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To calculate the concentration of a solution using acid-base titration data Correct In an acid-base
titration, an acid (or base) of known concentration is added to a base (or acid) of unknown
concentration until the number of moles of H and OH are equal, a condition called the
equivalence point. Since you know the number of moles of H (or OH ) that you added, you can
determine the number of moles of OH(or H) in the unknown solution. Part B How many moles
of HNOs are present if 5.80x102 mol of Ba(OH)2 was needed to neutralize the acid solution?
For example, a solution containing 1 mol of H2SO4 contains 2 mol of ionizable hydrogen atoms,
and would therefore require 2 mol of NaOH for neutralization Express your answer with the
appropriate units. View Available Hint(s) Value Units
Solution
Ba(OH)2Â Â +Â Â 2 HNO3Â Â Â -----------------> Ba(NO3)2 +Â Â 2 H2O
1 mol Ba(OH)2Â Â ------------> 2 mol HNO3
5.80 x 10^-2 mol -------------> ??
moles of HNO3 present = 5.80 x 10^-2 x 2
moles of HNO3 present = 0.116 mol

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To calculate the concentration of a solution using acid-base titration.docx

  • 1. To calculate the concentration of a solution using acid-base titration data Correct In an acid-base titration, an acid (or base) of known concentration is added to a base (or acid) of unknown concentration until the number of moles of H and OH are equal, a condition called the equivalence point. Since you know the number of moles of H (or OH ) that you added, you can determine the number of moles of OH(or H) in the unknown solution. Part B How many moles of HNOs are present if 5.80x102 mol of Ba(OH)2 was needed to neutralize the acid solution? For example, a solution containing 1 mol of H2SO4 contains 2 mol of ionizable hydrogen atoms, and would therefore require 2 mol of NaOH for neutralization Express your answer with the appropriate units. View Available Hint(s) Value Units Solution Ba(OH)2Â Â +Â Â 2 HNO3Â Â Â -----------------> Ba(NO3)2 +Â Â 2 H2O 1 mol Ba(OH)2Â Â ------------> 2 mol HNO3 5.80 x 10^-2 mol -------------> ?? moles of HNO3 present = 5.80 x 10^-2 x 2 moles of HNO3 present = 0.116 mol