1. Different Resistor Types:
Carbon film resistors:
The size of the resistor decides its
power rating (i.e., the maximum power
it can dissipate without burning).
Power rating from the top of the graph:
1/8 W
1/4 W
1/2 W
Metal film resistors: Used when a higher tolerance (more accurate value) is needed.
Power rating from the top of the
graph:
1/8 W (tolerance ±1%)
1/4 W (tolerance ±1%)
1 W (tolerance ±5%)
2 W (tolerance ±5%)
Reading resistor values from the colored bands:
Single-In-Line (SIL) Resistor network:
3. Different Capacitor Types:
Ceramic Capacitors: Limited to quite small values, but have high voltage ratings.
They range from 1pF to 0.47μF and are not polarized.
Reading Ceramic Capacitor values:
For the
number :
Mult iply
by:
LETTER
TOLERANCE
1 0 pF or LESS
TOLERANCE
OVER 1 0 pF
0 1 B + / - 0.1pF
1 10 C + / -0.25pF
2 100 D + / - 0.5pF
3 1000 F + / - 1.0pF + / - 1%
4 10,000 G + / - 2.0pF + / - 2%
5 100,000 H + / - 3%
J + / - 5%
8 0.01 K + / - 10%
9 0.1 M + / - 20%
Example: 102 means 10 (and two zeroes) 00 or 1,000 pF or .001uF.
Electrolytic Capacitors (Electrochemical type capacitors): Used for all values above
0.1μF. Electrolytics have lower accuracy and temperature stability than most other
types and are almost always polarised. It's usually best to only use an electrolytic
when no other type can be used, or for all values over 100μF.
From the left to right:
1μF (50V)
47μF (16V)
100μF (25V)
220μF (25V)
1000μF (50V)
4. Tantalum Capacitors: Tantalum capacitors pack a large capacity into a relatively
small and tough package compared to electrolytics, but have much smaller voltage
ratings. They are often polarized and range from 0.1μF to 100μF.
From the left to right:
0.33 μF (35V)
0.47 μF (35V)
10 μF (35V)
Polyester Film Capacitors (Green Caps): Ranging from 0.01μF to 5μF. They are
similar to ceramics with some larger values and a slightly larger construction. They
are not polarized.
Metallized Polyester Film Capacitors:
SMD Capacitors:
Variable Capacitors:
5. Different Inductor Types:
Inductors:
Reading Inductor values from color codes:
High Frequency Coils (ferrite core):
The Toroidal Coil:
6. Other interesting components:
Diodes:
LED (Light Emitting Diodes):
Transistors:
ICs (Integrated Circuits):
Pin Numbers:
Multimeters (Analog and Digital):
7. K. S School of Engineering and Management
Department of Electronics and Communication Engineering
A LAB MANUAL ON
ANALOG ELECTRONICS
Subject Code: 10ESL37
(As per VTU Syllabus)
PREPARED BY
Staff members :
Gopalakrishna Murthy C R
Sanjay Naik
Vinay R
8. AEC LAB MANUAL
CONTENTS
EXPT.
NO.
NAME OF THE EXPERIMENT
PAGE
NO.
01
Testing of Half wave, full wave and bridge rectifier
circuits with and without Capacitor filter.
01
02
Testing of Clamping circuits for Positive and Negative
clamping
10
03
Testing of Diode Clipping circuits (Single/Double ended)
for peak clipping, peak detection.
16
04 RC coupled amplifier using BJT and FET 23
05
Testing for the performance of BJT- Hartley oscillator /
Colpitt’s oscillator for RF range fo > 100KHz.
31
06
Testing for the performance of BJT-Crystal oscillator for
fo > 100KHz.
38
07
Wiring and testing for the performance of BJT-RC
phase shift oscillator for fo < 10Khz.
41
08
Wiring of two stage BJT Voltage series feedback
amplifier
45
09
Verification of Thevenin’s theorem and maximum
power transfer theorem for DC circuits.
51
10 Characteristics of Series and parallel resonance circuits. 55
11
Wiring of BJT Darlington emitter follower with and without
bootstrapping
59
12
Testing of a transformer less Class-B push pull power
amplifier and determination of its conversion efficiency.
63
13 Bibliography 65
14 Vivo-voce questions 66
Dept. of ECE, KSSEM Page 1
9. AEC LAB MANUAL
Ex.No:01 HALF WAVE, FULL WAVE AND BRIDGE RECTIFIER
a) HALF WAVE RECTIFIER
AIM:
To study Half Wave Rectifier and to calculate ripple factor, efficiency and
regulation with filter and without filter.
COMPONENTS REQUIRED:
Sl. No. Components Details Range/Specification Qty
1. Diodes BY127/IN4007 1 No.
2. Capacitor 0.1μf, 100μf Each 1 No.
3. Power Resistance Board (DRB) - 1 No.
4. Step down Transformer 12 -0-12 1 No.
5. CRO, Multimeter, milli ammeter, Connecting Board, wires and etc.
THEORY:
Rectifier circuits are used to convert AC in DC. Half wave rectifier circuit
diode (rectifying element) conducts only during positive half cycle of input ac
supply. The negative half cycles of ac supply are eliminated from the output. The dc
output waveform is expected to be a straight line but the half wave rectifier gives
output in the form of positive sinusoidal pulses. Thus the output is called pulsating
dc.
In Full wave rectifier both positive and negative half cycles of AC inputs are
converted in to pulsating DC output. Capacitor is used as a filtering element to
remove ac components from output and to convert pulsating DC in to Constant DC .
CIRCUIT DIAGRAM:
a) HALF WAVE RECTIFIER WITHOUT FILTER CAPACITOR
C2
0.1μF
A K
BY127
RL
Step down
Transformer
AC
(230V/50HZ)
12V
0
12V
Ammeter(0-250mA)
A
+ -
VODC VOAC
Dept. of ECE, KSSEM Page 2
10. AEC LAB MANUAL
Note: connect Voltmeter/Multimeter across load Resistor to measure VODC and CRO
terminals to observe the output wave forms.
b) HALF WAVE RECTIFIER WITH FILTER CAPACITOR
Step down
Transformer
AC
(230V/50HZ)
DESIGN:
rms IN 12
V V
A K
Ammeter(0-250mA)
A
+ -
0.1μF BY127
12V
0
12V
V V V INpeak INrms 2 16.97
V V / 5.4V O DC m
Given V 5V O DC
C1
100μF
I 100mA O DC
R V /I 50 L O DC O DC
Ripple = r = Vo rms / VO DC = 1.21
Design for the filter capacitor
Ripple = 1/ (23 f C RL)
Given r = 0.25
C = 1/(23 f r RL)
RL = 50
f = 50Hz
=95.43F 100F
RL
+
-
VODC VOAC
Efficiency = output Power (PDC) /Input Power (PAC)
(I2
DC * RL) / [(Irms)2 * (RL + RF + Rs)]
≈ 2 (Vodc)2/(Vi rms)2 ≈ 40.6%
C2
Dept. of ECE, KSSEM Page 3
11. AEC LAB MANUAL
Where Irms = Im/2 & Im = Vm/( RL + RF + Rs)
V V
Regulation % Regulation = 100
NL FL
V
FL
Where VNL = Vo(dc) & VFL = Vo(dc) - Idc (Rf + Rs) or VFL = Idc * RL
Rf = Diode forward Resistance & Rs = Transformer Secondary Resistance.
PROCEDURE:
1. Connections are made as shown in the circuit diagram
2. Set say 100Ω in DRB and Switch on the AC power supply
3. Observe the wave form on CRO across the load resistor
4. Note down RL, IDC, VODC, VINrms, and VOrms in the tabular column for different load
resistances. Don’t set zero resistance in DRB at any time.
5. Calculate the ripple and efficiency and Regulation for each load resistance.
6. With C filter calculate regulation and Compare the ripple factor rtheoretical with
rpractical for the design values of RL and Capacitor.
TABULAR COLUMN:
Sl.
No.
RL IDC
VO
(DC)
VIN
(AC)
VO
(AC)
Ripple Efficiency Regulation
Result:
(Without filter) Ripple = rtheoretical = 1.21 rpractical =___
(With Filter) rtheoretical = 1/ (23 f C RL) = 0.25 for C= 100F, r practical =___
Ripple factor = rpractical = Vorms/ Vodc
Efficiency = theoritical = 40.6% practical ≈ [2 (Vodc)2]/(Vi rms)2
V V
Regulation = % Regulation = 100
NL FL
V
FL
Where VNL = no load voltage = voltage across output by removing load resistance.
VFL = Full load voltage = Voltage across output with load resistance.
Dept. of ECE, KSSEM Page 4
12. AEC LAB MANUAL
WAVEFORMS:
20
0 t
VIN
- 20
Vo (Without Filter)
VO
0 t
Vo (with filter)
0 t
FULL WAVE RECTIFIER
VC
AIM:
To study the full wave rectifier and to calculate ripple factor and efficiency
and Regulation with filter and without filter.
