This document provides instructions for homework assignments on scientific conversions and the scientific method. Students are asked to complete conversions between various units including feet to centimeters, grams to millimeters, Celsius to Kelvin, and Kelvin to Fahrenheit. They are also asked to calculate volume, pressure, and moles using given formulas and values. The document defines Avogadro's number as the number of molecules or atoms in a mole of substance, which is used to determine the number of moles from a given number of atoms.

1. Homework
2
Due:
Monday,
August
22nd,
2011
Conversions
and
Scientific
Method
Instructions:
FIRST:
Read
(Analyzing
Data)
Chapter
2
Sections:
1
and
2...
It
may
not
be
the
same
Chapter
in
your
book,
but
look
for
the
Analyzing
Data
Chapter.
SECOND:
Carefully
analyze
the
conversions
below,
follow
each
step
to
make
sure
it
has
been
done
correctly.
If
you
find
an
error
make
corrections
(Circle
the
error.
Then
do
the
problem
again
showing
all
of
your
work,
steps
followed
and
units,
with
the
correction
and
the
right
answer).
THIRD:
Do
the
conversions
showing
all
of
your
work:
steps
followed,
units,
formulas
and
conversions!
FOURTH:
Define
Avogadro’s
number
and
what
it’s
used
for.
***All
you
have
to
turn
in
are
the
corrections
and
the
THIRD
and
FOURTH
instructions.
***Showing
your
work
is
part
of
your
grade
and
you
will
get
credit
for
it!!!!
***There
is
a
conversion
chart
attached
at
the
end
of
the
document
for
you
to
use.
Problems:
1.
12
feet
to
centimeters
1
meter
=
39.307
inches
1
foot
=
12
inches
12
feet
x
12
inches
x
1
meter
100
cm
=
366.35
centimeters
1
foot
39.307
inches
1
meter
2.
1Gm
to
mm
1
Gigameter
=
109
meters
1
meter
=
1000
millimeters
1
Gm
x
109
meters
x
1
meter
1000000
millimeters
1
Gm
1000
millimeters
3.
450
Celsius
to
Kelvin
oC
=
K
-­‐
273
à
first
solve
for
K
I) K
=
oC
+
273
II) K
=
450
+
273
III) K
=
723
K
4.
278
K
to
F
OC
=
K
+
273

2. Homework
2
Due:
Monday,
August
22nd,
2011
F
=
1.8C
+
32
There
are
two
ways
to
solve
this
problem.
I) C
=
278
+
273
=
551O
C
II) F
=
1.8
(551)
+
32
III) F
=
1023.8
OF
OR
–
using
substitution
I) F
=
1.8
(K
+
273)
+32
II) F
=
1.8
(278
+
273)
+
31
III) F
=
1023.8
OF
5.
What
is
the
volume
of
a
substance
that
has
a
mass
of
34.5
grams
and
a
density
of
3.45
g/m3
in
in3
D
=
mass/volume
I) Solve
for
volume:
v
=
m/D
II) V
=
(34.5
g)
/
(3.45
g/
m3)
III) V
=
10
m3
IV) Now
convert
from
m3
to
in3
1
meter
=
39.307
inches
10
m3
x
39.307
in
=
393.07
in3
1
m
6.
What
is
the
mass,
in
slugs,
of
an
object
that
applies
a
pressure
of
600
Pa
on
a
table
that
is
2
decimeters
by
2
decimeters?
P
=
mass
x
acceleration/
area
I) First
write
down
the
information
you
have:
i. P
=
600
Pa
ii. Acceleration:
9.8m/s2
iii. Are
=
length
x
length
=
2
decimeters
x
2
decimeters
=
4
dm2
1. You
have
to
convert
from
decimeters
to
meters
because
Pascals
use
meters
NOT
decimeters.
Meters
is
the
SI
unit
deci
is
the
PREFIX.
(
1
meter
=
10
decimeters)
4dm2
x
12meter
=
0.04
m2
102decimeters
iv. Mass
=
?
II) Then
solve
for
mass
using
the
formula
for
Pressure:
i. Mass
=
P
x
area
/
acceleration

3. Homework
2
Due:
Monday,
August
22nd,
2011
ii. Mass
=
600
Pa
x
0.04m2/
9.8m/s2
iii. Mass
=
2.449
kilograms
III) Now
convert
from
kilograms
to
slugs
1
kilogram
=
0.0.685
slugs
2.449
kg
x
0.0685
slugs
=
0.1676
slugs
1
kg
7.
Convert
to
scientific
notation:
0.3050
Ans:
3.05
x
101
8.
Convert
to
scientific
notation:
234500000000
Ans:
2.345
x
1011
9.
How
many
moles
of
Carbon
are
in
4.34x1023
atoms
of
Carbon?
1
mole
=
6.023x1023
atoms
(This
is
called
Avogadro’s
number:
the
number
of
molecules
of
atoms
in
a
mole
of
matter)
4.34x1023
atoms
of
C
x
1
mole
=
0.723
moles
of
C
6.023x10 23
atoms
11.
How
many
atoms
of
Helium
are
in
2
moles
of
Helium?
1
mole
=
6.023x1023
atoms
(Avogadro’s
number)
2
mol
He
x
6.023x1023
atoms
He
=
12.023x1023
atoms
He
1
mol
He
Conversions:
Please
do
the
following
conversions
(Show
all
of
your
work:
steps
followed,
units,
conversions,
formulas!)
1. What
volume
is
occupied
by
16.4
g
of
mercury
in
cm3?
(The
density
of
mercury
is
13.6
g/mL).
2. What
is
the
mass,
in
slugs,
of
an
object
that
is
applying
a
pressure,
to
another
object,
of
9.45x104
Pa?
(Use
gravitational
acceleration
=
9.8m/s2)
3. 55mL
to
in3
4. 90
g/cm3
to
km3
5. Convert
these
two
numbers
to
scientific
notation:
a. 0.0000000056
b. 45682980.0