅𝒙 (2x) = 20 sec 2x tan 2x 5. y = 𝟐 𝟑 sec(2x3) yꞌ = 𝟐 𝟑 sec 2x3 tan 2x3 𝒅 𝒅𝒙 (2x3) = 𝟐 𝟑 sec 2x3 tan 2x3.6x2 = 4x2sec 2x3 tan 2x3 6. s(t) = 4 cot 5t sꞌ(t) = -4 csc2 5t 𝒅 𝒅𝒕 (5t) = -20 csc2 5t
  • 12. 7. g(x) = 6tan3( 𝟐𝒙 𝟑 )-20√ 𝒙 gꞌ(x) = 6 sec6( 𝟐𝒙 𝟑 ) 𝒅 𝒅𝒙 ( 𝟐𝒙 𝟑 )-10𝒙 −𝟏 𝟐⁄ = 6 sec6( 𝟐𝒙 𝟑 ).( 𝟐𝒙 𝟑 ) − 𝟏𝟎𝒙 −𝟏 𝟐⁄ = 4 sec6( 𝟐𝒙 𝟑 )- 𝟏𝟎 √ 𝒙 8. f(x) = 2x sinx + cos 2x fꞌ(x) = 2 cos x 𝒅 𝒅𝒙 (x) + (-sin 2x) 𝒅 𝒅𝒙 (2x) = 2 cos x – 2 sin 2x 9. h(x) = 𝒔𝒊𝒏𝟑𝒙 𝟏+𝒔𝒊𝒏𝟑𝒙 hꞌ(x) = 𝒄𝒐𝒔 𝟑𝒙 𝒅 𝒅𝒙 (𝟑𝒙) 𝒄𝒐𝒔 𝟑𝒙 𝒅 𝒅𝒙 (𝟑𝒙) = 𝟑 𝒄𝒐𝒔 𝟑𝒙 𝟑 𝒄𝒐𝒔 𝟑𝒙 = 1 10. f(x) = e4xsin2x fꞌ(x) = e4x 𝒅 𝒅𝒙 (4x). cos 2x 𝒅 𝒅𝒙 (2x) = 4e4x.2cos 2x Temukan turunan dari fungsi yang diberikan 1. f(x) = sin-1( -x3) 6. f(x) = cos-1(x2) 2. h(x) = cos -1(ex) 7. h(x) = csc-1(2x) 3. g(x) = tan-1(x2) 8. g(x) = 4 sec-1( 𝒙 𝟐 ) 4. f(x) = cot-1(7x-5) 9. f(x) = x sin-1(7x2) 5. y = 𝟏 𝟓 sin-1(5x3) 10. y = arcsin(√𝟏 − 𝒙 𝟐)
  • 13. Jawaban : 1. f(x) = 𝑺𝒊𝒏−𝟏 (−𝒙 𝟑 ) fꞌ(x) = −𝟏 √ 𝟏−(−𝒙 𝟑 ) 𝟐 . 𝒅 𝒅𝒙 .(−𝒙 𝟑 ) = −𝟑𝒙 𝟐 √ 𝟏−𝒙 𝟗 2. h(x) = cos -1(ex) hꞌ(x) = −𝟏 √ 𝟏−(𝒆 𝒙) 𝟐 . 𝒅 𝒅𝒙 (ex) = −𝒆 𝒙 √ 𝟏−(𝒆 𝒙) 𝟐 3. g(x) = tan-1(x2) gꞌ(x) = 𝟏 𝟏+ (𝒙 𝟐) 𝟐. 𝒅 𝒅𝒙 (x2) = 𝟐𝒙 𝟏+ 𝒙 𝟒 4. f(x) = cot-1(7x-5) fꞌ(x) = −𝟏 𝟏+(𝟕𝑿−𝟓) 𝟐. 𝒅 𝒅𝒙 (7x-5) = −𝟕 𝟒𝟗𝑿 𝟐− 𝟕𝟎𝑿+𝟐𝟓 5. y = 𝟏 𝟓 sin-1(5x3) yꞌ = 𝟏 √ 𝟏+ (𝟓𝒙 𝟑 ) 𝟐 . 𝒅 𝒅𝒙 (5𝒙 𝟑 ). 𝟏 𝟏𝟓 = 𝟏 √ 𝟏+𝟐𝟓𝒙 𝟔 .15x2. 𝟏 𝟏𝟓 = 𝟏𝟓𝒙 𝟐 √ 𝟏+𝟐𝟓𝒙 𝟔.𝟏𝟓 6. f(x) = cos-1(x2) fꞌ(x) = 𝟏 √ 𝟏− (𝒙 𝟐 ) 𝟐 . 𝒅 𝒅𝒙 (x2) = −𝟐𝒙 √ 𝟏+𝒙 𝟒