COMPONENTS REQUIRED:
Sl. No. Components Details Specification Qty
1. Diodes BY127/IN4007 2 Nos.
2. Capacitor 0.1μf, 470μf Each 1 No.
3. Power Resistance Board (DRB) 1 No.
4. Step down Transformer 12 V 1 No.
5. CRO, Multimeter, Milli ammeter, Connecting Board and etc.
THEORY:
The center tapped full wave rectifier circuit is similar to a half wave rectifier
circuit, using two diodes and a center tapped transformer. Both the input half cycles
are converted into unidirectional pulsating DC.
Dept. of ECE, KSSEM Page 5
13. AEC LAB MANUAL
CIRCUIT DIAGRAM:
FULL WAVE RECTIFIER WITHOUT FILTER CAPACITOR
C2
0.1UF
A K
BY127
RL
12V
0
12V
Transformer
Ammeter (0-250mA)
A
+ -
VO(DC)
A K
BY127
FULL WAVE RECTIFIER WITH FILTER CAPACITOR
Step down
AC
(230V/50HZ)
AC
Step down
Transformer
(230V/50HZ)
DESIGN:
12V
0
12V
Vin rms = 12V
V V V INpeak INrms 2 16.97
A K
A K
VO DC = 2Vm/ = 10.8V
Given VO DC = 10V
Ammeter (0-250mA)
A
+ -
BY127 0.1UF
C1
470UF
BY127
IO DC = 100mA
RL = VO DC / IO DC = 100
Ripple = r = Vo rms / VO DC = 0.48
Design for the filter capacitor
Ripple = 1/ (43 f C RL)
Given r =0 .06
C = 1/(43 f r RL)
VO (AC)
C2
RL
+
-
VO(DC)
VO(AC)
Dept. of ECE, KSSEM Page 6
14. AEC LAB MANUAL
RL = 100
f = 50Hz
C = 470UF
Efficiency = PDC /PAC (I2
DC * RL) / [(Irms)2 * (RL + RF +Rs)]
Where Irms = IM/√2 and IM = VM /(RL + RF +Rs)
Efficiency = ≈ (Vodc)2/(Vi rms)2
V V
Regulation % Regulation = 100
NL FL
V
FL
Note: repeat the same procedure of HWR for calculating Regulation .
PROCEDURE:
1. Connections are made as shown in the circuit diagram
2. Switch on the AC power supply
3. Observe the wave form on CRO across the load resistor and measure the o/p
amplitude and frequency.
4. Note down RL, IDC, VODC , Vinac, Voac in the tabular column for different load
resistances.
5. Calculate the ripple and efficiency and regulation for each load resistance.
6. Repeat the above procedure with filter capacitor.
TABULAR COLUMN:
Sl.
No.
RL IDC VO (DC)
VIN
(AC)
VO (AC) Ripple Efficiency Regulation
(Without filter) Ripple = rtheoretical = 0.48 rpractical =___
(With Filter) rtheoretical = 1/ (43 f C RL) = 0.06 for C= 470F, r practical =___
Ripple factor = rpractical = Vorms/ Vodc
Efficiency = theoritical = 81.2% practical ≈ (Vodc)2/(Vi rms)2
V V
Regulation = % Regulation = 100
NL FL
V
FL
Where VNL = no load voltage = voltage across output by removing load resistance.
VFL = Full load voltage = Voltage across output with load resistance.
Dept. of ECE, KSSEM Page 7
15. AEC LAB MANUAL
WAVEFORMS:
0 t
-
Vo (Without Filter)
0
t
Vo (with filter)
0 t
VIN
VO
VC
Dept. of ECE, KSSEM Page 8
16. AEC LAB MANUAL
BRIDGE RECTIFIER
AIM:
To study the bridge rectifier and to calculate ripple factor and efficiency and
regulation with filter and without filter.
COMPONENTS REQUIRED:
Sl. No. Components Details Specification Qty
1. Diodes BY127/IN4007 4 Nos.
2. Capacitor 0.1μf, 470μf Each 1 No.
3. Power Resistance Board (DRB) 1 No.
4. Step down Transformer 12 V 1 No.
5. CRO, Multimeter, Milliammeter, Connecting Board
THEORY:
The bridge rectifier circuit is essentially a full wave rectifier circuit, using four
diodes, forming the four arms of an electrical bridge. To one diagonal of the bridge,
the ac voltage is applied through a transformer and the rectified dc voltage is taken
from the other diagonal of the bridge. The main advantage of this circuit is that it
does not require a center tap on the secondary winding of the transformer; ac
voltage can be directly applied to the bridge.
The bridge rectifier circuit is mainly used as a power rectifier circuit for
converting ac power to dc power, and a rectifying system in rectifier type ac
meters, such as ac voltmeter in which the ac voltage under measurement is first
converted into dc and measured with conventional meter.
CIRCUIT DIAGRAM:
BRIDGE RECTIFIER WITHOUT FILTER CAPACITOR
RL
BRIDGE
1
- +
4
3
2
C2
0.1UF
Step down
Transformer
AC
(230V/50HZ)
12V
0
12V
Vo
Ammeter(0-250mA)
A
+ -
Dept. of ECE, KSSEM Page 9
17. AEC LAB MANUAL
BRIDGE RECTIFIER WITH FILTER CAPACITOR
Step down
Transformer
AC
(230V/50HZ)
DESIGN:
2
12V
0
12V
Vin rms = 12V
V V V INpeak INrms 2 16.97
BRIDGE
1
- +
4
3
Ammeter(0-250mA)
VO DC = 2Vm/ = 10.8V
Given VO DC = 10V and IO DC = 100mA
RL = VO DC / IO DC = 100
Ripple = r = Vo rms / VO DC = 0.48
Design for the filter capacitor
Ripple = 1/(43 f C RL)
Given r = .06
C = 1/(43 f r RL)
RL = 100 and f = 50Hz
C = 470UF
Efficiency
= PDC /PAC
= (I2
C1
470UF
+ A
-
+ -
DC * RL) / [(Irms)2 * (RL + RF)] OR = 0.812/(1+2Rf/ RL)
Where Irms = Im/2, & Im = Vm/(2Rf+RL)
V V
Regulation % Regulation = 100
NL FL
V
FL
RL
C2
0.1UF
Vo
Dept. of ECE, KSSEM Page 10
18. AEC LAB MANUAL
PROCEDURE:
1. Connections are made as shown in the circuit diagram
2. Switch on the AC power supply
3. Observe the wave form on CRO across the load resistor and measure the o/p
amplitude and frequency.
4. Note down RL, IDC, VODC , Vinac, Voac in the tabular column for different load
resistances.
5. Calculate the ripple factor, efficiency and regulation for each load resistance.
6. Repeat the above procedure with filter capacitor.
TABULAR COLUMN:
Sl.
No.
RL
IDC VO (DC)
VIN
(AC)
VO (AC) Ripple Efficiency Regulation
Calculations are same as FWR
WAVEFORMS:
Vin
20
t
0
- 20
Vo
Vo (Without Filter)
0 t
Vo (with filter)
VC
t
Observation and Result:
Dept. of ECE, KSSEM Page 11
19. AEC LAB MANUAL
DIODE CLAMPING CIRCUITS
AIM: Testing of clamping circuits: positive /negative clamping.
COMPONENTS REQUIRED:
Sl.No Component Range Quantity
1 Resistor 100K 1
2 Diode 1N4001 2
3 Capacitor 1μF 1
4 DC variable Power supply (0-30) V 1
5 DSO - 1
6 Function Generator - 1
7 Connecting Wires - 1 set
Theory:
Clamper is a circuit that clamps a signal to a different DC level without changing the shape of
the applied signal. Clamping circuit introduces a DC level into an ac signal. The different types
of clampers are positive, negative and biased clampers. A clamping network must have a
capacitor, a diode and a load resistor. The magnitude R and C must be chosen such that time
constant RC is large enough to ensure that the voltage across the capacitor does not discharge
significantly during the interval when the diode is non conducting. By connecting suitable Dc
voltage in series with the diode, clamping level can be varied.
The clamper with a positive DC shift is called positive clamper (Negative peak clamper) and a
clamper with a negative DC shift is called negative clamper (Positive peak clamper).
Positive Peak Clamper: This pushes down the DC the positive peak of the input signal to level
above or below the reference level depending upon the DC offset voltage.
Negative Peak Clamper: This pushes down the DC the negative peak of the input signal to level
above or below the reference level depending upon the DC offset voltage.
Design:
Assume C, and for the clamping to occur select R such that RC T, where T is the period of the
input signal.
RC T ; Assume T = 2ms, let RC = 50T = 100ms
Let R= 100K
C = 1μF
Dept. of ECE, KSSEM Page 12
20. AEC LAB MANUAL
Positive peak clamper (Positive Reference)
Design:
Assume Vin = 10VP-P, Vref = 2V, VK = 0.6V
8
7
6
5
4
3
2
1
0
-1
-2
-3
-4
-5
-6
-7
-8
vi
vo
0 90 180 270 360 450
a. During the positive half of the input signal diode is forward biased D = ON
Applying KVL to the loop
Vin – VC – VK – VR = 0
VC = Vin– VK – VR
VC = 5V – 0.6V – 2V
VC = 2.4V
b. During the negative half of the input signal diode is reverse biased D = OFF
Applying KVL to the loop
Vin – VC – VO = 0
VO = Vin – VC
When Vin = 0V VO = -2.4V
Vin = 5V VO = 2.4V
Vin = -5V VO = -7.6V
The output varies between +2.4V to -7.6V
Dept. of ECE, KSSEM Page 13
21. AEC LAB MANUAL
Positive peak clamper (Negative Reference)
Design:
Assume Vin = 10VP-P, Vref = 2V, VK = 0.6V
8
7
6
5
4
3
2
1
0
-1
-2
-3
-4
-5
-6
-7
-8
-9
-10
-11
-12
vi
vo
0 90 180 270 360 450
a. During the positive half of the input signal diode is forward biased D = ON
Applying KVL to the loop
Vin – VC – VK – VR = 0
VC = Vin– VK + VR
VC = 5V – 0.6V + 2V
VC = 6.4V
b. During the negative half of the input signal diode is reverse biased D = OFF
Applying KVL to the loop
Vin – VC – VO = 0
VO = Vin – VC
When Vin = 0V VO = -6.4V
Vin = 5V VO = -1.4V
Vin = -5V VO = -11.4V
The output varies between -1.4V to -11.4V
Dept. of ECE, KSSEM Page 14
22. AEC LAB MANUAL
Negative Peak Clamper (Negative Reference)
Design:
Assume Vin = 10VP-P, Vref = 2V, VK = 0.6V
10
9
8
7
6
5
4
3
2
1
0
-1
-2
-3
-4
-5
-6
vi
vo
0 90 180 270 360 450
a. During the negative half of the input signal diode is forward biased D = ON
Applying KVL to the loop
-Vin + VC + VK + VR = 0
VC = - (-Vin – VK – VR)
VC = - (-5V + 0.6V + 2V)
VC = 2.4V
b. During the positive half of the input signal diode is reverse biased D = OFF
Applying KVL to the loop
Vin + VC – VO = 0
VO = Vin + VC
When Vin = 0V VO = 2.4V
Vin = 5V VO = 7.4V
Vin = -5V VO = -2.4V
The output varies between -2.4V to 7.6V
Dept. of ECE, KSSEM Page 15
23. AEC LAB MANUAL
Negative Peak Clamper (Positive Reference)
Design:
Assume Vin = 10VP-P, Vref = 2V, VK = 0.6V
12
11
10
9
8
7
6
5
4
3
2
1
0
-1
-2
-3
-4
-5
-6
vi
vo
0 90 180 270 360 450
a. During the negative half of the input signal diode is forward biased D = ON
Applying KVL to the loop
-Vin + VC + VK – VR = 0
VC = - (Vin – VK – VR)
VC = - (-5V + 0.6V – 2V)
VC = 6.4V
b. During the positive half of the input signal diode is reverse biased D = OFF
Applying KVL to the loop
Vin + VC – VO = 0
VO = Vin + VC
When Vin = 0V VO = 6.4V
Vin = 5V VO = 11.4V
Vin = -5V VO = 1.4V
The output varies between 1.4V to 11.4V
Dept. of ECE, KSSEM Page 16
24. AEC LAB MANUAL
Procedure:
1. Connect the circuit as shown in the figure.
2. Switch on the variable DC power supply, keeping voltage knobs at minimum position
and current knobs at maximum position and set reference voltage value.
3. Apply square wave or sine wave as an input signal at frequency say 1KHz and voltage
10V (p-p)
4. Observe the input and output waveforms on the CRO/DSO.
5. Vary the voltage and observe the clamping level of the output signal and note down the
value of clamping level.
Result:
Dept. of ECE, KSSEM Page 17
25. AEC LAB MANUAL
DIODE CLIPPING CIRCUITS
AIM:
Testing Of diode clipping (Single and Double Ended) circuits for peak clipping.
COMPONENTS REQUIRED:
Sl.No Component Range Quantity
1 Resistor 10K 1
2 Diode 1N4001 2
3 DC variable Power supply (0-30) V 1
4 DSO - 1
5 Function Generator - 1
6 Connecting Wires - 1 set
Clippers:
Clipping is defined as removing some part of the a.c signal without affecting the other parts of
the a.c signal. This kind of processing is useful in wave shaping, circuit protection and
communications. Clipper circuit are also called limiter circuit, are used to eliminate portions of
that are above or below a specified level. A simple application of a clipper is to limit the voltage
at the input to the electronic circuit so as to prevent the breakdown of the transistor in the circuit.
The circuit can be used to measure the frequency of the signal, so the amplitude is not an
important part of the signal.
Types of clipper circuits:
1. Series Clipper (Single ended and double ended)
2. Parallel Clipper (Single ended and double ended)
Design of R
The Value of R should be chosen as geometric mean of Rf and Rr of diode. Where Rf represents
dynamic forward resistance and Rr represents reverse resistance of the diode.
R = √ Say, Rf = 100Ω, Rr = 1MΩ, then R= 10KΩ.
Dept. of ECE Page 18
26. AEC LAB MANUAL
PARALLEL CLIPPERS (SINGLE ENDED)
PARALEL POSITIVE CLIPPER
Assume
6
5
4
3
2
1
0
-1
-2
-3
-4
-5
-6
vi
vo
0 90 180 270 360 450 540 630 720 810
Vi = 10VP-P, R = 10K, Vref = 1.4, VK = 0.6V Calculate VO.
Case 1: Case 1:
When Vi ≥ Vref + VK D = ON When Vi ≥ 1.4V + 0.6V D = ON
VO = Vref + VK VO = 1.4V + 0.6V
VO = 2V
Case 2: Case 2:
When Vi < Vref + VK D = OFF When Vi < 1.4V + 0.6V D = OFF
VO = Vi VO = Vi
TRANSFER CAHARACTERISTICS
3
2
1
0
-6 -4 -2 0 2 4 6
-1
-2
-3
-4
-5
-6
Dept. of ECE Page 19
27. AEC LAB MANUAL
PARALLEL NEGATIVE CLIPPER
Assume
6
5
4
3
2
1
0
-1
-2
-3
-4
-5
-6
vi
vo
0 90 180 270 360 450 540 630 720 810
Vi = 10VP-P, R = 10K, Vref = 1.4, VK = 0.6V Calculate VO.
Case 1: Case 1:
When Vi - [Vref + VK] D = ON When Vi - [1.4V+ 0.6V] D = ON
VO = - [Vref + VK] VO = - [1.4V+ 0.6V]
VO = - 2V
Case 2: Case 2:
When Vi - [Vref + VK] D = OFF When Vi - [1.4V+ 0.6V] D = OFF
VO = Vi VO = Vi
TRANSFER CHARACTERISTICS
6
5
4
3
2
1
0
-6 -4 -2 0 2 4 6
-1
-2
-3
Dept. of ECE Page 20
28. AEC LAB MANUAL
SERIES POSITIVE CLIPPERS
Assume
6.00
5.00
4.00
3.00
2.00
1.00
0.00
-1.00
-2.00
-3.00
-4.00
-5.00
-6.00
Vi
VO
0 90 180 270 360 450 540 630 720 810
Vi = 10VP-P, R = 10K, Vref = 2V, VK = 0.6V Calculate VO.
Case 1: Case 1:
When Vi [VR - VK] D = ON When Vi [2V-0.6V] D = ON
VO = Vi + VK VO = - 4.3V
Case 2: Case 2:
When Vi > [VR - VK] D = OFF When Vi > [VR - VK] D = OFF
VO = Vref VO = 2V
TRANSFER CHARACTERISTICS
3.00
2.00
1.00
0.00
-6.00 -4.00 -2.00 0.00 2.00 4.00 6.00
-1.00
-2.00
-3.00
-4.00
-5.00
Dept. of ECE Page 21
29. AEC LAB MANUAL
SERIES NEGATIVE CLIPPER
Assume
6
5
4
3
2
1
0
-1
-2
-3
-4
-5
-6
VI
VO
0 90 180 270 360 450 540 630 720 810
Vi = 10VP-P, R = 10K, Vref = 2V, VK = 0.6V Calculate VO.
Case1:
When Vi -[ VR - VK] D = ON
VO = Vi - VK
Case 2:
When Vi -[ VR - VK] D = ON
VO = VR
TRANSFER CHARACTERISTICS
6.00
5.00
4.00
3.00
2.00
1.00
0.00
-6.00 -4.00 -2.00 0.00 2.00 4.00 6.00
-1.00
-2.00
-3.00
Dept. of ECE Page 22
30. AEC LAB MANUAL
PARALLEL CLIPPING (DOUBLE ENDED)
Assume
6
5
4
3
2
1
0
-1
-2
-3
-4
-5
-6
vi
vo
0 90 180 270 360 450 540 630 720 810
Vi = 10VP-P, R = 10K, Vref1 = 1.4V, Vref2 = 1.4V, VK = 0.6V Calculate VO.