  • 14. 7. h(x) = csc-1(2x) hꞌ(x) = −𝟏 | 𝟐𝒙|√(𝟐𝒙) 𝟐− 𝟏 . 𝒅 𝒅𝒙 . (2x) = - 𝟐 𝟐𝒙 √ 𝟒𝒙 𝟐 − 𝟏 8. g(x) = 4 sec-1( 𝒙 𝟐 ) gꞌ(x) = 4. −𝟏 | 𝒙 𝟐 |√( 𝒙 𝟐 ) 𝟐 . 𝒅 𝒅𝒙 .( 𝒙 𝟐 ) = −𝟒 𝒙 𝟐 √ 𝒙 𝟐 𝟒 − 𝟏 . 𝟏 𝟒 = −𝟒 𝒙 𝟐 √ 𝒙 𝟐 𝟒 – 𝟏 .𝟒 9. f(x) = x sin-1(7x2) fꞌ(x) = 1. 𝟏 √ 𝟏− (𝟕𝒙 𝟐 ) 𝟐 . 𝒅 𝒅𝒙 .7x2 = 𝟏𝟒𝒙 √ 𝟏−𝟒𝟗𝒙 𝟒 10. y = arcsin(√𝟏 − 𝒙 𝟐) yꞌ = 𝟏 √ 𝟏− (√ 𝟏− 𝒙 𝟐 ) 𝟐 . 𝒅 𝒅𝒙 .√𝟏 − 𝒙 𝟐 = 𝟏 √𝟏− ( 𝟏−𝒙 𝟐 ) . 𝟏 𝟐⁄ (1 – x2) = 𝟏−𝒙 𝟐 𝟐√ 𝒙 𝟐 Temukan turunan dari fungsi yang diberikan 1. f(x) = x7 + 2x10 , Temukan fꞌꞌꞌ(x) 6. s(t) = 16t2- 𝟐𝒕 𝟑 +10 , Temukan sꞌꞌ(t) 2. h(x) = √ 𝒙𝟑 , Temukan hꞌꞌ(x) 7. g(x) = ln3x , Temukan 𝑫 𝒙 𝟑[ 𝒈(𝒙)] 3. g(x) = 2x , Temukan g(5)(x) 8. f(t) = 𝟏𝟎 𝒙 𝟓 + 𝒙 𝟑 𝟓 , Temukan f(4)(x) 4. f(x) = 5ex , Temukan f(4)(x) 9. f(x) = 32x , Temukan fꞌꞌꞌ(x) 5. y(x) = sin3x , Temukan 𝒅 𝟑 𝒚 𝒅 𝟑 𝒙 10. y = 𝒍𝒐𝒈 𝟐5x , Temukan 𝒅 𝟒 𝒚 𝒅 𝟒 𝒙
  • 15. Jawaban 1. f(x) = x7 + 2x10 fꞌ(x) = 7x6 + 20x9 fꞌꞌ(x) = 42x5 + 180x8 fꞌꞌꞌ(x) = 210x4 + 1440x7 2. h(x) = √ 𝒙𝟑 = 𝒙 𝟏 𝟑⁄ hꞌ(x) = 𝟏 𝟑⁄ 𝒙 𝟐 𝟑⁄ hꞌꞌ(x) = −𝟐 𝟗 𝒙 −𝟓 𝟑⁄ 3. g(x) = 2x gꞌ(x) = 2 gꞌꞌ(x) = 0 gꞌꞌꞌ(x) = 0 g4(x) = 0 4. f(x) = 5ex fꞌ(x) = 5ex.1 fꞌꞌ(x) = 5ex.1 = 5ex fꞌꞌꞌ(x) = 5ex.1 = 𝒅 𝟑 𝒈 𝒅 𝟑 𝒙 = 5ex 5. y = sin 3x 𝒅 𝟏 𝒚 𝒅 𝟏 𝒙 = 3 cos 3x 𝒅 𝟐 𝒚 𝒅 𝟐 𝒙 = -9 sin 3x 𝒅 𝟑 𝒚 𝒅 𝟑 𝒙 = - 27 cos 3x 6. s(t) = 16t2 - 𝟐𝒕 𝟑 + 10 sꞌ(t) = 32t - 𝟐 𝟑 sꞌꞌ(t) = 32
  • 16. 7. g(x) = ln 3x D1(x)[ 𝒈(𝒙)] = 𝟑 𝟑𝒙 = 𝟏 𝒙 = 𝒙−𝟏 D2(x)[ 𝒈(𝒙)] = −𝒙−𝟐 D3(x)[ 𝒈(𝒙)] = 𝟐𝒙−𝟑 8. f(x) = 𝟏𝟎 𝒙 𝟓 + 𝒙 𝟑 𝟓 = 𝟏𝟎𝒙−𝟓 + 𝟏 𝟓 𝒙 𝟑 fꞌ(x) = -50 𝒙−𝟔 + 𝟑 𝟓 𝒙 𝟐 fꞌꞌ(x) = 300 x-7 + 𝟔 𝟓 x fꞌꞌꞌ(x) = -2100 x-8 + 𝟔 𝟓 f4(x) = 16800 x-9 9. f(x) = 32x fꞌ(x) = 32x ln 3 . 2 fꞌꞌ(x) = 32x ln 3 . 𝟐 𝟑 fꞌꞌꞌ(x) = 32x ln 3 . 2 . 𝟏 𝟑 = 32x ln 3 . 𝟐 𝟗 10. g = log2 5x 𝒅ꞌ𝒚 𝒅ꞌ𝒙 = 𝟏 𝟓𝒙 𝐥𝐧 𝟐 . 5 = 𝟓 𝟓𝒙 𝐥𝐧 𝟐 𝒅ꞌꞌ𝒚 𝒅ꞌꞌ𝒙 = 𝟓 𝟓 . 𝟏 𝟐 .1 𝒅ꞌꞌꞌ𝒚 𝒅ꞌꞌꞌ𝒙 = 0 = 𝒅 𝟒 𝒚 𝒅 𝟒 𝒙 = 0