Case1: Case 1:
When Vi [VRef1 + VK] When Vi [1.4V + 0.6V]
VO = [VRef1 + VK] VO = 2V
Case 2: Case 2:
When Vi [VRef2 + VK] When Vi [1.4V + 0.6V]
VO = - [VRef2 + VK] VO = - 2V
Case 3: Case 3:
When - [VRef2 + VK] Vi < [Vref1 + VK] When - [1.4V + 0.6V] Vi < [1.4V + 0.6V]
VO = Vi VO = Vi
TRANSFER CHARACTERISTICS
3
2
1
0
-6 -4 -2 0 2 4 6
-1
-2
-3
Dept. of ECE Page 23
31. AEC LAB MANUAL
SERIES CLIPPING (DOUBLE ENDED)
Assume
6
5
4
3
2
1
0
-1
-2
-3
-4
-5
-6
vi
vo
0 90 180 270 360 450 540 630 720 810
Vi = 10VP-P, R = 10K, Vref1 = 1.4V, Vref2 = 1.4V, VK = 0.6V Calculate VO.
Case 1: Case 1:
When Vi [VRef1 + VK] D = ON When Vi [2V + 0.6V] D = ON
VO = Vi - VK - VR VO = 5V - 0.6V - 1.4V VO = 3V
Case 2: Case 2:
When Vi [VRef1 + VK] D = OFF When Vi [VRef1 + VK] D = OFF
VO = Vi - VK - VR VO = -5V + 0.6V + 1.4V
VO = - 3V
TRANSFER CHARACTERISTICS
4
3
2
1
0
-6 -4 -2 0 2 4 6
-1
-2
-3
-4
Dept. of ECE Page 24
32. AEC LAB MANUAL
RC COUPLED BJT AMPLIFIER
AIM:
Wiring of RC coupled single stage BJT amplifier and determination of the gain frequency
response, input and output impedance.
COMPONENTS REQUIRED:
Sl.No Components Range Quantity
1 Transistor SL-100 1
2 Resistors 22K,2.2K,4.7K,470Ω 1
3 Capacitors 0.47μF,47μF
0.47 μF =2
47 μF=1
4 Variable power supply (0-30)V 1
5 DSO - 1
6 Function Generaator - 1
7 Connecting wires - 1 set
THEORY:
A common emitter amplifier is defined as an electronic circuit with an ac input voltage applied
across the base and emitter pins of a bipolar junction transistor with the output voltage taken as
the voltage from the collector pin to ground. As the name suggests, the emitter is connected to a
reference ground. RC coupled amplifier is the one which amplifies the given small signal.
Basically it is the multi stage amplifier which usually has two or more stages.
In each stage, there will be there would be a CE amplifier present whose output is given as the
input to the next stage. The function of the input capacitor is to block the base from any DC shift
caused by the input signal. Allowing a DC shift to be felt at the base would continuously change
the Q point of the amplifier, resulting in erratic effects on the amplifier’s output voltage.
The input capacitor must allow all the ac signal components through. The function of the output
capacitor is to block the collector from DC shift that might be caused by the load. Failure to do
so would result in a Q-point shift. The bypass capacitor is used to short out the emitter resistor
during ac operation.
The two values of frequency for which the voltage gain of about 0.707 times the peak voltage
gain are called the low and high frequency roll-off. These correspond to the minimum and
maximum frequencies for the power carried by the signal is at most a factor of two smaller than
the maximum. Hence, the difference between the two frequencies is called the half power
bandwidth.
Dept. of ECE, KSSEM Page 25
33. AEC LAB MANUAL
CIRCUIT DIAGRAM:
Amplifier Design:
Select transistor SL-100 having the following specifications IE = IC = 2mA, β = 100, VCE = 5V
Selection of RE
VCC = 10V; VE =
; VE =
= 1V
VE = IERE; RE =
; RE =
= 0.5K; Select RE = 470Ω;
Selection of RC:
VCE =
; VCE =
= 5V
VCE = ICRC + VCE + VE
RC =
RC = 2KΩ; Select RC = 2.2K Ω;
Dept. of ECE, KSSEM Page 26
34. AEC LAB MANUAL
Selection of R1 and R2:
VB = VBE + VE; VB = 1.7V;
VB =
1.7V =
10R2 = 1.7R1 + 1.7 R2; R1 = 4.8R2;
Choose R2 = 4.7KΩ; R1 = 4.8 4.7K;
R1 = 22.56KΩ
Choose R1 = 22KΩ
Selection of bypass capacitor CE:
Let XCE =
; At f = 100Hz,
=
CE = 59 F; Choose CE = 47 F
Selection of Coupling Capacitors:
Select CC1 = CC2 = 0.47 F
Procedure:
1. Connections are made as shown in the circuit diagram.
2. The input voltage Vin is adjusted to a convenient value (10mV to 50mV) within the
distortion less limit and value must be kept constant throughout the experiment.
3. Frequency of the input signal is varied from 100Hz to 2MHz in steps and at each step,
corresponding output VO is noted down.
4. All readings are tabulated and graph of voltage gain in dB Vs frequency is drawn on a
Semi-log sheet.
5. 3dB bandwidth is determined from the frequency response curve.
Dept. of ECE, KSSEM Page 27
35. AEC LAB MANUAL
TABULAR COLUMN:
Frequency in Hz VO in Volts Gain in dB= 20log10(VO/Vin)
100Hz
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
2MHz
Input Impedance
Procedure:
1. A DRB is connected in series with the input as shown in the figure.
2. In the mid frequency region (with constant gain) with zero resistance (all the knobs of the
DRB in zero position) the output is measured.
3. Now the DRB resistance is increased till the output voltage falls to half of the initial
value.
4. The corresponding DRB value gives the input impedance of the circuit.
Dept. of ECE, KSSEM Page 28
36. AEC LAB MANUAL
Output impedance
Procedure:
1. A DRB is connected in series with the input as shown in the figure.
2. In the mid frequency region (with constant gain) with maximum resistance (all the knobs
of the DRB in maximum position) the output is measured.
3. Now the DRB resistance is decreased till the output voltage falls to half of the initial
value.
4. The corresponding DRB value gives the output impedance of the circuit
RESULT:
Gain AV
Bandwidth
Input impedance Zi
Output impedance ZO
Dept. of ECE, KSSEM Page 29
37. AEC LAB MANUAL
HARTLEY OSCILLATOR
AIM: Testing for the performance of BJT Hartley oscillator for fo =100KHz.
COMPONENTS REQUIRED:
Sl.No Components Range Quantity
1 Transistor SL-100 1
2 Resistors 22K,2.2K,4.7K,1K,470Ω, 1K POT 1
3 Capacitors 0.47μF,47μF
0.47 μF =2
47 μF=1
4 Variable power supply (0-30)V 1
5 DSO - 1
6 Function Generaator - 1
7 Connecting wires - 1 set
8 Decade Inductance box - 1
9 Decade Capacitane box - 1
THEORY:
When the collector supply voltage Vcc is switched on, collector current starts rising and charges
the capacitor C. When this capacitor is fully charged, it discharges through coils L1 and L2,
setting up damped harmonic oscillations in the tank circuit. The oscillatory current in the tank
circuit produces an a.c. voltage across L1 which is applied to the base emitter junction of the
transistor and appears in the amplified form in the collector circuit.
Feedback of energy from output (collector emitter circuit) to input (base-emitter circuit is)
accomplished through auto transformer action. The output of the amplifier is applied across the
inductor L1, and the voltage across L2 forms the feedback voltage. The coil L1, is inductively
coupled to coil L2, and the combination acts as an auto-transformer.
This energy supplied to the tank circuit overcomes the losses occurring in it. Consequently the
oscillations are sustained in the circuit. The energy supplied to the tank circuit is in phase with
the generated oscillations. The phase difference between the voltages across L1 and that across
L2 is always 180° because the centre of the two is grounded. A further phase of 180° is
introduced between the input and output voltages by the transistor itself. Thus the total phase
shift becomes 360O (or zero), thereby making the feedback positive or regenerative which is
essential for oscillations.
Dept. of ECE, KSSEM Page 30
39. AEC LAB MANUAL
R2 =
=
=
=
= 4.7KΩ.
R1 =
=
=
=
= 22KΩ.
Design of Tank Circuit:
Let fo = 100KHz
Choose L1 = 200 μH, L2 = 600 μH
Choose fo =
√
Calculate C = ?
C = 330 μF
PROCEDURE:
1. Connections are made as shown in the circuit diagram.
2. Measure the DC conditions.
3. Vary the 1K potentiometer so as to get an undistorted sine wave at the output.
4. Note down the amplitude and frequency of the output wave and frequency haas to match
with the theoritical frequency.
RESULT:
Frequency = Hz.
Amplitude = V.
Dept. of ECE, KSSEM Page 32
40. AEC LAB MANUAL
COLPITTS OSCILLATOR
AIM: Testing for the performance of BJT Colpitts oscillator for fo =100KHz.
COMPONENTS REQUIRED:
Sl.No Components Range Quantity
1 Transistor SL-100 1
2 Resistors 22K,2.2K,47K,1K, 470Ω,1K, POT 1
3 Capacitors 0.47μF,47μF
0.47 μF =2
47 μF=1
4 Variable power supply (0-30)V 1
5 DSO - 1
6 Function Generaator - 1
7 Connecting wires - 1 set
8 Decade Inductance box - 1
9 Decade Capacitance box - 1
THEORY:
The Colpitt’s oscillator is designed for generation of high frequency sinusoidal oscillations (radio
frequencies ranging from 10 KHz to 100MHz). They are widely used in commercial signal
generators up to 100MHz. Colpitt's oscillator is same as Hartley oscillator except for one
difference. Instead of using a tapped inductance, Colpitt's oscillator uses a tapped capacitance.
When the collector supply voltage Vcc is switched on, collector current starts rising and charges
the capacitors C1 and C2. When these capacitors are fully charged, they discharge through coil L
setting up damped harmonic oscillations in the tank circuit. The oscillatory current in the tank
circuit produces an a.c. voltage across C1, C2. The oscillation across C2 is applied to base-emitter
junction of the transistor and appears in the amplified form in the collector circuit and
overcomes the losses occurring in the tank circuit.
The feedback voltage (across the capacitor C2) is 180° out of phase with the output voltage
(across the capacitor C1), as the centre of the two capacitors is grounded. A phase shift of 180° is
produced by the feedback network and a further phase shift of 180° between the output and input
voltage is produced by the CE transistor. Hence, the total phase shift is 360° or 0°, which is
essential for sustained oscillations, as per, the Barkhausen criterion.
Dept. of ECE, KSSEM Page 33
42. AEC LAB MANUAL
R2 =
=
=
=
= 4.7KΩ.
R1 =
=
=
=
= 22KΩ.
DESIGN OF TANK CIRCUIT:
Let fo = 100KHz
Choose C1 = C2 = 1000pF
fo =
√
Calculate L = ?
L= 5mH
PROCEDURE:
1. Connections are made as shown in the circuit diagram.
2. Measure the DC conditions.
3. Vary the 1K potentiometer so as to get an undistorted sine wave at the output.
4. Note down the amplitude and frequency of the output wave and frequency haas to match
with the theoritical frequency.
RESULT:
Frequency = Hz.
Amplitude = V.
Dept. of ECE, KSSEM Page 35
43. AEC LAB MANUAL
BJT-CRYSTAL OSCILLATOR
AIM: Testing for the performance of the BJT- crystal oscillator for fo > 500KHz.
COMPONENTS REQUIRED:
Sl.No Components Range Quantity
1 Transistor SL-100 1
2 Crystal 2MHz 1
3 Resistors 22K, 2.7K, 47K, 470Ω, 1K POT 1
4 Capacitors 0.47μF, 47 μF
0.47 μF =2
47 μF=1
5 Variable power supply (0-30)V 1
6 Function Generator - 1
7 DSO - 1
8 Connecting wires - 1set
THEORY:
A crystal oscillator is basically a tuned oscillator using a pizeoelectric crystal asa resonant
circuit. The crystal has a greatest stability in holding consant charge at whatever frequency the
crystal is originally cut to operate. Crystal oscillators are used whenever great stability is
required, such as communication, transmitters and recievers.
Characteristics of a Quartz crystal
A quartz crystal exihibits the property that whenever mechanical stress is applied across one set
of its faces, a difference os potential develops acoss the opposite faces. This property of a crystal
is called pizeoelectric effect. Similarly, a voltage applied across one set of faces of the crystal
causes mechanical distortion in the cryatal shape. When alternating voltage is applied to a
crystal, mechanical vibrations are set up- these vibrations having a natural resonating frequency
dependent on the crystal.
The inductor L and the cappacitor C represents electrical equivalents of crystal mass and
compliance respectively, whereas resistance R is an electrical equivalent of the crystal structures
internal friction. The shunt capacitance CM represents the capacitance due to mechanical
mounting of the crystal. Because the crystal loses, represented by R, are small, the equivalent
cryatal Q factor is high typically 20,000. Values of Q up to almost 106 can be achieved by using
crystals. The crystal has two resonant frequencies. One resonant condition occurs when the
reactances of the series RLC leg are equal.
Depat. Of ECE, KSSEM Page 36
45. AEC LAB MANUAL
R2 =
=
=
=
= 4.7KΩ.
R1 =
=
=
=
= 22KΩ.
PROCEDURE:
1. Connections are made as shown in the circuit diagram.
2. Measure the DC conditions.
3. Vary the 1K potentiometer so as to get an undistorted sine wave at the output.
4. Note down the amplitude and frequency of the output wave and frequency haas to match
with the theoritical frequency.
RESULT:
Frequency = Hz.
Amplitude = V.
Depat. Of ECE, KSSEM Page 38
46. AEC LAB MANUAL
RC PHASE SHIFT OSCILLATOR
AIM: To generate the sinusoidal waveform of RF range using RC phase shift oscillator.
COMPONENTS REQUIRED:
Sl.No Components Range Quantity
1 Transistor SL-100 1
2 Resistors 22K,2.2K,47K,1K,1K and 10K POT
2.2K=4,
Others=1
3 Capacitors 0.47μF, 0.02μF
0.47 μF =2
47 μF=1
4 Variable power supply (0-30)V 1
5 DSO - 1
6 Function Generator - 1
7 Connecting wires - 1 set
.
THEORY:
The RC Oscillator which is also called a Phase Shift Oscillator produces a sine wave output
signal using regenerative feedback from the resistor-capacitor combination. This regenerative
feedback from the RC network is due to the ability of the capacitor to store an electric charge,
(similar to the LC tank circuit). This resistor-capacitor feedback network can be connected as
shown in the figure to produce a leading phase shift (phase advance network) or interchanged to
produce a lagging phase shift (phase retard network) the outcome is still the same as the sine
wave oscillations only occur at the frequency at which the overall phase-shift is 360o. By varying
one or more of the resistors or capacitors in the phase-shift network, the frequency can be varied
and generally this is done using a 3-ganged variable capacitor.
Since the resistor-capacitor combination in the RC Oscillator circuit also acts as an attenuator
producing an attenuation of -1/29th (Vo/Vi = β) per stage, the gain of the amplifier must be
sufficient to overcome the losses and in our three mesh network above the amplifier gain must be
greater than 29. The loading effect of the amplifier on the feedback network has an effect on the
frequency of oscillations and can cause the oscillator frequency to be up to 25% higher than
calculated. Then the feedback network should be driven from a high impedance output source
and fed into a low impedance load such as a common emitter transistor amplifier but better still
is to use an operational amplifier as it satisfies these conditions perfectly.
Dept. of ECE, KSSEM Page 39
48. AEC LAB MANUAL
VR2 = VBE – VBE = 1V + 0.6V = 1.6V & VR1 = VCC - VR2 = 10 – 1.6V = 8.4V
R2 =
=
=
=
= 4.7KΩ.
R1 =
=
=
=
= 22KΩ.
FEEDBACK CIRCUIT DESIGN:
If the frequency for the RC phase shift oscillator is say, 1 KHz, Then,
fo =
√ = 1KHz
Where k
, Choose k=1, so RC = R = 2.2KΩ. Substituting these values in the frequency
equation, we get C = 0.022μF.
The current gain of the transistor, β 4K + 23 +
PROCEDURE:
1. Connections are made as shown in the circuit diagram.
2. Measure the DC conditions.
3. Observe the sinusoidal waveform output and calculate the frequency using CRO/DSO.
4. Measure the phase difference between the output and at points A,B,C.
5. To observe the phase difference between the signals connect the output of the amplifier to
channel1 of the CRO/DSO and connect A or B or C to channel2 of the CRO/DSO.
6. Go to X-Y mode to observe the Lissajous figure, and also to measure the phase difference
between the output and A or B or C.
RESULT:
Dept. of ECE, KSSEM Page 41
49. AEC LAB MANUAL
VOLTAGE SERIES FEEDBACK AMPLIFIER
AIM:
To conduct an experiment on two-stage BJT small signal amplifier (with and without feedback).
COMPONENTS AND EQUIPMENTS REQUIRED:
Sl.No Components Range Quantity
1 Transistor SL-100 1
2 Resistors 22K,10K,2.2K,4.7K,470Ω,390 Ω,100 Ω 2
3 Capacitors 0.47μF,47μF
0.47 μF =3
47 μF=2
4 Variable power supply (0-30)V 1
5 DSO - 1
6 Function Generaator - 1
7 Connecting wires - 1 set
THEORY:
Feedback plays an important role in electronic circuits and the basic parameters such as input
impedance, output impedance, voltage or current gain and band width, may be altered
considerably in a desired direction by the use of feedback for a given amplifier. In any of the
feedback amplifiers, a part of the output signal is taken from the output of the amplifier and is
combined with the normal input signal and thereby the feedback is achieved. If the signal
feedback is aid the input signal, then it is said to positive feedback and if it is opposing, it is said
to be the negative feedback. Positive feedback is used in oscillators and negative feedback is
used wherever the gain has to be stabilized, bandwidth is to be increased and distortion has to be
reduced. There are four types of negative feedback amplifiers depending the input signal and
output signal that is feedback.
1. Voltage- series feedback
2. Voltage-shunt feedback
3. Current-series feedback
4. Current-shunt feedback
Voltage-Series Feedback Amplifier: In
this case, the part of the output voltage for the amplifier is feedback, which is in series opposition
with input. This reduces the gain, but stabilizes it. Also the input impedance and bandwidth
increases and output impedance decreases.
Dept. of ECE Page 42
50. AEC LAB MANUAL
CIRCUIT DIAGRAM
Fig: Voltage Series amplifier without feedback
Fig: Voltage Series amplifier with feedback
Dept. of ECE Page 43
51. AEC LAB MANUAL
Amplifier design:
It remains same as given for RC-coupled amplifier.
Here β =
=
=
, called as feedback factor.
Select RE = 390Ω; RE11 = 100Ω; RF = 10KΩ
PROCUDURE:
1. Connect the circuit as shown in the figure. Set the signal generator amplitude to 10mV
peak to peak sine waveform and observe the input and output signals of the circuit
simultaneously on the CRO/DSO.
2. By varying the frequency of the input from 100Hz to 2MHz range correspondingly note
down the output voltage.
3. Plot the gain in dB against frequency in a semi log graph sheet.
4. From the graph determine the bandwidth.
5. Repeat the same procedure for with feedback case also.
6. Calculate the input and output impedance in both the cases.
TABULAR COLUMN
F in Hz VO(P-P) in V AV =
Voltage gain in
dB = 10log10AV
Dept. of ECE Page 44
52. AEC LAB MANUAL
RESULT:
Gain AV without Feedback
Gain AV with Feedback
Bandwidth without Feedback
Bandwidth with Feedback
Input impedance Zi without feedback
Input impedance Zi with feedback
Output impedance ZO without feedback
Output impedance ZO with feedback
Dept. of ECE Page 45
53. AEC LAB MANUAL
THEVENIN’S AND MAXIMUM POWER TRANSFER THEOREM
AIM:
To verify Theveinin’s theorem.
COMPONENTS REQUIRED:
Sl. No Components Range Quantity
1 Resistors 1K 4
2 DC variable Power supply (0-30) V 1
3 Multimeter - 1
4 Connecting Wires - 1 Set
5 DRB - 1
THEVENIN’S THEOREM:
Statement: “Any linear, bilateral network containing energy sources and impedances can be
replaced with equivalent circuit consisting of a Voltage Source in series with Impedance”.
THEORY:
M Leon Thevenin a French engineer in 1863 developed the most important theorem of all
network theorems. Using Thevenin’s theorem any complex network can be replaced by a simple
equivalent circuit. The new simple single loop equivalent circuit enables us to make rapid
calculations of the current, voltage and power delivered to the load by the original network. It
also helps us to find the best value of load resistance needed for a particular application.
CIRCUIT DIAGRAM:
Given complex circuit
Fig. (1)
Measure the voltage across Load Resistance RL, i.e. across A and B and call that voltage as V1.
V1 =V.
Dept. of ECE, KSSEM Page 46
54. AEC LAB MANUAL
Step 1: Equivalent Circuit to find VTH by opening Load Resistance RL across A and B
Fig. (2)
Measure the voltage across A and B and call that voltage as VTH.
VTH =______V.
Step 2: Equivalent Circuit to find RTH by removing RL across A and B and shorting the
supply voltage.
Fig. (3)
Measure the Resistance across A and B and call that Resistance as RTH.
RTH =_____Ω.
Step3: Thevenin’s Equivalent circuit
Fig. (4)
Dept. of ECE, KSSEM Page 47
55. AEC LAB MANUAL
Measure the voltage across A and B and call that voltage as V2.
V2 =_____V.
If the voltage,V1 = V2, then Thevinin’s theorem is verified.
THEORETICAL CALCULATION:
VTH=
RTH =
+R2
PROCEDURE:
1. Connections are made as shown in fig. (1).
2. Keep the voltage knobs at minimum position and Current knobs at Maximum position
and then switch on the power supply and adjust the voltage to say 5 Volts.
3. Measure the voltage across RL and note down as V1 from fig. (1).
4. To measure VTH, Open circuits the load resistor RL as shown in fig. (2), measure the
voltage across terminal A and B, call that voltage as VTH.
5. To find the Thevinin’s impedance (RTH) measure the resistance between the terminals A
and B after shorting the supply voltage as shown in fig. (3).
6. Thevinin’s equivalent circuit connections are made by setting supply voltage to VTH and
decade resistance box to RTH and connect back the load resistor RL across A and B as
shown in Fig. (4).
7. Now measure the Voltage across load resistor RL with respect to Thevinin’s equivalent
circuit. i.e. V2
8. Verify the voltages V1 and V2.
RESULT:
Voltage across the load resistor RL with respect to complex circuit = V.
Voltage across the load resistor RL with respect to Thevinin’s equivalent circuit = V.
Dept. of ECE, KSSEM Page 48
56. AEC LAB MANUAL
MAXIMUM POWER TRANSFER THEOREM
AIM: To verify maximum power transfer theorem.
COMPONENTS REQUIRED:
Sl No Components Range Quantity
1 Resistors 1.5 K 1
2 DC variable Power
supply
(0-30) V 1
3 Multimeter - 1
4 Connecting Wires - 1 Set
5 DRB - 1
MAXIMUM POWER TRANSFER THEOREM:
Statement: Maximum power is delivered from a network to a load when the load resistance is
equal to the Thevenin’s resistance of the network.
THEORY:
In many practical applications a circuit is designed to supply power to the load. For example in
communication systems, antennas supply power to receivers, audio amplifiers supply power to
load speakers, transmitters supply power to loads. Maximum power transfer theorem plays an
important role in matching circuit’s loads.
CIRCUIT DIAGRAM:
Given complex circuit
Fig. (1): Complex Network
Dept. of ECE, KSSEM Page 49
57. AEC LAB MANUAL
Thevinin’s Equivalent circuit
Fig. (2): Thevinin’s Network
THEORITICAL CALCULATION:
VTH =
= 5V
RTH =
= 500Ω
PROCEDURE:
1. The resistance value in DRB is varied and the Voltage is noted down.
2. Connections are made as shown in the figure.
3. The power P is calculated using P= V2/RL.
4. A graph of load resistance Vs Power is plotted.
5. The maximum power occurs when RL = RS.
POWER Vs LOAD RESISTANCE CURVE:
P
Fig (3): Graph of Power v/s RL
Dept. of ECE, KSSEM Page 50
58. AEC LAB MANUAL
TABULAR COLUMN
RL in Ω VO in Volts P = V2/RL (mW)
100 Ω
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
1K Ω
RESULT:
Dept. of ECE, KSSEM Page 51
59. AEC LAB MANUAL
CHARACTERISTICS OF RESONANT CIRCUITS
AIM: To obtain the frequency response of RLC series and parallel resonant circuits and hence to
determine bandwidth and Q-factor.
COMPONENTS REQUIRED:
Sl.No Components Range Quantity
1 Resistors 1KΩ 1
2 DSO - 1
3 Decade Capacitance Box - 1
4 Decade Inductance Box - 1
5 Function Generator - 1
6 Connecting wires - 1 set
.
THEORY:
In a circuit containing capacitive and inductive components, the impedance of the circuit varies
as the applied voltage’s frequency is varied. At one point of frequency, the impedance offered by
the circuit will be purely resistive and so the current in the circuit and applied voltage will be in
phase. This phenomenon is called resonance and the frequency which causes resonance is called
resonant frequency.
SERIES RESONANCE CIRCUIT:
Dept. of ECE, KSSEM Page 52
60. AEC LAB MANUAL
DESIGN:
fo =
√
Let fo = 800Hz
Assume R = 1KΩ
C = 0.1μF
Calculate L value
L = 395.7mH
PROCEDURE:
1. Connections are made as shown in the circuit diagram.
2. AC supply is switched on. Input voltage is adjusted to 10VP-P.
3. The frequency is gradually varied from 100Hz to 2KHz. Different values of ‘f’ using
DSO and voltage is noted down. The results are tabulated in the tabular column.
4. Frequency response i.e a graph of frequency Vs current is drawn.
5. From the graph, resonant frequency fO is noted down at which current is maximum.
6. Lower half frequency and upper half frequency are noted down corresponding to a
current of IO/√ . Bandwidth = f2 – f1 = Hz.
7. Q-factor = f2/(f2-f1).
TABULAR COLUMN
Frequency in
Hz
Output Voltage VO
(V)
Dept. of ECE, KSSEM Page 53
61. AEC LAB MANUAL
FREQUENCY RESPONSE CURVE
VO (V)
F (Hz)
Fig: Graph of Voltage Vs Frequency
RESULT:
Resonant Frequency =
Bandwidth =
Upper and lower half frequencies =
Q-factor =
Dept. of ECE, KSSEM Page 54
62. AEC LAB MANUAL
PARALLEL RESONANCE CIRCUIT:
:
DESIGN:
fo =
√
Let fo = 800Hz
Assume R = 1KΩ
C = 0.1μF
Calculate L value
L = 395.7mH
PROCEDURE:
1. Connections are made as shown in the circuit diagram.
2. AC supply is switched on. Input voltage is adjusted to 10VP-P.
3. The frequency is gradually varied from 100Hz to 2KHz. Different values of ‘f’ using
DSO and voltage is noted down. The results are tabulated in the tabular column.
4. Frequency response i.e a graph of frequency Vs current is drawn.
5. From the graph, resonant frequency fO is noted down at which current is maximum.
6. Lower half frequency and upper half frequency are noted down corresponding to a
current of IO/√ . Bandwidth = f2 – f1 = Hz.
7. Q-factor = f2/(f2-f1).
Dept. of ECE, KSSEM Page 55
63. AEC LAB MANUAL
TABULAR COLUMN
Frequency in
Hz
Output Voltage VO
(V)
FREQUENCY RESPONSE CURVE:
VO(V)
F(Hz)
Fig: Graph of Voltage Vs Frequency
Dept. of ECE, KSSEM Page 56
64. AEC LAB MANUAL
RESULT:
Resonant Frequency =
Bandwidth =
Upper and lower half frequencies =
Q-factor =
Dept. of ECE, KSSEM Page 57
65. AEC LAB MANUAL
BJT DARLINGTON EMITTER FOLLOWER
AIM:
Wiring of BJT Darlington emitter follower with and without Bootstrapping and determination of
the gain, input impedance and output impedance.
COMPONENTS REQUIRED:
Sl.No Components Range Quantity
1 Resistors 1K, 220K, 330K, 4.7K 1
2 Capacitors 0.47μF 2
3 Transistor SL-100 2
4 D.C Variable Power supply (0-30)V 1
5 Multimeter - 1
6 Connecting Wires - 1set
7 Decade Resistance box - 1
THEORY:
In emitter follower, an input signal is applied to the base and the output is taken across the
emitter. The emitter follower has reasonably high input impedance and may be used whenever
impedance up to about 500K is needed. For higher input impedance, we may use two transistors
to form Darlington pair. The output voltage is always less than the input voltage due to drop
between the base and emitter. However, the voltage gain is approximately unity. In addition the
output voltage is in phase with the input voltage. Hence it is said to follow the input voltage with
an in phase relationship. This accounts for the terminology ’Emitter Follower’. The collector is at
ac ground; therefore the circuit is actually common collector amplifier. This circuit presents high
input impedance at the input and low output impedance at the output. It is therefore frequently
used for impedance matching purposes, where load impedance is matched to source impedance
for maximum signal transfer.
The Darlington connection shown is a connection of two transistors which results in a current
gain that is the product of the current gains of the individual transistors. Hence the Darlington
pair operates as one ‘Super Beta Transistor’ offering a very high current gain. The Darlington
Emitter follower is a CC configuration but has the following characteristics.
Voltage Gain = Almost Unity
Current Gain = Very High, a few thousands
Input Impedance = High, hundreds of KΩ
Output Impedance = Low, tens of Ohms
Dept. of ECE, KSSEM Page 58
66. AEC LAB MANUAL
Bootstrapped Emitter Follower: To overcome the decrease in the input impedance due to the
biasing resistors, the input circuit of fig.1 is modified by the addition of the resistor R3 and
capacitor in between R1 and R2 as shown in fig.2. The capacitance is chosen large enough to act
as a short circuit at the lowest frequency of operation. Hence the bottom of R3 is effectively
connected to output and the top of R3 is at the input. Using the concept of Miller’s theorem, the
biasing arrangement R1, R2, R3 represents the input impedance of R3/(1-AV), which is very very
high as AV is almost equal to 1. The term bootstrapping arises from the fact that, if one end of the
resistor of R3 changes in voltage, the other end of R3 moves through the same potential
difference, it is as if R3 is pulling itself by its bootstraps. The output impedance in this case will
be almost equal to that of Darlington circuit
DESIGN:
Let Q-point = (VCE2, IC2) = (5V, 5mA)
Let VCC = 2 VCE2 = 10V
RE =
=
=
=
RE = 1KΩ.
Consider β1 = β2 = β = 50.
IB2 = IE1 =
= 0.1mA
Therefore, IB1 =
=
=
= 0.002mA.
Applying KVL to B-E loop
V2 = 0.6V + 0.6V + 5V = 6.2V
R2 =
=
= 344KΩ. Select 330KΩ
R1 =
=
= 190KΩ. Select 220KΩ
Dept. of ECE, KSSEM Page 59
67. AEC LAB MANUAL
CIRCUIT DIAGRAM:
Fig: Darlington Emitter follower without bootstrap
Fig: Darlington Emitter follower with bootstrap
Dept. of ECE, KSSEM Page 60
68. AEC LAB MANUAL
PROCEDURE:
1. Place the components on the bread/spring board as shown in the figure.
2. Connect the signal generator and apply a sine wave of peak-to-peak amplitude 1V, 1KHz.
Connect the input and output of the circuit to the two channels of the CRO and observe
the waveforms.
3. Gradually increase the input signal until the signal gets distorted. When this happens
slightly reduce the input signal amplitude such that output is maximum undistorted
signal. Then measure the amplitude of the input and output waveform. Calculate the
voltage gain.
4. Connect input and output of the circuit to the two channels of the CRO/DSO and observe
the waveforms. Note down the corresponding waveform on the graph.
5. Find the input and output impedance per given procedure.
6. Connect the bootstrap circuit and make the necessary changes as per figure.
7. Find the input and output impedance with this circuit.
Input Impedance Zi
1. Adjust the input signal peak-peak in such that the output sine wave is not clipped.
2. Note down this value of the input Vin.(Let the frequency of the input signal be around
2KHz)
3. Note down the peak-peak amplitude of the corresponding output VO.
4. Connect a DRB (with zero resistance) in series with the function generator.
5. Increase the resistance in DRB and observe the magnitude of the output VO
simultaneously on the CRO/DSO.
6. When the magnitude of the output VO is reduced to half of its original value, stop varying
the potentiometer further and remove the DRB from the circuit.
7. Measure the value of resistance in DRB and this is measured value will be the input
impedance of the circuit.
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69. AEC LAB MANUAL
Output Impedance ZO
1. Adjust the input signal peak-peak in such that the output sine wave is not clipped.
2. Note down this value of the input Vin.
3. Note down the peak-peak amplitude of the corresponding output VO.
4. Connect a DRB (with maximum resistance) in parallel with the load.
5. When the magnitude of the output VO is reduced to half of its original value, stop varying
the potentiometer further and remove the DRB from the circuit.
6. Measure the value of resistance in DRB and this is measured value will be the output
impedance of the circuit.
RESULT:
Parameters AV = (VO/Vi) Zi ZO
Without Bootstrap
With Bootstrap
Dept. of ECE, KSSEM Page 62
70. AEC LAB MANUAL
TRANSFORMER-LESS CLASS B PUSH-PULL POWER AMPLIFIER
AIM:
Testing of a transformer less class-B push pull power amplifier and determination of its
conversion efficiency.
COMPONENTS REQUIRED:
Sl.No Components Range Quantity
1 Transistors SL-100, SK-100 1
2 Resistors 270Ω 2
3 Variable power supply (0-30)V 1
4 Function Generator - 1
5 DSO - 1
6 Decade Resistance box - 1
7 Connecting Wires - 1set
THEORY:
Push-pull amplifier is basically a class B amplifier, in which a transistor conducts for a half
cycle. For complete conduction, such an amplifier uses two transistors. The arrangement of
transistors is called complementary circuit. During the positive half of the input signal, the NPN
transistor conducts and during negative half of the input signal PNP transistor conducts. The
transistor conducts only if the input voltage across the threshold voltage of 0.7V. This is because
input itself biases the transistors. During this interval, no transistors conducts or output is zero.
This causes a distortion called crossover distortion. If the peak load-voltage equals the supply
voltage, maximum efficiency occurs and the value is 78.5%. The main disadvantage is it uses
two power supply and distortion itself.
Dept. of ECE, KSSEM Page 63
71. AEC LAB MANUAL
CIRCUIT DIAGRAM:
Fig. (1)
PROCEDURE:
1. Place the components on the spring board and connect them as shown in the fig.(1).
2. Connect one channel of the CRO to input signal and connect second channel to the
output.
3. Keep frequency of the function generator around 1KHz and increase the amplitude
around 10V and observe the input and output waveforms. Observe the crossover
distortion.
4. Gradually increase the input signal until the output signal gets distorted. When this
happens slightly reduce the input signal amplitude such that output is maximum
undistorted signal. Note down the Peak value of the output waveform and VCC.
5. Calculate the efficiency using the equation % efficiency =
.
Dept. of ECE, KSSEM Page 64
72. AEC LAB MANUAL
TABULAR COLUMN:
RL in KΩ %Efficiency
1KΩ
.
.
.
.
.
.
.
.
.
.
10KΩ
RESULT:
The efficiency of the class B power amplifier for different load resistance is verified.
Dept. of ECE, KSSEM Page 65
73. AEC LAB MANUAL
BIBLIOGRAPHY
1. “Electronic devices and circuit theory”, Robert L.Boylestad and
Louis Nashelsky.
2. “Integrated electronics”, Jacob Millman and Christos C Halkias.
3. “Electronic devices and circuits”, David A. Bell.
4. “Electronic devices and circuits”, G.K.Mittal.
Dept. of ECE, KSSEM Page 66
74. AEC LAB MANUAL
VIVA-VOCE QUESTIONS
1. What are conductors, insulators, and semi-conductors? Give egs.
2. Name different types of semiconductors.
3. What are intrinsic semiconductors and extrinsic semiconductors?
4. How do you get P-wpe and N-type semiconductors?
5. What is doping? Name different levels of doping.
6. Name different types of Dopants. .
7. What do you understand by Donor and acceptor atoms?
8. What is the other name for p-type and N-type semiconductors?
9. What are majority carriers and minority carriers?
10. What is the effect of temperature on semiconductors?
11. What is drift current? .
12. What is depletion region or space charge region?
13. What is junction potential or potential barrier in PN junctioI).?
14. What is a diode? Name different types of diodes and name its applications
15. What is biasing? Name different types w.r.t. Diode biasing
16. How does a diode behave in its forward and reverse biased conditions?
17. What is static and dyriantic resistance of diode?
18. Why the current in the fo~ard biased diode takes exponential path?
19. What do you understand 1?y AvaJanche breakdown and zener breakdown?
20. Why diode is called unidirectional device.
21. What is PIV of a diode
22. What is knee voltage or cut-in voltage?
23. What do you mean by transition capacitance or space charge capacitor?
24. What do you mean by diffusion capacitance or storage capacitance?
25. What is a transistor? Why is it called so? .
26. Name different types, of transistors?
27. Name different configurations in which the transistor is operated
28. Mention the applications of transistor. Explain how transistor is used as switch
29. What is transistor biasing? Why is it necessary?
30. What are the three different regions in which the transistor works?
31. Why trmisistor is called current controlled device?
32. What is FET? Why it is called so?
33. What are the parameters ofFET?
34. What are the characteristics of FET?
35. Why FET is known as voltage controlled device?
36. What are the differences between BJT and FET?
37. Mention applications ofFET. What is pinch offvQltage, VGS(ofJ) and lDss
38. What is an amplifier? What is the need for an amplifier circuit?
39. How do you classify amplifiers? ,
40. What is faithful amplification? How do you achieve this?
41. What is coupling? Name different type.s of coupling
42. What is operating point or quiescent point?
43. What do you mean by frequency response of an amplifier?
44. What are gain, Bandwidth, lower cutoff frequency and upper cutoff frequency?
45. What is the figure of merit of an amplifier circuit?
Dept. of ECE, KSSEM Page 67
75. AEC LAB MANUAL
46. What are the advantages of RC coupled amplifier?
47. Why a 3db point is taken to calculate Bandwidth?
48. What is semi-log graph sheet? Why it is used to plot frequency response?
49. How do you test a diode, transistor, FET?
50. How do you identify the tenninals of Diode, Transistor& FET? Mention the type
number of the devices used in your lab.
51. Describe the operation ofNPN transistor. Define reverse saturation current.
52. Explain Doping w.r.t. Three regions of transistor
53. Explain the terms hie/hib, hoelhob, hre/hrb, hre/hfb.
54. Explain thermal run-.taway. How it can'be prevented.
55. Define FET parameters and write the relation between them.
56. What are Drain Characteristics and transfer characteristics?
57. Explain the construction and working of FET
58. What is feedback? Name different types.
59. What is the effect of negative feedback on the characteristics of an amplifier?
60. Why common collector amplifier is known as emitter follower circuit?
61. What is the application of emitter follower ckt?
62. What is cascading and cascoding? Why do you cascade the amplifier ckts.?
63. How do you determine the value of capacitor?
64. Write down the diode current equation.
65. Write symbols of various passive and active components
66. How do you determine th~value of resistor by colour code method?
67. What is tolerance and power rating of resistor?
68. Name different types of resistors.
69. How do you c1assify resistors?
70. Name different types of capacitors..
71. What are clipping circuits? Classify them.
72. Mention the application of clipping circuits.
73. What are clamping circuits? Classify them
74. What is the other name of clamping circuits?
75. Mention the applications of clamping circuits.
76. 'What is Darlington emitter follower circuit?
77. Can we increase the number of transistors in Darlington emitter follower circuit?
Justify your answer.
78. What is the different between Darlington emitter follower circuit & Voltage follower
circuit using Op-Amp. Which is better.
79. Name different types of Emitter follower circuits.
80. What is an Oscillator? Classify them.
81. What ar~ The Blocks, which fonns an Oscillator circuits?
82. What are damped & Un-damped Oscillations?
83. What are Barkhausen's criteria?
84. What type of oscillator has got frequency stability?
85. What is the disadvantage of Hartley & Colpiit's Oscillator?
86. Why RC tank Circuit Oscillator is used for AF range?
87. Why LC tank Circuit Oscillator is used for RF range?
88. What type of feedback is used in Oscillator circuit?
89. In a Transistor type No. SL 100 and in Diode BY 127, what does SL and BY stands
Dept. of ECE, KSSEM Page 68
76. AEC LAB MANUAL
for
90. Classify Amplifiers based on: operating point selection.
91. What is the efficiency of Class B push pull amplifier?
92. What is the drawback of Class B Push pull Amplifier? How it is eliminated.
93. What is the advantage of having complimentary symmetry push pull amplifier?
94. What is Bootstrapping? What is the advantage of bootstrapping?
95. State Thevenin's Theorem and Max.power transfer theorem.
96. What is the figure of merit of resonance circuit?
97. What is the application of resonant circuit?
98. What is a rectifier? Classify.
99. What is the efficiency of half wave and full wave rectifier?
100. What is the advantage of Bridge rectifier of Centre tapped type FWR
101. What is the disadvantage of Bridge rectifier?
102. What is a filter?
103. Name different types of filter ckts.
104. Which type of filter is used in day to day application and why?
105. What is ripple and ripple factor? .
106. What is the theoretical value of ripple for Half Wave and .Full wave rectifier?
107. What is need for rectifier ckts.
108. Why a step down transformer is used at the input of Rectifier ckt.
109. What is TUF? .
110. What is regulation w.r.t rectifier? And how it is calculated?
111. What is figure of merit of Rectifier ckt.
Dept. of ECE, KSSEM Page 69
77. AEC LAB MANUAL
QUESTION BANK
ANALOG ELECTRONIC CIRCUITS LAB (10ESL37)
1. A) Design a positive clamping circuit for a given reference voltage of Vref=+2v.
B) Design a negative clamping circuit for a given reference voltage ofVref= -2v.
2. Conduct a suitable experiment to shift the given reference voltage waveform by 4v
a) Above the reference waveform b) Below the reference waveform
3. Design and rig up suitable circuits to shift the given reference sinusoidal input voltage
waveform as shown in the fig.
Vo V0
0 t
-1.5
-6.5 2.5
-11.5 0 t
-2.5
4. Design and rig up suitable circuits for the following transfer function as shown in the fig.
For a sinusoidal/triangular input.(any two to be specified)
Dept. of ECE, KSSEM Page 70
78. AEC LAB MANUAL
5. Design a suitable circuit to clip the reference voltage waveform at two different levels.
Also obtain its transfer characteristics.
6. Rig up a suitable circuit for
A) Diode positive peak clipping. B) Diode negative peak clipping.
7. Conduct an experiment to determine the gain v/s frequency response, input and output
impedances for a RC coupled single stage BJT amplifier.
8. Conduct an experiment to determine gain, input and output impedances for a Darlington
emitter follower circuit with and without bootstrap.
9. Conduct an experiment to obtain a relationship between the bandwidths for a voltage
series feedback circuit with and without feedback.
10. Design the LC oscillator circuits to generate frequency of oscillations at f=100 khz
Using BJT.
Dept. of ECE, KSSEM Page 71
79. AEC LAB MANUAL
11. Design and rig up Hartley and colpitts oscillator circuits for a given frequency using
BJT.
12. Conduct an experiment to generate the given frequency of an oscillation. (type of the
oscillator to be specified).
13. Conduct a suitable experiment to introduce a phase shift of 1800 at an audio frequency
Range.
14. Conduct a suitable experiment to produce sinusoidal oscillations using RC phase shift
network.
15. Conduct a suitable experiment to determine the frequency of oscillations of a given crystal.
16. Determine ripple factor, regulation and efficiency of Half wave Rectifier Circuit with and
Without Capacitor filter.
17. Determine ripple factor, regulation and efficiency of center tapped Full wave Rectifier Circuit with
and Without Capacitor filter.
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80. AEC LAB MANUAL
18. Determine ripple factor, regulation and efficiency of Bridge Rectifier Circuit with and
Without Capacitor filter.
19. Conduct an experiment to verify Thevenin’s Theorem and Maximum Power Transfer theorem.
20. Rig up suitable circuit to determine the Characteristics of Series and Parallel resonant circuits
21. Rig up suitable circuit to determine the Characteristics of RLC circuits.
Dept. of ECE, KSSEM Page 73